[R] A simple question
Hello, I am trying to create a matrix that looks like this, using the stri_locate_all function. x - ABCDJAKSLABCDAKJSABCD m - stri_locate_all_regex(x, 'ABCD') m [[1]] start end [1,] 1 4 [2,]10 13 [3,]18 21 I tried converting m into a matrix, however it always seems to wrap around the wrong way: output - matrix(unlist(m), ncol = 2, byrow = TRUE) output [,1] [,2] [1,]1 10 [2,] 184 [3,] 13 21 I want to output the start locations in the first column and the end locations in the second column into a matrix to look like this. [,1] [,2] [1,] 1 4 [2,]10 13 [3,]18 21 Thank you for your help, Alex [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Matrix Manipulation
Hi guys, Suppose I have an extremely large data frame with 2 columns and .5 mil rows. For example, the last 6 rows may look like this: . .. ... 89 100 93 120 95 125 101NA 115NA 123NA 124NA I would like to manipulate this data frame to output a data frame that looks like:, 10089, 93, 95 120101, 115 125123, 124 What would be the absolute quickest way to do this, given that there are many rows? Currently I have this: # m is the large two column data frame end - na.omit(m[,'V2']); out - data.frame(End=end, Start=unname(sapply(split(m[,'V1'],findInterval(m[,'V1'],end))[as.character(0:c(length(end)-1))],paste,collapse='.'))) However this is taking a little bit too long. Thank you for your help! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
