[R] extract positions from matrix
Hi everyone, I tried to solve this problem but I could not find the solution. I have about 105 matrices of equal size in the memory of**R, I need to do is extract from these matrices some known positions and create a new matrix with these columns. Show you an example with only three matrices (but in my case I have hundreds of them). A=matrix(1:15,5) [,1] [,2] [,3] [1,] 1 6 11 [2,] 2 7 12 [3,] 3 8 13 [4,] 4 9 14 [5,] 5 10 15 B=matrix(15:29,5) [,1] [,2] [,3] [1,] 15 20 25 [2,] 16 21 26 [3,] 17 22 27 [4,] 18 23 28 [5,] 19 24 29 C=matrix(30:44,5) [,1] [,2] [,3] [1,] 30 35 40 [2,] 31 36 41 [3,] 32 37 42 [4,] 33 38 43 [5,] 34 39 44 The positions I wish to extract are 1 and 5 of the first row of each matrix (in my case are 25positions) and with this generate a new matrix with the form d= [,1] [,2] [,3] [1,] 1 15 30 [2,] 5 19 34 The ideais to builda loop toextract thisinformation from hundredsmatrices, butI failed todo so. Any helpwould be greatthank you very muchin advance regards .jpg [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] tuning random forest. An unexpected result
Dear Researches, I am using RF (in regression way) for analize several metrics extract from image. I am tuning RF setting a loop using different range of mtry, tree and nodesize using the lower value of MSE-OOB mtry from 1 to 5 nodesize from1 to 10 tree from 1 to 500 using this paper as refery Palmer, D. S., O'Boyle, N. M., Glen, R. C., Mitchell, J. B. O. (2007). Random Forest Models To Predict Aqueous Solubility. Journal of Chemical Information and Modeling, 47, 150-158. my problem is the following using data(airquality) : the tunning parameters with the lower value is: print(result.mtry.df[result.mtry.df$RMSE == min(result.mtry.df$RMSE),]) *RMSE = 15.44751 MSE = 238.6257 mtry = 3 nodesize = 5 tree = 35* the numer of tree is very low, different respect how i can read in several pubblications And the second value lower is a tunning parameters with *tree = 1* print(head(result.mtry.df[ with(result.mtry.df, order(MSE)), ])) RMSE MSE mtry nodesize tree 12035 15.44751 238.625735 35 *18001 15.44861 238.6595471 *7018 16.02354 256.753925 18 20031 16.02536 256.812151 31 11037 16.02862 256.916533 37 11612 16.05162 257.654434 112 i am wondering if i wrong in the setting or there are some aspects i don't conseder. thanks for attention and thanks in advance for suggestions and help Gianni [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Predicting response from new curves using fda package
Basically all I want to do is predict a scalar response using some curves. I've got as far as doing a regression (using fRegress from the fda package) but have no idea how to apply the results to a NEW set of curves (for prediction). I have N=536 curves, and 536 scalar responses. Here's what I've done so far: * I've created a basis for the curves. * I've created a fdPar object to introduce a penalty * I've created the fd object using smooth.basis to smooth the curves with the chosen penalty on the specified basis. * I've ran a regression using fRegress(), regressing the curves on the scalar response. Now, all I'd like to do, is use that regression to produce predictions for a new set of data that I have. I can't seem to find an easy way to do this. Cheers [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] help
hello mr martin i need the program of lower incomplet Gamma function, and i dont know any thing about mathematica, my gamma function is Y(1/2,r^2/4*teta), r is variable. pleasr help me, its emmidiate for me. all the best somaye node [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Spatial Statistics using R
Thanks a lot for the guidance. I will take a look at these options. Ravi -- View this message in context: http://r.789695.n4.nabble.com/Spatial-Statistics-using-R-tp4079092p4082354.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] building biOps on macports, and configure--vars
Please don't ask non-R programming questions on R-help. This is best asked on R-sig-mac, including details of how you built your R. But the short answer is not to mix macports with the CRAN build of R. And there are matching libs for CRAN's build at http://r.research.att.com/libs/ On Thu, 17 Nov 2011, Timothy Teravainen wrote: All, the MacOSX binary build of the biOps package is broken on cran, so I am trying to compile from source. I am very close; the trick is apparently that this package depends on fftw3, libjpeg and libtiff. My fftw3 is in /usr/local/, but my libjpeg and libtiff are in /opt/local/ since i got them through macports. In general, I'd like to keep as many of my third-party libraries as I can in the macports system, which means that I need to point R CMD INSTALL to /opt/local. Here is the problem I am running into: This is my current command-line: sudo R CMD INSTALL --configure-vars='LIBS=-L/opt/local/lib CPPFLAGS=-I/opt/local/include/' --configure-args='--includedir=/opt/local/include --libdir=/opt/local/include' biOps_0.2.1.1.tar.gz I found that by using the configure--vars argument i can get the 'configure' script to finish (without the configure--vars argument, the 'configure' script of course fails to find libjpeg and libtiff, and exits). However, after 'configure' runs, when the installer actually tries to build the biOps package, it fails as follows: gcc-4.2 -arch x86_64 -std=gnu99 -I/Library/Frameworks/R.framework/Resources/include -I/Library/Frameworks/R.framework/Resources/include/x86_64 -I/usr/local/include-fPIC -g -O2 -c jpegio.c -o jpegio.o jpegio.c:36:21: error: jpeglib.h: No such file or directory pegio.c: In function ‘read_jpg_img_info’: jpegio.c:52: error: storage size of ‘cinfo’ isn’t known jpegio.c:53: error: storage size of ‘jerr’ isn’t known [[... about 30 lines of this follow...]] make: *** [jpegio.o] Error 1 ERROR: compilation failed for package ‘biOps’ The problem is, obviously, that the gcc call is missing -I/opt/local/include, even though I put that in both --configure-vars and --configure-args! I also note, that the '--configure-args' seems to have no effect at all. It's '--configure-vars' that allows the 'configure' script to finish successfully. I've searched and read various docs, but I don't know what else I can do at this point (i'd like to avoid copying my libraries into /usr/local if at all possible, and it does seem that the point of the configure--foo arguments is to let me do that). Am I missing a necessary argument? Is it a bug in the biOps package? Is there any solution/workaround that doesn't involve copying stuff into /usr/local? Thanks for any help. Yours, Timothy Teravainen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Brian D. Ripley, rip...@stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595__ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Fisher Exact Test
This mean First, I am no expert but I am analyzing some marketing data. I have information on two versions of the same site, and I have data on the number of times people filled out a form on each version of the site. Sample data: Site 1 Site 2 Filled out form1035 Did not fill out form 5040 dat2 = matrix(c(10,50,35,40), ncol=2) dat2 fisher.test(dat2) fisher.test(dat2) Fisher's Exact Test for Count Data data: dat2 p-value = 0.0002381 alternative hypothesis: true odds ratio is not equal to 1 95 percent confidence interval: 0.09056509 0.54780215 sample estimates: odds ratio 0.2311144 I'm really not sure if I set up the test properly, but I can obviously reject the null hypothesis given the low p-value. Site 2 converts better than site 2 at a statistically significant threshold. Am I running my code wrong? Can anyone help? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Adding a year to existing date
Hi
On 17/11/11 17:33, arunkumar wrote:
Hi
I need to add an year to and date field in the dataframe.
Please help me
X Date
1 2008-01-01
2 2008-02-01
3 2003-03-01
I can't find anything built in. This is probably because year is an
ill-defined
unit; years vary in length in a somewhat peculiar fashion. So doing
arithmetic
with respect to years is frowned on.
However you might try this:
`%+%` - function(x,y){
if(!isTRUE(all.equal(y,round(y stop(Argument \y\ must be an
integer.\n)
x - as.POSIXlt(x)
x$year - x$year+y
as.Date(x)
}
Then:
xxx - as.Date(c(2008-01-01,2008-02-01,2003-03-01))
xxx %+% 1
[1] 2009-01-01 2009-02-01 2004-03-01
another option is
paste((as.numeric(format(xxx, %Y))+1), format(xxx,%m-%d), sep=-)
Regards
Petr
Dunno what dangers lurk; caveat utilitor.
cheers,
Rolf Turner
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