Re: [R] Odp: Help me with prediction in linear model

2010-07-26 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 24.07.2010 11:48:11:

 
 Thanks Murphy and pikal,
 
 I need another help,for fitting first fourier transformation ,i used
 following thing .Please advise on this
 
 
 beer_monthl has 400+ records
 
 EXample:
  head(beer_monthly)
   beer
 1 93.2
 2 96.0
 3 95.2
 4 77.1
 5 70.9
 6 64.8
 
 
 
 
 time-seq(1956,1995.2,length=length(beer_monthly))

Even this is not working

time-seq(1956,1995.2,length=length(beer_monthly))
Error in seq.default(1956, 1995.2, length = length(beer_monthly)) : 
  object 'beer_monthly' not found

 sin.t-sin(2*pi*time)
 cos.t-cos(2*pi*time)
 beer_fit_fourier=lm(beer_monthly[,1]~poly(time,2)+sin.t+cos.t) #this is 
not
 working

gives me result without error

 beer_fit_fourier=lm(beer_monthly[,1]~time+time2+sin.t+cos.t) #it is 
working
 
 
 #prediction is not workinng
 
 tpred_four - data.frame(time = seq(1995, 1998, length = 20))
 predict(beer_fit_fourier, newdata = tpred_four)
 

You'd rather read some documentation about lm and predict. You do not have 
variables sin.t and cos.t in your newdata.

Please do read docs, posting guide and provide reproducible example.

 Is there any way to fit first fourier  frequency ,
 
 Please assist.
 
 Thanks in advance
 
 
 
 
 
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 and provide commented, minimal, self-contained, reproducible code.

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Re: [R] Odp: Help me with prediction in linear model

2010-07-24 Thread Research student

Thanks Murphy and pikal,

I need another help,for fitting first fourier transformation ,i used
following thing .Please advise on this


beer_monthl has 400+ records

EXample:
 head(beer_monthly)
  beer
1 93.2
2 96.0
3 95.2
4 77.1
5 70.9
6 64.8




time-seq(1956,1995.2,length=length(beer_monthly))
sin.t-sin(2*pi*time)
cos.t-cos(2*pi*time)
beer_fit_fourier=lm(beer_monthly[,1]~poly(time,2)+sin.t+cos.t) #this is not
working
beer_fit_fourier=lm(beer_monthly[,1]~time+time2+sin.t+cos.t) #it is working


#prediction is not workinng

tpred_four - data.frame(time = seq(1995, 1998, length = 20))
predict(beer_fit_fourier, newdata = tpred_four)

Is there any way to fit first fourier  frequency ,

Please assist.

Thanks in advance





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__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.


[R] Odp: Help me with prediction in linear model

2010-07-22 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 21.07.2010 17:46:02:

 
 Hi R-community,
 I have the code as follows,i Fitted model as follows
 lbeer-log(beer_monthly)
 t-seq(1956,1995.2,length=length(beer_monthly)) #beer_monthly contains 
400+
 entries

not needed
 t2=t^2

 beer_fit_parabola=lm(lbeer~t+t2)

beer_fit_parabola=lm(lbeer~t+I(t^2))

you can use poly(t,2) but coefficients are not directly applicable in 
equation.

 
 Below is not working for me.
 Please help me in preparing the new data set for the below prediction
 
 
 
 
predict(beer_fit_parabola,newdata=data.frame(t=seq(1995,1998,length=20),t2=seq
 (1995,1998,length=20))

predict(beer_fit_parabola,newdata=data.frame(t=seq(1995,1998,length=20))

shall be enough
Regards
Petr


 
 #it is listing all 400+ entries ,but not 20 ahead prediction.
 
 Thanks In advance for your help
 -- 
 View this message in context: 
http://r.789695.n4.nabble.com/Help-me-with-
 prediction-in-linear-model-tp2297313p2297313.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.