Re: [R] Help with assigning a value based on existing numbers

2010-03-28 Thread Petr PIKAL 
Hi


Jessica Cathro jcat...@london.edu napsal dne 26.03.2010 15:33:19:

 Hi
 Can you explain what the purpose of the cut function is, and how I would
 use it?

?cut

x-runif(100)*300
cut(x, breaks=seq(0,300,50), labels=letters[1:6])

Regards
Petr


 Thanks
 Jessica
 
 _
 
 Jessica Cathro | Business Analyst | Executive Education 
 London Business School | Regent's Park | London NW1 4SA | United Kingdom
 Switchboard +44 (0)20 7000 7000| Direct line +44 (0)20 7000 7383 |
 Email jcat...@london.edu
 
 www.london.edu | London experience. World impact.
 -Original Message-
 From: Petr PIKAL [mailto:petr.pi...@precheza.cz] 
 Sent: 26 March 2010 14:00
 To: Jessica Cathro
 Cc: r-help@r-project.org
 Subject: Odp: [R] Help with assigning a value based on existing numbers
 
 Hi
 
 again a work for cut.
 
 See ?cut and notice a labels option.
 
 Regards
 Petr
 
 r-help-boun...@r-project.org napsal dne 26.03.2010 11:37:20:
 
  Hi All
  
  I have a column/variable called time difference.  It has a whole list
 of
  numbers from 0 through to the hundreds eg 236.  I want to assign a
  corresponding name to each variable from a predefined list: Month or
  less, 1 -2 months, 2-3 months etc
  
  So the result would look something like:
  
  Time Difference   Month
  
  1  Month or less
  
  365 1-2 years
  
  52   2-3 months
  
  Etc
  
  
  
  I have tried using if elseif (as shown below), but it kept coming up
  with the error:
  
  Error:
  
  In if (curvedata$Date.difference == NULL) { :
  
the condition has length  1 and only the first element will be used
  
  2: In if (curvedata$Date.difference = 29) { :
  
the condition has length  1 and only the first element will be used
  
  3: In if (curvedata$Date.difference = 59) { :
  
the condition has length  1 and only the first element will be used
  
  
  
  If Else Statement:
  
  month -if (curvedata$Date.difference ==NULL) {Month -0}  ifelse
  
  (curvedata$Date.difference =29) {Month -month or less} else if
  
  (curvedata$Date.difference =59) {Month -1-2 months} else if
  
  (curvedata$Date.difference =89) {Month -2-3 months} else if
  
  (curvedata$Date.difference =119) {Month -3-4 months} else if
  
  (curvedata$Date.difference =149) {Month -4-5 months} else if
  
  (curvedata$Date.difference =179) {Month -5-6 months} else if
  
  (curvedata$Date.difference =209) {Month -6-7 months} else if
  
  (curvedata$Date.difference =239) {Month -7-8 months} else if
  
  (curvedata$Date.difference =269) {Month -8-9 months} else if
  
  (curvedata$Date.difference =299) {Month -9-10 months} else if
  
  (curvedata$Date.difference =329) {Month -10-11 months} else if
  
  (curvedata$Date.difference =359) {Month -11-12 months} else if
  
  (curvedata$Date.difference =719) {Month -1-2 years} else 
  
  {Month -More than 2 years}
  
  
  
  I'm pretty new to R, so any help would be appreciated.
  
  Thanks
  
  Jessica
  
  _
  
  Jessica Cathro | Business Analyst | Executive Education 
  London Business School | Regent's Park | London NW1 4SA | United
 Kingdom
  Switchboard +44 (0)20 7000 7000| Direct line +44 (0)20 7000 7383 |
  Email jcat...@london.edu mailto:jcat...@london.edu 
  
  www.london.edu http://www.london.edu/  | London experience. World
  impact.
  
  
  __
  
  This email has been scanned by the MessageLabs Email Security System
  on behalf of the London Business School community.
  For more information please visit http://www.messagelabs.com/email
  __
 [[alternative HTML version deleted]]
  
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
 __
 
 This email has been scanned by the MessageLabs Email Security System
 on behalf of the London Business School community.
 For more information please visit http://www.messagelabs.com/email
 __
 
 __
 
 This email has been scanned by the MessageLabs Email Security System
 on behalf of the London Business School community.
 For more information please visit http://www.messagelabs.com/email
 __

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide

[R] Help with assigning a value based on existing numbers

2010-03-26 Thread Jessica Cathro 
Hi All

I have a column/variable called time difference.  It has a whole list of
numbers from 0 through to the hundreds eg 236.  I want to assign a
corresponding name to each variable from a predefined list: Month or
less, 1 -2 months, 2-3 months etc

So the result would look something like:

Time Difference   Month

1  Month or less

365 1-2 years

52   2-3 months

Etc

 

I have tried using if elseif (as shown below), but it kept coming up
with the error:

Error:

In if (curvedata$Date.difference == NULL) { :

  the condition has length  1 and only the first element will be used

2: In if (curvedata$Date.difference = 29) { :

  the condition has length  1 and only the first element will be used

3: In if (curvedata$Date.difference = 59) { :

  the condition has length  1 and only the first element will be used

 

If Else Statement:

month -if (curvedata$Date.difference ==NULL) {Month -0}  ifelse

(curvedata$Date.difference =29) {Month -month or less} else if

(curvedata$Date.difference =59) {Month -1-2 months} else if

(curvedata$Date.difference =89) {Month -2-3 months} else if

(curvedata$Date.difference =119) {Month -3-4 months} else if

(curvedata$Date.difference =149) {Month -4-5 months} else if

(curvedata$Date.difference =179) {Month -5-6 months} else if

(curvedata$Date.difference =209) {Month -6-7 months} else if

(curvedata$Date.difference =239) {Month -7-8 months} else if

(curvedata$Date.difference =269) {Month -8-9 months} else if

(curvedata$Date.difference =299) {Month -9-10 months} else if

(curvedata$Date.difference =329) {Month -10-11 months} else if

(curvedata$Date.difference =359) {Month -11-12 months} else if

(curvedata$Date.difference =719) {Month -1-2 years} else 

{Month -More than 2 years}

 

I'm pretty new to R, so any help would be appreciated.

Thanks

Jessica

_

Jessica Cathro | Business Analyst | Executive Education 
London Business School | Regent's Park | London NW1 4SA | United Kingdom
Switchboard +44 (0)20 7000 7000| Direct line +44 (0)20 7000 7383 |
Email jcat...@london.edu mailto:jcat...@london.edu 

www.london.edu http://www.london.edu/  | London experience. World
impact.


__

This email has been scanned by the MessageLabs Email Security System
on behalf of the London Business School community.
For more information please visit http://www.messagelabs.com/email
__
[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Re: [R] Help with assigning a value based on existing numbers

2010-03-26 Thread sjaffe 

An expression like v = 52, where v is a vector, will produce a vector
resulting from comparing each entry -- that is why you see the message.

What you want to do is logical subscripting.  For example

names - character( nrow( curveData ) )

names[ curvedata$Date.difference = 29  ] =  1 month

etc.

Also, to test for a NULL value do not compare to the string NULL, use the
test operator is.null:

names[ is.null( curvedata$Date.difference ) ] = missing

-- 
View this message in context: 
http://n4.nabble.com/Help-with-assigning-a-value-based-on-existing-numbers-tp1692200p1692321.html
Sent from the R help mailing list archive at Nabble.com.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.