[R] how to plot the spectrum by log-log axis
hi I have a wind dataset and I want to analze its spectrum with the x-axis and y-axis in log .But I found that when I set log=dB in spectrum as shown below,what I can get is a figure by log y-axis. How could I get a log-axis figure both in x-axis and y-axis ? thank you . yylab-c(Wind Spectrum(db) ) YY=c(-40,40) spectrum(ww_spec,log = dB,ylim=YY,main=maininfo,ylab=yylab) -- TANG Jie [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to plot the spectrum by log-log axis
Futher more When I write as below :,the result is still not satisfied . asp=spectrum(ww_spec) windspec=data.frame(asp) plot(windspec,log=dB) 2014/1/7 Jie Tang totang...@gmail.com hi I have a wind dataset and I want to analze its spectrum with the x-axis and y-axis in log .But I found that when I set log=dB in spectrum as shown below,what I can get is a figure by log y-axis. How could I get a log-axis figure both in x-axis and y-axis ? thank you . yylab-c(Wind Spectrum(db) ) YY=c(-40,40) spectrum(ww_spec,log = dB,ylim=YY,main=maininfo,ylab=yylab) -- TANG Jie -- TANG Jie Email: totang...@gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help
Hi and what is wrong with e.g. fit - neuralnet(pH~station+month, data=yourdata) As I said I am not an expert in neural nets but here is some explanation how it works http://gekkoquant.com/2012/05/26/neural-networks-with-r-simple-example/ based on that after fitting you could do compute(fit, testdata) where testdata shall be station and month. However for time series it can be more appropriate something like ARIMA modelling. Petr From: javad bayat [mailto:j.bayat...@gmail.com] Sent: Monday, January 06, 2014 5:58 PM To: PIKAL Petr Subject: Re: [R] help Dear Petr; I want to write function that: for example for pH: according these 20 months predict the variability of pH for next month and stations. all best. On Mon, Jan 6, 2014 at 7:23 PM, PIKAL Petr petr.pi...@precheza.czmailto:petr.pi...@precheza.cz wrote: Hi can you be more specific? In what aspect those packages does not comply with your data? What did you do for testing it? I am not an expert in neural networks but I do not see anything which prevents using your data in nnet. Petr -Original Message- From: r-help-boun...@r-project.orgmailto:r-help-boun...@r-project.org [mailto:r-help-bounces@r-mailto:r-help-bounces@r- project.orghttp://project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 3:16 PM To: R-help@r-project.orgmailto:R-help@r-project.org Subject: Re: [R] help Dear Petr; I saw the nnet and neuralnet packag, and I cant find some thing relating with my data based on neural network. On Mon, Jan 6, 2014 at 10:55 AM, PIKAL Petr petr.pi...@precheza.czmailto:petr.pi...@precheza.cz wrote: Hi Why you did not use dput for sending data? It is far better than picture, which can not be used without retyping. Redarding neural network, did you try e.g. nnet or neuralnet package. Petr -Original Message- From: r-help-boun...@r-project.orgmailto:r-help-boun...@r-project.org [mailto:r-help-bounces@r-mailto:r-help-bounces@r- project.orghttp://project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 7:37 AM To: R-help@r-project.orgmailto:R-help@r-project.org Subject: Re: [R] help Dear all; many thanks for your answers. Hear is my data (not all row: the station was 8 station at 20 month) which I forward it as image. I hope some one can help me to do Neural network for prediction of next month. many thanks. all bests. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.commailto:bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.commailto:bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.orgmailto:R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.commailto:bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to plot the spectrum by log-log axis
I use windlog=log10(windspec) plot(windlog) it seems good but stupid is there any better method ? 2014/1/7 Jie Tang totang...@gmail.com Futher more When I write as below :,the result is still not satisfied . asp=spectrum(ww_spec) windspec=data.frame(asp) plot(windspec,log=dB) 2014/1/7 Jie Tang totang...@gmail.com hi I have a wind dataset and I want to analze its spectrum with the x-axis and y-axis in log .But I found that when I set log=dB in spectrum as shown below,what I can get is a figure by log y-axis. How could I get a log-axis figure both in x-axis and y-axis ? thank you . yylab-c(Wind Spectrum(db) ) YY=c(-40,40) spectrum(ww_spec,log = dB,ylim=YY,main=maininfo,ylab=yylab) -- TANG Jie -- TANG Jie Email: totang...@gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China -- TANG Jie Email: totang...@gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help
Dear Javad Bayat I think that people on this list has been most helpful to your with your questions about how to use neural networks in R. Now you have come to the point where you need a more statistical understanding of your data before you can decide whether neural network methods is really the best way for you to do forecasting. Let me illustrate that. I'm doing this in R. ### Rscript start ## import your data bayat - read.table(bayat.txt, h = TRUE) ## attach the neuralnet package library(neuralnet) ## fit a simple model fit - neuralnet(pH ~ station + month, data = bayat) ## create new data into the future futuredata - expand.grid(station = 1:8, month = 21:25) ## do predictions predictions - compute(fit, futuredata) predictions - data.frame(predictions[[neurons]][[1]][,2:3], pH = predictions$net.result) head(predictions) station month pH 1 121 8.294072681 2 221 8.294072683 3 321 8.294072684 4 421 8.294072685 5 521 8.294072685 6 621 8.294072686 ## plot the results together with original data library(lattice) library(latticeExtra) xyplot(pH ~ month|factor(station), data = bayat, type = b, layout = c(4,2), xlim = c(0:26))+ xyplot(pH ~ month|factor(station), data = predictions, type = b, layout = c(4,2), col = red) ## calculate mean pH for each station aggregate(list(pH = bayat$pH), by = list(station = bayat$station), mean) station pH 1 1 8.3215 2 2 8.4640 3 3 8.2890 4 4 8.2100 5 5 8.3240 6 6 8.4575 7 7 8.2085 8 8 8.0645 ## overall mean of pH mean(bayat$pH) [1] 8.292375 ### Rscript end ### Here is my comment to the results. I have attached the plot as a png file (hope it makes its way to the list). The blue curve is the original data and red curve is the predictions into the future. As you can see the levels of pH is somewhat constant during the measurement periods. The deviations from constant levels may be due solely to measurement errors. As you can see from the figure that using the fitted simple neural network to forecast is not that good. It seem that the neural network forecast the value of pH to be the overall mean for all stations. Your're a master student so I would strongly suggest that you consider the following points together with your supervisor. 1. Make plots of your data(all responses) to see how your data behave and show the plots to your supervisor. 2. Discuss with your supervisor what kind of underlying processes the data comes from. Then you can probably make some assumptions on some cyclic behavior of the data such as a seasonal variation (as month = 1:20 this variable does not define any seasonality). 3. Is neural network really the method to use here? Discuss with your supervisor whether there could be other methods from theory on time series analysis that could be useful. 4. Have a look at the Task Views at CRAN (http://cran.r-project.org/web/views/): see e.g. TimeSeries, MachineLearning, Environmetrics, Econometrics, Finance. I do not have time to help you further. If you have further questions please contact your supervisor. Yours sincerely / Med venlig hilsen Frede Aakmann Tøgersen Specialist, M.Sc., Ph.D. Plant Performance Modeling Technology Service Solutions T +45 9730 5135 M +45 2547 6050 fr...@vestas.com http://www.vestas.com Company reg. name: Vestas Wind Systems A/S This e-mail is subject to our e-mail disclaimer statement. Please refer to www.vestas.com/legal/notice If you have received this e-mail in error please contact the sender. -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of PIKAL Petr Sent: 7. januar 2014 09:01 To: javad bayat Cc: R-help@r-project.org Subject: Re: [R] help Hi and what is wrong with e.g. fit - neuralnet(pH~station+month, data=yourdata) As I said I am not an expert in neural nets but here is some explanation how it works http://gekkoquant.com/2012/05/26/neural-networks-with-r-simple- example/ based on that after fitting you could do compute(fit, testdata) where testdata shall be station and month. However for time series it can be more appropriate something like ARIMA modelling. Petr From: javad bayat [mailto:j.bayat...@gmail.com] Sent: Monday, January 06, 2014 5:58 PM To: PIKAL Petr Subject: Re: [R] help Dear Petr; I want to write function that: for example for pH: according these 20 months predict the variability of pH for next month and stations. all best. On Mon, Jan 6, 2014 at 7:23 PM, PIKAL Petr petr.pi...@precheza.czmailto:petr.pi...@precheza.cz wrote: Hi can you be more specific? In what aspect those packages does not comply with your data? What did you do for testing it? I am not an expert in neural networks but I do not see anything which prevents using your data in nnet. Petr -Original Message- From:
[R] The R Journal, Volume 5, Issue 2
Dear all, The latest issue of The R Journal is now available at http://journal.r-project.org/archive/2013-2/ Many thanks to all contributors. Hadley -- Editor-in-chief, The R Journal ___ r-annou...@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-announce __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How do I perform conditional annotation of lattice panel plots?
My apologies for asking this question that may have been asked before. I am trying to plot activity dependent on time conditioned by the subject. Code for sample data below. So I have something like this xyplot(Activity~Time|Subject). This works fine, but now I want to show where on these activity curves Event A occurs. This is to explore the relationship between A and activity. I tried this: xyplot(EventA+Activity~Time|Subject) but then the numerical ordering gets out of order. Ideally Event A could be denoted by a vertical line cutting through the curve at the day Event A occurred, but some other way to denote it would be great! Here is my sample data as R code: Subject-c(1,1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4) Day-c(1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6) Activity-c(2,3,4,3,7,4,5,8,2,8,4,6,2,5,3,8,9,5,6,3,4,5,6,7) EventA-c(Yes,NA,Yes,NA,NA,NA,Yes,NA,NA,NA,NA,NA, Yes,NA,NA,NA,NA,NA,NA,NA,Yes,NA,NA,NA) Data-data.frame(cbind(Subject,Day,Activity,EventA)) Subject Day Activity EventA 11 12Yes 21 23 NA 31 34Yes 41 43 NA 51 57 NA 61 64 NA 72 15Yes 82 28 NA 92 32 NA 10 2 48 NA 11 2 54 NA 12 2 66 NA 13 3 12Yes 14 3 25 NA 15 3 33 NA 16 3 48 NA 17 3 59 NA 18 3 65 NA 19 4 16 NA 20 4 23 NA 21 4 34Yes 22 4 45 NA 23 4 56 NA 24 4 67 NA Any ideas on how to do this would be appreciated! Thanks very much in advance! This email message may contain legally privileged and/or confidential information. If you are not the intended recipient(s), or the employee or agent responsible for the delivery of this message to the intended recipient(s), you are hereby notified that any disclosure, copying, distribution, or use of this email message is prohibited. If you have received this message in error, please notify the sender immediately by e-mail and delete this email message from your computer. Thank you. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] NAs introduced by coercion warning, while plotting data
Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
From your output, it looks like 'datalist' is a character string and not a numeric vector as you expect. Try doing: str(datalist) to see the structure and to use dput(datalist) to post the data. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:01 AM, Baro babak...@gmail.com wrote: thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
Thank you sir: If I am tying str(datalist) I have this output chr 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, | __truncated__ and if I try: dput(datalist) I have: 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 ; On Tue, Jan 7, 2014 at 7:11 AM, jim holtman jholt...@gmail.com wrote: From your output, it looks like 'datalist' is a character string and not a numeric vector as you expect. Try doing: str(datalist) to see the structure and to use dput(datalist) to post the data. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:01 AM, Baro babak...@gmail.com wrote: thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list
Re: [R] help
I apologies for asking this question; I run the codes but why all the prediction for pH in 21-25 month are so close? station month pH 1 21 8.275635958 2 21 8.275635962 3 21 8.275635963 4 21 8.275635963 5 21 8.275635963 6 21 8.275635963 On Tue, Jan 7, 2014 at 2:12 PM, javad bayat j.bayat...@gmail.com wrote: Dear Pikal Petr; thanks for code. It was usefull. On Tue, Jan 7, 2014 at 11:30 AM, PIKAL Petr petr.pi...@precheza.czwrote: Hi and what is wrong with e.g. fit - neuralnet(pH~station+month, data=yourdata) As I said I am not an expert in neural nets but here is some explanation how it works http://gekkoquant.com/2012/05/26/neural-networks-with-r-simple-example/ based on that after fitting you could do compute(fit, testdata) where testdata shall be station and month. However for time series it can be more appropriate something like ARIMA modelling. Petr *From:* javad bayat [mailto:j.bayat...@gmail.com] *Sent:* Monday, January 06, 2014 5:58 PM *To:* PIKAL Petr *Subject:* Re: [R] help Dear Petr; I want to write function that: for example for pH: according these 20 months predict the variability of pH for next month and stations. all best. On Mon, Jan 6, 2014 at 7:23 PM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi can you be more specific? In what aspect those packages does not comply with your data? What did you do for testing it? I am not an expert in neural networks but I do not see anything which prevents using your data in nnet. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 3:16 PM To: R-help@r-project.org Subject: Re: [R] help Dear Petr; I saw the nnet and neuralnet packag, and I cant find some thing relating with my data based on neural network. On Mon, Jan 6, 2014 at 10:55 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi Why you did not use dput for sending data? It is far better than picture, which can not be used without retyping. Redarding neural network, did you try e.g. nnet or neuralnet package. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 7:37 AM To: R-help@r-project.org Subject: Re: [R] help Dear all; many thanks for your answers. Hear is my data (not all row: the station was 8 station at 20 month) which I forward it as image. I hope some one can help me to do Neural network for prediction of next month. many thanks. all bests. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
I am reading only one Cell of Excel On Tue, Jan 7, 2014 at 7:18 AM, Dániel Kehl ke...@ktk.pte.hu wrote: Hi, are you reading only one cell of your Excel file? It seems your datalist is not numeric but text. Try saving your Excel file as csv or text, reading in data might be much more straightforward! best daniel Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ; meghatalmaz#243;: Baro [babak...@gmail.com] Küldve: 2014. január 7. 16:01 To: PIKAL Petr Cc: R help Tárgy: Re: [R] NAs introduced by coercion warning, while plotting data thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
Hi, are you reading only one cell of your Excel file? It seems your datalist is not numeric but text. Try saving your Excel file as csv or text, reading in data might be much more straightforward! best daniel Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ; meghatalmaz#243;: Baro [babak...@gmail.com] Küldve: 2014. január 7. 16:01 To: PIKAL Petr Cc: R help Tárgy: Re: [R] NAs introduced by coercion warning, while plotting data thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
You may want to understand how your data is coming out of Excel. You are getting just a single character string. Here is code to convert the string to numerics and plot: x - 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 ; # remove commas and semicolons for reading x - gsub(,|;, '', x) # read in the data xin - scan(text = x, what = 0) plot(xin) Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:15 AM, Baro babak...@gmail.com wrote: Thank you sir: If I am tying str(datalist) I have this output chr 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, | __truncated__ and if I try: dput(datalist) I have: 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 ; On Tue, Jan 7, 2014 at 7:11 AM, jim holtman jholt...@gmail.com wrote: From your output, it looks like 'datalist' is a character string and not a numeric vector as you expect. Try doing: str(datalist) to see the structure and to use dput(datalist) to post the data. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:01 AM, Baro babak...@gmail.com wrote: thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of Baro Sent:
Re: [R] NAs introduced by coercion warning, while plotting data
Hi I usually read data from Excel this way. open Excel file mark values you want to copy press Ctrl-C type in R command window datalist - read.delim(clipboard) in that case datalist shall be data.frame with probably one column so plot(datalist[,1],type=l,ylim=c(-1,+1)) shall do what you want. Anyway, R ships with nice manual R-Intro which is often overlooked by newbies. Maybe it could be emphasized during installation process or within each start of R, user shall be reminded from within Rprofile until he/she learns how to get rid of it. Regards Petr From: Baro [mailto:babak...@gmail.com] Sent: Tuesday, January 07, 2014 4:02 PM To: PIKAL Petr Cc: R help Subject: Re: [R] NAs introduced by coercion warning, while plotting data thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.czmailto:petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I presume that the story is not as simple as plotting a vector as you have suggested. Petr -Original Message- From: r-help-boun...@r-project.orgmailto:r-help-boun...@r-project.org [mailto:r-help-bounces@r-mailto:r-help-bounces@r- project.orghttp://project.org] On Behalf Of Baro Sent: Tuesday, January 07, 2014 3:40 PM To: R help Subject: [R] NAs introduced by coercion warning, while plotting data Hi all I have such a Data and I want to plot them but I get this warning Warning message: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, - 0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, - 0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, - 0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, - 0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, - 0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 Why do I get this warning? how can I solve it? [[alternative HTML version deleted]] __ R-help@r-project.orgmailto:R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] NAs introduced by coercion warning, while plotting data
thank you sir, it works On Tue, Jan 7, 2014 at 7:27 AM, jim holtman jholt...@gmail.com wrote: You may want to understand how your data is coming out of Excel. You are getting just a single character string. Here is code to convert the string to numerics and plot: x - 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 ; # remove commas and semicolons for reading x - gsub(,|;, '', x) # read in the data xin - scan(text = x, what = 0) plot(xin) Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:15 AM, Baro babak...@gmail.com wrote: Thank you sir: If I am tying str(datalist) I have this output chr 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, | __truncated__ and if I try: dput(datalist) I have: 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 ; On Tue, Jan 7, 2014 at 7:11 AM, jim holtman jholt...@gmail.com wrote: From your output, it looks like 'datalist' is a character string and not a numeric vector as you expect. Try doing: str(datalist) to see the structure and to use dput(datalist) to post the data. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Jan 7, 2014 at 10:01 AM, Baro babak...@gmail.com wrote: thank you for your answer, I am reading my Data from an excel File. This is my R code: srow-2421 wb - loadWorkbook(C:\\users\\Babak\\Desktop\\spalte205.xls) dat -readWorksheet(wb, sheet=getSheets(wb)[1], startRow=srow, endRow=srow, startCol=spalte, endCol=spalte,header=FALSE) datalist-dat[,1] datalist-sub(;,,datalist) datalist plot(datalist,type=l,ylim=c(-1,+1)) as an output of my data, I see: datalist [1] 7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738 On Tue, Jan 7, 2014 at 6:54 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi I did not get any error with your data plot(test) dput(test) c(7.0121, -0.673354, 0.749622, -0.549641, 0.435662, -0.328995, 0.0869976, -0.0851428, -0.191019, 0.188799, -0.373707, 0.434814, -0.51979, 0.61944, -0.554766, 0.662571, -0.557779, 0.543724, -0.452397, 0.293651, -0.248438, 0.0532787, -0.0185775, -0.176117, 0.222021, -0.34723, 0.407796, -0.416123, 0.497159, -0.435225, 0.473375, -0.370811, 0.33683, -0.273933, 0.149871, -0.142623, -0.0253748, 0.0205145, -0.134123, 0.167995, -0.209844, 0.266891, -0.242527, 0.326598, -0.235483, 0.275738, -0.195738, 0.168225, -0.114333, 0.0593316, -0.0583527, -0.016594, 0.0363428, -0.0533603, 0.106158, -0.129363, 0.131993, -0.134909, 0.135686, -0.125387, 0.0866545, -0.0668686, 0.043161, -0.0229738) You shall explain more clearly what you did (code) and what are your data (dput) I
Re: [R] help
Hi You have got an extensive explanation by Frede Aakmann Tøgersen. I consider it pretty strightforward and I do not have anything to add. Do not expect that somebody can change your result, if your data does not support it. Regards Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of javad bayat Sent: Tuesday, January 07, 2014 4:24 PM To: R-help@r-project.org Subject: Re: [R] help I apologies for asking this question; I run the codes but why all the prediction for pH in 21-25 month are so close? station month pH 1 21 8.275635958 2 21 8.275635962 3 21 8.275635963 4 21 8.275635963 5 21 8.275635963 6 21 8.275635963 On Tue, Jan 7, 2014 at 2:12 PM, javad bayat j.bayat...@gmail.com wrote: Dear Pikal Petr; thanks for code. It was usefull. On Tue, Jan 7, 2014 at 11:30 AM, PIKAL Petr petr.pi...@precheza.czwrote: Hi and what is wrong with e.g. fit - neuralnet(pH~station+month, data=yourdata) As I said I am not an expert in neural nets but here is some explanation how it works http://gekkoquant.com/2012/05/26/neural-networks-with-r-simple- exampl e/ based on that after fitting you could do compute(fit, testdata) where testdata shall be station and month. However for time series it can be more appropriate something like ARIMA modelling. Petr *From:* javad bayat [mailto:j.bayat...@gmail.com] *Sent:* Monday, January 06, 2014 5:58 PM *To:* PIKAL Petr *Subject:* Re: [R] help Dear Petr; I want to write function that: for example for pH: according these 20 months predict the variability of pH for next month and stations. all best. On Mon, Jan 6, 2014 at 7:23 PM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi can you be more specific? In what aspect those packages does not comply with your data? What did you do for testing it? I am not an expert in neural networks but I do not see anything which prevents using your data in nnet. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 3:16 PM To: R-help@r-project.org Subject: Re: [R] help Dear Petr; I saw the nnet and neuralnet packag, and I cant find some thing relating with my data based on neural network. On Mon, Jan 6, 2014 at 10:55 AM, PIKAL Petr petr.pi...@precheza.cz wrote: Hi Why you did not use dput for sending data? It is far better than picture, which can not be used without retyping. Redarding neural network, did you try e.g. nnet or neuralnet package. Petr -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of javad bayat Sent: Monday, January 06, 2014 7:37 AM To: R-help@r-project.org Subject: Re: [R] help Dear all; many thanks for your answers. Hear is my data (not all row: the station was 8 station at 20 month) which I forward it as image. I hope some one can help me to do Neural network for prediction of next month. many thanks. all bests. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com -- Best Regards Javad Bayat M.Sc. Environment Engineering Shahid Beheshti (National) University (SBU) Alternative Mail: bayat...@yahoo.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. __
Re: [R] How do I perform conditional annotation of lattice panel plots?
Chen, George George.Chen at roswellpark.org writes:
My apologies for asking this question that may have
been asked before. I am trying to plot activity
dependent on time conditioned by the subject.
Code for sample data below.
So I have something like this
xyplot(Activity~Time|Subject).
This works fine, but now I want to show
where on these activity curves Event A occurs.
This is to explore the
relationship between A and activity.
I tried this:
xyplot(EventA+Activity~Time|Subject)
but then the numerical ordering gets out of order.
Ideally Event A could be denoted by a vertical line
cutting through the curve at the day Event A occurred, but
some other way to denote it would be great!
-snip -
Any ideas on how to do this would be appreciated!
Thanks very much in advance!
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[[alternative HTML version deleted]]
You used Time in your formula but Day in
your data so I changed the formula to Day
assuming that's what you meant
Perhaps, not the most elegant solution, but
how about something like this
library(lattice)
Subject-c(1,1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4)
Day-c(1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6)
Activity-c(2,3,4,3,7,4,5,8,2,8,4,6,2,5,3,8,9,5,6,3,4,5,6,7)
EventA-c(Yes,NA,Yes,NA,NA,NA,Yes,NA,NA,NA,NA,NA,
Yes,NA,NA,NA,NA,NA,NA,NA,Yes,NA,NA,NA)
Data-data.frame(cbind(Subject,Day,Activity,EventA))
xyplot(Activity~ Day | Subject)
xyplot(Activity ~ Day | Subject, data = Data,
subscripts = TRUE,
panel = function(x, y, subscripts, ...){
panel.xyplot(x, y)
wh - Data[subscripts, ]
panel.abline(v = wh$Day[!is.na(wh$EventA)])
})
--
Kenneth Knoblauch
Inserm U846
Stem-cell and Brain Research Institute
Department of Integrative Neurosciences
18 avenue du Doyen Lépine
69500 Bron
France
tel: +33 (0)4 72 91 34 77
fax: +33 (0)4 72 91 34 61
portable: +33 (0)6 84 10 64 10
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[R] Question regarding the package rugarch
Dear all, I have a question regarding the package rugarch. I would like to fit a garch model with exogenous variables using rugarch. My code is as follows, where data.reg is a time series object where the first column corresponds to the response variable and the remainder columns are the exogenous variables. spec - ugarchspec(variance.model = list(model = sGARCH, garchOrder = c(1, 1), submodel = NULL, external.regressors = NULL, variance.targeting = FALSE), mean.model = list(armaOrder = c(1, 1), external.regressors = data.reg[,-1])) #, distribution.model = norm, start.pars = list(), fixed.pars = list())) garch - ugarchfit(spec=spec,data=data.reg[,1],solver.control=list(trace=0)) When running the second command, the following error appears: Error in pars[idx[mxreg, 1]:idx[mxreg, 2], 1] = fit.mean[i] : replacement has length zero How can I solve this problem? Thanks for your help Corina __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] with() and within() functions inside lapply() not seeing outside of its environment?
Hi,
I have a list of sublists, and I want to add and/or remove elements in
each sublist in accordance with a code snippet. I had thought that an
elegant way to do that is using a combination of lapply() and within().
However, the code in the within() call doesn't seem to be able to see
objects outside of it. For (a simplified) example,
f - function(x){
y - list(y1=list())
y - lapply(y, within, {z-x})
y
}
f(1)
My understanding is that what should happen is that lapply() would
execute
within(y[[y1]], {z-x}),
with 1 substituted for x, within() would notice that z has been assigned
1, returning list(z=1), which then gets put into a list as element named
y1, so the function should ultimately return
list(y1=list(z=1))
What I get instead (on R 3.0.2 and current trunk, both on Linux) is
Error in eval(expr, envir, enclos) : object 'x' not found
Am I doing something wrong, or is this a bug?
Thanks in advance,
Pavel
P.S. If I hard-code the value for x, i.e.,
f - function(){
y - list(y1=list())
y - lapply(y, within, {z-1})
y
}
f()
it returns list(y1=list(z=1)) as expected.
P.P.S. with() has the same problem:
f - function(x){
y - list(y1=list())
w - lapply(y, with, x)
w
}
f(1)
produces the exact same error as within().
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[R] How to apply correctly.
Folks,
# I have the following function:
breakByFreq-function(freq, defData) {
breakUpFun-function(freq, defs) {
if(freq != 1) {
defs-diff(c(0, defs))
defs-cumsum(rep(defs/freq, each = freq))
}
defs
}
defMat-sapply(defData[,-1], function(x) breakUpFun(freq, x))
data.frame(Year = 1:nrow(defMat), defMat)
}
# And this data (year column and then 2 columns of data):
dum-structure(list(Year = 1:10,
c1 = c(0.01, 0.02, 0.03, 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.1),
c2 = c(0.02, 0.04, 0.06, 0.08, 0.1, 0.12, 0.14, 0.16, 0.18, 0.2)),
.Names = c(Year, c1, c2), row.names = c(NA, -10L), class = data.frame)
# This works:
breakByFreq(1, dum)
# This doesn't:
breakByFreq(1, dum[,-3])
# How do I use and choose the appropriate apply function to make this work when
there is one and or more columns to be processed.
Thanks for your time,
KW
--
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Re: [R] Packaging: Doubt in relation with R CMD Rd2pdf packagename
Thanks Rich. I used your indications, but it was correctly in PATH variable. My
path is C:\Program Files (x86)\MiKTeX 2.9\miktex\bin.
I send you a print. Do you have any other idea?.
Thanks again.
Eva
El Lunes 6 de enero de 2014 23:36, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Hi everybody,
I have created a package without documentation and now I want to create it with
a pdf manual. That is the reason why I have created the .Rd files in man
folder. In this way I obtain a pdf manual usind R CMD check packagename, but
it ignores the \code{\link{function.name}}... I mean the function.name does not
appear as a hiperlink although I use \link in the rd file.
I supose (I don't know if that is true) that the hiperlink and index requires
other way of generating the pdf manual, but when I use R CMD Rd2pdf
packagename I obtain the following error:
Error: running 'texti2dvi' on 'Rd2.tex' failed
LaTeX errors:
!pdfTeX error: pdflatex.EXE file t1-zi4r-0: Fot t1-zi4r-0 at 540 not found --
Fatal error ocurred, no output PDF file produced!
Error in running tools::texti2pdf()
Sometimes the message error mentions inconsolata and zi4.sty. Then I install
(or uninstall) inconsolata since MikTex package manager and the error turns to
the other I described.
I am using MikTeX 2.9 in Windows 8. I have tested in Windows 7 and the results
are the same.
How can I obtain the pdf manual?. The fact of solving this problem is very
important for me.
Thank you in advance.
Regards.
Eva__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Packaging: Doubt in relation with R CMD Rd2pdf packagename
The image suggests that you are missing a font. Someone else might be
able to help with that.
On Tue, Jan 7, 2014 at 12:50 PM, Eva Prieto Castro evapcas...@yahoo.es wrote:
Thanks Rich. I used your indications, but it was correctly in PATH variable.
My path is C:\Program Files (x86)\MiKTeX 2.9\miktex\bin.
I send you a print. Do you have any other idea?.
Thanks again.
Eva
El Lunes 6 de enero de 2014 23:36, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Hi everybody,
I have created a package without documentation and now I want to create it
with a pdf manual. That is the reason why I have created the .Rd files in
man folder. In this way I obtain a pdf manual usind R CMD check
packagename, but it ignores the \code{\link{function.name}}... I mean the
function.name does not appear as a hiperlink although I use \link in the rd
file.
I supose (I don't know if that is true) that the hiperlink and index
requires other way of generating the pdf manual, but when I use R CMD
Rd2pdf packagename I obtain the following error:
Error: running 'texti2dvi' on 'Rd2.tex' failed
LaTeX errors:
!pdfTeX error: pdflatex.EXE file t1-zi4r-0: Fot t1-zi4r-0 at 540 not found
-- Fatal error ocurred, no output PDF file produced!
Error in running tools::texti2pdf()
Sometimes the message error mentions inconsolata and zi4.sty. Then I install
(or uninstall) inconsolata since MikTex package manager and the error turns
to the other I described.
I am using MikTeX 2.9 in Windows 8. I have tested in Windows 7 and the
results are the same.
How can I obtain the pdf manual?. The fact of solving this problem is very
important for me.
Thank you in advance.
Regards.
Eva
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] with() and within() functions inside lapply() not seeing outside of its environment?
On 07/01/2014 10:35 AM, Pavel N. Krivitsky wrote:
Hi,
I have a list of sublists, and I want to add and/or remove elements in
each sublist in accordance with a code snippet. I had thought that an
elegant way to do that is using a combination of lapply() and within().
However, the code in the within() call doesn't seem to be able to see
objects outside of it. For (a simplified) example,
f - function(x){
y - list(y1=list())
y - lapply(y, within, {z-x})
y
}
f(1)
My understanding is that what should happen is that lapply() would
execute
within(y[[y1]], {z-x}),
with 1 substituted for x, within() would notice that z has been assigned
1, returning list(z=1), which then gets put into a list as element named
y1, so the function should ultimately return
list(y1=list(z=1))
What I get instead (on R 3.0.2 and current trunk, both on Linux) is
Error in eval(expr, envir, enclos) : object 'x' not found
Am I doing something wrong, or is this a bug?
I wouldn't call it a bug, but it's a documented limitation, if you know
how to read it. As documented, the expression is evaluated with the
caller's environment as the parent environment. But here the caller is
some code in lapply, not your function f. x is not found there.
I think this modification works, and is maybe the simplest way to get it
to work:
f - function(x){
y - list(y1=list())
mywithin - function(...) within(...)
y - lapply(y, mywithin, {z-x})
y
}
The idea here is that the calling frame of f is the environment of
mywithin(), so x is found there.
Duncan Murdoch
Thanks in advance,
Pavel
P.S. If I hard-code the value for x, i.e.,
f - function(){
y - list(y1=list())
y - lapply(y, within, {z-1})
y
}
f()
it returns list(y1=list(z=1)) as expected.
P.P.S. with() has the same problem:
f - function(x){
y - list(y1=list())
w - lapply(y, with, x)
w
}
f(1)
produces the exact same error as within().
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to apply correctly.
I think you will be okay if you change
one line to:
defMat-sapply(defData[,-1, drop=FALSE], function(x) breakUpFun(freq, x))
In your example that doesn't work you are
ending up with a vector rather than a one
column data frame.
Pat
On 07/01/2014 17:44, Keith S Weintraub wrote:
Folks,
# I have the following function:
breakByFreq-function(freq, defData) {
breakUpFun-function(freq, defs) {
if(freq != 1) {
defs-diff(c(0, defs))
defs-cumsum(rep(defs/freq, each = freq))
}
defs
}
defMat-sapply(defData[,-1], function(x) breakUpFun(freq, x))
data.frame(Year = 1:nrow(defMat), defMat)
}
# And this data (year column and then 2 columns of data):
dum-structure(list(Year = 1:10,
c1 = c(0.01, 0.02, 0.03, 0.04, 0.05, 0.06, 0.07, 0.08, 0.09, 0.1),
c2 = c(0.02, 0.04, 0.06, 0.08, 0.1, 0.12, 0.14, 0.16, 0.18, 0.2)),
.Names = c(Year, c1, c2), row.names = c(NA, -10L), class = data.frame)
# This works:
breakByFreq(1, dum)
# This doesn't:
breakByFreq(1, dum[,-3])
# How do I use and choose the appropriate apply function to make this work when there is
one and or more columns to be processed.
Thanks for your time,
KW
--
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @burnsstat @portfolioprobe
http://www.portfolioprobe.com/blog
http://www.burns-stat.com
(home of:
'Impatient R'
'The R Inferno'
'Tao Te Programming')
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to apply correctly.
Thanks Patrick,
That did the trick.
Oddly enough (or maybe not that oddly) I was looking through The R Inferno to
try and find the answer. Since I often forget that there are other parameters
available to '[' I never made it to 8.1.44 on dropping dimensions.
Hopefully this lesson will stick with me!
Thanks again,
All the best,
Happy New Year,
KW
--
On Jan 7, 2014, at 1:32 PM, Patrick Burns pbu...@pburns.seanet.com wrote:
I think you will be okay if you change
one line to:
defMat-sapply(defData[,-1, drop=FALSE], function(x) breakUpFun(freq, x))
In your example that doesn't work you are
ending up with a vector rather than a one
column data frame.
Pat
On 07/01/2014 17:44, Keith S Weintraub wrote:
Folks,
# I have the following function:
breakByFreq-function(freq, defData) {
breakUpFun-function(freq, defs) {
if(freq != 1) {
defs-diff(c(0, defs))
defs-cumsum(rep(defs/freq, each = freq))
}
defs
}
defMat-sapply(defData[,-1], function(x) breakUpFun(freq, x))
data.frame(Year = 1:nrow(defMat), defMat)
}
# And this data (year column and then 2 columns of data):
dum-structure(list(Year = 1:10,
c1 = c(0.01, 0.02, 0.03, 0.04, 0.05, 0.06, 0.07, 0.08, 0.09,
0.1),
c2 = c(0.02, 0.04, 0.06, 0.08, 0.1, 0.12, 0.14, 0.16, 0.18,
0.2)),
.Names = c(Year, c1, c2), row.names = c(NA, -10L), class =
data.frame)
# This works:
breakByFreq(1, dum)
# This doesn't:
breakByFreq(1, dum[,-3])
# How do I use and choose the appropriate apply function to make this work
when there is one and or more columns to be processed.
Thanks for your time,
KW
--
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @burnsstat @portfolioprobe
http://www.portfolioprobe.com/blog
http://www.burns-stat.com
(home of:
'Impatient R'
'The R Inferno'
'Tao Te Programming')
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] with() and within() functions inside lapply() not seeing outside of its environment?
On 07 Jan 2014, at 19:19 , Duncan Murdoch murdoch.dun...@gmail.com wrote:
I wouldn't call it a bug, but it's a documented limitation, if you know how
to read it. As documented, the expression is evaluated with the caller's
environment as the parent environment. But here the caller is some code in
lapply, not your function f. x is not found there.
I'd also consider it a bit brave to rely on ...-args to lapply being passed
down unevaluated, but that does apparently work.
At any rate, you cannot both have x evaluated in the frame of f, and the
assignment to z _not_ evaluated there.
I think this modification works, and is maybe the simplest way to get it to
work:
f - function(x){
y - list(y1=list())
mywithin - function(...) within(...)
y - lapply(y, mywithin, {z-x})
y
}
There is also brute-force substitution:
f - function(x){
+ y - list(y1=list())
+ y - eval(bquote(lapply(y, within, {z-.(x)})))
+ y
+ }
f(1)
$y1
$y1$z
[1] 1
The idea here is that the calling frame of f is the environment of
mywithin(), so x is found there.
Duncan Murdoch
Thanks in advance,
Pavel
P.S. If I hard-code the value for x, i.e.,
f - function(){
y - list(y1=list())
y - lapply(y, within, {z-1})
y
}
f()
it returns list(y1=list(z=1)) as expected.
P.P.S. with() has the same problem:
f - function(x){
y - list(y1=list())
w - lapply(y, with, x)
w
}
f(1)
produces the exact same error as within().
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.
--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk Priv: pda...@gmail.com
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Re: [R] Packaging: Doubt in relation with R CMD Rd2pdf packagename
Hi again:
Rich, I see your messages but they are sent to another mail address so I have
to write from here without using your answer.
I think the problem is that inconsolata.sty is not found, and zi4.sty is not
found.
I have read several documents in www about this question but I can not solve it.
Please could anybody help me?
Thanks.
Eva
El Martes 7 de enero de 2014 20:00, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Thanks Rich. I used your indications, but it was correctly in PATH variable. My
path is C:\Program Files (x86)\MiKTeX 2.9\miktex\bin.
I send you a print. Do you have any other idea?.
Thanks again.
Eva
El Lunes 6 de enero de 2014 23:36, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Hi everybody,
I have created a package without documentation and now I want to create it with
a pdf manual. That is the reason why I have created the .Rd files in man
folder. In this way I obtain a pdf manual usind R CMD check packagename, but
it ignores the \code{\link{function.name}}... I mean the function.name does not
appear as a hiperlink although I use \link in the rd file.
I supose (I don't know if that is true) that the hiperlink and index requires
other way of generating the pdf manual, but when I use R CMD Rd2pdf
packagename I obtain the following error:
Error: running 'texti2dvi' on 'Rd2.tex' failed
LaTeX errors:
!pdfTeX error: pdflatex.EXE file t1-zi4r-0: Fot t1-zi4r-0 at 540 not found --
Fatal error ocurred, no output PDF file produced!
Error in running tools::texti2pdf()
Sometimes the message error mentions inconsolata and zi4.sty. Then I install
(or uninstall) inconsolata since MikTex package manager and the error turns to
the other I described.
I am using MikTeX 2.9 in Windows 8. I have tested in Windows 7 and the results
are the same.
How can I obtain the pdf manual?. The fact of solving this problem is very
important for me.
Thank you in advance.
Regards.
Eva
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Levelplots with non-continuous x-axis breaks
Patrick,
You were pretty close.
To fix the code you have, just change matrix to mymatrix in two places,
and either specify the argument data= or place the heat.colors bit first in
the matrix function.
Or ... you could use the array() function instead, to shorten up the code a
little.
mycol - array(heat.colors(max(mymatrix[, 3:5]))[mymatrix[, 3:5]],
dim=dim(mymatrix))
Jean
On Mon, Jan 6, 2014 at 9:19 PM, Pachapep pacha...@gmail.com wrote:
Hi all,
I have a matrix which I want to plot in color. I have extensively looked
at level plot and heatmap/heatmap.2, but I would like to be able to manage
the size of the bins (boxes) on my X axis. So I thought of simply using
the rect() function, but I cant get around assigning the correct colors to
all the values. I have built a RectPlotter() function that takes the start
and stop as well as the value assigned to each bin.
Here is what I have done so far (after countless hours of despair):
RectPlotter - function(matrixval, ycoord, height, mycolors){
rect(matrixval[,1], (ycoord-(0.4*height)), matrixval[,2],
(ycoord+(0.4*height)), col=mycolors, border = NA)
}
starts - c(1,5,8,15)
ends - c(5, 8, 15, 25)
vals1 - c(2, 15, 7, 13)
vals2 - c(7, 2, 1, 26)
vals3 - c(52, 1, 29, 18)
mymatrix - cbind(starts, ends, vals1, vals2, vals3)
# This gives me an error
mycol- matrix(nrow=dim(mymatrix)[1], ncol=dim(mymatrix)[2],
heat.colors(max(matrix[,3:5]))[matrix[,3:5]])
At the end, I would like to have something like a levelplot, but using the
starts and ends as x-axis.
Any help would be highly appreciated. Thanks!
Patrick
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PLEASE do read the posting guide
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and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Packaging: Doubt in relation with R CMD Rd2pdf packagename
Hi Rich, Hi everybody
I have solved the problem!. I installed MikTeX 2.9 again, but this time I chose
basic installation (the other one I had chosen complete installation). I
noticed a diference if we compare with the previous situation: now R and MikTeX
are installed in the same folder (ProgramFiles) - in the previous situation R
was in Program Files and MikTeX was in Program Files (x86).
Now R CMD check runs correctly and R CMD Rd2pdf runs correctly too.
I am very happy with the results!.
Thank you!
Eva
El Martes 7 de enero de 2014 18:50, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Thanks Rich. I used your indications, but it was correctly in PATH variable. My
path is C:\Program Files (x86)\MiKTeX 2.9\miktex\bin.
I send you a print. Do you have any other idea?.
Thanks again.
Eva
El Lunes 6 de enero de 2014 23:36, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Hi everybody,
I have created a package without documentation and now I want to create it with
a pdf manual. That is the reason why I have created the .Rd files in man
folder. In this way I obtain a pdf manual usind R CMD check packagename, but
it ignores the \code{\link{function.name}}... I mean the function.name does not
appear as a hiperlink although I use \link in the rd file.
I supose (I don't know if that is true) that the hiperlink and index requires
other way of generating the pdf manual, but when I use R CMD Rd2pdf
packagename I obtain the following error:
Error: running 'texti2dvi' on 'Rd2.tex' failed
LaTeX errors:
!pdfTeX error: pdflatex.EXE file t1-zi4r-0: Fot t1-zi4r-0 at 540 not found --
Fatal error ocurred, no output PDF file produced!
Error in running tools::texti2pdf()
Sometimes the message error mentions inconsolata and zi4.sty. Then I install
(or uninstall) inconsolata since MikTex package manager and the error turns to
the other I described.
I am using MikTeX 2.9 in Windows 8. I have tested in Windows 7 and the results
are the same.
How can I obtain the pdf manual?. The fact of solving this problem is very
important for me.
Thank you in advance.
Regards.
Eva
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Re: [R] Packaging: Doubt in relation with R CMD Rd2pdf packagename
On 14-01-07 3:35 PM, Eva Prieto Castro wrote:
Hi Rich, Hi everybody
I have solved the problem!. I installed MikTeX 2.9 again, but this time I chose
basic installation (the other one I had chosen complete installation). I
noticed a diference if we compare with the previous situation: now R and MikTeX
are installed in the same folder (ProgramFiles) - in the previous situation R
was in Program Files and MikTeX was in Program Files (x86).
I would guess the change of location isn't what solved this, but rather
that the basic installation loads LaTeX packages on demand, so you
probably get newer versions.
Duncan Murdoch
Now R CMD check runs correctly and R CMD Rd2pdf runs correctly too.
I am very happy with the results!.
Thank you!
Eva
El Martes 7 de enero de 2014 18:50, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Thanks Rich. I used your indications, but it was correctly in PATH variable. My
path is C:\Program Files (x86)\MiKTeX 2.9\miktex\bin.
I send you a print. Do you have any other idea?.
Thanks again.
Eva
El Lunes 6 de enero de 2014 23:36, Eva Prieto Castro evapcas...@yahoo.es
escribió:
Hi everybody,
I have created a package without documentation and now I want to create it with a pdf
manual. That is the reason why I have created the .Rd files in man folder. In this way I
obtain a pdf manual usind R CMD check packagename, but it ignores the
\code{\link{function.name}}... I mean the function.name does not appear as a hiperlink
although I use \link in the rd file.
I supose (I don't know if that is true) that the hiperlink and index requires other way
of generating the pdf manual, but when I use R CMD Rd2pdf packagename I
obtain the following error:
Error: running 'texti2dvi' on 'Rd2.tex' failed
LaTeX errors:
!pdfTeX error: pdflatex.EXE file t1-zi4r-0: Fot t1-zi4r-0 at 540 not found --
Fatal error ocurred, no output PDF file produced!
Error in running tools::texti2pdf()
Sometimes the message error mentions inconsolata and zi4.sty. Then I install
(or uninstall) inconsolata since MikTex package manager and the error turns to
the other I described.
I am using MikTeX 2.9 in Windows 8. I have tested in Windows 7 and the results
are the same.
How can I obtain the pdf manual?. The fact of solving this problem is very
important for me.
Thank you in advance.
Regards.
Eva
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
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and provide commented, minimal, self-contained, reproducible code.
[R] A calculation in data.frame
Hi,
I have to perform some formula driven calculation in a data.frame (as defined
below). Let say I have following DF:
DF - data.frame(A1 = c('a', 'a', 'a', 'b', 'b', 'b', 'c', 'c', 'c'), A2 =
c('m', 'n', 'p', 'm', 'n', 'p', 'm', 'n', 'p'), A3 = c(1,2,3,4,5,6,7,8,9))
DF
A1 A2 A3
1 a m 1
2 a n 2
3 a p 3
4 b m 4
5 b n 5
6 b p 6
7 c m 7
8 c n 8
9 c p 9
Now let say, user gives one formula which will be applied on the elements of A1
column. Let say the formula looks like:
z = a + 2*b + c (infact the formula will be arbitrary like z = f(a, b, c))
Once such formula is given, the result will be like (for the columns A1, A2, A3
respectively)
z m 16
z n 20
z p 24
the last column comes from the fact that 1 + 2*4 + 7 = 16, 2 + 2*5 + 8 = 20, 3
+ 2*6 + 9 = 24
Given that the formula wil be user defined, and to be applied on some
data.frame like DF, I am seeking some automated way to accomplice the task for
really big DF of previous kind and fairly complex formula.
Can somebody suggest me for efficient way to perform this task in R?
Really appreciate your help.
Thanks,
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] A calculation in data.frame
HI,
May be this helps:
library(reshape2)
df1 - dcast(DF,A2~A1,value.var=A3)
z - function(a,b,c){a+2*b+c}
within(df1, newCol - z(a,b,c))
# A2 a b c newCol
#1 m 1 4 7 16
#2 n 2 5 8 20
#3 p 3 6 9 24
On Tuesday, January 7, 2014 4:15 PM, Ron Michael ron_michae...@yahoo.com
wrote:
Hi,
I have to perform some formula driven calculation in a data.frame (as defined
below). Let say I have following DF:
DF - data.frame(A1 = c('a', 'a', 'a', 'b', 'b', 'b', 'c', 'c', 'c'), A2 =
c('m', 'n', 'p', 'm', 'n', 'p', 'm', 'n', 'p'), A3 = c(1,2,3,4,5,6,7,8,9))
DF
A1 A2 A3
1 a m 1
2 a n 2
3 a p 3
4 b m 4
5 b n 5
6 b p 6
7 c m 7
8 c n 8
9 c p 9
Now let say, user gives one formula which will be applied on the elements of A1
column. Let say the formula looks like:
z = a + 2*b + c (infact the formula will be arbitrary like z = f(a, b, c))
Once such formula is given, the result will be like (for the columns A1, A2, A3
respectively)
z m 16
z n 20
z p 24
the last column comes from the fact that 1 + 2*4 + 7 = 16, 2 + 2*5 + 8 = 20, 3
+ 2*6 + 9 = 24
Given that the formula wil be user defined, and to be applied on some
data.frame like DF, I am seeking some automated way to accomplice the task for
really big DF of previous kind and fairly complex formula.
Can somebody suggest me for efficient way to perform this task in R?
Really appreciate your help.
Thanks,
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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and provide commented, minimal, self-contained, reproducible code.
[R] about R
Hello, I am a master student in Educational Measurement and Evaluation, my thesis subject is comparison of estimation methods used for confirmatory factor analysis. For my thesis study, I need to generate datas that provides some features. I will generate these datas by changing correlation between factors, number of factors, types of items, number of items for a factor, sample size(for example, i want to generate seperate datas for 200 and 500 as sample size ). I would be very grateful if you would help me to generate these datas using R. I installed the R program, also installed the psych package but I could not go any further to generate my desired datas. Best Regards, Sevda [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] about R
Look at the mvrnorm function in the MASS package. The within or transform functions may also be of use to you in creating the data as a combination of the factors that you create using mvrnorm. On Tue, Jan 7, 2014 at 2:15 PM, sevda datlı sevdad...@gmail.com wrote: Hello, I am a master student in Educational Measurement and Evaluation, my thesis subject is “comparison of estimation methods used for confirmatory factor analysis”. For my thesis study, I need to generate datas that provides some features. I will generate these datas by changing correlation between factors, number of factors, types of items, number of items for a factor, sample size(for example, i want to generate seperate datas for 200 and 500 as sample size ). I would be very grateful if you would help me to generate these datas using R. I installed the R program, also installed the “psych” package but I could not go any further to generate my desired datas. Best Regards, Sevda [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Gregory (Greg) L. Snow Ph.D. 538...@gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Levelplots with non-continuous x-axis breaks
Patrick,
You should cc r-help on all correspondence so that others can follow the
thread.
The color range will be matched to the x argument you provide to the
color.scale function (in package plotrix). So you don't need to manually
provide the min and max yourself. If for some reason you did need to
provide that information, you would use the xrange argument not the
extremes argument (which is expecting colors).
mycolors - color.scale(mymatrix[,-(1:2)], c(0,1,1), c(1,1,0), c(1,0,1))
Jean
On Tue, Jan 7, 2014 at 4:16 PM, Pachapep pacha...@gmail.com wrote:
Hi Jean
Thanks for the quick answer. It looks like it works, but the issue is that
my real data fluctuates between 0 and 2, so I everything is red.
I tried using another function (color.scale), which works but gives me
grey scale only (no colors) although I dont really understand why - its a
detail, but it's kind of a bummer..
mycolors - color.scale(mymatrix[,-(1:2)], c(0,1,1), c(1,1,0), c(1,0,1),
extremes=c(min(mymatrix[,-(1:2)]), max(mymatrix[,-(1:2)])))
Is there a way to make an array using the min and max of the matrix (as I
used in color.scale() above) so that the colors go from blue to red?
Thanks again for the help.
Patrick
On Jan 7, 2014, at 15:04, Adams, Jean jvad...@usgs.gov wrote:
Patrick,
You were pretty close.
To fix the code you have, just change matrix to mymatrix in two
places, and either specify the argument data= or place the heat.colors bit
first in the matrix function.
Or ... you could use the array() function instead, to shorten up the code
a little.
mycol - array(heat.colors(max(mymatrix[, 3:5]))[mymatrix[, 3:5]],
dim=dim(mymatrix))
Jean
On Mon, Jan 6, 2014 at 9:19 PM, Pachapep pacha...@gmail.com wrote:
Hi all,
I have a matrix which I want to plot in color. I have extensively looked
at level plot and heatmap/heatmap.2, but I would like to be able to manage
the size of the bins (boxes) on my X axis. So I thought of simply using
the rect() function, but I cant get around assigning the correct colors to
all the values. I have built a RectPlotter() function that takes the start
and stop as well as the value assigned to each bin.
Here is what I have done so far (after countless hours of despair):
RectPlotter - function(matrixval, ycoord, height, mycolors){
rect(matrixval[,1], (ycoord-(0.4*height)), matrixval[,2],
(ycoord+(0.4*height)), col=mycolors, border = NA)
}
starts - c(1,5,8,15)
ends - c(5, 8, 15, 25)
vals1 - c(2, 15, 7, 13)
vals2 - c(7, 2, 1, 26)
vals3 - c(52, 1, 29, 18)
mymatrix - cbind(starts, ends, vals1, vals2, vals3)
# This gives me an error
mycol- matrix(nrow=dim(mymatrix)[1], ncol=dim(mymatrix)[2],
heat.colors(max(matrix[,3:5]))[matrix[,3:5]])
At the end, I would like to have something like a levelplot, but using
the starts and ends as x-axis.
Any help would be highly appreciated. Thanks!
Patrick
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Re: [R] Dataset to single column matrix
Krishia wrote Hello, I am pretty new to R and would like to transform my 272x12 matrix into a 3264X1. I'm trying to have the setup change from: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 13,14,15,16,17,18,19,20,21,22, 23, 24 etc. to 1 2 3 4 5 6 7 8 9 10 11 12 etc. Any suggestions? Thanks in advance Krishia Is this what you are looking for? # Create example matrice m - matrix(c(1,2,3,4,5,6,7,8,9,10,11,12), nrow=4, byrow=TRUE) # Create vector v - c(t(m)) HTH Pete -- View this message in context: http://r.789695.n4.nabble.com/Dataset-to-single-column-matrix-tp4683231p4683238.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Dataset to single column matrix
On Tue, Jan 7, 2014 at 8:30 PM, Pete Brecknock peter.breckn...@bp.com wrote: Krishia wrote Hello, I am pretty new to R and would like to transform my 272x12 matrix into a 3264X1. I'm trying to have the setup change from: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 13,14,15,16,17,18,19,20,21,22, 23, 24 etc. to 1 2 3 4 5 6 7 8 9 10 11 12 etc. Any suggestions? Thanks in advance Krishia Is this what you are looking for? # Create example matrice m - matrix(c(1,2,3,4,5,6,7,8,9,10,11,12), nrow=4, byrow=TRUE) # Create vector v - c(t(m)) Or just dim(m) - NULL Best, Ista HTH Pete -- View this message in context: http://r.789695.n4.nabble.com/Dataset-to-single-column-matrix-tp4683231p4683238.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How do I perform conditional annotation of lattice panel plots?
Hi George If you did not want a line through the point try this xyplot(Activity ~ Day | Subject, data = Data,pch = ifelse(is.na(Data$EventA), 1,16), col = ifelse(is.na(Data$EventA), 4,2)) You could make a column of it otherwise change EventA to numeric - easier to work with Regards Duncan Duncan Mackay Department of Agronomy and Soil Science University of New England Armidale NSW 2351 Email: home: mac...@northnet.com.au -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Chen, George Sent: Wednesday, 8 January 2014 00:07 To: r-help@r-project.org Subject: [R] How do I perform conditional annotation of lattice panel plots? My apologies for asking this question that may have been asked before. I am trying to plot activity dependent on time conditioned by the subject. Code for sample data below. So I have something like this xyplot(Activity~Time|Subject). This works fine, but now I want to show where on these activity curves Event A occurs. This is to explore the relationship between A and activity. I tried this: xyplot(EventA+Activity~Time|Subject) but then the numerical ordering gets out of order. Ideally Event A could be denoted by a vertical line cutting through the curve at the day Event A occurred, but some other way to denote it would be great! Here is my sample data as R code: Subject-c(1,1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4) Day-c(1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6,1,2,3,4,5,6) Activity-c(2,3,4,3,7,4,5,8,2,8,4,6,2,5,3,8,9,5,6,3,4,5,6,7) EventA-c(Yes,NA,Yes,NA,NA,NA,Yes,NA,NA,NA,NA,NA, Yes,NA,NA,NA,NA,NA,NA,NA,Yes,NA,NA,NA) Data-data.frame(cbind(Subject,Day,Activity,EventA)) Subject Day Activity EventA 11 12Yes 21 23 NA 31 34Yes 41 43 NA 51 57 NA 61 64 NA 72 15Yes 82 28 NA 92 32 NA 10 2 48 NA 11 2 54 NA 12 2 66 NA 13 3 12Yes 14 3 25 NA 15 3 33 NA 16 3 48 NA 17 3 59 NA 18 3 65 NA 19 4 16 NA 20 4 23 NA 21 4 34Yes 22 4 45 NA 23 4 56 NA 24 4 67 NA Any ideas on how to do this would be appreciated! Thanks very much in advance! This email message may contain legally privileged and/or confidential information. If you are not the intended recipient(s), or the employee or agent responsible for the delivery of this message to the intended recipient(s), you are hereby notified that any disclosure, copying, distribution, or use of this email message is prohibited. If you have received this message in error, please notify the sender immediately by e-mail and delete this email message from your computer. Thank you. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Dataset to single column matrix
On 08/01/14 15:09, Ista Zahn wrote: On Tue, Jan 7, 2014 at 8:30 PM, Pete Brecknock peter.breckn...@bp.com wrote: Krishia wrote Hello, I am pretty new to R and would like to transform my 272x12 matrix into a 3264X1. I'm trying to have the setup change from: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 13,14,15,16,17,18,19,20,21,22, 23, 24 etc. to 1 2 3 4 5 6 7 8 9 10 11 12 etc. Any suggestions? Thanks in advance Krishia Is this what you are looking for? # Create example matrice m - matrix(c(1,2,3,4,5,6,7,8,9,10,11,12), nrow=4, byrow=TRUE) # Create vector v - c(t(m)) Or just dim(m) - NULL No. That produces column-by-column order, and it appears that the OP wanted row-by-row order, which is what Peter's solution gives. BTW it is considered more politically correct to use as.vector(M) rather than c(M) to turn a matrix into a vector, although the result is exactly the same. cheers, Rolf Turner __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to detect a sequence of NA values?
Hi, Try: rl - rle(is.na(a)) max(rl$lengths[rl$values]) #[1] 3 A.K. Hi, I'd like to detect whether a vector contains a sequence of NA values of a certain length. So, for example, if I have a vector a = c(1,NA,NA,4,NA,NA,NA,5); how can I find what the longest sequence of NAs is (in this case 3)? Note that this is different from simply summing the number of NA values in the vector (which would be 5 in this case)... Thanks for your help ! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Dataset to single column matrix
Hi, You could try: mat1 - matrix(1:(272*12),ncol=12,byrow=TRUE) mat2 - t(mat1) dim(mat2) - c(272*12,1) #or mat3 - matrix(as.vector(mat2),ncol=1) identical(mat2,mat3) #[1] TRUE A.K. Hello, I am pretty new to R and would like to transform my 272x12 matrix into a 3264X1. I'm trying to have the setup change from: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 13,14,15,16,17,18,19,20,21,22, 23, 24 etc. to 1 2 3 4 5 6 7 8 9 10 11 12 etc. Any suggestions? Thanks in advance __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Implementing A Formula
Hello R Mailing List Members, My name is Peter. I am a high school student who is doing a senior thesis in statistical analysis. As you can see that I have chosen R. So for the project I am working with a member of the US Navy and analyzing some data. So for this data I am using a formula to find a cooling coefficient. This formula gets it own column in the table/display frame. So I wanted to know if put this formula into the display frame would I need to go row by row plugging this formula in to only take data from that individual row or would it just do that for me? If I did have to do it row by row would there be anyway I could expedite the process because it is over 2000 rows. Thank you for any help you are able to give me. -Peter [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Patterns on postal codes
Hi all, I'm pretty new to R and have a question. I have a postal_code field which can have a variety of values such as: For US postal codes: 22942-0173 or 32601 For Canada postal codes: N9YZE6 or S7V 1J9 What I want to do is represent these as patterns, such as: US: N- or N Canada: ANAAAN or ANA NAN where N = any number and A = any alpha character, space = space, etc (other characters such as ' should be represented as '. Ultimately I want to count these to see how many have a pattern of N-, ANA NAN, etc so that I can visualize the outliers. Does anyone know if there is a built-in function in R to do this? Currently, the str() function on the postal_code field shows a factor with 90,993 levels which isn't particularly helpful. Thanks in advance! -- Jeff [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Implementing A Formula
Hi Is is something like this that you want? mydata - data.frame(a=1:10, b=11:20, c=21:30, d=31:40, e=41:50) myfun - function(a,b,c)a*b+c mydata$cool - do.call(myfun, mydata[,c(a, b, c)]) mydata ## a b c d e cool ## 1 1 11 21 31 41 32 ## 2 2 12 22 32 42 46 ## 3 3 13 23 33 43 62 ## 4 4 14 24 34 44 80 ## 5 5 15 25 35 45 100 ## 6 6 16 26 36 46 122 ## 7 7 17 27 37 47 146 ## 8 8 18 28 38 48 172 ## 9 9 19 29 39 49 200 ## 10 10 20 30 40 50 230 Yours sincerely / Med venlig hilsen Frede Aakmann Tøgersen Specialist, M.Sc., Ph.D. Plant Performance Modeling Technology Service Solutions T +45 9730 5135 M +45 2547 6050 fr...@vestas.com http://www.vestas.com Company reg. name: Vestas Wind Systems A/S This e-mail is subject to our e-mail disclaimer statement. Please refer to www.vestas.com/legal/notice If you have received this e-mail in error please contact the sender. -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Norman McBride Sent: 7. januar 2014 23:46 To: r-help@r-project.org Subject: [R] Implementing A Formula Hello R Mailing List Members, My name is Peter. I am a high school student who is doing a senior thesis in statistical analysis. As you can see that I have chosen R. So for the project I am working with a member of the US Navy and analyzing some data. So for this data I am using a formula to find a cooling coefficient. This formula gets it own column in the table/display frame. So I wanted to know if put this formula into the display frame would I need to go row by row plugging this formula in to only take data from that individual row or would it just do that for me? If I did have to do it row by row would there be anyway I could expedite the process because it is over 2000 rows. Thank you for any help you are able to give me. -Peter [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Patterns on postal codes
Hi Something like this. ## 4 valid zips + 4 invalid zips zipcode - c(22942-0173, 32601, N9YZE6, S7V 1J9, 0022942-0173, 32-601, NN9YZE6, S7V 1J9) tmp - gsub([[:space:]], _, zipcode) tmp - gsub([[:alpha:]], A, tmp) tmp - gsub([[:digit:]], N, tmp) tmp ## [1] N- NANAAAN ANA_NAN NNN- ## [6] NN-NNN AANAAAN ANA__NAN patterns - c(N-, N, ANAAAN, ANA_NAN) zipcode[tmp %in% patterns] ## [1] 22942-0173 32601 N9YZE6 S7V 1J9 zipcode[!tmp %in% patterns] ## [1] 0022942-0173 32-601 NN9YZE6 S7V 1J9 Yours sincerely / Med venlig hilsen Frede Aakmann Tøgersen Specialist, M.Sc., Ph.D. Plant Performance Modeling Technology Service Solutions T +45 9730 5135 M +45 2547 6050 fr...@vestas.com http://www.vestas.com Company reg. name: Vestas Wind Systems A/S This e-mail is subject to our e-mail disclaimer statement. Please refer to www.vestas.com/legal/notice If you have received this e-mail in error please contact the sender. -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Jeff Johnson Sent: 8. januar 2014 00:11 To: r-help@r-project.org Subject: [R] Patterns on postal codes Hi all, I'm pretty new to R and have a question. I have a postal_code field which can have a variety of values such as: For US postal codes: 22942-0173 or 32601 For Canada postal codes: N9YZE6 or S7V 1J9 What I want to do is represent these as patterns, such as: US: N- or N Canada: ANAAAN or ANA NAN where N = any number and A = any alpha character, space = space, etc (other characters such as ' should be represented as '. Ultimately I want to count these to see how many have a pattern of N-, ANA NAN, etc so that I can visualize the outliers. Does anyone know if there is a built-in function in R to do this? Currently, the str() function on the postal_code field shows a factor with 90,993 levels which isn't particularly helpful. Thanks in advance! -- Jeff [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Different colours for LatticeExtra graphs
Hello, I am using the panel.3dpolygon function from the LatticeExtra package. I am graphing a matrix. I can't find a way in which each polygon is presented in a different color. The description of the function says that the col argument permits vectors (the components of which are colors) to be associated with each bar in a panel.3dbars graph, but nothing with panel.3dpolygon... I write a vector while using the function, but it will only use the first component of the vector to give color to the whole graph. Thanks, Alvaro -- View this message in context: http://r.789695.n4.nabble.com/Different-colours-for-LatticeExtra-graphs-tp4683250.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Raster in parallel computing?
Hi everyone, I am using the package raster to interpolate a large number of rasters (~1million) of different resolutions to a unique 1degree resolution grid and wonder if you know if it is possible to do this in parallel computer?. My code (example below) works like a charm but it will take 30 days to process all the rasters. Sadly, the process only uses one core of my computer. I wonder if there is a way to run this code (example below) in parallel computer?. Thanks, Camilo TEST CODE## library (raster) #creates 3 test rasters a - raster(nrow=3, ncol=3) a[] - 1:9 b - raster(nrow=3, ncol=3) b[] - 10:18 c - raster(nrow=3, ncol=3) c[] - 19:27 #concatenates the rasters d-brick(a,b,c) #creates a raster at a different resolution s - raster(nrow=10, ncol=10) #interpolates data from the brick to the new resolution s - resample(d, s, method='bilinear') __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
