See ?weekdays, which says
Note:
Other components such as the day of the month or the year are very
easy to compute: just use 'as.POSIXlt' and extract the relevant
component.
so
as.POSIXlt(MyDate)$year+1900
[1] 1994
is how you are expected to do it.
On Tue, 6 Oct 2009, joris meys wrote:
Hi all,
this one left me a bit puzzled, as I don't seem to find a function to
perform this easily. I must have overlooked the obvious, so sorry in
advance.
I have a list of dates in numerical format (i.e. 34576), defined as
the number of days that passed since january 1st 1900. So I apply the
function :
MyDate <-as.Date(34576,origin="1900-01-01")
MyDate
[1] "1994-09-01"
But then I want to do something like :
MyYear <- a.year.function(MyDate)
MyYear should have the numerical value 1994. Alas, I don't find any
function like that. I know I can take a substring of MyDate and
convert to numeric, or even use the function "seq()" :
length ( seq ( as.Date("1900-01-01"), MyDate, "years" ) ) + 1900 - 1
[1] 1994
but that seems quite a way around. Can somebody tell me where the
appropriate function is hiding?
Thank you in advance.
Joris
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