Re: [R] Get means of matrix
Hi Jesus, While I do not have your data and cannot test this, the problem may be that you are using two different names for the data frame. Is this more or less what you want? datos<-data.frame(x1=sample(20:40,40,TRUE),x2=sample(20:40,40,TRUE), x3=sample(20:40,40,TRUE),csvdata=rep(1:2,each=20)) sapply(datos[datos$csvdata==1,],mean,na.rm=TRUE) sapply(datos[datos$csvdata==2,],mean,na.rm=TRUE) Jim On Wed, Nov 18, 2015 at 9:19 PM, Jesús Para Fernández < j.para.fernan...@hotmail.com> wrote: > Hi everyone > > I have a dataframe "data" wich is the result of join multiple csv (400 > rows and 600cols every csv). The "data" dataframe has n rows and m columns > (20 rows and 600 cols) , and I have add a new colum, "csvdata", in > which I specify the number of csv at wich those data belong. > > So, the dataframe "data" looks like: > > x1x2 x3xncsvdata > 21 2332121 > 27 2139141 > 24 2230111 > .. > 21 2432 19 2 > 27 2139142 > .. > 27 22 3011n > > > > I want to store into a matrix the mean values of different substes of data > of every csv, for example: > > region1,1 (rows 1:20,columns 1:20) for every "csvdata" value > region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value > > > And so on for hole data.frame. > > I have tryed: > > area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) > area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) > > But this error is the output I obtain: > > Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) : > arguments must have same length > > I´m sure that it is not very complex to do it, but I have no idea of how > to do it. > > Thanks for all. > > > [[alternative HTML version deleted]] > > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Get means of matrix
Hi See in line > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Jesús > Para Fernández > Sent: Wednesday, November 18, 2015 11:20 AM > To: r-help@r-project.org > Subject: [R] Get means of matrix > > Hi everyone > > I have a dataframe "data" wich is the result of join multiple csv (400 > rows and 600cols every csv). The "data" dataframe has n rows and m > columns (20 rows and 600 cols) , and I have add a new colum, > "csvdata", in which I specify the number of csv at wich those data > belong. > > So, the dataframe "data" looks like: > > x1x2 x3xncsvdata > 21 2332121 > 27 2139141 > 24 2230111 > .. > 21 2432 19 2 > 27 2139142 > .. > 27 22 3011n > > > > I want to store into a matrix the mean values of different substes of > data of every csv, for example: > > region1,1 (rows 1:20,columns 1:20) for every "csvdata" value region 2,1 > (rows 21:40,columns 1:20) para every "csvdata" value > > And so on for hole data.frame. > > I have tryed: > > area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) > area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) > > But this error is the output I obtain: > > Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) : > arguments must have same length Most probably length(datos$csvdata) is not 20 as you specified by data[1:20,1]. If you have already number of csv file in your data$csvdata you can do area <- aggregate(data[,1:n], list(data$csvdata), mean, na.rm=TRUE) If you want to aggregate each 20 rows you can elaborate index ind <- rep(1:20, each=20) area <- aggregate(data[,1:n], list(ind), mean, na.rm=TRUE) Cheers Petr > > I m sure that it is not very complex to do it, but I have no idea of > how to do it. > > Thanks for all. > > > [[alternative HTML version deleted]] Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému. Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat. Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu. V případě, že je tento e-mail součástí obchodního jednání: - vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu. - a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou. - trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech. - odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which
[R] Get means of matrix
Hi everyone I have a dataframe "data" wich is the result of join multiple csv (400 rows and 600cols every csv). The "data" dataframe has n rows and m columns (20 rows and 600 cols) , and I have add a new colum, "csvdata", in which I specify the number of csv at wich those data belong. So, the dataframe "data" looks like: x1x2 x3xncsvdata 21 2332121 27 2139141 24 2230111 .. 21 2432 19 2 27 2139142 .. 27 22 3011n I want to store into a matrix the mean values of different substes of data of every csv, for example: region1,1 (rows 1:20,columns 1:20) for every "csvdata" value region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value And so on for hole data.frame. I have tryed: area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T) But this error is the output I obtain: Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) : arguments must have same length I�m sure that it is not very complex to do it, but I have no idea of how to do it. Thanks for all. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Get means of matrix
Hi:
Here's another way to look at the problem. Instead of manually adding
a new column after k datasets have been read in, read your individual
data files into a list, as long as they all have the same variable
names and the same class (in this case, data.frame). Then create a
vector of names for the list components and use 'apply family' logic
to get the column means, returning the combined results to a data
frame or matrix. Here's a toy example to illustrate the point.
Firstly, three data frames are created and saved to external files:
# Create some artificial data and ship to external files
d1 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))
d2 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))
d3 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))
write.csv(d1, file = "d1.csv", row.names = TRUE, quote = FALSE)
write.csv(d2, file = "d2.csv", row.names = TRUE, quote = FALSE)
write.csv(d3, file = "d3.csv", row.names = TRUE, quote = FALSE)
###
# Now, read them back in and store them in a list object
# Vector of file names to process
files <- paste0("d", 1:3, ".csv")
# Create the list of data frames and assign names to list components
L <- lapply(files, function(x) read.csv(x, header = TRUE))
names(L) <- paste0("d", 1:3)
# Compute column means from each list component and row bind them
# Method 1: base R
do.call(rbind, lapply(L, colMeans))
# Method 2: plyr package
library(plyr)
ldply(L, colMeans)
Dennis
On Wed, Nov 18, 2015 at 2:19 AM, Jesús Para Fernández
wrote:
> Hi everyone
>
> I have a dataframe "data" wich is the result of join multiple csv (400 rows
> and 600cols every csv). The "data" dataframe has n rows and m columns (20
> rows and 600 cols) , and I have add a new colum, "csvdata", in which I
> specify the number of csv at wich those data belong.
>
> So, the dataframe "data" looks like:
>
> x1x2 x3xncsvdata
> 21 2332121
> 27 2139141
> 24 2230111
> ..
> 21 2432 19 2
> 27 2139142
> ..
> 27 22 3011n
>
>
>
> I want to store into a matrix the mean values of different substes of data of
> every csv, for example:
>
> region1,1 (rows 1:20,columns 1:20) for every "csvdata" value
> region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value
>
>
> And so on for hole data.frame.
>
> I have tryed:
>
> area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
> area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
>
> But this error is the output I obtain:
>
> Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) :
> arguments must have same length
>
> I´m sure that it is not very complex to do it, but I have no idea of how to
> do it.
>
> Thanks for all.
>
>
> [[alternative HTML version deleted]]
>
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
