Re: [R] Problem reading dates from Excel

2013-02-08 Thread David Winsemius

On Feb 8, 2013, at 10:55 AM, Edwin Isensee wrote:

 I'm using the read.xls function from gdata package to read one Excel file,
 like the example below:
 
 library(gdata)
 my_file - '/Users/Desktop/Project.xlsx'
 valores - read.xls(my_file)
 
 The problem is: one of the columns at the Excel file holds date information
 like 1-Jan-13, 5-Jan-13, 25-Jan-13.

Actually it holds them as number of days and only displayes themin htat format.


 At Excel these information are treated
 as dates. When I read the file into a dataframe the corresponding data
 frame column holds numeric information like 41275, 41279, 41299. How can I
 convert these numeric information into the original date information?

The easiest way would be to create a format in Excel. -mm-dd should work 
well. Otherwise you should read the documentation about date encoding. You can 
take those values and add them to something like:  as.Date(1900-01-01). I say 
something like because Excel date calculations have always had a strange bug 
that MS  refuses to acknowledge or fix that may make the date one or two days 
more or  less.

  as.Date(1900-01-01) +c( 41275, 41279, 41299)
 [1] 2013-01-03 2013-01-07 2013-01-27

 Thanks,
 Edwin
 
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David Winsemius
Alameda, CA, USA

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Re: [R] Problem reading dates from Excel

2013-02-08 Thread Ben Bolker
David Winsemius dwinsemius at comcast.net writes:

 On Feb 8, 2013, at 10:55 AM, Edwin Isensee wrote:
 
  I'm using the read.xls function from gdata package to read one Excel file,
  like the example below:
  
  library(gdata)
  my_file - '/Users/Desktop/Project.xlsx'
  valores - read.xls(my_file)
  
  The problem is: one of the columns at the Excel file holds date information
  like 1-Jan-13, 5-Jan-13, 25-Jan-13.
 
 Actually it holds them as number of days and only displays them in
  that format.
 
  At Excel these information are treated
  as dates. When I read the file into a dataframe the corresponding data
  frame column holds numeric information like 41275, 41279, 41299. How can I
  convert these numeric information into the original date information?

 The easiest way would be to create a format in Excel. -mm-dd
 should work well. Otherwise you should read the documentation about
 date encoding. You can take those values and add them to something
 like: as.Date(1900-01-01). I say something like because Excel
 date calculations have always had a strange bug that MS refuses to
 acknowledge or fix that may make the date one or two days more or
 less.

   as.Date(1900-01-01) +c( 41275, 41279, 41299)
  [1] 2013-01-03 2013-01-07 2013-01-27
 

 The HFWutils package, now archived, had a function that
did this.  I extracted just that function: below I also
post some information about where (I think) the
Excel date bug referred to above comes from -- an
interesting historical story.
  If you are using dates before Feb 1900, watch out (and
read below)!

## from http://cran.r-project.org/src/contrib/Archive/
## HFWutils/HFWutils_0.9.2008.05.17.tar.gz

excelDate2Date - function(excelDate) {
Date - excelDate + as.Date(1900-01-01) - 2
## FIXME: add if 1900-Feb-28 switch?
return(Date)
}

## http://www.cpearson.com/excel/datetime.htm
## Dates

## The integer portion of the number, d, represents the number of
## days since 1900-Jan-0.  For example, the date 19-Jan-2000 is stored
## as 36,544, since 36,544 days have passed since 1900-Jan-0.  The
## number 1 represents 1900-Jan-1.  It should be noted that the number
## 0 does not represent 1899-Dec-31.  It does not. If you use the
## MONTH function with the date 0, it will return January, not
## December.  Moreover, the YEAR function will return 1900, not 1899.

## Actually, this number is one greater than the actual number of
## days.  This is because Excel behaves as if the date 1900-Feb-29
## existed.  It did not.  The year 1900 was not a leap year (the year
## 2000 is a leap year).  In Excel, the day after 1900-Feb-28 is
## 1900-Feb-29.  In reality, the day after 1900-Feb-28 was 1900-Mar-1.
## This is not a bug.  Indeed, it is by design.  Excel works this
## way because it was truly a bug in Lotus 123.  When Excel was
## introduced, 123 has nearly the entire market for spreadsheet
## software.  Microsoft decided to continue Lotus' bug, in order to
## fully compatible.  Users who switched from 123 to Excel would not
## have to make any changes to their data.  As long as all your dates
## later than 1900-Mar-1, this should be of no concern.

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Re: [R] Problem reading dates from Excel

2013-02-08 Thread Orvalho Augusto
I do not promise much. But try to use XLConnect package. It requires rJava
package which requires java on your system.

Good luck
Orvalho

On Fri, Feb 8, 2013 at 8:55 PM, Edwin Isensee edwin.isen...@gmail.comwrote:

 I'm using the read.xls function from gdata package to read one Excel file,
 like the example below:

 library(gdata)
 my_file - '/Users/Desktop/Project.xlsx'
 valores - read.xls(my_file)

 The problem is: one of the columns at the Excel file holds date information
 like 1-Jan-13, 5-Jan-13, 25-Jan-13. At Excel these information are treated
 as dates. When I read the file into a dataframe the corresponding data
 frame column holds numeric information like 41275, 41279, 41299. How can I
 convert these numeric information into the original date information?

 Thanks,
 Edwin

 [[alternative HTML version deleted]]

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


[[alternative HTML version deleted]]

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