Re: [R] How to subtract the counter i in for loop?
On 30-11-2012, at 07:18, C W wrote:
thanks, Berend. Both of your code works great. Is there a function that can
do it?
Something like this:
x - matrix(NA, nrow=15, ncol=2)
for(i in 1:15){
x[i,] - sample(c(NA, 20, 77), 2, prob=c(0.2, 0.3, 0.4))
}
x
[,1] [,2]
[1,] NA 77
[2,] 77 NA
[3,] NA 77
[4,] 77 20
[5,] 77 20
[6,] 77 20
[7,] 20 NA
[8,] 77 20
[9,] 77 NA
[10,] 77 NA
[11,] 77 20
[12,] 20 77
[13,] NA 77
[14,] 77 20
[15,] 77 20
I want to have a column of 15 samples without NA's. Is there an R function
like ifelse()?
It's not clear what you exactly want.
A matrix with 15 rows and some columns?
How do you want to remove the NA's in each column?
Then why don't you leave out the NA in the sample?
Berend
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[R] How to subtract the counter i in for loop?
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think the i
in else is not getting subtracted. How should I get it to work?
Thanks,
Mike
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Re: [R] How to subtract the counter i in for loop?
Mike,
Based on this example, what do you want
samples
to look like?
It's not clear to me what you're trying to do with
i-1
Jean
C W tmrs...@gmail.com wrote on 11/29/2012 03:55:12 PM:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think the
i
in else is not getting subtracted. How should I get it to work?
Thanks,
Mike
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
Use a while loop instead of a for loop. I don't think what you have coded makes
any sense, but fighting the for loop over control of the indexing variable is a
recipe for failure.
---
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DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
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C W tmrs...@gmail.com wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think
the i
in else is not getting subtracted. How should I get it to work?
Thanks,
Mike
[[alternative HTML version deleted]]
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
On Nov 29, 2012, at 1:55 PM, C W wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
If you expected the else clause to assign something to the samples vector, you
are mistaken.
}
}
The problem is that the returning vector still contains NA, I think the i
in else is not getting subtracted. How should I get it to work?
You could start by telling us what you wanted to happen. You can change the
index of a for loop inside the body, but it will not back up the process
since at the end of the loop the next i will not depend on what you changed
it to inside the loop.
--
David Winsemius, MD
Alameda, CA, USA
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
Hi Jean,
I am going through vector x, if it is less than 200, fill it into samples.
I am having trouble with indexing x.
For example,
samples -rep(NA, 10)
at i=2
x[2], 225200 is not true; and samples[2] remains NA.
The loop continues to i=3, leaving x[2]=NA. I don't want that to happen, I
want to fill up x[2] with value, in our case it's 111.
Mike
On Thu, Nov 29, 2012 at 5:39 PM, Jean V Adams jvad...@usgs.gov wrote:
Mike,
Based on this example, what do you want
samples
to look like?
It's not clear to me what you're trying to do with
i-1
Jean
C W tmrs...@gmail.com wrote on 11/29/2012 03:55:12 PM:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think the
i
in else is not getting subtracted. How should I get it to work?
Thanks,
Mike
[[alternative HTML version deleted]]
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
I want to fill up vector a with vector b. The condition is: b200,
otherwise don't fill it up.
Mike
On Thu, Nov 29, 2012 at 6:11 PM, David Winsemius dwinsem...@comcast.netwrote:
On Nov 29, 2012, at 1:55 PM, C W wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
If you expected the else clause to assign something to the samples vector,
you are mistaken.
}
}
The problem is that the returning vector still contains NA, I think the
i
in else is not getting subtracted. How should I get it to work?
You could start by telling us what you wanted to happen. You can change
the index of a for loop inside the body, but it will not back up the
process since at the end of the loop the next i will not depend on what
you changed it to inside the loop.
--
David Winsemius, MD
Alameda, CA, USA
[[alternative HTML version deleted]]
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
Mike,
I'm still not sure what you want
samples
to look like, but here are a couple possibilities, using a different x.
library(zoo)
x - c(50, 250, 100, 300, 300, 20, 40, 800)
samples1 - ifelse(x200, x, NA)
samples2 - na.locf(samples1)
samples3 - samples1[!is.na(samples1)]
samples1
samples2
samples3
samples1
[1] 50 NA 100 NA NA 20 40 NA
samples2
[1] 50 50 100 100 100 20 40 40
samples3
[1] 50 100 20 40
Jean
C W tmrs...@gmail.com wrote on 11/29/2012 05:16:49 PM:
Hi Jean,
I am going through vector x, if it is less than 200, fill it into
samples.
I am having trouble with indexing x.
For example,
samples -rep(NA, 10)
at i=2
x[2], 225200 is not true; and samples[2] remains NA.
The loop continues to i=3, leaving x[2]=NA. I don't want that to
happen, I want to fill up x[2] with value, in our case it's 111.
Mike
On Thu, Nov 29, 2012 at 5:39 PM, Jean V Adams jvad...@usgs.gov wrote:
Mike,
Based on this example, what do you want
samples
to look like?
It's not clear to me what you're trying to do with
i-1
Jean
C W tmrs...@gmail.com wrote on 11/29/2012 03:55:12 PM:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think
the i
in else is not getting subtracted. How should I get it to work?
Thanks,
Mike
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
On Nov 29, 2012, at 3:25 PM, C W wrote:
I want to fill up vector a with vector b.
Vector a? Vector b?
The condition is: b200, otherwise don't fill it up.
That would seem to be the current behavior, subject of course to an agreed upon
definition for filling up.
It's possible , even likely, that you can get what you want with no loop at
all.
samples[ x 200 ] - x[ x 200 ]
--
David.
Mike
On Thu, Nov 29, 2012 at 6:11 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Nov 29, 2012, at 1:55 PM, C W wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
If you expected the else clause to assign something to the samples vector,
you are mistaken.
}
}
The problem is that the returning vector still contains NA, I think the i
in else is not getting subtracted. How should I get it to work?
You could start by telling us what you wanted to happen. You can change the
index of a for loop inside the body, but it will not back up the process
since at the end of the loop the next i will not depend on what you changed
it to inside the loop.
--
David Winsemius, MD
Alameda, CA, USA
David Winsemius, MD
Alameda, CA, USA
[[alternative HTML version deleted]]
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
David,
Your results is,
samples
[1] 111 NA 111 NA 111 NA 111 NA 111 NA
It still has NA's in it. I want it look like this,
samples
[1] 111 111 111 111 111
thanks,
Mike
On Thu, Nov 29, 2012 at 7:55 PM, David Winsemius dwinsem...@comcast.netwrote:
On Nov 29, 2012, at 3:25 PM, C W wrote:
I want to fill up vector a with vector b.
Vector a? Vector b?
The condition is: b200, otherwise don't fill it up.
That would seem to be the current behavior, subject of course to an agreed
upon definition for filling up.
It's possible , even likely, that you can get what you want with no loop
at all.
samples[ x 200 ] - x[ x 200 ]
--
David.
Mike
On Thu, Nov 29, 2012 at 6:11 PM, David Winsemius
dwinsem...@comcast.netwrote:
On Nov 29, 2012, at 1:55 PM, C W wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
If you expected the else clause to assign something to the samples
vector, you are mistaken.
}
}
The problem is that the returning vector still contains NA, I think
the i
in else is not getting subtracted. How should I get it to work?
You could start by telling us what you wanted to happen. You can change
the index of a for loop inside the body, but it will not back up the
process since at the end of the loop the next i will not depend on what
you changed it to inside the loop.
--
David Winsemius, MD
Alameda, CA, USA
David Winsemius, MD
Alameda, CA, USA
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to subtract the counter i in for loop?
On 30-11-2012, at 05:47, C W wrote:
David,
Your results is,
samples
[1] 111 NA 111 NA 111 NA 111 NA 111 NA
It still has NA's in it. I want it look like this,
samples
[1] 111 111 111 111 111
You don't need the for loop at all.
samples - x[x200]
or
samples - x[which(x200)]
Your for loop should look something like this
k - 1
for(i in 1:10){
if(x[i]200){
samples[k] - x[i]
k - k+1
}
}
na.omit(samples)
Berend
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Re: [R] How to subtract the counter i in for loop?
thanks, Berend. Both of your code works great. Is there a function that
can do it?
Something like this:
x - matrix(NA, nrow=15, ncol=2)
for(i in 1:15){
x[i,] - sample(c(NA, 20, 77), 2, prob=c(0.2, 0.3, 0.4))
}
x
[,1] [,2]
[1,] NA 77
[2,] 77 NA
[3,] NA 77
[4,] 77 20
[5,] 77 20
[6,] 77 20
[7,] 20 NA
[8,] 77 20
[9,] 77 NA
[10,] 77 NA
[11,] 77 20
[12,] 20 77
[13,] NA 77
[14,] 77 20
[15,] 77 20
I want to have a column of 15 samples without NA's. Is there an R function
like ifelse()?
Mike
On Fri, Nov 30, 2012 at 12:24 AM, Berend Hasselman b...@xs4all.nl wrote:
On 30-11-2012, at 05:47, C W wrote:
David,
Your results is,
samples
[1] 111 NA 111 NA 111 NA 111 NA 111 NA
It still has NA's in it. I want it look like this,
samples
[1] 111 111 111 111 111
You don't need the for loop at all.
samples - x[x200]
or
samples - x[which(x200)]
Your for loop should look something like this
k - 1
for(i in 1:10){
if(x[i]200){
samples[k] - x[i]
k - k+1
}
}
na.omit(samples)
Berend
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