Re: [R] a very simple question
On Mar 18, 2012, at 4:43 PM, Dajiang Liu wrote: Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. It has already been explained on this list ... frequently in FAQt. Locate the FAQ and search for a question about why R doesn't think two numbers are equal. The FAQ should be part of a standard instalL on the main help page. Regards,Dajiang [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
As to the reasons, David as given you the necessary hints. In order to get around the issue, here is what I do: a - round( 0.1 * ( 1:9 ), 1 ) a [1] 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 which( a == 0.3 ) [1] 3 Rgds, Rainer Original-Nachricht Datum: Sun, 18 Mar 2012 21:43:54 + Von: Dajiang Liu ldjst...@hotmail.com An: r-help@r-project.org Betreff: [R] a very simple question Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. Regards,Dajiang [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- --- Gentoo Linux with KDE __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
On Sun, Mar 18, 2012 at 09:43:54PM +, Dajiang Liu wrote: Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. Hi. A simple way to detect rounding problems is subtracting the numbers. a = 0.1*(1:4) a - 0.3 [1] -2.00e-01 -1.00e-01 5.551115e-17 1.00e-01 Use rounding to avoid it as suggested by others. Petr Savicky. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
Thanks a lot for the clarification. I just find it very bizarre that if you run a=0.1*(1:9);which(a==0.4) it returns the right answer. Anyway, I will pay attention next time. Thanks a lot. Date: Mon, 19 Mar 2012 08:59:59 +0100 From: rainer.schuerm...@gmx.net Subject: Re: [R] a very simple question To: ldjst...@hotmail.com; r-help@r-project.org As to the reasons, David as given you the necessary hints. In order to get around the issue, here is what I do: a - round( 0.1 * ( 1:9 ), 1 ) a [1] 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 which( a == 0.3 ) [1] 3 Rgds, Rainer Original-Nachricht Datum: Sun, 18 Mar 2012 21:43:54 + Von: Dajiang Liu ldjst...@hotmail.com An: r-help@r-project.org Betreff: [R] a very simple question Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. Regards,Dajiang [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- --- Gentoo Linux with KDE [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
On 19-03-2012, at 13:47, Dajiang Liu wrote: Thanks a lot for the clarification. I just find it very bizarre that if you run a=0.1*(1:9);which(a==0.4) it returns the right answer. Anyway, I will pay attention next time. Thanks a lot. Look at a = 0.1*(1:4) a - 0.4 [1] -0.3 -0.2 -0.1 0.0 Berend Date: Mon, 19 Mar 2012 08:59:59 +0100 From: rainer.schuerm...@gmx.net Subject: Re: [R] a very simple question To: ldjst...@hotmail.com; r-help@r-project.org As to the reasons, David as given you the necessary hints. In order to get around the issue, here is what I do: a - round( 0.1 * ( 1:9 ), 1 ) a [1] 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 which( a == 0.3 ) [1] 3 Rgds, Rainer Original-Nachricht Datum: Sun, 18 Mar 2012 21:43:54 + Von: Dajiang Liu ldjst...@hotmail.com An: r-help@r-project.org Betreff: [R] a very simple question Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. Regards,Dajiang [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- --- Gentoo Linux with KDE [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
On 19-Mar-2012 Dajiang Liu wrote: Thanks a lot for the clarification. I just find it very bizarre that if you run a=0.1*(1:9);which(a==0.4) it returns the right answer. Anyway, I will pay attention next time. Thanks a lot. The basic explanation is that, for an integer r (0r10), what is stored in binary representation by R for 0.1*r or for 0.r or for r/10 is always an approximation to the exact value (with the possible exception of r=5). The exact detail of the binary representation may depend on how it was obtained, by any of several different methods of calculation which, mathematically, are exactly equivalent but, in the binary representations stored in the computer, may be slightly different. Examples: 0.1*(1:9) - (1:9)/10 # [1] 0.00e+00 0.00e+00 5.551115e-17 0.00e+00 # [5] 0.00e+00 1.110223e-16 1.110223e-16 0.00e+00 # [8] 0.00e+00 0.1*(1:9) - c(0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9) # [1] 0.00e+00 0.00e+00 5.551115e-17 0.00e+00 # [5] 0.00e+00 1.110223e-16 1.110223e-16 0.00e+00 # [8] 0.00e+00 # (1:9)/10 - c(0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9) # [1] 0 0 0 0 0 0 0 0 0 cumsum(rep(0.3,9))/3 - (1:9)/10 # [1] -1.387779e-17 -2.775558e-17 0.00e+00 -5.551115e-17 # [5] 0.00e+00 0.00e+00 1.110223e-16 -1.110223e-16 # [9] -1.110223e-16 and so on ... The third example suggests that when R is given a decimal fraction 0.r it recognises that this is equivalent to r/10 and calculates it accordingly, hence the agreement between (1:9)/10 and c(0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9). (I would need to check the source code to verify that statement, however). The short answer (as has been pointed out) is that you cannot count on exact agreement, within R (or most other numerical software), between a value calculated by one numerical method and the value calculated by another numerical method which is mathematically equivalent. Some numerical software will work by storing the expression given to it not as a number but as a sequence of operations performed on given digits, only evaluating this at the last moment along with other similar expressions, working within the scale (e.g. decimal scale for numbers given like 123.456) thus obtaining maximum accuracy within the allocated storage. An example it the arbitrary-precision calculator 'bc'. Many (most?) hand-held digital calculators work to an internal decimal representation such as BCD (binary-coded decimal) where each byte is split into two half-bytes of 4 binary digits, each capable of storing a number from 0 to 9; then they can perform exact decimal arithmetic (to within the precision of storage) for decimal numbers, avoiding the imprecision resulting from conversion to binary (but may exhibit similar problems to the above for binary input). Ted. - E-Mail: (Ted Harding) ted.hard...@wlandres.net Date: 19-Mar-2012 Time: 15:02:03 This message was sent by XFMail __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] a very simple question
On Mon, Mar 19, 2012 at 12:47:12PM +, Dajiang Liu wrote: Thanks a lot for the clarification. I just find it very bizarre that if you run a=0.1*(1:9);which(a==0.4) it returns the right answer. Anyway, I will pay attention next time. Thanks a lot. Hi. Yes, these things are bizarre sometimes. Compare print(0.1, digits=20) # [1] 0.1555 print(4*0.1, digits=20) # [1] 0.4000222 print(0.4, digits=20) # [1] 0.4000222 Equality of the last two is the reason for which(0.1*(1:9) == 0.4) [1] 4 while for 0.3, we get print(3*0.1, digits=20) # [1] 0.30004441 print(0.3, digits=20) # [1] 0.2999889 See http://rwiki.sciviews.org/doku.php?id=misc:r_accuracy for further hints. Petr Savicky. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] a very simple question
Dear All, I have a seemingly very simple question, but I just cannot figure out the answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But obviously, the third element of a is equal to 0.3. I must have missed something. Can someone kindly explain why? Thanks a lot. Regards,Dajiang [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A very simple question
Or
k - c(1,1,1,2,2,1,1)
k[!(k==3)]
[1] 1 1 1 2 2 1 1
On Wed, May 14, 2008 at 1:59 PM, Julian Burgos
[EMAIL PROTECTED] wrote:
Try this:
k=c(1,1,1,2,2,1,1,1)
k[(k!=1)]
[1] 2 2
k[(k!=2)]
[1] 1 1 1 1 1 1
k[(k!=3)]
[1] 1 1 1 2 2 1 1 1
Julian
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
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Re: [R] A very simple question
There have been several solutions like:
k[k != 3]
The more general form of this idea is:
k[!(k %in% 3)]
Sticking closer to the original form would be:
out - which(k == 3)
if(length(out)) k[-out] else k
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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[R] A very simple question
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] A very simple question
k - c(1,1,1,2,2,1,1,1)
k[k != 1]
[1] 2 2
k[k != 2]
[1] 1 1 1 1 1 1
k[k != 3]
[1] 1 1 1 2 2 1 1 1
-Christos
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Shubha
Vishwanath Karanth
Sent: Wednesday, May 14, 2008 11:16 AM
To: [EMAIL PROTECTED]
Subject: [R] A very simple question
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself
should be my result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged
i...{{dropped:13}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] A very simple question
On 5/14/2008 11:16 AM, Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
Look at the result of which(k==3) to see why your approach does not
work. You might try this instead:
k - c(1,1,1,2,2,1,1,1)
k[!(k==1)]
[1] 2 2
k[!(k==2)]
[1] 1 1 1 1 1 1
k[!(k==3)]
[1] 1 1 1 2 2 1 1 1
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and provide commented, minimal, self-contained, reproducible code.
--
Chuck Cleland, Ph.D.
NDRI, Inc. (www.ndri.org)
71 West 23rd Street, 8th floor
New York, NY 10010
tel: (212) 845-4495 (Tu, Th)
tel: (732) 512-0171 (M, W, F)
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Re: [R] A very simple question
l[!l==3]
On 14 May 2008, at 17:16, Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged i...
{{dropped:13}}
__
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PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.
Ingmar Visser
Department of Psychology, University of Amsterdam
Roetersstraat 15
1018 WB Amsterdam
The Netherlands
t: +31-20-5256723
[[alternative HTML version deleted]]
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Re: [R] A very simple question
Use logical subscripts rather than which:
k - c(1,1,1,2,2,1,1,1)
k[ k != 1 ]
[1] 2 2
k[ k != 2 ]
[1] 1 1 1 1 1 1
k[ k != 3 ]
[1] 1 1 1 2 2 1 1 1
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Shubha
Vishwanath Karanth
Sent: Wednesday, May 14, 2008 9:16 AM
To: [EMAIL PROTECTED]
Subject: [R] A very simple question
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself
should be my result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged
i...{{dropped:13}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] A very simple question
Try this:
k=c(1,1,1,2,2,1,1,1)
k[(k!=1)]
[1] 2 2
k[(k!=2)]
[1] 1 1 1 1 1 1
k[(k!=3)]
[1] 1 1 1 2 2 1 1 1
Julian
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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[R] A Very Simple Question
Hi Rusers! I am ashed of asking such a simple question. X-matrix(rnorm(24), 4) X0-apply(X,2,mean) What I want is a matrix which consists of colums such as X[,1]--X0[1]. X-X0 doesn't work. Perhaps apply function? Thanks in advance. Yukihiro Ishii 2-3-28 Tsurumakiminami, Hadano, 250-0002 Japan +81463691922 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A Very Simple Question
On 5/13/2008 10:27 AM, Yukihiro Ishii wrote: Hi Rusers! I am ashed of asking such a simple question. X-matrix(rnorm(24), 4) X0-apply(X,2,mean) What I want is a matrix which consists of colums such as X[,1]--X0[1]. X-X0 doesn't work. Perhaps apply function? scale(X, scale=FALSE) ?scale Thanks in advance. Yukihiro Ishii 2-3-28 Tsurumakiminami, Hadano, 250-0002 Japan +81463691922 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Chuck Cleland, Ph.D. NDRI, Inc. (www.ndri.org) 71 West 23rd Street, 8th floor New York, NY 10010 tel: (212) 845-4495 (Tu, Th) tel: (732) 512-0171 (M, W, F) fax: (917) 438-0894 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A Very Simple Question
?sweep -Original Message- From: Yukihiro Ishii [EMAIL PROTECTED] To: r-help@r-project.org r-help@r-project.org Sent: 5/13/08 8:30 AM Subject: [R] A Very Simple Question Hi Rusers! I am ashed of asking such a simple question. X-matrix(rnorm(24), 4) X0-apply(X,2,mean) What I want is a matrix which consists of colums such as X[,1]--X0[1]. X-X0 doesn't work. Perhaps apply function? Thanks in advance. Yukihiro Ishii 2-3-28 Tsurumakiminami, Hadano, 250-0002 Japan +81463691922 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A Very Simple Question
See ?scale HTH, Giovanni Date: Tue, 13 May 2008 23:27:59 +0900 From: Yukihiro Ishii [EMAIL PROTECTED] Sender: [EMAIL PROTECTED] Precedence: list DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=ybb20050223; d=ybb.ne.jp; Hi Rusers! I am ashed of asking such a simple question. X-matrix(rnorm(24), 4) X0-apply(X,2,mean) What I want is a matrix which consists of colums such as X[,1]--X0[1]. X-X0 doesn't work. Perhaps apply function? Thanks in advance. Yukihiro Ishii 2-3-28 Tsurumakiminami, Hadano, 250-0002 Japan +81463691922 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Giovanni Petris [EMAIL PROTECTED] Associate Professor Department of Mathematical Sciences University of Arkansas - Fayetteville, AR 72701 Ph: (479) 575-6324, 575-8630 (fax) http://definetti.uark.edu/~gpetris/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] A very simple question
Hi all, My apologies for a very simple question. I just downloaded R 2.6.0. I want to bring in all of the objects from 2.5.0 that I see when I type ls(). I have no idea how to do that. Thanks in advance. David -- === David Kaplan, Ph.D. Professor Department of Educational Psychology University of Wisconsin - Madison Educational Sciences, Room 1061 1025 W. Johnson Street Madison, WI 53706 email: [EMAIL PROTECTED] Web: http://www.education.wisc.edu/edpsych/facstaff/kaplan/kaplan.htm Phone: 608-262-0836 Fax: 608-262-0843 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] A very simple question
?save.image ?load HTH. tc On 10/23/07, David Kaplan [EMAIL PROTECTED] wrote: Hi all, My apologies for a very simple question. I just downloaded R 2.6.0. I want to bring in all of the objects from 2.5.0 that I see when I type ls(). I have no idea how to do that. Thanks in advance. David -- === David Kaplan, Ph.D. Professor Department of Educational Psychology University of Wisconsin - Madison Educational Sciences, Room 1061 1025 W. Johnson Street Madison, WI 53706 email: [EMAIL PROTECTED] Web: http://www.education.wisc.edu/edpsych/facstaff/kaplan/kaplan.htm Phone: 608-262-0836 Fax: 608-262-0843 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Tim Calkins 0406 753 997 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
