Re: [R] Alignment of the title in a key for xyplot in lattice.
On 24/12/19 2:29 pm, Jim Lemon wrote: Hi Rolf, Following the docs back to draw.key, It looks like the ellipsis argument is ignored. I was hoping for a brilliant solution along the lines of: adj=0 that could be passed down the functions like a hot potato, but was disappointed. Thanks for giving it some thought. Actually I've found a work-around: make the title the first entry of the text component of the key, with the corresponding entries of the other components being NA. And omitting the "title" argument. An example of the result is attached. It satisfies me, at least! :-) cheers, Rolf -- Honorary Research Fellow Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 xmpl2.pdf Description: Adobe PDF document __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help with if statement with two conditions
Hi Jim, Burt and all who have been so helpful - very much appreciated!
I have managed to get the code to run correctly by extending the parentheses
around the whole statement, including the &, rather than parentheses around the
two clauses on either side of the &.
It seems to have done the trick!
I am not sure how to close the thread - I hate to waste anyone's time on a
problem that is no longer a problem! I am new to this forum
Thanks again for all the feedback and help everyone!
-Kimberly
-Original Message-
From: Jim Lemon
Sent: Monday, December 23, 2019 3:33 PM
To: Steinmann, Kimberly@CDPR ; r-help mailing
list
Subject: Re: [R] help with if statement with two conditions
EXTERNAL:
Hi Kimberley,
Since you are using a loop and therefore testing one value of v_trends_lbs at a
time, the "&" in the "if" statement should be "&&".
Pinching Bert's example but using a for loop instead of ifelse:
x <- seq(-2,2,.25)
v_lbs<-rep("",length(x))
for(i in 1:length(x)) {
if(is.na(x[i])) v_lbs<-"0"
else {
if(x[i] < 0.51 && x[i] > 0) v_lbs[i]<-"<1"
else v_lbs[i] <- format(round(x[i]), big.mark=",",scientific=FALSE) } } x
v_lbs
I think this gives you the "right" answer, as I have used 0.51 to avoid the
rounding problem at 0.5. I can see that the output is feeding into something
else, and an incorrect value at the end of your calculations would be more
difficult to track back. Bert's "ifelse" is a more elegant way to do this,
although not quote as easy for the beginner to understand.
Jim
On Tue, Dec 24, 2019 at 7:33 AM Steinmann, Kimberly@CDPR
wrote:
>
> Hi - i am not super familiar with R, but need to modify my predecessor's R
> code so that if a variable is >0 and < 0.5, it will be replaced with <1. I
> have looked at a bunch of forum threads on the subject, but cannot seem to
> get anything to work Any help at what i might be doing wrong much
> appreciated. I am definitely an R newbie!
>
> current code that works:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> my attempt to add a >0 that gets an error pointing at the & sign:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) & (v_trends_lbs[i, j] > 0) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> Thanks for any help!
>
>
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Re: [R] Alignment of the title in a key for xyplot in lattice.
Hi Rolf, Following the docs back to draw.key, It looks like the ellipsis argument is ignored. I was hoping for a brilliant solution along the lines of: adj=0 that could be passed down the functions like a hot potato, but was disappointed. Jim On Tue, Dec 24, 2019 at 9:26 AM Rolf Turner wrote: > > > The title of a key seems to be horizontally centred in the key; I would > like to have it aligned with the left hand edge. I.e. I would like the > first letter of the title to have the same horizontal position as the > first letters of the text strings. > > E.g. in the attached example I would like the "P" in "Point type" to be > directly above the "o" in "obsd" and "f" in "fitted". > > Is there any way to effect this? Thanks. > > cheers, > > Rolf Turner > > -- > Honorary Research Fellow > Department of Statistics > University of Auckland > Phone: +64-9-373-7599 ext. 88276 > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help with if statement with two conditions
Hi Kimberley, Given the number of posts that read "I have a problem, please advise", your concern for our mental welfare is a great Xmas present. Jim On Tue, Dec 24, 2019 at 10:38 AM Steinmann, Kimberly@CDPR wrote: > > I am not sure how to close the thread - I hate to waste anyone's time on a > problem that is no longer a problem! I am new to this forum > __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Converting AIS Message to Number
Hi Paul,
For your first question:
max(file.info(".")$mtime)
[1] "2019-12-21 21:04:19 AEDT"
As for the second, I didn't know what an AIS file was, so I googled
it. I still don't know, so I don't have a clue how to turn a string
like that into a number.
Jim
On Tue, Dec 24, 2019 at 5:14 AM Paul Bernal wrote:
>
> Dear friends,
>
> Hope you are doing great. I would like to process an AIS file (which comes
> in either a .txt or .csv format). The AIS file is contained in a specific
> path, say C:/AISFiles/File.txt. The file contains messages like the
> following:
> !AIVDM,2,1,2,A,5EPtgd42CRtIADNU@N0 (all of this is a single message).
>
> Is there a way to make R automatically retrieve the latest file saved on
> the path, take each message and convert it to a number?
>
> Best regards,
>
> Paul
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] help with if statement with two conditions
Hi Kimberley,
Since you are using a loop and therefore testing one value of
v_trends_lbs at a time, the "&" in the "if" statement should be "&&".
Pinching Bert's example but using a for loop instead of ifelse:
x <- seq(-2,2,.25)
v_lbs<-rep("",length(x))
for(i in 1:length(x)) {
if(is.na(x[i])) v_lbs<-"0"
else {
if(x[i] < 0.51 && x[i] > 0) v_lbs[i]<-"<1"
else v_lbs[i] <- format(round(x[i]), big.mark=",",scientific=FALSE)
}
}
x
v_lbs
I think this gives you the "right" answer, as I have used 0.51 to
avoid the rounding problem at 0.5. I can see that the output is
feeding into something else, and an incorrect value at the end of your
calculations would be more difficult to track back. Bert's "ifelse" is
a more elegant way to do this, although not quote as easy for the
beginner to understand.
Jim
On Tue, Dec 24, 2019 at 7:33 AM Steinmann, Kimberly@CDPR
wrote:
>
> Hi - i am not super familiar with R, but need to modify my predecessor's R
> code so that if a variable is >0 and < 0.5, it will be replaced with <1. I
> have looked at a bunch of forum threads on the subject, but cannot seem to
> get anything to work Any help at what i might be doing wrong much
> appreciated. I am definitely an R newbie!
>
> current code that works:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> my attempt to add a >0 that gets an error pointing at the & sign:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) & (v_trends_lbs[i, j] > 0) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> Thanks for any help!
>
>
> CONFIDENTIALITY NOTICE: This e-mail message, including a...{{dropped:10}}
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Alignment of the title in a key for xyplot in lattice.
The title of a key seems to be horizontally centred in the key; I would like to have it aligned with the left hand edge. I.e. I would like the first letter of the title to have the same horizontal position as the first letters of the text strings. E.g. in the attached example I would like the "P" in "Point type" to be directly above the "o" in "obsd" and "f" in "fitted". Is there any way to effect this? Thanks. cheers, Rolf Turner -- Honorary Research Fellow Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 xmpl.pdf Description: Adobe PDF document __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Split
Dear Burt, you gave a very elegant solution. Many thanks! Jeff, I understand your solution, thank you very much for your time! Colleague Milos, patronage is exactly what I need. I hope for your further guidance! (Rcmdr is not enough for some purposes.) Dear Ivan, I used your solution! It's the most understandable for me! Thanks!!! __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help with if statement with two conditions
WITHOUT going through your code carefully (but where is v_lbs first
defined?), maybe something like this is what you want:
> x <- seq(-2,2,.25)
> x
[1] -2.00 -1.75 -1.50 -1.25 -1.00 -0.75 -0.50 -0.25 0.00 0.25 0.50
0.75 1.00
[14] 1.25 1.50 1.75 2.00
> x <- ifelse(x>0 & x<1, '<1', format(round(x,2), big.mark=",",
scientific=FALSE) )
> x
[1] "-2.00" "-1.75" "-1.50" "-1.25" "-1.00" "-0.75" "-0.50" "-0.25" " 0.00"
[10] "<1""<1""<1"" 1.00" " 1.25" " 1.50" " 1.75" " 2.00"
... or maybe not. You decide.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Dec 23, 2019 at 12:33 PM Steinmann, Kimberly@CDPR <
kimberly.steinm...@cdpr.ca.gov> wrote:
> Hi - i am not super familiar with R, but need to modify my predecessor's R
> code so that if a variable is >0 and < 0.5, it will be replaced with <1. I
> have looked at a bunch of forum threads on the subject, but cannot seem to
> get anything to work Any help at what i might be doing wrong much
> appreciated. I am definitely an R newbie!
>
> current code that works:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> my attempt to add a >0 that gets an error pointing at the & sign:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) & (v_trends_lbs[i, j] > 0) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> Thanks for any help!
>
>
> CONFIDENTIALITY NOTICE: This e-mail message, including a...{{dropped:10}}
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] R code required
You are corresponding to a mailing list, but you need to be corresponding with the author of the paper you are referring to. I have no idea who that is or what the paper is that you are referring to. On December 23, 2019 6:32:26 AM PST, Salwa El-Aty wrote: > > >Dear Sir >I want to help me about to send the R Code of paper which title >Inference of Generalized endpoint inflated binomial regression . In . > 2017 >Best Regards >Salwa. A.Mousa > >Sent from my Samsung device > > [[alternative HTML version deleted]] > >__ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. -- Sent from my phone. Please excuse my brevity. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help with if statement with two conditions
What does the error message say?
On Mon, Dec 23, 2019, 3:33 PM Steinmann, Kimberly@CDPR <
kimberly.steinm...@cdpr.ca.gov> wrote:
> Hi - i am not super familiar with R, but need to modify my predecessor's R
> code so that if a variable is >0 and < 0.5, it will be replaced with <1. I
> have looked at a bunch of forum threads on the subject, but cannot seem to
> get anything to work Any help at what i might be doing wrong much
> appreciated. I am definitely an R newbie!
>
> current code that works:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> my attempt to add a >0 that gets an error pointing at the & sign:
> v_lbs_list <- ""
> for (j in 2:(p_num_years+1)) {
> if (is.na(v_trends_lbs[i, j])) {
> v_lbs <- ' 0 '
> } else if (v_trends_lbs[i, j] < 0.5) & (v_trends_lbs[i, j] > 0) {
> v_lbs <- ' $<$1 '
> } else {
> v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
> scientific=FALSE)
> }
> v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
> }
>
> Thanks for any help!
>
>
> CONFIDENTIALITY NOTICE: This e-mail message, including a...{{dropped:10}}
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Tinn-R project: new version (6.01.01.03) released
Josè Sent from Yahoo Mail on Android On Mon, Dec 23, 2019 at 12:15 PM, Abby Spurdle wrote: Hi Jose,Same here, I use tinn-R on a daily basis..thanks for the update and have a merry christmas That's awesome. I used Tinn-R, back in 2006, when I starting learning nontrivial R programming. I used it extensively, before shifting to my own (still incomplete) programming environment. Back then, Emacs (with ESS) had the monopoly on Linux, and Tinn-R was leading the race on Windows. You've made extremely valuable contributions to the R community. And I look forward to seeing future progress... Abs On Tue, Dec 24, 2019 at 3:40 AM Jose Claudio Faria wrote: > > Hi, > > A new version of Tinn-R project (6.01.01.03) was released today. > > Download: > - https://nbcgib.uesc.br/tinnr/en/download > - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/ > > What is new: > - https://nbcgib.uesc.br/tinnr/en/download#patch > - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/6.1.1.3/ > > Best, > ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ > Jose Claudio Faria > UESC/DCET/Brasil > joseclaudio.faria at gmail.com > Telefones: > 55(73)3680.5545 - UESC > 55(73)99966.9100 - VIVO > ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ > > If you have software to deal with statistics, you have arms; > if you have good software, you have arms and legs; > if you have software like R, you have arms, legs and wings... > the height of your flight depends only on you! > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] R code required
Dear Sir I want to help me about to send the R Code of paper which title Inference of Generalized endpoint inflated binomial regression . In . 2017 Best Regards Salwa. A.Mousa Sent from my Samsung device [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] help with if statement with two conditions
Hi - i am not super familiar with R, but need to modify my predecessor's R code
so that if a variable is >0 and < 0.5, it will be replaced with <1. I have
looked at a bunch of forum threads on the subject, but cannot seem to get
anything to work Any help at what i might be doing wrong much appreciated. I am
definitely an R newbie!
current code that works:
v_lbs_list <- ""
for (j in 2:(p_num_years+1)) {
if (is.na(v_trends_lbs[i, j])) {
v_lbs <- ' 0 '
} else if (v_trends_lbs[i, j] < 0.5) {
v_lbs <- ' $<$1 '
} else {
v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
scientific=FALSE)
}
v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
}
my attempt to add a >0 that gets an error pointing at the & sign:
v_lbs_list <- ""
for (j in 2:(p_num_years+1)) {
if (is.na(v_trends_lbs[i, j])) {
v_lbs <- ' 0 '
} else if (v_trends_lbs[i, j] < 0.5) & (v_trends_lbs[i, j] > 0) {
v_lbs <- ' $<$1 '
} else {
v_lbs <- format(round(v_trends_lbs[i, j]), big.mark=",",
scientific=FALSE)
}
v_lbs_list <- paste(v_lbs_list, ' & ', v_lbs)
}
Thanks for any help!
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Re: [R] Tinn-R project: new version (6.01.01.03) released
Hi Jose, That's awesome. I used Tinn-R, back in 2006, when I starting learning nontrivial R programming. I used it extensively, before shifting to my own (still incomplete) programming environment. Back then, Emacs (with ESS) had the monopoly on Linux, and Tinn-R was leading the race on Windows. You've made extremely valuable contributions to the R community. And I look forward to seeing future progress... Abs On Tue, Dec 24, 2019 at 3:40 AM Jose Claudio Faria wrote: > > Hi, > > A new version of Tinn-R project (6.01.01.03) was released today. > > Download: > - https://nbcgib.uesc.br/tinnr/en/download > - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/ > > What is new: > - https://nbcgib.uesc.br/tinnr/en/download#patch > - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/6.1.1.3/ > > Best, > ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ > Jose Claudio Faria > UESC/DCET/Brasil > joseclaudio.faria at gmail.com > Telefones: > 55(73)3680.5545 - UESC > 55(73)99966.9100 - VIVO > ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ > > If you have software to deal with statistics, you have arms; > if you have good software, you have arms and legs; > if you have software like R, you have arms, legs and wings... > the height of your flight depends only on you! > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Split
J have just seen your follow-up post (out of tread). I don’t want to be
rude or patronizing but few caveats.
Neither R nor R help are meant to be user friendly. Learning curve is steep
but very rewarding at the end.
Problem you have can be solved in a literary hundred ways. Unfortunately,
your question was not a reproducible example and you got most complicated
answer. Apply entourage is kind of dark art in R, so I offered different
solutions, and hope that my answer helped.
Being medic too, I understand your pain, but for the star I suggest Rcmdr.
Regards,
Miloš
On Mon, 23 Dec 2019 at 20:36, Bert Gunter wrote:
> Do you mean IQR? -- I don't know what ICR means.
> If so, see IQR.
>
> More generally see ?by or more generally ?tapply to obtain whatever sort of
> summary you want.
>
> e.g.
>
> > d <-data.frame( x = runif(10), w = rep(c("a","b"),5))
> > by(d$x, d$w, FUN = function(x)c(median = median(x),IQR = IQR(x)))
> d$w: a
>median IQR
> 0.5469662 0.4548506
> --
> d$w: b
>median IQR
> 0.6860975 0.3456893
>
>
> -- Bert
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Mon, Dec 23, 2019 at 9:15 AM Medic wrote:
>
> > I have
> > mydata$var
> > #this is ONE group of patients
> >
> > And I would like to get
> > median and ICR of mydata$var.
> >
> > How can I get this?
> > With summary (mydata$var)!
> >
> > Ok!
> >
> > And now I would like to get THE SAME, but for TWO group: male and
> > female (which are contained in the group mydata$var)
> >
> > How can I get this?
> > First I need to split mydata$var by mydata$sex, and then take:
> >
> > summary (for male)
> > and
> > summary (for female)
> >
> > That's all I want
> >
> > Bert,
> > ave(mydata$var, madata$sex, FUN=median)
> > gives me:
> > [1] 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6
> > 5.6 5.6 5.6 5.6
> > [21] 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0
> > 6.0 6.0 6.0 6.0
> > What is it?
> > It is an endless(???) repetition of the median.
> > Moreover, there is no ICR.
> >
> > Jeff,
> > your constructions are too complicated for me
> > ===
> > P.S. Such simple thing and so difficult?! (I begin think about the
> Excel.)
> >
> > __
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
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Re: [R] Split
Do you mean IQR? -- I don't know what ICR means.
If so, see IQR.
More generally see ?by or more generally ?tapply to obtain whatever sort of
summary you want.
e.g.
> d <-data.frame( x = runif(10), w = rep(c("a","b"),5))
> by(d$x, d$w, FUN = function(x)c(median = median(x),IQR = IQR(x)))
d$w: a
median IQR
0.5469662 0.4548506
--
d$w: b
median IQR
0.6860975 0.3456893
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Dec 23, 2019 at 9:15 AM Medic wrote:
> I have
> mydata$var
> #this is ONE group of patients
>
> And I would like to get
> median and ICR of mydata$var.
>
> How can I get this?
> With summary (mydata$var)!
>
> Ok!
>
> And now I would like to get THE SAME, but for TWO group: male and
> female (which are contained in the group mydata$var)
>
> How can I get this?
> First I need to split mydata$var by mydata$sex, and then take:
>
> summary (for male)
> and
> summary (for female)
>
> That's all I want
>
> Bert,
> ave(mydata$var, madata$sex, FUN=median)
> gives me:
> [1] 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6
> 5.6 5.6 5.6 5.6
> [21] 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0
> 6.0 6.0 6.0 6.0
> What is it?
> It is an endless(???) repetition of the median.
> Moreover, there is no ICR.
>
> Jeff,
> your constructions are too complicated for me
> ===
> P.S. Such simple thing and so difficult?! (I begin think about the Excel.)
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Split
If I understand correctly you need summary by group. I would suggest arsenal package and tableby tab1 <- tableby(group ~ anova(var, "meansd", digits=1) + #mean and sd + round to 1 digit + anova kwt(var, "medianq1q3", digits=1) , #median q1 and q3 + round to 1 digit + Kruskal-Wallis data=sn.l.v2.t0) summary(tab1,text=TRUE) #output as txt to console write2word(tab1,"tab1.docx", pfootnote=TRUE) #save as formatted word table or even simpler using Rcmdr - Statistics - Numerical summaries and tha choose summarize by groups Milos On Mon, 23 Dec 2019 at 15:57, Medic wrote: > I have > mydata$var > > and I have > mydata$group #two group > > I would like to split > mydata$var > by > mydata$group #to get var1 and var2 > > And then get > summary (var1, var2) #this is my finite aim > > How to encode it all? > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Converting AIS Message to Number
The "digest" package might be what you're looking for: messages --> numerics Or perhaps you want to create a hash in R. Search on "hashing in R" or similar for info on this. See ?file.info for obtaining file info, including date/time info. Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Mon, Dec 23, 2019 at 10:14 AM Paul Bernal wrote: > Dear friends, > > Hope you are doing great. I would like to process an AIS file (which comes > in either a .txt or .csv format). The AIS file is contained in a specific > path, say C:/AISFiles/File.txt. The file contains messages like the > following: > !AIVDM,2,1,2,A,5EPtgd42CRtIADNU@N0 `0?0kk3k`40CP,0*2D,1532995201 > (all of this is a single message). > > Is there a way to make R automatically retrieve the latest file saved on > the path, take each message and convert it to a number? > > Best regards, > > Paul > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Converting AIS Message to Number
Dear friends, Hope you are doing great. I would like to process an AIS file (which comes in either a .txt or .csv format). The AIS file is contained in a specific path, say C:/AISFiles/File.txt. The file contains messages like the following: !AIVDM,2,1,2,A,5EPtgd42CRtIADNU@N0https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Split
On Mon, 23 Dec 2019 17:56:35 +0300 Medic wrote: > I would like to split > mydata$var > by > mydata$group #to get var1 and var2 There is the split() function that does exactly that (except it returns a list instead of multiple variables)... > And then get > summary (var1, var2) #this is my finite aim ...and you can either use lapply() on the list returned by split() or tapply() to both split the dataset into groups and call summary() on each in one expression. See ?tapply and example(tapply) for more info. -- Best regards, Ivan __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] all the MAE metric values are missing (Error message)
What Jim is alluding to is that sometimes in the process of reading in data a small typo can mean that what was intended to be a numeric variable is read in as a factor. So he was suggesting that you double check that this has not happened to you. Michael On 23/12/2019 11:45, Neha gupta wrote: Hi Jim, Another possibility is that the values used in the initial calculation have been read in as factors Which calculation you are talking about? I did not use factors as variable. Regards On Mon, Dec 23, 2019 at 3:12 AM Jim Lemon wrote: Hi Neha, Well, that's a clue to why you are getting NAs: log10(0) [1] -Inf Another possibility is that the values used in the initial calculation have been read in as factors. Jim On Mon, Dec 23, 2019 at 10:55 AM Neha gupta wrote: Hi Jim The objective function is passed to san_res where we have defined the 4 parameters of gbm and the values are initialized in san_res. The output variable price has only three values: 0, 1, 2 (like categorical values), so someone told me try to remove the log10 from the price. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Michael http://www.dewey.myzen.co.uk/home.html __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Split
I have mydata$var #this is ONE group of patients And I would like to get median and ICR of mydata$var. How can I get this? With summary (mydata$var)! Ok! And now I would like to get THE SAME, but for TWO group: male and female (which are contained in the group mydata$var) How can I get this? First I need to split mydata$var by mydata$sex, and then take: summary (for male) and summary (for female) That's all I want Bert, ave(mydata$var, madata$sex, FUN=median) gives me: [1] 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 5.6 [21] 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 6.0 What is it? It is an endless(???) repetition of the median. Moreover, there is no ICR. Jeff, your constructions are too complicated for me === P.S. Such simple thing and so difficult?! (I begin think about the Excel.) __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Split
Not clear what you mean by
summary (var1, var2)
? That is not a legal way to call summary. Perhaps
mt <- mtcars[,c("cyl","hp")]
mt$cyl <- factor( mt$cyl )
mtl <- split(mt[,"hp",drop=FALSE], mt$cyl)
lapply(mtl,summary)
On December 23, 2019 6:56:35 AM PST, Medic wrote:
>I have
>mydata$var
>
>and I have
>mydata$group #two group
>
>I would like to split
>mydata$var
>by
>mydata$group #to get var1 and var2
>
>And then get
>summary (var1, var2) #this is my finite aim
>
>How to encode it all?
>
>__
>R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
--
Sent from my phone. Please excuse my brevity.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] R API Call Failure Help
Thanks. I stand corrected. But... https://shiny.rstudio.com/ Cheers, Bert On Mon, Dec 23, 2019 at 6:29 AM Jeff Newmiller wrote: > Shiny is not an app... it is a contributed R package on CRAN. Of course, > with 15000 packages on CRAN this mailing list cannot necessarily support > questions about all of them (read the Posting Guide). > > That said, this question does not seem like the use of shiny is > necessarily relevant because shiny itself does not define nor support calls > to APIs. That is, I am not convinced that a shiny support forum is the > right place to get an answer. > > Given this, you (OP) may be able to make a reproducible example in R > [1][2][3] that does not involve shiny and we could at least help identify > which forum should be consulted. Of course this reprex would be useful to > post in whatever forum appears to be relevant, or it could help you to > understand the problem well enough to solve it yourself. > > [1] > http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example > > [2] http://adv-r.had.co.nz/Reproducibility.html > > [3] https://cran.r-project.org/web/packages/reprex/index.html (read the > vignette) > > > On December 22, 2019 3:44:19 PM PST, Bert Gunter > wrote: > >I think this is the wrong list. Shiny is an RStudio app and is not part > >of > >R. You need to post on the RStudio site. > > > > > >Bert Gunter > > > >"The trouble with having an open mind is that people keep coming along > >and > >sticking things into it." > >-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > > > >On Sun, Dec 22, 2019 at 3:15 PM Vinish Vishwanathan > > > >wrote: > > > >> Hello All, > >> > >> I just subscribed to this mail list and needed some help on an > >ongoing > >> issue with details stated below > >> > >> Issue: An API call from R Shiny App to a server in Cloud fails with > >error: > >> > >> Error:* SSL read: error::lib(0):func(0):reason(0), errno 110 > >> * Connection died, retrying a fresh connect > >> * Closing connection 18 > >> > >> Details: I am using the httr to do a POST call to the API. > >> > >> Help Needed: Anyone from experience calling APIs from R, if can help > >to > >> identify the cause for the error. > >> > >> My feeling is, its because of http Keep Alive and anyone parameter of > >it > >> which is not respected/expired, but not sure. > >> > >> -- > >> Regards > >> Vinish Viswanathan > >> > >> [[alternative HTML version deleted]] > >> > >> __ > >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > >> http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > >> > > > > [[alternative HTML version deleted]] > > > >__ > >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >https://stat.ethz.ch/mailman/listinfo/r-help > >PLEASE do read the posting guide > >http://www.R-project.org/posting-guide.html > >and provide commented, minimal, self-contained, reproducible code. > > -- > Sent from my phone. Please excuse my brevity. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Split
?ave Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Mon, Dec 23, 2019 at 6:57 AM Medic wrote: > I have > mydata$var > > and I have > mydata$group #two group > > I would like to split > mydata$var > by > mydata$group #to get var1 and var2 > > And then get > summary (var1, var2) #this is my finite aim > > How to encode it all? > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Split
I have mydata$var and I have mydata$group #two group I would like to split mydata$var by mydata$group #to get var1 and var2 And then get summary (var1, var2) #this is my finite aim How to encode it all? __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Tinn-R project: new version (6.01.01.03) released
Hi, A new version of Tinn-R project (6.01.01.03) was released today. Download: - https://nbcgib.uesc.br/tinnr/en/download - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/ What is new: - https://nbcgib.uesc.br/tinnr/en/download#patch - https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/6.1.1.3/ Best, ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ Jose Claudio Faria UESC/DCET/Brasil joseclaudio.faria at gmail.com Telefones: 55(73)3680.5545 - UESC 55(73)99966.9100 - VIVO ///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\ If you have software to deal with statistics, you have arms; if you have good software, you have arms and legs; if you have software like R, you have arms, legs and wings... the height of your flight depends only on you! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R API Call Failure Help
Shiny is not an app... it is a contributed R package on CRAN. Of course, with 15000 packages on CRAN this mailing list cannot necessarily support questions about all of them (read the Posting Guide). That said, this question does not seem like the use of shiny is necessarily relevant because shiny itself does not define nor support calls to APIs. That is, I am not convinced that a shiny support forum is the right place to get an answer. Given this, you (OP) may be able to make a reproducible example in R [1][2][3] that does not involve shiny and we could at least help identify which forum should be consulted. Of course this reprex would be useful to post in whatever forum appears to be relevant, or it could help you to understand the problem well enough to solve it yourself. [1] http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example [2] http://adv-r.had.co.nz/Reproducibility.html [3] https://cran.r-project.org/web/packages/reprex/index.html (read the vignette) On December 22, 2019 3:44:19 PM PST, Bert Gunter wrote: >I think this is the wrong list. Shiny is an RStudio app and is not part >of >R. You need to post on the RStudio site. > > >Bert Gunter > >"The trouble with having an open mind is that people keep coming along >and >sticking things into it." >-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > >On Sun, Dec 22, 2019 at 3:15 PM Vinish Vishwanathan > >wrote: > >> Hello All, >> >> I just subscribed to this mail list and needed some help on an >ongoing >> issue with details stated below >> >> Issue: An API call from R Shiny App to a server in Cloud fails with >error: >> >> Error:* SSL read: error::lib(0):func(0):reason(0), errno 110 >> * Connection died, retrying a fresh connect >> * Closing connection 18 >> >> Details: I am using the httr to do a POST call to the API. >> >> Help Needed: Anyone from experience calling APIs from R, if can help >to >> identify the cause for the error. >> >> My feeling is, its because of http Keep Alive and anyone parameter of >it >> which is not respected/expired, but not sure. >> >> -- >> Regards >> Vinish Viswanathan >> >> [[alternative HTML version deleted]] >> >> __ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > [[alternative HTML version deleted]] > >__ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. -- Sent from my phone. Please excuse my brevity. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] all the MAE metric values are missing (Error message)
Hi Jim, Another possibility is that the values used in the initial calculation have been read in as factors Which calculation you are talking about? I did not use factors as variable. Regards On Mon, Dec 23, 2019 at 3:12 AM Jim Lemon wrote: > Hi Neha, > Well, that's a clue to why you are getting NAs: > > log10(0) > [1] -Inf > > Another possibility is that the values used in the initial calculation > have been read in as factors. > > Jim > > On Mon, Dec 23, 2019 at 10:55 AM Neha gupta > wrote: > > > > Hi Jim > > > > The objective function is passed to san_res where we have defined the 4 > parameters of gbm and the values are initialized in san_res. > > > > The output variable price has only three values: 0, 1, 2 (like > categorical values), so someone told me try to remove the log10 from the > price. > > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
