Re: [R] Equivalent of intervals() in lmer

2008-04-23 Thread Michael Kubovy
Dear Friends,

(1) There may be a solution for those (e.g., experimental  
psychologists) who are *not at all* interested in generalizing the  
absolute level of the response variable (say, reaction time, rt) to  
other subjects, but *only* to generalize the effect of the manipulated  
variables within subjects (because that's what the theory speaks to)  
to other subjects. First, center the predictor(s) so as to remove any  
spurious correlation between mean and intercept, and then write the  
random effect w/o an intercept. Now the model will not address whether  
rt is different from 0, it will only estimate the slope and whether  
it's different from 0:

require(lme4)
require(gmodels)
data(sleepstudy)
ss - sleepstudy
ss$days - with(ss, Days - mean(Days))
(fm1 - lmer(Reaction ~ days + (days|Subject), ss))
(fm3 - lmer(Reaction ~ days + (-1 + days|Subject), ss))
ci(fm1)
ci(fm3) # CIs for days are about 14% smaller

(2) When the predictor is not continuous, this approach doesn't work.  
A solution for a designed experiment is to plot CIs for differences,  
i.e., 5%LSDs (rather than plot the CIs on cell means). Those CIs are  
smaller and address the question of interest. Here is a one-way ANOVA:

recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,
15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),
subj = factor(rep(1:10, each = 3)))
(fr.lmer - lmer(rcl ~ time -1 +(1 | subj), fr))
mm - unique(model.matrix(~ time -1, fr))
cm - mm[1, ] - mm[3, ]
cm1 - mm[1, ] - mm[2, ]
estimable(fr.lmer, cm = cm, conf.into = 0.95)
estimable(fr.lmer, cm = cm1, conf.into = 0.95)

plot mean \pm 2* 0.366 and call it a 5%LSD (uncorrected for multiple  
comparisons)

In the case of a more-than-one-way ANOVA with interaction (say 2x2),  
choose which simple effects are of interest, get SEs for those; and  
then plot the four points with the CIs. These are not quite right for  
the difference between simple effects, but I don't know what to do  
about that.
_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
Lab:B019+1-434-982-4751
Fax:+1-434-982-4766
WWW:http://www.people.virginia.edu/~mk9y/

On Apr 21, 2008, at 9:05 AM, Dieter Menne wrote:

 Douglas Bates bates at stat.wisc.edu writes:

 If you want to examine the three means then you should fit the  
 model as
 lmer(rcl ~ time - 1 + (1 | subj), fr)

 True, but for the notorious error bars in plots that reviewers  
 always request
 the 0.35 is probable more relevant than the 1.87. Which I think is  
 justified in
 this case, but in most non-orthogonal designs with three or more  
 factors, where
 we have a mixture of between/withing subject, there is no clear  
 solution. What
 to do when required to produce error-bars that reasonably mirror p- 
 values?

 It's easier with British Journals  in the medical field that often  
 have
 statistical professionals as reviewers, but many American Journals  
 with their
 amateur physician/statisticians (why no t-test on raw data?) drive  
 me nuts.

 Dieter

 #-
 library(lme4)
 recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,
 15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
 fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),
 subj = factor(rep(1:10, each = 3)))
 fr.lmer - lmer(rcl ~ time -1 +(1 | subj), fr)
 summary(fr.lmer)
 fr.lmer - lmer(rcl ~ time +(1 | subj), fr)
 summary(fr.lmer)
 --
 Fixed effects:
  Estimate Std. Error t value
 time1   11.000  1.879   5.853
 time2   13.000  1.879   6.918
 time5   14.200  1.879   7.556

 Fixed effects:
Estimate Std. Error t value
 (Intercept)  11. 1.8793   5.853
 time2 2. 0.3507   5.703
 time5 3.2000 0.3507   9.125


[[alternative HTML version deleted]]

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Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Dieter Menne
kedar nadkarni nadkarnikedar at gmail.com writes:

   I have been trying to obtain confidence intervals for the fit after having
 used lmer by using intervals(), but this does not work. intervals() is
 associated with lme but not with lmer(). What is the equivalent for
 intervals() in lmer()? 

ci in Gregory Warnes' package gmodels can do this. However, think twice if you
really need lmer. Why not lme? It is well documented and has many features that
are currently not in lmer. 

Dieter

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Michael Kubovy
To help Kedar a bit:

Here is one way:

recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,  
15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),  
subj = factor(rep(1:10, each = 3)))
(fr.lmer - lmer(rcl ~ time + (1 | subj), fr))
require(gmodels)
ci(fr.lmer)

Now I have a problem to which I would very much appreciate having a  
solution:

The model fr.lmer gives a SE of 1.8793 for the (Intercept) and 0.3507  
for the other levels. The reason is that the first took account of the  
variability of the effect of subjects. Or using simulation:
  Estimate CI lower  CI upper Std. Error p-value
(Intercept) 11.107202 6.458765 15.208065  2.1587362   0.004
time22.012064 1.301701  2.795128  0.3743050   0.000
time53.206834 2.502870  3.939791  0.3694384   0.000

Now if I need to draw CI bars around the three means, it seems to me  
that they should be roughly 11, 13, and 16.2, each  \pm 0.75, because  
I'm trying to estimate the variability of patterns within subjects,  
and am not interested in the subject to subject variation in the mean  
for the purposes of prediction.

This what the authors in the paper cited below call on p. 402 a  
narrow [as opposed to a broad] inference space. My question: ***How  
do I extract the three narrow CIs from the lmer?***
@ARTICLE{BlouinRiopelle2005,
   author = {Blouin, David C. and Riopelle, Arthur J.},
   title = {On confidence intervals for within-subjects designs},
   journal = {Psychological Methods},
   year = {2005},
   volume = {10},
   pages = {397--412},
   number = {4},
   month = dec,
   abstract = {Confidence intervals (CIs) for means are frequently  
advocated as alternatives
to null hypothesis significance testing (NHST), for which a common
theme in the debate is that conclusions from CIs and NHST should
be mutually consistent. The authors examined a class of CIs for which
the conclusions are said to be inconsistent with NHST in within- 
subjects
designs and a class for which the conclusions are said to be  
consistent.
The difference between them is a difference in models. In particular,
the main issue is that the class for which the conclusions are said
to be consistent derives from fixed-effects models with subjects
fixed, not mixed models with subjects random. Offered is mixed model
methodology that has been popularized in the statistical literature
and statistical software procedures. Generalizations to different
classes of within-subjects designs are explored, and comments on
the future direction of the debate on NHST are offered.},
   url = {http://search.epnet.com/login.aspx?direct=truedb=pdhan=met104397 
}
}

_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
Lab:B019+1-434-982-4751
Fax:+1-434-982-4766
WWW:http://www.people.virginia.edu/~mk9y/

On Apr 21, 2008, at 2:24 AM, Dieter Menne wrote:

 kedar nadkarni nadkarnikedar at gmail.com writes:

  I have been trying to obtain confidence intervals for the fit  
 after having
 used lmer by using intervals(), but this does not work. intervals()  
 is
 associated with lme but not with lmer(). What is the equivalent for
 intervals() in lmer()?

 ci in Gregory Warnes' package gmodels can do this. However, think  
 twice if you
 really need lmer. Why not lme? It is well documented and has many  
 features that
 are currently not in lmer.

 Dieter

[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Douglas Bates
On 4/21/08, Michael Kubovy [EMAIL PROTECTED] wrote:
 To help Kedar a bit:

  Here is one way:

  recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,
  15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
  fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),
  subj = factor(rep(1:10, each = 3)))
  (fr.lmer - lmer(rcl ~ time + (1 | subj), fr))
  require(gmodels)
  ci(fr.lmer)

  Now I have a problem to which I would very much appreciate having a
  solution:

  The model fr.lmer gives a SE of 1.8793 for the (Intercept) and 0.3507
  for the other levels. The reason is that the first took account of the
  variability of the effect of subjects. Or using simulation:
   Estimate CI lower  CI upper Std. Error p-value
  (Intercept) 11.107202 6.458765 15.208065  2.1587362   0.004
  time22.012064 1.301701  2.795128  0.3743050   0.000
  time53.206834 2.502870  3.939791  0.3694384   0.000

  Now if I need to draw CI bars around the three means, it seems to me
  that they should be roughly 11, 13, and 16.2, each  \pm 0.75, because
  I'm trying to estimate the variability of patterns within subjects,
  and am not interested in the subject to subject variation in the mean
  for the purposes of prediction.

If you want to examine the three means then you should fit the model as
lmer(rcl ~ time - 1 + (1 | subj), fr)

  This what the authors in the paper cited below call on p. 402 a
  narrow [as opposed to a broad] inference space. My question: ***How
  do I extract the three narrow CIs from the lmer?***
  @ARTICLE{BlouinRiopelle2005,
author = {Blouin, David C. and Riopelle, Arthur J.},
title = {On confidence intervals for within-subjects designs},
journal = {Psychological Methods},
year = {2005},
volume = {10},
pages = {397--412},
number = {4},
month = dec,
abstract = {Confidence intervals (CIs) for means are frequently
  advocated as alternatives
 to null hypothesis significance testing (NHST), for which a common
 theme in the debate is that conclusions from CIs and NHST should
 be mutually consistent. The authors examined a class of CIs for which
 the conclusions are said to be inconsistent with NHST in within-
  subjects
 designs and a class for which the conclusions are said to be
  consistent.
 The difference between them is a difference in models. In particular,
 the main issue is that the class for which the conclusions are said
 to be consistent derives from fixed-effects models with subjects
 fixed, not mixed models with subjects random. Offered is mixed model
 methodology that has been popularized in the statistical literature
 and statistical software procedures. Generalizations to different
 classes of within-subjects designs are explored, and comments on
 the future direction of the debate on NHST are offered.},
url = {http://search.epnet.com/login.aspx?direct=truedb=pdhan=met104397
  }
  }

  _
  Professor Michael Kubovy
  University of Virginia
  Department of Psychology
  USPS: P.O.Box 400400Charlottesville, VA 22904-4400
  Parcels:Room 102Gilmer Hall
  McCormick RoadCharlottesville, VA 22903
  Office:B011+1-434-982-4729
  Lab:B019+1-434-982-4751
  Fax:+1-434-982-4766
  WWW:http://www.people.virginia.edu/~mk9y/


  On Apr 21, 2008, at 2:24 AM, Dieter Menne wrote:

   kedar nadkarni nadkarnikedar at gmail.com writes:
  
I have been trying to obtain confidence intervals for the fit
   after having
   used lmer by using intervals(), but this does not work. intervals()
   is
   associated with lme but not with lmer(). What is the equivalent for
   intervals() in lmer()?
  
   ci in Gregory Warnes' package gmodels can do this. However, think
   twice if you
   really need lmer. Why not lme? It is well documented and has many
   features that
   are currently not in lmer.
  
   Dieter


 [[alternative HTML version deleted]]


  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Dieter Menne
Douglas Bates bates at stat.wisc.edu writes:

 If you want to examine the three means then you should fit the model as
 lmer(rcl ~ time - 1 + (1 | subj), fr)
 

True, but for the notorious error bars in plots that reviewers always request
the 0.35 is probable more relevant than the 1.87. Which I think is justified in
this case, but in most non-orthogonal designs with three or more factors, where
we have a mixture of between/withing subject, there is no clear solution. What
to do when required to produce error-bars that reasonably mirror p-values? 

It's easier with British Journals  in the medical field that often have
statistical professionals as reviewers, but many American Journals with their
amateur physician/statisticians (why no t-test on raw data?) drive me nuts.

Dieter


#-
library(lme4)
recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,  
15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),  
subj = factor(rep(1:10, each = 3)))
fr.lmer - lmer(rcl ~ time -1 +(1 | subj), fr)
summary(fr.lmer)
fr.lmer - lmer(rcl ~ time +(1 | subj), fr)
summary(fr.lmer)



--

Fixed effects:
  Estimate Std. Error t value
time1   11.000  1.879   5.853
time2   13.000  1.879   6.918
time5   14.200  1.879   7.556


Fixed effects:
Estimate Std. Error t value
(Intercept)  11. 1.8793   5.853
time2 2. 0.3507   5.703
time5 3.2000 0.3507   9.125

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Michael Kubovy
Thanks Doug,

You write: If you want to examine the three means then you should fit  
the model as lmer(rcl ~ time - 1 + (1 | subj), fr)

I do just that (which is what Dieter just sent). But the CIs are much  
too big compared to the CIs for differences between means (which  
should be bigger than the CIs on the means themselves). If you write  
the model as ~ 1 - time, then the CIs are roughly of the same (large)  
size. But I'm really interested in the CIs on the means that capture  
the variability *within* subjects. I believe that this is what  
experimentalists in psychology need (and have been debating for a long  
time what the correct analysis is that produces these error bars). The  
theory is not about generalizing to people, but generalizing to  
responses to different  situations within people. The article by  
Brillouin and Riopelle (2005) is the only one that tries to do this  
within the framework of LMEMs that I know of, and it's couched in  
terms of SAS.

For the moment I wonder if the solution is not to use CIs based on the  
two low SEs produced by the ~ 1 - time model, and to treat them as  
least-significant difference intervals.
_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
Lab:B019+1-434-982-4751
Fax:+1-434-982-4766
WWW:http://www.people.virginia.edu/~mk9y/




On Apr 21, 2008, at 7:56 AM, Douglas Bates wrote:

 On 4/21/08, Michael Kubovy [EMAIL PROTECTED] wrote:
 To help Kedar a bit:

 Here is one way:

 recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,
 15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
 fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),
 subj = factor(rep(1:10, each = 3)))
 (fr.lmer - lmer(rcl ~ time + (1 | subj), fr))
 require(gmodels)
 ci(fr.lmer)

 Now I have a problem to which I would very much appreciate having a
 solution:

 The model fr.lmer gives a SE of 1.8793 for the (Intercept) and 0.3507
 for the other levels. The reason is that the first took account of  
 the
 variability of the effect of subjects. Or using simulation:
  Estimate CI lower  CI upper Std. Error p-value
 (Intercept) 11.107202 6.458765 15.208065  2.1587362   0.004
 time22.012064 1.301701  2.795128  0.3743050   0.000
 time53.206834 2.502870  3.939791  0.3694384   0.000

 Now if I need to draw CI bars around the three means, it seems to me
 that they should be roughly 11, 13, and 16.2, each  \pm 0.75, because
 I'm trying to estimate the variability of patterns within subjects,
 and am not interested in the subject to subject variation in the mean
 for the purposes of prediction.

 If you want to examine the three means then you should fit the model  
 as
 lmer(rcl ~ time - 1 + (1 | subj), fr)

 This what the authors in the paper cited below call on p. 402 a
 narrow [as opposed to a broad] inference space. My question: ***How
 do I extract the three narrow CIs from the lmer?***
 @ARTICLE{BlouinRiopelle2005,
   author = {Blouin, David C. and Riopelle, Arthur J.},
   title = {On confidence intervals for within-subjects designs},
   journal = {Psychological Methods},
   year = {2005},
   volume = {10},
   pages = {397--412},
   number = {4},
   month = dec,
   abstract = {Confidence intervals (CIs) for means are frequently
 advocated as alternatives
to null hypothesis significance testing (NHST), for which a  
 common
theme in the debate is that conclusions from CIs and NHST  
 should
be mutually consistent. The authors examined a class of CIs  
 for which
the conclusions are said to be inconsistent with NHST in  
 within-
 subjects
designs and a class for which the conclusions are said to be
 consistent.
The difference between them is a difference in models. In  
 particular,
the main issue is that the class for which the conclusions  
 are said
to be consistent derives from fixed-effects models with  
 subjects
fixed, not mixed models with subjects random. Offered is  
 mixed model
methodology that has been popularized in the statistical  
 literature
and statistical software procedures. Generalizations to  
 different
classes of within-subjects designs are explored, and  
 comments on
the future direction of the debate on NHST are offered.},
   url = {http://search.epnet.com/login.aspx?direct=truedb=pdhan=met104397
 }
 }

 _
 Professor Michael Kubovy
 University of Virginia
 Department of Psychology
 USPS: P.O.Box 400400Charlottesville, VA 22904-4400
 Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
 Office:B011+1-434-982-4729
 Lab:B019+1-434-982-4751
 Fax:   

Re: [R] Equivalent of intervals() in lmer

2008-04-21 Thread Michael Kubovy
Sorry, I meant to say: For the moment I wonder if the solution is not  
to use CIs based on the  two low SEs produced by the ~ time model, and  
to treat them as  least-significant difference intervals.
_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
Lab:B019+1-434-982-4751
Fax:+1-434-982-4766
WWW:http://www.people.virginia.edu/~mk9y/

On Apr 21, 2008, at 9:23 AM, Michael Kubovy wrote:

 Thanks Doug,

 You write: If you want to examine the three means then you should fit
 the model as lmer(rcl ~ time - 1 + (1 | subj), fr)

 I do just that (which is what Dieter just sent). But the CIs are much
 too big compared to the CIs for differences between means (which
 should be bigger than the CIs on the means themselves). If you write
 the model as ~ 1 - time, then the CIs are roughly of the same (large)
 size. But I'm really interested in the CIs on the means that capture
 the variability *within* subjects. I believe that this is what
 experimentalists in psychology need (and have been debating for a long
 time what the correct analysis is that produces these error bars). The
 theory is not about generalizing to people, but generalizing to
 responses to different  situations within people. The article by
 Brillouin and Riopelle (2005) is the only one that tries to do this
 within the framework of LMEMs that I know of, and it's couched in
 terms of SAS.

 For the moment I wonder if the solution is not to use CIs based on the
 two low SEs produced by the ~ 1 - time model, and to treat them as
 least-significant difference intervals.

 On Apr 21, 2008, at 7:56 AM, Douglas Bates wrote:

 On 4/21/08, Michael Kubovy [EMAIL PROTECTED] wrote:
 To help Kedar a bit:

 Here is one way:

 recall - c(10, 13, 13, 6, 8, 8, 11, 14, 14, 22, 23, 25, 16, 18, 20,
 15, 17, 17, 1, 1, 4, 12, 15, 17, 9, 12, 12, 8, 9, 12)
 fr - data.frame(rcl = recall, time = factor(rep(c(1, 2, 5), 10)),
 subj = factor(rep(1:10, each = 3)))
 (fr.lmer - lmer(rcl ~ time + (1 | subj), fr))
 require(gmodels)
 ci(fr.lmer)

 Now I have a problem to which I would very much appreciate having a
 solution:

 The model fr.lmer gives a SE of 1.8793 for the (Intercept) and  
 0.3507
 for the other levels. The reason is that the first took account of
 the
 variability of the effect of subjects. Or using simulation:
 Estimate CI lower  CI upper Std. Error p-value
 (Intercept) 11.107202 6.458765 15.208065  2.1587362   0.004
 time22.012064 1.301701  2.795128  0.3743050   0.000
 time53.206834 2.502870  3.939791  0.3694384   0.000

 Now if I need to draw CI bars around the three means, it seems to me
 that they should be roughly 11, 13, and 16.2, each  \pm 0.75,  
 because
 I'm trying to estimate the variability of patterns within subjects,
 and am not interested in the subject to subject variation in the  
 mean
 for the purposes of prediction.

 If you want to examine the three means then you should fit the model
 as
 lmer(rcl ~ time - 1 + (1 | subj), fr)

 This what the authors in the paper cited below call on p. 402 a
 narrow [as opposed to a broad] inference space. My question:  
 ***How
 do I extract the three narrow CIs from the lmer?***
 @ARTICLE{BlouinRiopelle2005,
  author = {Blouin, David C. and Riopelle, Arthur J.},
  title = {On confidence intervals for within-subjects designs},
  journal = {Psychological Methods},
  year = {2005},
  volume = {10},
  pages = {397--412},
  number = {4},
  month = dec,
  abstract = {Confidence intervals (CIs) for means are frequently
 advocated as alternatives
   to null hypothesis significance testing (NHST), for which a
 common
   theme in the debate is that conclusions from CIs and NHST
 should
   be mutually consistent. The authors examined a class of CIs
 for which
   the conclusions are said to be inconsistent with NHST in
 within-
 subjects
   designs and a class for which the conclusions are said to be
 consistent.
   The difference between them is a difference in models. In
 particular,
   the main issue is that the class for which the conclusions
 are said
   to be consistent derives from fixed-effects models with
 subjects
   fixed, not mixed models with subjects random. Offered is
 mixed model
   methodology that has been popularized in the statistical
 literature
   and statistical software procedures. Generalizations to
 different
   classes of within-subjects designs are explored, and
 comments on
   the future direction of the debate on NHST are offered.},
  url = {http://search.epnet.com/login.aspx?direct=truedb=pdhan=met104397
 }
 }

 On Apr 21, 2008, at 2:24 AM, Dieter Menne wrote:

 kedar nadkarni nadkarnikedar at gmail.com writes:

 I have been trying to obtain 

[R] Equivalent of intervals() in lmer

2008-04-20 Thread kedar nadkarni
Hi all,
  I have been trying to obtain confidence intervals for the fit after having
used lmer by using intervals(), but this does not work. intervals() is
associated with lme but not with lmer(). What is the equivalent for
intervals() in lmer()? I could not get this information from the
documentation.
Regards,
Kedar

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