[R] YourCast Data Format
Dear R-List, I have data that is collected in panels like this (output from the dput() function, the first 20 observations in the data set): structure(list(Country = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Belgium, Denmark, Czech.Republic, Germany, Estonia, Greece, Spain, France, Ireland, Italy, Cyprus, Latvia, Lithuania, Luxembourg, Hungary, Malta, Netherlands, Austria, Poland, Portugal, Slovenia, Slovakia, Bulgaria, Romania, Finland, Sweden, UK), class = factor), Year = c(2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004), Month = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8), Yes = c(21L, 18L, 20L, 19L, 31L, 39L, 28L, 2L, 28L, 21L, 26L, 50L, 14L, 28L, 50L, 83L, 10L, 25L, 22L, 6L), No = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 4L, 0L, 0L, 0L, 0L), Abstention = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 3L, 0L, 0L, 0L, 0L), No.Neg = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), Abstention.Neg = c(0L, 0L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L), Yes.Neg = c(1L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L), Yes.Pos = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), Missing = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), Enlargement = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1)), .Names = c(Country, Year, Month, Yes, No, Abstention, No.Neg, Abstention.Neg, Yes.Neg, Yes.Pos, Missing, Enlargement), row.names = c(NA, 20L), class = data.frame) The data set has in total 27 countries for the years 1999 to 2008, but with unbalanced panels. I want to be able to estimate a model and do forecasting for each country in the data set. I have been looking into the YourCast package from King et al. but since I have all my data in a single file, I am at a loss as to how to create a data object that the yourcast() function will accept. Does anyone know how to do this without going through the tedious procedure of manually splitting the data file up into the different cross sections? Best, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Voting power indices
Dear R-experts, I was wondering if anyone know of a library in R that has functions for calculating the Banzhaf and Shaply-Shubik indeces? Best, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Reshaping data
Hi Dennis,
Thanks for the answer, it works perfectly for two time intervals, but
if I add a third interval like this:
ID begin_t1end_t1 begin_t2end_t2
begin_t3end_t3
Thomas 11/03/0413/05/0604/02/0716/05/08
09/06/0927/01/10
... ... ... ...
...
Jens24/01/0223/05/0307/06/0314/11/05
16/02/0624/08/09
and write out the reshape function like this:
d2 - reshape(d, varying = list(c(begin_t1, begin_t2, begin_t3),
c(end_t1, end_t2, end_t3)), v.names = c('Begin_Time',
'End_Time'), idvar = 'ID', direction = 'long')
then I get the following error:
Error in `[.data.frame`(data, , varying[[j]][i]) :
undefined columns selected
What am i doing wrong?
Best, Thomas
On 20 Jul 2010, at 04:44, Dennis Murphy wrote:
Hi:
Here's one solution using function reshape() in the stats package
(adapted from an R-help solution by Thomas Lumley on Nov. 26, 2002):
d - read.table(textConnection(
+ ID begin_t1end_t1
begin_t2end_t2
+ Thomas 11/03/0413/05/0604/02/07
16/05/08
+ Jens24/01/0223/05/0307/06/03
14/11/05),
+ header = TRUE)
d
ID begin_t1 end_t1 begin_t2 end_t2
1 Thomas 11/03/04 13/05/06 04/02/07 16/05/08
2 Jens 24/01/02 23/05/03 07/06/03 14/11/05
d2 - reshape(d, varying = list(c('begin_t1', 'begin_t2'),
c('end_t1', 'end_t2')),
v.names = c('Begin_Time', 'End_Time'), idvar = 'ID',
direction = 'long')
# Result could use some cleanup:
rownames(d2) - NULL# clear the created row names
d2 - d2[order(d2$ID), -2] # sort by name, removing the
time order (variable 2)
d2
ID Begin_Time End_Time
2 Jens 24/01/02 23/05/03
4 Jens 07/06/03 14/11/05
1 Thomas 11/03/04 13/05/06
3 Thomas 04/02/07 16/05/08
HTH,
Dennis
On Mon, Jul 19, 2010 at 3:48 PM, Thomas Jensen
thomas.jen...@eup.gess.ethz.ch
wrote:
Dear All,
I have some data in the following shape:
ID begin_t1end_t1
begin_t2end_t2
Thomas 11/03/0413/05/0604/02/07
16/05/08
... ... ... ...
...
Jens24/01/0223/05/0307/06/03
14/11/05
I would like to reshape this data to have the following form:
ID Begin_Time End_Time
Thomas 11/03/0413/05/06
Thomas 04/02/0716/05/08
... ... ...
Jens24/01/0223/05/03
Jens07/06/0314/11/05
I have been doing some google searches and looked at the reshape
library, but so far I have not been able to shape the data like I
want. If you guys could help, I would greatly appreciate it!
Best, Thomas
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[[alternative HTML version deleted]]
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[R] Reshaping data
Dear All, I have some data in the following shape: ID begin_t1end_t1 begin_t2end_t2 Thomas 11/03/0413/05/0604/02/0716/05/08 ... ... ... ... ... Jens24/01/0223/05/0307/06/0314/11/05 I would like to reshape this data to have the following form: ID Begin_Time End_Time Thomas 11/03/0413/05/06 Thomas 04/02/0716/05/08 ... ... ... Jens24/01/0223/05/03 Jens07/06/0314/11/05 I have been doing some google searches and looked at the reshape library, but so far I have not been able to shape the data like I want. If you guys could help, I would greatly appreciate it! Best, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Help with dates and characters
Dear R Experts, I have a vector of dates in character format like this: date 2000-01-01 2000-01-23 2001-03-12 ... ... ... 2009-12-31 I would like to delete the last part of the character string (i.e. the day part), so the vector looks like this: date 2000-01 2000-01 2001-03 ... ... ... 2009-03 I have been looking into regular expressions, but i find this very confusing. Thank you for your help, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Creating quarterly data
Dear R Experts, I have data in the following format x1 x2 time 2 4 1 3 1 2 4 6 3 1 4 4 5 6 5 8 5 6 . . . . . . . . . 1 5 399 3 4 400 Time represents each month which simply has a number from 1 to 400 (i.e. the data covers 400 months). I would like to somehow create two new variables which counts x1 and x2 as quarterly data in stead of monthly. Like this: x1 x1 Quarter 10 12 1 12 15 2 . . . . . . . . . 23 21 100 Can any one tell me how this can be done in R? With kind regards, Thomas Jensen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating quarterly data
Thanks, Allan, that did the trick :) Best, Thomas On Jun 28, 2010, at 6:13 PM, Allan Engelhardt wrote: One approach: d - data.frame(x1=c(2,3,4,1,5,8), x2=c(4,1,6,4,6,5), time=1:6) d$quarter - (d$time-1) %/% 4 # Or whatever your logic is aggregate(cbind(x1,x2) ~ quarter, data = d, sum) # quarter x1 x2 # 1 0 10 15 # 2 1 13 11 Hope this helps Allan On 28/06/10 13:23, Thomas Jensen wrote: Dear R Experts, I have data in the following format x1x2time 241 312 463 144 565 856 ... ... ... 15399 34400 Time represents each month which simply has a number from 1 to 400 (i.e. the data covers 400 months). I would like to somehow create two new variables which counts x1 and x2 as quarterly data in stead of monthly. Like this: x1x1Quarter 10121 12152 ... ... ... 2321100 Can any one tell me how this can be done in R? With kind regards, Thomas Jensen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Event History Data Recoding
Dear R list, I have an event history data set that is structured like this: Legislative act Discussion Agreement Time Event Act12006-05-30 2006-06-19 201 Act22004-03-01 2004-06-14 105 1 . . . I have information on the meetings in the legislature between adoption periods in a separate variable (the start and stop dates are included): Act1 meeting:2006-05-30, 2006-06-19. Act2 meeting: 2004-03-22, 2004-04-26, 2004-06-14. I want to code this as a discrete event data set, so it should look like this: Legislative act Event Meeting Time Count Act1 0 2006-05-30 1 Act1 1 2006-06-07 2 Act2 0 2004-03-22 1 Act2 0 2004-04-26 2 Act2 1 2004-06-14 3 Can anyone tell me if it is possible to do this recoding in R, or do I have to do it by hand? Best, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Event History Data Recoding
Thanks Josh, But I am not sure if the reshape function can create new rows based on the meeting variable. For the second act there are three meetings, i.e. one meeting between discussion and agreement, and this should be entered as a separate row. Best, Thomas On Fri, 2010-04-23 at 07:45 -0700, Joshua Wiley wrote: If you are talking about changing from a wide format to long take a look at ?reshape --- Josh On Fri, Apr 23, 2010 at 7:09 AM, Thomas Jensen thomas.jen...@eup.gess.ethz.ch wrote: Dear R list, I have an event history data set that is structured like this: Legislative act Discussion Agreement Time Event Act12006-05-30 2006-06-19 201 Act22004-03-01 2004-06-14 105 1 . . . I have information on the meetings in the legislature between adoption periods in a separate variable (the start and stop dates are included): Act1 meeting:2006-05-30, 2006-06-19. Act2 meeting: 2004-03-22, 2004-04-26, 2004-06-14. I want to code this as a discrete event data set, so it should look like this: Legislative act Event Meeting Time Count Act1 0 2006-05-30 1 Act1 1 2006-06-07 2 Act2 0 2004-03-22 1 Act2 0 2004-04-26 2 Act2 1 2004-06-14 3 Can anyone tell me if it is possible to do this recoding in R, or do I have to do it by hand? Best, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Create a new variable
Dear R-list,
Sorry for spamming the list lately, I am just learning the more advanced
aspects of R!
I have some data that looks like this:
Out Country1 Country 2 Country 3 ... CountryN
1 1 1 1 1
0 1 1 0 1
1 1 0 1 0
I want to create a new variable that counts the number of zeros in every
row whenever Out is equal to 1, and else it is a zero, so it would look
like this:
new_var
0
0
2
I have tried the following:
for (i in length(Out)){
if (Out == 1) {new_var - sum(dat[i,] != 1)}
else {new_var - 0}
}
but this gives me an error message.
Best, Thomas
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[R] Finding common an unique elements in character vectors
Dear R-list, I have a problem which I think is quite basic, but so far google has not helped me. I have two vectors like this: vector_1 - c(Belgium, Spain, Greece, Ireland, Luxembourg, Netherlands, Portugal) vector_2 - c(Denmark, Luxembourg) I would like to find the elements in vector_1 that are not in vector_2 so that i get a vector with these countries: Belgium, Spain, Greece, Ireland, Netherlands, Portugal. Thanks a lot, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Transform data set
Dear R Experts, I am having some trouble creating a variable in R. I have data on self-placement of voters, their placement of parties, and which party they feel closest to. The data is structured like this: Party_Closelrplaceself lrplaceParty1 lrplaceParty2 ... party1 2 4 5 party2 5 6 4 party1 6 2 1 etc... I want to format the data set so it looks like this: Party_Close lrplacepartyclose lrplaceself party14 2 party24 5 party12 6 Any help is greatly appreciated! With kind regards, Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Count of entries in a row of a data frame
Dear R-list, I have data in the following format: Country 1 Country 2Country 3 ... 1 0 10 2 1 02 3 0 10 Now I would like to create a variable that counts every non-zero element of the rows, so for the above example it would be: Count 1 1 2 2 3 1 Any help from is greatly appreciated! With kind regards Thomas __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Breadt-first-search algorithm
Dear R-list, does anyone of you know whether there exist a breadth-first-search algorithm for R? Best, Thomas Jensen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] selecting columns based on values of two variables
Dear R-list, I am having troubles selecting rows from a very large data-set containing distances between capitals. The structure of the data-set looks like this: numaida numbidb kmdist midist 12 USA 20 CAN 731 456 22 USA 31 BHM 16231012 32 USA 40 CUB 18131130 I want to select a subset of these dyads, and have tried the following code: subset(capdist,ida == c(DEN,SWD,FIN) idb == c(DEN,SWD,FIN)) This should ideally give me the dyads involving only Denmark, Sweden and Finland, however i get the error message: [1] numa idanumb idbkmdist midist 0 rows (or 0-length row.names) Warning messages: 1: In is.na(e1) | is.na(e2) : longer object length is not a multiple of shorter object length 2: In `==.default`(ida, c(DEN, SWD, FIN)) : longer object length is not a multiple of shorter object length 3: In is.na(e1) | is.na(e2) : longer object length is not a multiple of shorter object length 4: In `==.default`(idb, c(DEN, SWD, FIN)) : longer object length is not a multiple of shorter object length Any help would be greatly appreciated, Best, Thomas Jensen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Creating adjacency matrix from a data frame
Dear R-list, Sorry for spamming the list, but I am just learning how to manipulate data in R, so if this is a trivial question I am sorry. I have the following data which list the distance between capitals: ida idb kmdist 7108UK BEL 313 7110UK FRN 365 7116UK POR 1618 I would like to convert this into an a valued adjacency matrix that looks like this: BEL FRN POR UK 313 365 1618 The full data set has all possible pairings between countries, so the end goal should be a symmetric adjacency matrix. Thank you, Thomas Jensen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
