Re: [R] Reordering levels of a factor within a lattice dotplot
On Fri, Jun 22, 2012 at 5:50 PM, maxbre mbres...@arpa.veneto.it wrote:
Given my reproducible example
myexample-structure(list(site = structure(c(4L, 2L, 2L, 4L, 2L, 4L, 4L,
3L, 1L, 3L, 1L, 1L, 3L, 4L, 5L, 2L), .Label = c(A, B, C,
D, E), class = factor), obs = c(0.302, 0.956, 0.72, 1.21,
0.887, 0.728, 1.294, 20.493, 0.902, 0.031, 0.468, 2.318, 4.795,
89.581, 4.59, 3618.353), sample = structure(c(6L, 6L, 2L, 8L,
7L, 7L, 9L, 4L, 4L, 1L, 1L, 3L, 3L, 10L, 11L, 5L), .Label = c(18/08/2009,
20/04/2009, 03/12/2008, 17/03/2009, 05/01/2012, 21/04/2009,
17/07/2009, 17/04/2009, 21/07/2009, 29/01/2009, 16/07/2008
), class = factor, scores = structure(c(2, 3, 2, 3, 4, 4, 2,
5, 2, 4, 2), .Dim = 11L, .Dimnames = list(c(18/08/2009, 21/04/2009,
20/04/2009, 17/07/2009, 17/04/2009, 21/07/2009, 03/12/2008,
16/07/2008, 17/03/2009, 29/01/2009, 05/01/2012), .Names =
c(site,
obs, sample), row.names = c(NA, -16L), class = data.frame)
I want to dotplot with lattice the observations (obs) against sampling dates
(sample) for each site but I need to reorder the factor levels of sampling
dates based on the value of observations within each site (rather than
keeping the original arbitrary data)
These are my two best (?) attempts both of them not properly working for
different reasons
#start
library(lattice); library(latticeExtra)
#first attempt
myexample$sample-
with(myexample, reorder(sample,obs))
dotplot(sample ~ obs | site, data=myexample,
scales=list(x=list(log=TRUE), y=list(relation=free)),
xscale.components = xscale.components.logpower,
strip=FALSE, strip.left=TRUE, layout=c(1,5),
index.cond= function(x,y){median(x)},
panel = function(x,y,...) {
panel.dotplot(x,y,...)
panel.abline(v = median(x), col.line=red, lty=dotted)
}
)
#second attempt
myexample$sample-
with(myexample, reorder(reorder(sample,obs), as.numeric(site)))
dotplot(sample ~ obs | site, data=myexample,
scales=list(x=list(log=TRUE), y=list(relation=free)),
xscale.components = xscale.components.logpower,
strip=FALSE, strip.left=TRUE, layout=c(1,5),
index.cond= function(x,y){median(x)},
panel = function(x,y,...) {
panel.dotplot(x,y,...)
panel.abline(v = median(x), col.line=red, lty=dotted)
}
)
#end
There is to note the presence of some ties (i.e. same sampling dates,
particularly noticeable for site A and B).
The number of factor levels related to sampling dates (11) is different than
total number of observations (17): is this responsible for the lack of
reordering for factor sample in the dotplot?
How to fix this ? How to get a neat y axis without that “holes” in between
of the sampling dates within each site?
Should I try to make somehow as much factor levels as the observations so
that to avoid this sort of problem? Is there any alternative solution?
Yes, you need to avoid duplicates. Here is one way to do that:
myexample$sampleLabel - as.character(myexample$sample)
myexample$sampleId - gl(length(myexample$sample), 1)
myexample$sample2 -
with(myexample, reorder(reorder(sampleId, obs),
as.numeric(site)))
## correct plot, but useless y-axis labels
dotplot(sample2 ~ reorder(site, obs) | site, data = myexample,
scales=list(x=list(log=TRUE), y=list(relation=free)),
xscale.components = xscale.components.logpower,
strip=FALSE, strip.left=TRUE, layout=c(1,5))
## match reordered levels with original order, and set axis labels
nl - as.numeric(levels(myexample$sample2))
dotplot(sample2 ~ obs | reorder(site, obs), data = myexample,
scales=list(x=list(log=TRUE), y=list(relation=free)),
ylim = myexample$sampleLabel[nl],
xscale.components = xscale.components.logpower,
strip=FALSE, strip.left=TRUE, layout=c(1,5))
-Deepayan
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Re: [R] Reordering levels of a factor within a lattice dotplot
thanks a lot deepayan, I will study carefully your code! thanks max -- View this message in context: http://r.789695.n4.nabble.com/Reordering-levels-of-a-factor-within-a-lattice-dotplot-tp4634201p4634277.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] matching a string with multiple conditions using grep
Suppose I have a vector [A_cont_1, A_cont_12, B_treat_8, AB_cont_22, cont_21_Aa], I hope I can extract the strings which include 3 short strings, say A, cont and 2, that is to say, A_cont_12, AB_cont_22 and cont_21_Aa will be extract, using a relatively short code (using grep?). Would you please to give some idea? Thank you ! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] incomplete gamma function with negative arguments
Dear list, Is there an incomplete gamma function in R that can take negative arguments? If not, pointers to its implementation will be greatly appreciated. I know the 'Igamma' function in 'zipfR' package. However, Igamma(a,x) only takes positive x. (When x is negative, this function should return a value that is complex. Matlab function 'gammainc' can handle negative arguments. But it is an internal Matlab function, so I don't get to see how it is done.) Thanks! X.W. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Uniroot error message with in intergration
Many thanks Ellison
I have modified it as you suggested but I have this error message Error
in f(lower, ...) : unused argument(s) (N = 54)
I am not sure which arguments I have missed?
*y - function(t,n){
diff - 0.5
df1 - 2*n-2
ncp1 - sqrt((diff^2*n)/2)
p - 1- pt(t,df=df1)
test - qt((1-p),df=df1,ncp=ncp1)*(1/sqrt(2))
return(test)
}
integ - function(n){
1-integrate(y,lower=0,upper=2.7,n)$value -0.8
}
uniroot(integ,lower=0,upper=1000,N=n)
traceback()*
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Re: [R] matching a string with multiple conditions using grep
Hello, Try the following. wanted - c(A_cont_12, AB_cont_22, cont_21_Aa) x - c(A_cont_1, A_cont_12, B_treat_8, AB_cont_22, cont_21_Aa) pattern - c(A, cont, 2) ix - Reduce(``, lapply(pattern, grepl, x)) # This does the trick identical(wanted, x[ix]) See ?Reduce. Hope this helps, Rui Barradas Em 23-06-2012 11:19, Zhipeng Wang escreveu: Suppose I have a vector [A_cont_1, A_cont_12, B_treat_8, AB_cont_22, cont_21_Aa], I hope I can extract the strings which include 3 short strings, say A, cont and 2, that is to say, A_cont_12, AB_cont_22 and cont_21_Aa will be extract, using a relatively short code (using grep?). Would you please to give some idea? Thank you ! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Event Studies in R
Dear all I tried finding a package for event studies but unfortunately without success. Does anyone know which package suits best for such an analysis? Thank you in advance. Regards [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Can't save a plot
Hi,
I can't save a plot in R. Even the most simple examples taken from the
internet doesn't work:
jpeg('rplot.jpg')
plot(1:10)
dev.off()
The message that I receive is:
jpeg('rplot.jpg')
plot(1:10)
dev.off()
null device
1
I've also tried using png, pdf, and so on...
I've windows 7 64b.
Ive tried R 2.15.0 x86 and x64, same result in both.
Can anyone tell me what is wrong?
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Re: [R] Can't save a plot
Are you sure it's not working? That's exactly what the console is
supposed to display (the message means you've switched from the jpeg
_to_ the null device) -- check again to make sure the file wasn't
created -- I think you'll be pleasantly surprised.
If you're not sure where to check, look in the directory returned by
getwd(); you can do this from within R by using list.files()
Best,
Michael
On Sat, Jun 23, 2012 at 5:47 AM, Tomek.Tarczynski
tomek.tarczyn...@gmail.com wrote:
Hi,
I can't save a plot in R. Even the most simple examples taken from the
internet doesn't work:
jpeg('rplot.jpg')
plot(1:10)
dev.off()
The message that I receive is:
jpeg('rplot.jpg')
plot(1:10)
dev.off()
null device
1
I've also tried using png, pdf, and so on...
I've windows 7 64b.
Ive tried R 2.15.0 x86 and x64, same result in both.
Can anyone tell me what is wrong?
--
View this message in context:
http://r.789695.n4.nabble.com/Can-t-save-a-plot-tp4634281.html
Sent from the R help mailing list archive at Nabble.com.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Boxplot with Log10 and base-exponent axis
Thank you! This works good. I understand that the value are now in Log10 scale, although I did not understand what is happening at line 4 of your script. I would like to ask how can I change the y limits since they now depend on par(user). What if I'd like y limits extending from 1000 to 1 000 000? I've tried to modify ylim (line 3) and ceiling (line 4) but I obtained errors. Best wishes, Luigi ### UPDATED EXAMPLE # generationg random numbers x-runif(100, min=0, max=10) #plotting boxplot(x, log = y, yaxt=n) ylim - par(usr)[3:4] log10AtY - seq(ceiling(ylim[1]), floor(ylim[2])) axis(side=2, at=10^log10AtY, lab=as.expression(lapply(log10AtY, function(y)bquote(10^.(y) # -- Your Response The key is to supply an expression, not text, to the labels argument to axis. See help(plotmath) for details. Here is an example: 1 x - list(One=10^(sin(1:10)+5), Two=10^(cos(1:30)*2)) 2 boxplot(x, log=y, yaxt=n) 3 ylim - par(usr)[3:4] 4 log10AtY - seq(ceiling(ylim[1]), floor(ylim[2])) 5 axis(side=2, at=10^log10AtY, lab=as.expression(lapply(log10AtY, function(y)bquote(10^.(y) Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Luigi Sent: Friday, June 22, 2012 7:54 AM To: r-help@r-project.org Subject: [R] Boxplot with Log10 and base-exponent axis Dear all, I would like to (i) produce boxplot graphs with axis in logarithm in base 10 and (ii) showing the values on the axis in 10^exponent format rather than 10E+exponent. To illustrate with an example, I have some widely spread data that I chart plot using boxplot() [figure on the left]; the log=y option of boxplot() I obtained the natural logarithm conversion of the data and the unfriendly notation baseE+exponent [figure on the centre]; if I log10 the data I obtain the desired plot, but the axis are showing only the exponent. [figure on the right]. Can anybody help? Best regards Luigi Marongiu, MSc ### EXAMPLE # generationg random numbers x-runif(100, min=0, max=10) # create plot par(mfrow = c(1,3)) #plotting in the left side boxplot(x, xlab=Linear values) #plotting in the centre boxplot(x, log = y, xlab=y axis logged) # creating log10 values and plotting on the right side Log.base10.x-log10(x) boxplot(Log.base10.x, xlab=LOG10 of data) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Event Studies in R
Ivan, You need to be more specific if you want an answer. What kind of events? With or without attributes? Species extinction? Formula 1 races? Web clicks? Jim Porzak Minted.com San Francisco, CA www.linkedin.com/in/jimporzak use R! Group SF: www.meetup.com/R-Users/ On Sat, Jun 23, 2012 at 5:36 AM, ivan i.pet...@gmail.com wrote: Dear all I tried finding a package for event studies but unfortunately without success. Does anyone know which package suits best for such an analysis? Thank you in advance. Regards [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Problem with converting character vector to time
It's not entirely clear where your trying to go with your problem, but one 'solution' depending on your destination could be: time_obj-format(as.POSIXct(test,format=%H:%M:%S),format=%H:%M:%S) time_obj [1] 00:49:19 class(time_obj) [1] character But this is a fairly unsatisfactory solution since it simply undoes the application of as.POSIXct Perhaps you can share more of your problem so folks responding know where you're trying to get to. -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-converting-character-vector-to-time-tp4634283p4634293.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Event Studies in R
I suspect Ivan is looking for packages to do discrete-event simulation like simulation of queues. Paul On Sat, Jun 23, 2012 at 5:15 PM, Jim Porzak jpor...@gmail.com wrote: Ivan, You need to be more specific if you want an answer. What kind of events? With or without attributes? Species extinction? Formula 1 races? Web clicks? Jim Porzak Minted.com San Francisco, CA www.linkedin.com/in/jimporzak use R! Group SF: www.meetup.com/R-Users/ On Sat, Jun 23, 2012 at 5:36 AM, ivan i.pet...@gmail.com wrote: Dear all I tried finding a package for event studies but unfortunately without success. Does anyone know which package suits best for such an analysis? Thank you in advance. Regards [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Boxplot with Log10 and base-exponent axis
To change the y-limits you need to add ylim=c(min,max) to the call to boxplot. The limits there should be in the units of the y variable (not its log10). par(usr)[3:4] report the y-limits on the log10 scale (they will be expanded a bit from your desired limits so the plot does not extend all the way to edge). boxplot(abs(tan(1:100)), log=y, ylim=c(.001, 1000)) par(usr)[3:4] [1] -3.24 3.24 10 ^ par(usr)[3:4] [1] 5.754399e-04 1.737801e+03 Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com -Original Message- From: Luigi [mailto:marongiu.lu...@gmail.com] Sent: Saturday, June 23, 2012 8:49 AM To: William Dunlap Cc: 'Martin Maechler'; r-help@r-project.org Subject: RE: [R] Boxplot with Log10 and base-exponent axis Thank you! This works good. I understand that the value are now in Log10 scale, although I did not understand what is happening at line 4 of your script. I would like to ask how can I change the y limits since they now depend on par(user). What if I'd like y limits extending from 1000 to 1 000 000? I've tried to modify ylim (line 3) and ceiling (line 4) but I obtained errors. Best wishes, Luigi ### UPDATED EXAMPLE # generationg random numbers x-runif(100, min=0, max=10) #plotting boxplot(x, log = y, yaxt=n) ylim - par(usr)[3:4] log10AtY - seq(ceiling(ylim[1]), floor(ylim[2])) axis(side=2, at=10^log10AtY, lab=as.expression(lapply(log10AtY, function(y)bquote(10^.(y) # -- Your Response The key is to supply an expression, not text, to the labels argument to axis. See help(plotmath) for details. Here is an example: 1 x - list(One=10^(sin(1:10)+5), Two=10^(cos(1:30)*2)) 2 boxplot(x, log=y, yaxt=n) 3 ylim - par(usr)[3:4] 4 log10AtY - seq(ceiling(ylim[1]), floor(ylim[2])) 5 axis(side=2, at=10^log10AtY, lab=as.expression(lapply(log10AtY, function(y)bquote(10^.(y) Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Luigi Sent: Friday, June 22, 2012 7:54 AM To: r-help@r-project.org Subject: [R] Boxplot with Log10 and base-exponent axis Dear all, I would like to (i) produce boxplot graphs with axis in logarithm in base 10 and (ii) showing the values on the axis in 10^exponent format rather than 10E+exponent. To illustrate with an example, I have some widely spread data that I chart plot using boxplot() [figure on the left]; the log=y option of boxplot() I obtained the natural logarithm conversion of the data and the unfriendly notation baseE+exponent [figure on the centre]; if I log10 the data I obtain the desired plot, but the axis are showing only the exponent. [figure on the right]. Can anybody help? Best regards Luigi Marongiu, MSc ### EXAMPLE # generationg random numbers x-runif(100, min=0, max=10) # create plot par(mfrow = c(1,3)) #plotting in the left side boxplot(x, xlab=Linear values) #plotting in the centre boxplot(x, log = y, xlab=y axis logged) # creating log10 values and plotting on the right side Log.base10.x-log10(x) boxplot(Log.base10.x, xlab=LOG10 of data) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Event Studies in R
Bill Alpert and I thought about creating a package from when we worked together on an event study. But our experience was that most of the work was in aligning the data and virtually none of what we did was generalizable. Maybe someone has found a way to make a useful package, but I'm doubtful. Pat On 23/06/2012 13:36, ivan wrote: Dear all I tried finding a package for event studies but unfortunately without success. Does anyone know which package suits best for such an analysis? Thank you in advance. Regards [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Patrick Burns pbu...@pburns.seanet.com twitter: @portfolioprobe http://www.portfolioprobe.com/blog http://www.burns-stat.com (home of 'Some hints for the R beginner' and 'The R Inferno') __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Can't save a plot
I'm a bit ashamed, because it actually works, but I'd some problems with the privilages because it is not working when I set wd to c:\, when I changed I used default wd everything is working. Thanks for pointing out my ingorance! Best, Tomek -- View this message in context: http://r.789695.n4.nabble.com/Can-t-save-a-plot-tp4634281p4634289.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] sparse distance object?
R community, I am trying to cluster large omics datasets (10,000-20,000 variables). Obviously, with datasets of this size, PC memory is an issue. I am using a custom distance metric, and am able to generate a dissimilarity matrix in sparse format. To cluster, for example, using heirarchical clustering (hclust, or fastcluster::hclust), I need to submit the dataset as a distance object. I can use as.dist() to acheive this, but in doing so the sparse matrix format is expanded to its full form, which quickly consumes all the memory on most desktop PCs. My question is then: 1. Is there a clustering tool that can take as input a sparse dissimilarity matrix directly without expanding it? 2. alternatively, is there a sparse distance object format that I can't seem to find (an alternative to as.dist(), for example)? Any advice is appreciated. Corey [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Using at.level() with a MCMCglmm zero-inflated poisson model
I have a question for users of MCMCglmm that have experience implementing the zero-inflated poisson model. I find that the documentation, and previous questions, do not offer a lot of clear guidance on specifying and interpreting the zipoisson model. In particular, I see a lot of zero-inflated poisson examples that use the at.level(trait, x):variableName syntax. Specifically, the MCMCglmm course notes, available on the package's CRAN page, uses the following example on page 102: m5d.1 - MCMCglmm(art ~ trait - 1 + at.level(trait, 1):fem + at.level(trait, 1):mar + at.level(trait, 1):kid5 + at.level(trait, 1):phd + at.level(trait, 1):ment, rcov = ~idh(trait):units, data = bioChemists, prior = prior.m5d.1, family = zipoisson, verbose = FALSE) I have been unable to find an answer to the following questions and would appreciate any guidance: 1) Does at.level(trait, 1) index the poisson latent variable, or is that at.level(trait,2)? More generally, how does one find out what levels, and what values, are indexed with trait? 2) Why is the example specified only using the trait 1? That is, why not estimate the model in the following fashion: m5d.1 - MCMCglmm(art ~ trait + trait:fem + trait:mar + trait:kid5 + trait:phd + trait:ment, rcov = ~idh(trait):units, data = bioChemists, prior = prior.m5d.1, family = zipoisson, verbose = FALSE) 3) How do we properly interpret the results from the two models, say using summary(m5d.1) ? I would appreciate any pointers to relevant documentation/examples. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] matching a string with multiple conditions using grep
Dear Barradas, and Dear A.K.
Thank you so much for the solutions. I got them.
I think I will study more about regular expression and apply family.
Best Regards,
Wang
2012/6/24 arun smartpink...@yahoo.com
Hi,
Try this:
vec1-c(A_cont_1, A_cont_12, B_treat_8, AB_cont_22, cont_21_Aa)
vec2-grep((A){0,1}.*cont.*2,vec1)
vec1[vec2]
[1] A_cont_12 AB_cont_22 cont_21_Aa
A.K.
- Original Message -
From: Zhipeng Wang wa...@kuhp.kyoto-u.ac.jp
To: r-help@r-project.org
Cc:
Sent: Saturday, June 23, 2012 6:19 AM
Subject: [R] matching a string with multiple conditions using grep
Suppose I have a vector [A_cont_1, A_cont_12, B_treat_8,
AB_cont_22, cont_21_Aa], I hope I can extract the strings which include
3 short strings, say A, cont and 2, that is to say, A_cont_12,
AB_cont_22 and cont_21_Aa will be extract, using a relatively short
code (using grep?).
Would you please to give some idea? Thank you !
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