Re: [R] glmer.nb: function not in downloaded lme4 package?

2013-05-19 Thread Niklas Fischer
Thanks in advance!


2013/5/18 Ben Bolker bbol...@gmail.com

 Ross Marriott Ross.Marriott at fish.wa.gov.au writes:

 
  Dear R Help,
 
  I would like to use the glmer.nb function for mixed modelling using
 negative binomial distribution please.
 
  On the CRAN website apparently this function is
  called from the lme4 package (version 0.9911-1).
 
  I have downloaded the latest version of the lme4 package
   (version 0.99-2) and have recently
  reinstalled the latest version of 64-bit R (version 3.0.1)
   but after loading the package and calling:
 

   This question would probably be better on the
 r-sig-mixed-mod...@r-project.org list.

glmer.nb() is _only_ in development versions of lme4,
 not in the stable version on CRAN, and furthermore it is
 still quite new and poorly tested.  If you want to try it
 out you are probably best of installing from github via
 install_github in the devtools package.  Alternatively
 you could try the glmmADMB package, on r-forge.

   Ben Bolker

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[R] index of quantile variation (iqv)

2013-05-19 Thread Niklas Fischer
Dear all,

I would like to compute index of quantile variation (iqv) for each
observation in my survey data according to their responses on three
categorical variable.

Do you know iqv function for this purpose in a package?

All the best,
Niklas

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[R] exporting data into STATA

2013-05-18 Thread Niklas Fischer
Dear All,

I am not very familiar with ASCII file format, and now I am trying to
export R data frame into STATA
When I run write.dta command, there is a warning below appear.

5: In abbreviate(ll, 80L) : abbreviate used with non-ASCII chars

Do you have any suggestion to fix it?

All the bests

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Re: [R] frequency table-visualization for complex categorical variables

2013-02-26 Thread Niklas Fischer
Hi again,



Thanks for Anthony about the links on reproducible codes.



Thanks for Rui about ordering when rows are intact.



One more question





Here is your code.



x -
cbind(
sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
sample( LETTERS[1:6] , 100 , replace = TRUE )
)

y - as.matrix( x )

w2 - apply( y , 1 , paste0 , collapse =  )
table(w2)







Do you know any trick to organize merge certain elements together?

For example, if the final table includes

BCC, CCB, CBC how should I sum frequency of one element like BCC? I have a
very long table it would be indeed very useful!





Niklas.

2013/2/25 Rui Barradas ruipbarra...@sapo.pt

 Hello,

 I disagree with the way you've sorted the matrix, like this all A's become
 first, then B's, etc, irrespective of the respondents. Each row is a
 respondent, and the rows should be kept intact, but with a different
 ordering. To this effect, use order():

 z - y[order(y[,1], y[,2], y[,3]), ]


 Then use the rest of your code.

 Or, which would save us the sorting, paste the rows elements together
 directly from matrix 'y' and use the fact that table() sorts its output.

 w2 - apply( y , 1 , paste0 , collapse =  )
 table(w2)


 Hope this helps,

 Rui Barradas

 Em 25-02-2013 18:32, Anthony Damico escreveu:

  in the future, please provide R code to re-create some example data :)
 read
 http://stackoverflow.com/**questions/5963269/how-to-make-**
 a-great-r-reproducible-**exampleforhttp://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-examplefor
 more detail..



 # create a data table with three unique columns' values..
 # treat these values just like letters
 x -
  cbind(
  sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
  sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
  sample( LETTERS[1:6] , 100 , replace = TRUE )
  )

 # look at x.. this is good data i hope?
 x

 # convert this to a matrix
 y - as.matrix( x )

 # i don't think you care about ordering, so sort left-to-rightwards
 z - apply( y , 2 , sort )

 # look at your results
 z

 # paste these results together across the matrix
 w - apply( z , 1 , paste0 , collapse =  )

 # count the final distinct results
 table( w )




 On Mon, Feb 25, 2013 at 1:04 PM, Niklas Fischer
 niklasfischer...@gmail.com**wrote:

  Dear R users,

 I have three questions measuring close relationships.
 The questions are same and the respondents put the answer in order.

 I'd like to examine the pattern of answers and visualize it.

 For example q1 (A,B,C,D,E) and q2 and q3 are the same. If the respondents
 selects A B C (so BCA or BAC or CBA or CAB), I'd like to construct
 frequency table for ABC and other combinations for example DEF.


 Unfortunately, there are many answers, and three-way contingency table
 includes lots of cells which make it diffucult to interpret and requires
 lots of extra work to organize data.

 What is the best way to construct fruequency table of these kind of
 variables and to visulize the results with the most simple form


 All the bests,
 Niklas

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Re: [R] frequency table-visualization for complex categorical variables

2013-02-26 Thread Niklas Fischer
Thanks Rui,
It is very useful indeed.
Bests,
Niklas

2013/2/26 Rui Barradas ruipbarra...@sapo.pt

 Hello,

 I'm not sure I understand, do you want to treat BCC, CBC and CCB as the
 same? If so try

 w2 - apply( y , 1 , function(x) paste0(sort(x) , collapse =  ))

 table(w2)


 Hope this helps,

 Rui Barradas

 Em 26-02-2013 13:58, Niklas Fischer escreveu:

 Hi again,



 Thanks for Anthony about the links on reproducible codes.



 Thanks for Rui about ordering when rows are intact.



 One more question





 Here is your code.



 x -
  cbind(
  sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
  sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
  sample( LETTERS[1:6] , 100 , replace = TRUE )
  )

 y - as.matrix( x )

 w2 - apply( y , 1 , paste0 , collapse =  )
 table(w2)







 Do you know any trick to organize merge certain elements together?

 For example, if the final table includes

 BCC, CCB, CBC how should I sum frequency of one element like BCC? I have a
 very long table it would be indeed very useful!





 Niklas.

 2013/2/25 Rui Barradas ruipbarra...@sapo.pt

  Hello,

 I disagree with the way you've sorted the matrix, like this all A's
 become
 first, then B's, etc, irrespective of the respondents. Each row is a
 respondent, and the rows should be kept intact, but with a different
 ordering. To this effect, use order():

 z - y[order(y[,1], y[,2], y[,3]), ]


 Then use the rest of your code.

 Or, which would save us the sorting, paste the rows elements together
 directly from matrix 'y' and use the fact that table() sorts its output.

 w2 - apply( y , 1 , paste0 , collapse =  )
 table(w2)


 Hope this helps,

 Rui Barradas

 Em 25-02-2013 18:32, Anthony Damico escreveu:

   in the future, please provide R code to re-create some example data :)

 read
 http://stackoverflow.com/questions/5963269/how-to-make-http://stackoverflow.com/**questions/5963269/how-to-make-**
 a-great-r-reproducible-exampleforhttp://**
 stackoverflow.com/questions/**5963269/how-to-make-a-great-r-**
 reproducible-exampleforhttp://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-examplefor
 

 more detail..



 # create a data table with three unique columns' values..
 # treat these values just like letters
 x -
   cbind(
   sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
   sample( LETTERS[1:6] , 100 , replace = TRUE ) ,
   sample( LETTERS[1:6] , 100 , replace = TRUE )
   )

 # look at x.. this is good data i hope?
 x

 # convert this to a matrix
 y - as.matrix( x )

 # i don't think you care about ordering, so sort left-to-rightwards
 z - apply( y , 2 , sort )

 # look at your results
 z

 # paste these results together across the matrix
 w - apply( z , 1 , paste0 , collapse =  )

 # count the final distinct results
 table( w )




 On Mon, Feb 25, 2013 at 1:04 PM, Niklas Fischer
 niklasfischer...@gmail.comwrote:

   Dear R users,


 I have three questions measuring close relationships.
 The questions are same and the respondents put the answer in order.

 I'd like to examine the pattern of answers and visualize it.

 For example q1 (A,B,C,D,E) and q2 and q3 are the same. If the
 respondents
 selects A B C (so BCA or BAC or CBA or CAB), I'd like to construct
 frequency table for ABC and other combinations for example DEF.


 Unfortunately, there are many answers, and three-way contingency table
 includes lots of cells which make it diffucult to interpret and
 requires
 lots of extra work to organize data.

 What is the best way to construct fruequency table of these kind of
 variables and to visulize the results with the most simple form


 All the bests,
 Niklas

   [[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-helphttps://stat.ethz.ch/mailman/**listinfo/r-help
 https://stat.**ethz.ch/mailman/listinfo/r-**helphttps://stat.ethz.ch/mailman/listinfo/r-help
 

 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.htmlhttp://www.R-project.org/**posting-guide.html
 http://www.**R-project.org/posting-guide.**htmlhttp://www.R-project.org/posting-guide.html
 

 and provide commented, minimal, self-contained, reproducible code.


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 PLEASE do read the posting guide http://www.R-project.org/**
 posting-guide.html 
 http://www.R-project.org/**posting-guide.htmlhttp://www.R-project.org/posting-guide.html
 

 and provide commented, minimal, self-contained, reproducible code.





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[R] colineraity among categorical variables (multinom)

2012-11-10 Thread Niklas Fischer
Dear all users,

Id like to ask you how to make decision about colinearity among
categorical independent variables
when the model is multinomial logistic regression.

Any help is appreciated,
Niklas

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] colineraity among categorical variables (multinom)

2012-11-10 Thread Niklas Fischer
Btw, I tried out variance inflation factor(vif)
but it works for glm models(lm) but not multinom or nnet class
Bests,

2012/11/10 Niklas Fischer niklasfischer...@gmail.com

 Dear all users,

 Id like to ask you how to make decision about colinearity among
 categorical independent variables
 when the model is multinomial logistic regression.

 Any help is appreciated,
 Niklas



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[R] error about xtable and addmargins

2012-09-25 Thread Niklas Fischer
Dear all,

Tried to add column margins of a sample data. The data was extracted from
xtable library,

it gives erroro the below,

appreciated if you have any idea.

Bests,


head(iris)
irisk-head(iris)
table-xtable(irisk,digits=2)
table2 - xtable(addmargins(as.matrix(irisk),
2), digits = 0)
Error in FUN(newX[, i], ...) : invalid 'type' (character) of argument

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Re: [R] create new variable with ifelse? (reproducible example)

2012-09-16 Thread Niklas Fischer
Thank you very much for very valuable comments.

They are very informative.

Bests,
Niklas

2012/9/16 Ted Harding ted.hard...@wlandres.net

 [See at end]
 On 15-Sep-2012 20:36:49 Niklas Fischer wrote:
  Dear R users,
 
  I have a reproducible data and try to create new variable clo is 1  if
  know variable is equal to very well or fairly well and getalong is 4
 or
  5
  otherwise it is 0.

 [A]
 rep_data- read.table(header=TRUE, text=
id1id2know getalong
10016_a1 10016_a2   very well4
10035_a1 10035_a2 fairly well   NA
10036_a1 10036_a2   very well3
10039_a1 10039_a2   very well5
10067_a1 10067_a2   very well5
10076_a1 10076_a2 fairly well5
 )

 rep_data$clo- ifelse((rep_data$know==c(fairly well,very well) 
 rep_data$getalong==c(4,5)),1,0)

  For sure, something must be wrong, I couldn't find it out.

 rep_data
   id1id2 know getalong clo
 10016_a1 10016_a2   very well4   0
 10035_a1 10035_a2 fairly well   NA   0
 10036_a1 10036_a2   very well3   0
 10039_a1 10039_a2   very well5   0
 10067_a1 10067_a2   very well5   0
 10076_a1 10076_a2 fairly well5   0

  Any help is appreciated..
  Bests,
  Niklas

 There are several things wrong with the way you are trying to do it,
 and indeed it is a bit complicated!

 First: if the above table (at [A] above) is the format in which
 you input the data, then you should either comma-separate your
 data fields (and use sep=, in read.table(), or else just use
 read.csv()), or else enclose the two-word fields within ...,
 i.e. EITHER:
 [B]
id1,   id2,   know,   getalong
10016_a1, 10016_a2,   very well,4
10035_a1, 10035_a2, fairly well,   NA
10036_a1, 10036_a2,   very well,3
10039_a1, 10039_a2,   very well,5
10067_a1, 10067_a2,   very well,5
10076_a1, 10076_a2, fairly well,5

 OR:
 [C]
id1id2know getalong
10016_a1 10016_a2   very well4
10035_a1 10035_a2 fairly well   NA
10036_a1 10036_a2   very well3
10039_a1 10039_a2   very well5
10067_a1 10067_a2   very well5
10076_a1 10076_a2 fairly well5

 Otherwise, in your original format, read.table() will read in
 FIVE fields, since it will treat very and well as separate,
 and will treat fairly and well as separate. Furthermore,
 it will match the header getalong with the 5th field (4,NA,etc),
 the header know with the 4th field (well,well,...,well),
 header id2 with the 3rd field (very,fairly,very,...,fairly),
 and header id1 with the 2nd field (10016_a2).

 And even further more, the first field will become the row-names
 of the dataframe and will no longer be data!

 Second: Use of == to compare $know with very well and
 fairly well will not work as you expect. In your comparison

   rep_data$know==c(fairly well,very well)

 you will get the result:

   # [1] FALSE FALSE FALSE  TRUE FALSE FALSE

 rather then your expected

   # [1] TRUE TRUE TRUE TRUE TRUE TRUE.

 This is because == will compare $know with ONE ELEMENT of
 c(fairly well,very well), and will recycle these elements,
 so it will compare $know successively with

 fairly well,very well fairly well,very well fairly well,very
 well

 and since $know is

 very well,fairly well,very well,very well,very well,fairly well

 the only match is in the 4th instance, which is why you get

   # [1] FALSE FALSE FALSE  TRUE FALSE FALSE

 A better comparison is to use the %in operator, as in:

   rep_data$know %in% c(fairly well,very well)
   # [1] TRUE TRUE TRUE TRUE TRUE TRUE

 so you can in the end do:

   rep_data$clo-
 ifelse((rep_data$know %in% c(fairly well,very well)) 
(rep_data$getalong %in% c(4,5)),1,0)

 which results in:

   rep_data
   #id1  id2know getalong clo
   # 1 10016_a1 10016_a2   very well4   1
   # 2 10035_a1 10035_a2 fairly well   NA   0
   # 3 10036_a1 10036_a2   very well3   0
   # 4 10039_a1 10039_a2   very well5   1
   # 5 10067_a1 10067_a2   very well5   1
   # 6 10076_a1 10076_a2 fairly well5   1

 Finally, I suppose it is a happy coincidence that

   NA %in% c(4,5)

 yields FALSE rather than what R might have been written to yield,
 i.e. NA -- since NA is basically a synonym for something that we
 do not know the value of, strictly speaking we do not know the
 value of NA %in% c(4,5). It is possible that the something that
 we do not know the value of could be either 4 or 5, in which case
 NA %in% c(4,5) would be TRUE; but it is also possible that the
 something that we do not know

Re: [R] create new variable with ifelse? (reproducible example)

2012-09-16 Thread Niklas Fischer
Thanks Rui and Stephen,

They look very interesting. I am glad there are many ways to do so.

All the bests,

2012/9/16 Rui Barradas ruipbarra...@sapo.pt

 Hello,

 Here's another one.

 logic.result - with(rep_data, know %in% c(very well, fairly well) 
 getalong %in% c(4,5))
 rep_data$clo - 1*logic.result # coerce to numeric

 Rui Barradas

 Em 16-09-2012 13:29, Stephen Politzer-Ahles escreveu:

  Hi Niklas,

 I like A.K.'s method. Here's another way to do what I think is the same
 thing you're asking for (this is how I did it before I knew ifelse()
 existed!)

 rep_data$clo - 0
 rep_data[ rep_data$know %in% c(very well, fairly well) 
 rep_data$getalong %in% c(4,5),]$clo - 1

 Best,
 Steve

 --

 Message: 25
 Date: Sat, 15 Sep 2012 23:36:49 +0300
 From: Niklas Fischer niklasfischer...@gmail.com
 To: r-help@r-project.org
 Subject: [R] create new variable with ifelse? (reproducible example)
 Message-ID:
  CADWGO2zANM_UK8qf=**JLZHRSqgtPC=NX+rU2kXx=1etw0uQv**
 x...@mail.gmail.com 1etw0uqv...@mail.gmail.com
 Content-Type: text/plain

 Dear R users,

 I have a reproducible data and try to create new variable clo is 1  if
 know variable is equal to very well or fairly well and getalong is 4
 or
 5
 otherwise it is 0.

 rep_data- read.table(header=TRUE, text=
 id1id2know getalong
 10016_a1 10016_a2   very well4
 10035_a1 10035_a2 fairly well   NA
 10036_a1 10036_a2   very well3
 10039_a1 10039_a2   very well5
 10067_a1 10067_a2   very well5
 10076_a1 10076_a2 fairly well5
 )


 rep_data$clo- ifelse((rep_data$know==c(**fairly well,very well) 
 rep_data$getalong==c(4,5)),1,**0)

 For sure, something must be wrong, I couldn't find it out.

 rep_data

id1id2 know getalong clo
 10016_a1 10016_a2   very well4   0
 10035_a1 10035_a2 fairly well   NA   0
 10036_a1 10036_a2   very well3   0
 10039_a1 10039_a2   very well5   0
 10067_a1 10067_a2   very well5   0
 10076_a1 10076_a2 fairly well5   0

 Any help is appreciated..
 Bests,
 Niklas

 [[alternative HTML version deleted]]

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[R] create new variable with ifelse? (reproducible example)

2012-09-15 Thread Niklas Fischer
Dear R users,

I have a reproducible data and try to create new variable clo is 1  if
know variable is equal to very well or fairly well and getalong is 4 or
5
otherwise it is 0.

rep_data- read.table(header=TRUE, text=
   id1id2know getalong
   10016_a1 10016_a2   very well4
   10035_a1 10035_a2 fairly well   NA
   10036_a1 10036_a2   very well3
   10039_a1 10039_a2   very well5
   10067_a1 10067_a2   very well5
   10076_a1 10076_a2 fairly well5
)


rep_data$clo- ifelse((rep_data$know==c(fairly well,very well) 
rep_data$getalong==c(4,5)),1,0)

For sure, something must be wrong, I couldn't find it out.

rep_data

  id1id2 know getalong clo
10016_a1 10016_a2   very well4   0
10035_a1 10035_a2 fairly well   NA   0
10036_a1 10036_a2   very well3   0
10039_a1 10039_a2   very well5   0
10067_a1 10067_a2   very well5   0
10076_a1 10076_a2 fairly well5   0

Any help is appreciated..
Bests,
Niklas

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[R] practical way to change column names?

2012-08-27 Thread Niklas Fischer
Dear R helpers,
I have a social network data including repated measures of ten alters (whom
you contact) and their attributes(gender, age, strength of tie).

I wrote variables related with alters just for wrote alter 1 and alter 2.

I'd like to change the like below. I'd change each name separetely.

Do you know any pratical way to change it?
All the bests,
Niklas

variables for alter 1
g61a (id)
g62a (gender)
g63a (age)
g63aa (tie)
g63aan (tie friequency)

variables for alter 2
g61b
g62b
g63b
g64b
g64bb
g64bbn

new names

alterid_1
alterag_1
alteraa_1
alatert_1
altersf_1

alterid_2
alterag_2
alteraa_2
alatert_2
altersf_2

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[R] extracting and combining statistics like BIC, Rsquare

2012-07-23 Thread Niklas Fischer
Dear all,

I'd like to ask you if there is a way to combine Rsquare, BIC, AIC values
after making imputations in R.

There are five data sets I imputed with mice and and than when I create new
variable and apply ologit model,
I could extract Beta coefficients and its standard errors, but don't know
how to extract these statistics above because they cannot with variance or
covariance function.

Do you know alternative ways?
Bests
Niklas

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[R] converting list/data.frame to mids/mi object (multiple imputation)

2012-07-16 Thread Niklas Fischer
Dear R Users,

After imputation, I've created latent variable, but couldn't convert it
back to mids object.
Do you have any suggestion how to convert data.frame/list to mids(for mice)
or mi(for mi pakcage)

Any help is appreciated.


Niklas

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[R] how to pool imputed data sets with latent class analysis and binary logistic regression

2012-07-15 Thread Niklas Fischer
Dear All,

I've used mice package for my latent class analysis and binary logistic
regression

I've imputed five data sets and with long format I've added new variable
that shows latent class membership.

And then in addition to other variables, I'll use binary logistic
regression and try to pool the estimates.
However I couldn't create data.frame to mids objects, and therefore it
produced the error below:

Error in pool(fit) : The object must have class 'mira'

Do you have any suggestions? I'd appreciated if you have time and respond
my e-mail.

Bests,
Niklas

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