Re: [R] converting MATLAB -> R | element-wise operation
... and here is a more or less direct translation of the Matlab code that should now be obvious given your previous responses: > m <- matrix(1:6, nr=2, byrow = TRUE) ## Matlab order > m [,1] [,2] [,3] [1,]123 [2,]456 > sweep(m, 2, 2:4, "/") [,1] [,2] [,3] [1,] 0.5 0.667 0.75 [2,] 2.0 1.667 1.50 Cheers, Bert On Tue, Feb 27, 2024 at 1:03 PM Evan Cooch wrote: > So, trying to convert a very long, somewhat technical bit of lin alg > MATLAB code to R. Most of it working, but raninto a stumbling block that > is probaably simple enough for someone to explain. > > Basically, trying to 'line up' MATLAB results from an element-wise > division of a matrix by a vector with R output. > > Here is a simplified version of the MATLAB code I'm translating: > > NN = [1, 2, 3; 4, 5, 6]; % Example matrix > lambda = [2, 3, 4]; % Example vector > result_matlab = NN ./ lambda; > > which yields > > 0.5 0.7 0.75000 > 2.0 1.7 1.5 > > > So, the only way I have stumbled onto in R to generate the same results > is to use 'sweep'. The following 'works', but I'm hoping someone can > explain why I need something as convoluted as this seems (to me, at least). > > NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix > lambda <- c(2, 3, 4) # Example vector > sweep(NN, 2, lambda, "/") > > > [,1] [,2] [,3] > [1,] 0.5 0.667 0.75 > [2,] 2.0 1.667 1.50 > > First tried the more 'obvious' NN/lambda, but that yields 'the wrong > answer' (based solely on what I'm trying to accomplish): > > > [,1] [,2] [,3] > [1,] 0.50 0.5 1.0 > [2,] 1.33 2.5 1.5 > > So, why 'sweep'? > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] converting MATLAB -> R | element-wise operation
Why anything but sweep? The fundamental data type in Matlab is a matrix... they don't have vectors, they have Nx1 matrices and 1xM matrices. Vectors don't have any concept of "row" vs. "column". Straight division is always elementwise with recycling as needed, and matrices are really vectors in row-major order: 1 2 3 4 5 6 is really 1 4 2 5 3 6 and when you do straight division NN / lambda then lambda is repeated: 1 4 2 5 3 6 2 3 4 2 3 4 to get 0.5 1.3 0.5 2.5 1.0 1.5 but if you transpose first 1 4 2 5 3 6 then that corresponds to an underlying vector: 1 2 3 4 5 6 which lines up with lambda in t(NN)/lambda as: 1 2 3 4 5 6 2 3 4 2 3 4 to obtain: 0.50 0.67 0.75 2.0 1.67 1.50 and inherits the dimensions of t(NN): 0.50 2.00 0.67 1.67 0.75 1.50 which can be transposed back as in t( t( NN ) / lambda ): 0.50 0.67 0.75 2.00 1.67 1.50 but that requires a lot of moving elements around while sweep does not. Operators are not necessarily "better" than named functions... they just look different. On February 27, 2024 11:54:26 AM PST, Evan Cooch wrote: >So, trying to convert a very long, somewhat technical bit of lin alg >MATLAB code to R. Most of it working, but raninto a stumbling block that >is probaably simple enough for someone to explain. > >Basically, trying to 'line up' MATLAB results from an element-wise >division of a matrix by a vector with R output. > >Here is a simplified version of the MATLAB code I'm translating: > >NN = [1, 2, 3; 4, 5, 6]; % Example matrix >lambda = [2, 3, 4]; % Example vector >result_matlab = NN ./ lambda; > >which yields > > 0.5 0.7 0.75000 > 2.0 1.7 1.5 > > >So, the only way I have stumbled onto in R to generate the same results >is to use 'sweep'. The following 'works', but I'm hoping someone can >explain why I need something as convoluted as this seems (to me, at least). > >NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix >lambda <- c(2, 3, 4) # Example vector >sweep(NN, 2, lambda, "/") > > > [,1] [,2] [,3] >[1,] 0.5 0.667 0.75 >[2,] 2.0 1.667 1.50 > >First tried the more 'obvious' NN/lambda, but that yields 'the wrong >answer' (based solely on what I'm trying to accomplish): > > > [,1] [,2] [,3] >[1,] 0.50 0.5 1.0 >[2,] 1.33 2.5 1.5 > >So, why 'sweep'? > > [[alternative HTML version deleted]] > >__ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. -- Sent from my phone. Please excuse my brevity. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] [External] converting MATLAB -> R | element-wise operation
> t(t(NN)/lambda) [,1] [,2] [,3] [1,] 0.5 0.667 0.75 [2,] 2.0 1.667 1.50 > R matrices are column-based. MATLAB matrices are row-based. > On Feb 27, 2024, at 14:54, Evan Cooch wrote: > > So, trying to convert a very long, somewhat technical bit of lin alg > MATLAB code to R. Most of it working, but raninto a stumbling block that > is probaably simple enough for someone to explain. > > Basically, trying to 'line up' MATLAB results from an element-wise > division of a matrix by a vector with R output. > > Here is a simplified version of the MATLAB code I'm translating: > > NN = [1, 2, 3; 4, 5, 6]; % Example matrix > lambda = [2, 3, 4]; % Example vector > result_matlab = NN ./ lambda; > > which yields > > 0.5 0.7 0.75000 > 2.0 1.7 1.5 > > > So, the only way I have stumbled onto in R to generate the same results > is to use 'sweep'. The following 'works', but I'm hoping someone can > explain why I need something as convoluted as this seems (to me, at least). > > NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix > lambda <- c(2, 3, 4) # Example vector > sweep(NN, 2, lambda, "/") > > > [,1] [,2] [,3] > [1,] 0.5 0.667 0.75 > [2,] 2.0 1.667 1.50 > > First tried the more 'obvious' NN/lambda, but that yields 'the wrong > answer' (based solely on what I'm trying to accomplish): > > >[,1] [,2] [,3] > [1,] 0.50 0.5 1.0 > [2,] 1.33 2.5 1.5 > > So, why 'sweep'? > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.r-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] converting MATLAB -> R | element-wise operation
So, trying to convert a very long, somewhat technical bit of lin alg MATLAB code to R. Most of it working, but raninto a stumbling block that is probaably simple enough for someone to explain. Basically, trying to 'line up' MATLAB results from an element-wise division of a matrix by a vector with R output. Here is a simplified version of the MATLAB code I'm translating: NN = [1, 2, 3; 4, 5, 6]; % Example matrix lambda = [2, 3, 4]; % Example vector result_matlab = NN ./ lambda; which yields 0.5 0.7 0.75000 2.0 1.7 1.5 So, the only way I have stumbled onto in R to generate the same results is to use 'sweep'. The following 'works', but I'm hoping someone can explain why I need something as convoluted as this seems (to me, at least). NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix lambda <- c(2, 3, 4) # Example vector sweep(NN, 2, lambda, "/") [,1] [,2] [,3] [1,] 0.5 0.667 0.75 [2,] 2.0 1.667 1.50 First tried the more 'obvious' NN/lambda, but that yields 'the wrong answer' (based solely on what I'm trying to accomplish): [,1] [,2] [,3] [1,] 0.50 0.5 1.0 [2,] 1.33 2.5 1.5 So, why 'sweep'? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
