Re: [R] Data handling
Thanks A.K. and Jim! Thanks very much, both solution works fine! But I can´t figure out what was the problem with my code. Make step-by-step is not recommended? Is just that difference? Thanks again for help! Raoni 2013/10/15 arun smartpink...@yahoo.com Try: op - options(digits.secs=4) TimeCC - as.POSIXct(paste0(paste(teste[,1],teste[,2]), sub(^0,,teste[,3])),format=%m/%d/%y %H:%M:%OS) options(op) #reset A.K. On Tuesday, October 15, 2013 10:29 AM, Raoni Rodrigues caciquesamu...@gmail.com wrote: Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of seconds. I need to have a vector in a format year-month-day hh:mm:ss.. Or, in format: format = %F %H:%M:%OS4, as POSIXct class. I made the the conversion step-by-step to have sure that nothing is missed in the way: options (digits.sec = 4) getOption (digits.sec) [1] 4 teste$Date1 = as.Date (teste$Date, format = %m/%d/%y) class (teste$Date1) [1] Date teste$Fraction = sub (0., , teste$Fraction) teste$TimeC = paste (teste$Time, teste$Fraction, sep = .) teste$TimeCC = paste (teste$Date1, teste$TimeC) head (teste) Date Time Fraction Date1TimeC TimeCC 1 06/19/13 22:15:39 .325 2013-06-19 22:15:39.325 2013-06-19 22:15:39.3205 2 06/19/13 22:15:44 .325 2013-06-19 22:15:44.325 2013-06-19 22:15:44.3205 3 06/19/13 22:15:49 .325 2013-06-19 22:15:49.325 2013-06-19 22:15:49.3205 4 06/19/13 22:15:54 .325 2013-06-19 22:15:54.325 2013-06-19 22:15:54.3205 5 06/19/13 22:15:59 .325 2013-06-19 22:15:59.325 2013-06-19 22:15:59.3205 6 06/19/13 22:16:09 .325 2013-06-19 22:16:09.325 2013-06-19 22:16:09.3205 So far so well. The problem is when I tried to convert to POSIXct class. If I use just: teste$TimeCC = format (teste$TimeCC, format = %F %H:%M:%OS4) teste$TimeCC = as.POSIXct (teste$TimeCC) I lost the fraction of seconds. If I use: teste$TimeCC = as.POSIXct(strptime (teste$TimeCC, format = %F %H:%M:%OS4)) I lost all information and get just NA. Thanks in advanced, -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com dput of input data structure(list(Date = c(06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13), Time = c(22:15:39, 22:15:44, 22:15:49, 22:15:54, 22:15:59, 22:16:09), Fraction = c(0.3205, 0.3205, 0.3205, 0.3205, 0.3205, 0.3205)), .Names = c(Date, Time, Fraction), row.names = c(NA, 6L), class = data.frame) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Data handling
Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of seconds. I need to have a vector in a format year-month-day hh:mm:ss.. Or, in format: format = %F %H:%M:%OS4, as POSIXct class. I made the the conversion step-by-step to have sure that nothing is missed in the way: options (digits.sec = 4) getOption (digits.sec) [1] 4 teste$Date1 = as.Date (teste$Date, format = %m/%d/%y) class (teste$Date1) [1] Date teste$Fraction = sub (0., , teste$Fraction) teste$TimeC = paste (teste$Time, teste$Fraction, sep = .) teste$TimeCC = paste (teste$Date1, teste$TimeC) head (teste) Date Time Fraction Date1TimeC TimeCC 1 06/19/13 22:15:39 .325 2013-06-19 22:15:39.325 2013-06-19 22:15:39.3205 2 06/19/13 22:15:44 .325 2013-06-19 22:15:44.325 2013-06-19 22:15:44.3205 3 06/19/13 22:15:49 .325 2013-06-19 22:15:49.325 2013-06-19 22:15:49.3205 4 06/19/13 22:15:54 .325 2013-06-19 22:15:54.325 2013-06-19 22:15:54.3205 5 06/19/13 22:15:59 .325 2013-06-19 22:15:59.325 2013-06-19 22:15:59.3205 6 06/19/13 22:16:09 .325 2013-06-19 22:16:09.325 2013-06-19 22:16:09.3205 So far so well. The problem is when I tried to convert to POSIXct class. If I use just: teste$TimeCC = format (teste$TimeCC, format = %F %H:%M:%OS4) teste$TimeCC = as.POSIXct (teste$TimeCC) I lost the fraction of seconds. If I use: teste$TimeCC = as.POSIXct(strptime (teste$TimeCC, format = %F %H:%M:%OS4)) I lost all information and get just NA. Thanks in advanced, -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com dput of input data structure(list(Date = c(06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13), Time = c(22:15:39, 22:15:44, 22:15:49, 22:15:54, 22:15:59, 22:16:09), Fraction = c(0.3205, 0.3205, 0.3205, 0.3205, 0.3205, 0.3205)), .Names = c(Date, Time, Fraction), row.names = c(NA, 6L), class = data.frame) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data handling
Try: op - options(digits.secs=4) TimeCC - as.POSIXct(paste0(paste(teste[,1],teste[,2]), sub(^0,,teste[,3])),format=%m/%d/%y %H:%M:%OS) options(op) #reset A.K. On Tuesday, October 15, 2013 10:29 AM, Raoni Rodrigues caciquesamu...@gmail.com wrote: Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of seconds. I need to have a vector in a format year-month-day hh:mm:ss.. Or, in format: format = %F %H:%M:%OS4, as POSIXct class. I made the the conversion step-by-step to have sure that nothing is missed in the way: options (digits.sec = 4) getOption (digits.sec) [1] 4 teste$Date1 = as.Date (teste$Date, format = %m/%d/%y) class (teste$Date1) [1] Date teste$Fraction = sub (0., , teste$Fraction) teste$TimeC = paste (teste$Time, teste$Fraction, sep = .) teste$TimeCC = paste (teste$Date1, teste$TimeC) head (teste) Date Time Fraction Date1 TimeC TimeCC 1 06/19/13 22:15:39 .325 2013-06-19 22:15:39.325 2013-06-19 22:15:39.3205 2 06/19/13 22:15:44 .325 2013-06-19 22:15:44.325 2013-06-19 22:15:44.3205 3 06/19/13 22:15:49 .325 2013-06-19 22:15:49.325 2013-06-19 22:15:49.3205 4 06/19/13 22:15:54 .325 2013-06-19 22:15:54.325 2013-06-19 22:15:54.3205 5 06/19/13 22:15:59 .325 2013-06-19 22:15:59.325 2013-06-19 22:15:59.3205 6 06/19/13 22:16:09 .325 2013-06-19 22:16:09.325 2013-06-19 22:16:09.3205 So far so well. The problem is when I tried to convert to POSIXct class. If I use just: teste$TimeCC = format (teste$TimeCC, format = %F %H:%M:%OS4) teste$TimeCC = as.POSIXct (teste$TimeCC) I lost the fraction of seconds. If I use: teste$TimeCC = as.POSIXct(strptime (teste$TimeCC, format = %F %H:%M:%OS4)) I lost all information and get just NA. Thanks in advanced, -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com dput of input data structure(list(Date = c(06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13), Time = c(22:15:39, 22:15:44, 22:15:49, 22:15:54, 22:15:59, 22:16:09), Fraction = c(0.3205, 0.3205, 0.3205, 0.3205, 0.3205, 0.3205)), .Names = c(Date, Time, Fraction), row.names = c(NA, 6L), class = data.frame) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data handling
Try this; your time is converted back to a character string if you want to show the fractional part. x - read.table(text = Date Time Fraction + 06/19/13 22:15:39 0.3205 + 06/19/13 22:15:44 0.3205 + 06/19/13 22:15:49 0.3205 + 06/19/13 22:15:54 0.3205 + 06/19/13 22:15:59 0.3205 + 06/19/13 22:16:09 0.3205, as.is = TRUE, header = TRUE) x$newTime - as.POSIXct( + paste0(x$Date, ' ', x$Time , '.', substring(x$Fraction, 3)) + , format = %m/%d/%y %H:%M:%OS + ) x$formatted - format(x$newTime, format = %m/%d/%y %H:%M:%OS4) x Date Time Fraction newTime formatted 1 06/19/13 22:15:39 0.3205 2013-06-19 22:15:39 06/19/13 22:15:39.3204 2 06/19/13 22:15:44 0.3205 2013-06-19 22:15:44 06/19/13 22:15:44.3204 3 06/19/13 22:15:49 0.3205 2013-06-19 22:15:49 06/19/13 22:15:49.3204 4 06/19/13 22:15:54 0.3205 2013-06-19 22:15:54 06/19/13 22:15:54.3204 5 06/19/13 22:15:59 0.3205 2013-06-19 22:15:59 06/19/13 22:15:59.3204 6 06/19/13 22:16:09 0.3205 2013-06-19 22:16:09 06/19/13 22:16:09.3204 Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Oct 15, 2013 at 10:27 AM, Raoni Rodrigues caciquesamu...@gmail.com wrote: Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of seconds. I need to have a vector in a format year-month-day hh:mm:ss.. Or, in format: format = %F %H:%M:%OS4, as POSIXct class. I made the the conversion step-by-step to have sure that nothing is missed in the way: options (digits.sec = 4) getOption (digits.sec) [1] 4 teste$Date1 = as.Date (teste$Date, format = %m/%d/%y) class (teste$Date1) [1] Date teste$Fraction = sub (0., , teste$Fraction) teste$TimeC = paste (teste$Time, teste$Fraction, sep = .) teste$TimeCC = paste (teste$Date1, teste$TimeC) head (teste) Date Time Fraction Date1TimeC TimeCC 1 06/19/13 22:15:39 .325 2013-06-19 22:15:39.325 2013-06-19 22:15:39.3205 2 06/19/13 22:15:44 .325 2013-06-19 22:15:44.325 2013-06-19 22:15:44.3205 3 06/19/13 22:15:49 .325 2013-06-19 22:15:49.325 2013-06-19 22:15:49.3205 4 06/19/13 22:15:54 .325 2013-06-19 22:15:54.325 2013-06-19 22:15:54.3205 5 06/19/13 22:15:59 .325 2013-06-19 22:15:59.325 2013-06-19 22:15:59.3205 6 06/19/13 22:16:09 .325 2013-06-19 22:16:09.325 2013-06-19 22:16:09.3205 So far so well. The problem is when I tried to convert to POSIXct class. If I use just: teste$TimeCC = format (teste$TimeCC, format = %F %H:%M:%OS4) teste$TimeCC = as.POSIXct (teste$TimeCC) I lost the fraction of seconds. If I use: teste$TimeCC = as.POSIXct(strptime (teste$TimeCC, format = %F %H:%M:%OS4)) I lost all information and get just NA. Thanks in advanced, -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com dput of input data structure(list(Date = c(06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13), Time = c(22:15:39, 22:15:44, 22:15:49, 22:15:54, 22:15:59, 22:16:09), Fraction = c(0.3205, 0.3205, 0.3205, 0.3205, 0.3205, 0.3205)), .Names = c(Date, Time, Fraction), row.names = c(NA, 6L), class = data.frame) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data handling
FYI. The fractional part is printed as '3204' instead of '3205' since with POSIXct you only have accuracy to the millisecond for times around now. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Oct 15, 2013 at 12:45 PM, jim holtman jholt...@gmail.com wrote: Try this; your time is converted back to a character string if you want to show the fractional part. x - read.table(text = Date Time Fraction + 06/19/13 22:15:39 0.3205 + 06/19/13 22:15:44 0.3205 + 06/19/13 22:15:49 0.3205 + 06/19/13 22:15:54 0.3205 + 06/19/13 22:15:59 0.3205 + 06/19/13 22:16:09 0.3205, as.is = TRUE, header = TRUE) x$newTime - as.POSIXct( + paste0(x$Date, ' ', x$Time , '.', substring(x$Fraction, 3)) + , format = %m/%d/%y %H:%M:%OS + ) x$formatted - format(x$newTime, format = %m/%d/%y %H:%M:%OS4) x Date Time Fraction newTime formatted 1 06/19/13 22:15:39 0.3205 2013-06-19 22:15:39 06/19/13 22:15:39.3204 2 06/19/13 22:15:44 0.3205 2013-06-19 22:15:44 06/19/13 22:15:44.3204 3 06/19/13 22:15:49 0.3205 2013-06-19 22:15:49 06/19/13 22:15:49.3204 4 06/19/13 22:15:54 0.3205 2013-06-19 22:15:54 06/19/13 22:15:54.3204 5 06/19/13 22:15:59 0.3205 2013-06-19 22:15:59 06/19/13 22:15:59.3204 6 06/19/13 22:16:09 0.3205 2013-06-19 22:16:09 06/19/13 22:16:09.3204 Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Oct 15, 2013 at 10:27 AM, Raoni Rodrigues caciquesamu...@gmail.com wrote: Hello all, I'm having a problem with data handling. My input data is (dput in the after the signature): Date Time Fraction 06/19/13 22:15:39 0.3205 06/19/13 22:15:44 0.3205 06/19/13 22:15:49 0.3205 06/19/13 22:15:54 0.3205 06/19/13 22:15:59 0.3205 06/19/13 22:16:09 0.3205 Date in format month/day/year, Time in HH:MM:SS and fraction represents the fractions of seconds. I need to have a vector in a format year-month-day hh:mm:ss.. Or, in format: format = %F %H:%M:%OS4, as POSIXct class. I made the the conversion step-by-step to have sure that nothing is missed in the way: options (digits.sec = 4) getOption (digits.sec) [1] 4 teste$Date1 = as.Date (teste$Date, format = %m/%d/%y) class (teste$Date1) [1] Date teste$Fraction = sub (0., , teste$Fraction) teste$TimeC = paste (teste$Time, teste$Fraction, sep = .) teste$TimeCC = paste (teste$Date1, teste$TimeC) head (teste) Date Time Fraction Date1TimeC TimeCC 1 06/19/13 22:15:39 .325 2013-06-19 22:15:39.325 2013-06-19 22:15:39.3205 2 06/19/13 22:15:44 .325 2013-06-19 22:15:44.325 2013-06-19 22:15:44.3205 3 06/19/13 22:15:49 .325 2013-06-19 22:15:49.325 2013-06-19 22:15:49.3205 4 06/19/13 22:15:54 .325 2013-06-19 22:15:54.325 2013-06-19 22:15:54.3205 5 06/19/13 22:15:59 .325 2013-06-19 22:15:59.325 2013-06-19 22:15:59.3205 6 06/19/13 22:16:09 .325 2013-06-19 22:16:09.325 2013-06-19 22:16:09.3205 So far so well. The problem is when I tried to convert to POSIXct class. If I use just: teste$TimeCC = format (teste$TimeCC, format = %F %H:%M:%OS4) teste$TimeCC = as.POSIXct (teste$TimeCC) I lost the fraction of seconds. If I use: teste$TimeCC = as.POSIXct(strptime (teste$TimeCC, format = %F %H:%M:%OS4)) I lost all information and get just NA. Thanks in advanced, -- Raoni Rosa Rodrigues Research Associate of Fish Transposition Center CTPeixes Universidade Federal de Minas Gerais - UFMG Brasil rodrigues.ra...@gmail.com dput of input data structure(list(Date = c(06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13, 06/19/13), Time = c(22:15:39, 22:15:44, 22:15:49, 22:15:54, 22:15:59, 22:16:09), Fraction = c(0.3205, 0.3205, 0.3205, 0.3205, 0.3205, 0.3205)), .Names = c(Date, Time, Fraction), row.names = c(NA, 6L), class = data.frame) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Data handling/optimum glm method.
Hi there, I am trying to fit a generalised linear model to some loan application and default data. The purpose of this is to eventually work out the probability an applicant will default. However, R seems to crash or die when I run glm on anything greater than a 5-way saturated model for my data. My first question: is the best way to fit a generalised linear model in R to fit the saturated model and extract the significant terms only, or to start at the null model and to work up to the optimum one? I am importing a csv file with 3500 rows and 27 columns (3500x27 matrix). My second question: is there anyway to increase the memory I have so R can cope with more analysis? I can send my code if it would help to answer the question. Kind regards, AJC Sent from my BlackBerry smartphone from Virgin Media __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data handling/optimum glm method.
abigailclifton at me.com writes: I am trying to fit a generalised linear model to some loan application and default data. The purpose of this is to eventually work out the probability an applicant will default. However, R seems to crash or die when I run glm on anything greater than a 5-way saturated model for my data. What does crash or die mean? Are you getting error messages? What are they? Is the R application actually quitting? My first question: is the best way to fit a generalised linear model in R to fit the saturated model and extract the significant terms only, or to start at the null model and to work up to the optimum one? This is more of a statistical practice question than an R question. Opinions differ but in general I would say if it is computationally feasible that you should start (and maybe finish) with the full model. I am importing a csv file with 3500 rows and 27 columns (3500x27 matrix). My second question: is there anyway to increase the memory I have so R can cope with more analysis? help(Memory-limits) I can send my code if it would help to answer the question. Please read the posting guide (link at the bottom of every R-help posting) and follow its advice. We don't know enough about your situation to help. You could also try reading http://tinyurl.com/reproducible-000 ... This works for me: z - matrix(rnorm(3500*27),ncol=27) y - sample(0:1,replace=TRUE,size=3500) colnames(z) - c(letters,A) d - data.frame(y=y,z) gg - glm(y~.,data=d,family=binomial) gg - glm(y~a*b*c*d*e*f*g*h,data=d,family=binomial) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data handling/optimum glm method.
Ben: On Thu, Mar 29, 2012 at 5:41 AM, Ben Bolker bbol...@gmail.com wrote: abigailclifton at me.com writes: I am trying to fit a generalised linear model to some loan application and default data. The purpose of this is to eventually work out the probability an applicant will default. However, R seems to crash or die when I run glm on anything greater than a 5-way saturated model for my data. What does crash or die mean? Are you getting error messages? What are they? Is the R application actually quitting? My first question: is the best way to fit a generalised linear model in R to fit the saturated model and extract the significant terms only, or to start at the null model and to work up to the optimum one? This is more of a statistical practice question than an R question. Opinions differ Well, to clarify: I do not think opinions differ on the first proposal -- reduce model to only significant terms. This should **not** be done. I also would say (more tentatively) that modern practice rejects the notion of an optimum model to begin with,preferring shrinkage of other methodology. Cheers, Bert but in general I would say if it is computationally feasible that you should start (and maybe finish) with the full model. I am importing a csv file with 3500 rows and 27 columns (3500x27 matrix). My second question: is there anyway to increase the memory I have so R can cope with more analysis? help(Memory-limits) I can send my code if it would help to answer the question. Please read the posting guide (link at the bottom of every R-help posting) and follow its advice. We don't know enough about your situation to help. You could also try reading http://tinyurl.com/reproducible-000 ... This works for me: z - matrix(rnorm(3500*27),ncol=27) y - sample(0:1,replace=TRUE,size=3500) colnames(z) - c(letters,A) d - data.frame(y=y,z) gg - glm(y~.,data=d,family=binomial) gg - glm(y~a*b*c*d*e*f*g*h,data=d,family=binomial) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Bert Gunter Genentech Nonclinical Biostatistics Internal Contact Info: Phone: 467-7374 Website: http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Handling
Hi, I have managed to convert my data frames into xts such as : str(z) An âxtsâ object from 1983-01-03 19:00:00 to 2006-01-01 22:00:00 containing: Data: num [1:182959, 1:2] 12.6 11.3 12.7 12.8 10.9 ... - attr(*, dimnames)=List of 2 ..$ : NULL ..$ : chr [1:2] v DD Indexed by objects of class: [POSIXt,POSIXct] TZ: Original class: 'data.frame' xts Attributes: NULL I have a second set of data and would like to pull out the values of v when time series from z and z1 are exact. I have tried to look at cbind etc, but I am stuck and very confused! Any help is appreciated On Fri, Jul 30, 2010 at 12:44 PM, raghu [via R] ml-node+2307836-1452362937-369...@n4.nabble.comml-node%2b2307836-1452362937-369...@n4.nabble.com wrote: Convert your datasets into xts objects and then do a cbind ordering by the column you want. Do a ?cbind. HTH Raghu On Fri, Jul 30, 2010 at 10:33 AM, Lily_stats [via R] [hidden email]http://user/SendEmail.jtp?type=nodenode=2307836i=0 wrote: Hi, I am very new to R so these questions may seem simple! I have a huge 2 sets of data(matrix 5x2++) in the following formats , for example data.txt and data2.txt: Date Time X Y 03/03/1983 20:00 0.1 990 I would like to recreate a new matrix which filters through data.txt and data2.txt to get something as below : Date Time X_data1 X_data2 Y_data1 Y_data2 31/12/2000 12:00 2.25 0990 So I basically need : 1) When Date AND Time from data1.txt and data2.txt match, list the corresponding X and Y values (X_data1,X_data2,Y_data1,Y_data2) Thank you in advance, and I hope I have been clear enough in my message -- View message @ http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307770.htmlhttp://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307770.html?by-user=t To start a new topic under R help, email [hidden email]http://user/SendEmail.jtp?type=nodenode=2307836i=1 To unsubscribe from R help, click here. -- 'Raghu' -- View message @ http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307836.html To unsubscribe from Data Handling, click here (link removed) . -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2310318.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Handling
Hi, I am trying to convert my dataset into xts. I have tried the following : data1-read.table(data1.txt,header=F) data2-read.table(data2.txt,header=F) data1.xtsas.xts(data1,descr=my new xts object) However, I get an error : Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format I understand that my date and time format might not be accepted and have tried to convert this but failed. Could you suggest something ? My date is in the format : dd/mm/ My time is in the format : hh:00 Thank you in advance -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307936.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Handling
On Fri, Jul 30, 2010 at 9:02 AM, Lily_stats sund...@gmail.com wrote: Hi, I am trying to convert my dataset into xts. I have tried the following : data1-read.table(data1.txt,header=F) data2-read.table(data2.txt,header=F) data1.xtsas.xts(data1,descr=my new xts object) However, I get an error : Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format I understand that my date and time format might not be accepted and have tried to convert this but failed. Could you suggest something ? My date is in the format : dd/mm/ My time is in the format : hh:00 Thank you in advance -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307936.html Sent from the R help mailing list archive at Nabble.com. Can't say too much since there is no detail in your post but you can do something like this: library(xts) # this also loads zoo library(chron) # if you wish to use chron z - read.zoo(...) x - as.xts(z) where you may need to use FUN= and possibly the index.column= and other arguments to read.zoo. See ?read.zoo and the R News 4/1 article on dates. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Data Handling
Hi, I am very new to R so these questions may seem simple! I have a huge 2 sets of data(matrix 5x2++) in the following formats , for example data.txt and data2.txt: Date Time X Y 03/03/1983 20:00 0.1 990 I would like to recreate a new matrix which filters through data.txt and data2.txt to get something as below : Date Time X_data1 X_data2 Y_data1 Y_data2 31/12/2000 12:00 2.25 0 990 So I basically need : 1) When Date AND Time from data1.txt and data2.txt match, list the corresponding X and Y values (X_data1,X_data2,Y_data1,Y_data2) Thank you in advance, and I hope I have been clear enough in my message -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307770.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Handling
Convert your datasets into xts objects and then do a cbind ordering by the column you want. Do a ?cbind. HTH Raghu On Fri, Jul 30, 2010 at 10:33 AM, Lily_stats [via R] ml-node+2307770-1033893256-309...@n4.nabble.comml-node%2b2307770-1033893256-309...@n4.nabble.com wrote: Hi, I am very new to R so these questions may seem simple! I have a huge 2 sets of data(matrix 5x2++) in the following formats , for example data.txt and data2.txt: Date Time X Y 03/03/1983 20:00 0.1 990 I would like to recreate a new matrix which filters through data.txt and data2.txt to get something as below : Date Time X_data1 X_data2 Y_data1 Y_data2 31/12/2000 12:00 2.25 0990 So I basically need : 1) When Date AND Time from data1.txt and data2.txt match, list the corresponding X and Y values (X_data1,X_data2,Y_data1,Y_data2) Thank you in advance, and I hope I have been clear enough in my message -- View message @ http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307770.html To start a new topic under R help, email ml-node+789696-608741344-309...@n4.nabble.comml-node%2b789696-608741344-309...@n4.nabble.com To unsubscribe from R help, click here (link removed) . -- 'Raghu' -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307836.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Handling
Please try: data - xts(data[,2:n], order.by=as.POSIXct(strptime(data[,1], %d/%m/%Y))) Use similar strptime for hours also.n=number of columns. Good Luck Raghu On Fri, Jul 30, 2010 at 2:02 PM, Lily_stats [via R] ml-node+2307936-1777222343-309...@n4.nabble.comml-node%2b2307936-1777222343-309...@n4.nabble.com wrote: Hi, I am trying to convert my dataset into xts. I have tried the following : data1-read.table(data1.txt,header=F) data2-read.table(data2.txt,header=F) data1.xtsas.xts(data1,descr=my new xts object) However, I get an error : Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format I understand that my date and time format might not be accepted and have tried to convert this but failed. Could you suggest something ? My date is in the format : dd/mm/ My time is in the format : hh:00 Thank you in advance -- View message @ http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307936.html To start a new topic under R help, email ml-node+789696-608741344-309...@n4.nabble.comml-node%2b789696-608741344-309...@n4.nabble.com To unsubscribe from R help, click here (link removed) . -- 'Raghu' -- View this message in context: http://r.789695.n4.nabble.com/Data-Handling-tp2307770p2307959.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
