Re: [R] extract AICc from model in glmulti object
Hi, Is there an easy way to extract the AICc from a model within a glmulti object? I see the AIC, but not AICc. For example: data(mtcars) cardata = mtcars library(glmulti) # create models global = glm(mpg ~ ., data=mtcars) models = glmulti(global, level=1, crit=aicc, confsetsize=50, plotty=F) # the AICc are here tableofdata = weightable(models) # but can I get it for a specific model here? # Because I also want to get other data in a loop from these objects, such as coefficients.. summary(models@objects[[1]]) Should this post be in a SIG list? I couldn't figure out which one.. Thanks! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] correlation with missing values.. different answers
Hi, I can't seem to figure out why this gives me different answers. Probably something obvious, but I thought they would be the same. This is an minimal example from the help page of cor() : ## swM := swiss with 3 missings : swM - swiss colnames(swM) - abbreviate(colnames(swiss), min=6) swM[1,2] - swM[7,3] - swM[25,5] - NA # create 3 missing cor(swM, use = na.or.complete) Frtlty Agrclt Exmntn Eductn Cathlc Infn.M Frtlty 1.000 0.37821953 -0.6548306 -0.67421581 0.4772298 0.38781500 Agrclt 0.3782195 1. -0.7127078 -0.64337782 0.4014837 -0.07168223 Exmntn -0.6548306 -0.71270778 1.000 0.69776906 -0.6079436 -0.10710047 Eductn -0.6742158 -0.64337782 0.6977691 1. -0.1701445 -0.08343279 Cathlc 0.4772298 0.40148365 -0.6079436 -0.17014449 1.000 0.17221594 Infn.M 0.3878150 -0.07168223 -0.1071005 -0.08343279 0.1722159 1. # why isn't this the same? cor(swM[,c(1:2)], use = na.or.complete) FrtltyAgrclt Frtlty 1.000 0.3920289 Agrclt 0.3920289 1.000 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] correlation with missing values.. different answers
Thanks, I did not realize it was deleting rows! I was afraid to try pairwise.complete.obs because it said something about resulting in a matrix which is not positive semi-definite (and googling that term just confused me more). But I ran the dataset through JMP and got the same answers so I think that pairwise.complete.obs works for what I want to do. On Sun, Apr 13, 2014 at 7:36 PM, arun smartpink...@yahoo.com wrote: Hi, I think in this case, when you use na.or.complete, all the NA rows are removed for the full dataset. cor(swM[-1,1:2]) # FrtltyAgrclt #Frtlty 1.000 0.3920289 #Agrclt 0.3920289 1.000 cor(swM[-1,])[1:2,1:2] #FrtltyAgrclt #Frtlty 1.000 0.3920289 #Agrclt 0.3920289 1.000 May be you can try with pairwise.complete.obs cor(swM, use = pairwise.complete.obs) # Frtlty Agrclt Exmntn Eductn Cathlc Infn.M #Frtlty 1.000 0.39202893 -0.6531492 -0.66378886 0.4723129 0.41655603 #Agrclt 0.3920289 1. -0.7150561 -0.65221506 0.4152007 -0.03648427 #Exmntn -0.6531492 -0.71505612 1.000 0.69921153 -0.6003402 -0.11433546 #Eductn -0.6637889 -0.65221506 0.6992115 1. -0.1791334 -0.09932185 #Cathlc 0.4723129 0.41520069 -0.6003402 -0.17913339 1.000 0.18503786 #Infn.M 0.4165560 -0.03648427 -0.1143355 -0.09932185 0.1850379 1. cor(swM[,1:2],use=pairwise.complete.obs) # FrtltyAgrclt #Frtlty 1.000 0.3920289 #Agrclt 0.3920289 1.000 A.K. On Sunday, April 13, 2014 9:11 PM, Paul Tanger paul.tan...@colostate.edu wrote: Hi, I can't seem to figure out why this gives me different answers. Probably something obvious, but I thought they would be the same. This is an minimal example from the help page of cor() : ## swM := swiss with 3 missings : swM - swiss colnames(swM) - abbreviate(colnames(swiss), min=6) swM[1,2] - swM[7,3] - swM[25,5] - NA # create 3 missing cor(swM, use = na.or.complete) Frtlty Agrclt Exmntn Eductn Cathlc Infn.M Frtlty 1.000 0.37821953 -0.6548306 -0.67421581 0.4772298 0.38781500 Agrclt 0.3782195 1. -0.7127078 -0.64337782 0.4014837 -0.07168223 Exmntn -0.6548306 -0.71270778 1.000 0.69776906 -0.6079436 -0.10710047 Eductn -0.6742158 -0.64337782 0.6977691 1. -0.1701445 -0.08343279 Cathlc 0.4772298 0.40148365 -0.6079436 -0.17014449 1.000 0.17221594 Infn.M 0.3878150 -0.07168223 -0.1071005 -0.08343279 0.1722159 1. # why isn't this the same? cor(swM[,c(1:2)], use = na.or.complete) FrtltyAgrclt Frtlty 1.000 0.3920289 Agrclt 0.3920289 1.000 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] split dataframe by sample()
Hi, I seemingly have a simple problem, but I've spend hours reading guides posts on this forum and I can't seem to piece together what I need. I have a dataframe where I want to divide it into two subsets: a sample, and the remainder of the dataframe in a new frame. I've tried this: split(df, sample(nrow(df), size=100, replace=FALSE)) another way would be to make a new dataframe of my sample and (something I can do in SQL but not R) then select rows that are NOT in the sample dataframe. Thanks for any help! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
