Re: [R] Date seq question
On Fri, Jan 20, 2012 at 12:12 PM, cameron raymond...@invesco.com wrote: Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i have What i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) Try this. It only uses plain R. f inputs a Date class date and returns the index in dt which contains the last date in the prior month (or NA if none) assuming that dt is sorted: dt - as.Date(date, %m/%d/%Y) ym - format(dt, %Y %m) f - function(x) tail(c(NA, which(ym x)), 1) dt[sapply(ym, f)] -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Date seq question
On Sat, Jan 21, 2012 at 5:20 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: On Fri, Jan 20, 2012 at 12:12 PM, cameron raymond...@invesco.com wrote: Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i have What i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) Try this. It only uses plain R. f inputs a Date class date and returns the index in dt which contains the last date in the prior month (or NA if none) assuming that dt is sorted: dt - as.Date(date, %m/%d/%Y) ym - format(dt, %Y %m) f - function(x) tail(c(NA, which(ym x)), 1) dt[sapply(ym, f)] Just one correction. f takes a ym-style string, not a Date. -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Date seq question
Here is another way: date - + c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, + 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, + 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) x.input - as.POSIXlt(date, format = '%m/%d/%Y', tz = GMT) x - x.input # make a copy # force to the first day of the month x$mday - 1L # now get last day of previous month x - x - 24 * 3600 # subtract 24 hours (in seconds) data.frame(today = x.input, last = x) today last 1 2011-09-22 2011-08-31 2 2011-09-23 2011-08-31 3 2011-09-26 2011-08-31 4 2011-09-27 2011-08-31 5 2011-09-28 2011-08-31 6 2011-09-29 2011-08-31 7 2011-09-30 2011-08-31 8 2011-10-17 2011-09-30 9 2011-10-18 2011-09-30 10 2011-10-19 2011-09-30 11 2011-10-20 2011-09-30 12 2011-10-21 2011-09-30 13 2011-10-24 2011-09-30 14 2011-10-25 2011-09-30 On Sat, Jan 21, 2012 at 5:21 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: On Sat, Jan 21, 2012 at 5:20 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: On Fri, Jan 20, 2012 at 12:12 PM, cameron raymond...@invesco.com wrote: Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i have What i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) Try this. It only uses plain R. f inputs a Date class date and returns the index in dt which contains the last date in the prior month (or NA if none) assuming that dt is sorted: dt - as.Date(date, %m/%d/%Y) ym - format(dt, %Y %m) f - function(x) tail(c(NA, which(ym x)), 1) dt[sapply(ym, f)] Just one correction. f takes a ym-style string, not a Date. -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Date seq question
Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i haveWhat i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) -- View this message in context: http://r.789695.n4.nabble.com/Date-seq-question-tp4313861p4313861.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Date seq question
Try this: date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) library(lubridate) date - as.Date(date, format = %m/%d/%Y) # Convert character to an actual date day(date) - 1; # Shift every date to the first day of its month date - 1 # And go one day previous Michael On Fri, Jan 20, 2012 at 12:12 PM, cameron raymond...@invesco.com wrote: Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i have What i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 date - c(9/22/2011,9/23/2011,9/26/2011,9/27/2011,9/28/2011,9/29/2011,9/30/2011,10/17/2011, 10/18/2011,10/19/2011,10/20/2011,10/21/2011,10/24/2011,10/25/2011,10/26/2011,11/17/2011,11/18/2011,11/21/2011,11/22/2011,11/23/2011,11/25/2011,11/28/2011,11/29/2011,11/30/2011, 12/9/2011,12/12/2011,12/13/2011,12/14/2011,12/15/2011,12/16/2011,12/19/2011,12/20/2011,12/21/2011,12/22/2011) -- View this message in context: http://r.789695.n4.nabble.com/Date-seq-question-tp4313861p4313861.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Date seq question
On 1/20/2012 9:12 AM, cameron wrote: Can anyone please help me with this? I have a list of business dates. What I want is to have last day of last month and paste them on next month. What i haveWhat i want 5725 2011-09-22 5726 2011-09-23 5727 2011-09-26 5728 2011-09-27 5729 2011-09-28 5730 2011-09-29 5731 2011-09-30 5742 2011-10-17 2011-09-30 5743 2011-10-18 2011-09-30 5744 2011-10-19 2011-09-30 5745 2011-10-20 2011-09-30 5746 2011-10-21 2011-09-30 5747 2011-10-24 2011-09-30 5748 2011-10-25 2011-09-30 *5749 2011-10-26* 2011-09-30 5765 2011-11-17 2011-10-26 5766 2011-11-18 2011-10-26 5767 2011-11-21 2011-10-26 5768 2011-11-22 2011-10-26 5769 2011-11-23 2011-10-26 5770 2011-11-25 2011-10-26 5771 2011-11-28 2011-10-26 5772 2011-11-29 2011-10-26 *5773 2011-11-30* 2011-10-26 5780 2011-12-09 2011-11-30 5781 2011-12-12 2011-11-30 5782 2011-12-13 2011-11-30 5783 2011-12-14 2011-11-30 5784 2011-12-15 2011-11-30 5785 2011-12-16 2011-11-30 5786 2011-12-19 2011-11-30 5787 2011-12-20 2011-11-30 5788 2011-12-21 2011-11-30 5789 2011-12-22 2011-11-30 Reformatting the data you gave: date- c(9/22/2011, 9/23/2011, 9/26/2011, 9/27/2011, 9/28/2011, 9/29/2011, 9/30/2011, 10/17/2011, 10/18/2011, 10/19/2011, 10/20/2011, 10/21/2011, 10/24/2011, 10/25/2011, 10/26/2011, 11/17/2011, 11/18/2011, 11/21/2011, 11/22/2011, 11/23/2011, 11/25/2011, 11/28/2011, 11/29/2011, 11/30/2011, 12/9/2011, 12/12/2011, 12/13/2011, 12/14/2011, 12/15/2011, 12/16/2011, 12/19/2011, 12/20/2011, 12/21/2011, 12/22/2011) Here is a solution using plyr and zoo: library(plyr) library(zoo) DF - data.frame(date) DF - mutate(DF, dt = as.Date(date, format=%m/%d/%Y), ym = as.yearmon(dt)) lastday - ddply(DF, .(ym), summarise, last=max(dt)) lastday - mutate(lastday, ym=ym+(1/12)) merge(DF, lastday, all.x=TRUE) I first turn the strings into dates, and then into yearmons (year-month) which is what I need zoo for. Use ddply to get the last date within each year-month group. Add one month to the yearmon summaries to go to the next month. Then merge these two back together, implicitly by the yearmon. You could then delete any of the intermediate result columns if you like. -- Brian S. Diggs, PhD Senior Research Associate, Department of Surgery Oregon Health Science University __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Date seq question
Thanks Michael and Brian Thanks for your time. -- View this message in context: http://r.789695.n4.nabble.com/Date-seq-question-tp4313861p4314793.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
