[R] Question on list object
Dear all, let say, I have following list object: listObj - vector(list, length = 3) listObj[[1]] - rnorm(3) listObj[[2]] - rnorm(4) listObj[[3]] - rnorm(5) Now I want to convert above list into a Matrix. Ofcourse I can do it using Reduce(rbind, listObj). However as you notice that as elements of that list are arbitrary length vectors, I cant use this trick. What I want is to have a matrix with 3x5 dimension, where the remaining element of each row with be filled with NA, i.e I want : rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) Is there any better way on how I can do that more directly? Thanks and regards, [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Question on list object
Hi Christofer, You might try sapply(listObj, function(l) l[1:max(sapply(listObj, length))] ) HTH, Jorge On Wed, Apr 27, 2011 at 1:23 PM, Bogaso Christofer wrote: Dear all, let say, I have following list object: listObj - vector(list, length = 3) listObj[[1]] - rnorm(3) listObj[[2]] - rnorm(4) listObj[[3]] - rnorm(5) Now I want to convert above list into a Matrix. Ofcourse I can do it using Reduce(rbind, listObj). However as you notice that as elements of that list are arbitrary length vectors, I cant use this trick. What I want is to have a matrix with 3x5 dimension, where the remaining element of each row with be filled with NA, i.e I want : rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) Is there any better way on how I can do that more directly? Thanks and regards, [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Question on list object
Here's one way:
uselen = max(sapply(listObj,length))
do.call(rbind,lapply(listObj,function(x){length(x) = uselen;x}))
[,1] [,2] [,3] [,4] [,5]
[1,] 0.0702225 -1.143031 1.6437560 NANA
[2,] -0.6100869 2.657910 -0.6028418 -0.7739858NA
[3,] -2.5787357 1.381395 -1.6545857 0.8239982 -1.169961
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Wed, 27 Apr 2011, Bogaso Christofer wrote:
Dear all, let say, I have following list object:
listObj - vector(list, length = 3)
listObj[[1]] - rnorm(3)
listObj[[2]] - rnorm(4)
listObj[[3]] - rnorm(5)
Now I want to convert above list into a Matrix. Ofcourse I can do it using
Reduce(rbind, listObj). However as you notice that as elements of that
list are arbitrary length vectors, I cant use this trick. What I want is to
have a matrix with 3x5 dimension, where the remaining element of each row
with be filled with NA, i.e I want :
rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]])
Is there any better way on how I can do that more directly?
Thanks and regards,
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Question on list object
Try this: sapply(listObj, '[', 1:max(sapply(listObj, length))) On Wed, Apr 27, 2011 at 2:23 PM, Bogaso Christofer bogaso.christo...@gmail.com wrote: Dear all, let say, I have following list object: listObj - vector(list, length = 3) listObj[[1]] - rnorm(3) listObj[[2]] - rnorm(4) listObj[[3]] - rnorm(5) Now I want to convert above list into a Matrix. Ofcourse I can do it using Reduce(rbind, listObj). However as you notice that as elements of that list are arbitrary length vectors, I cant use this trick. What I want is to have a matrix with 3x5 dimension, where the remaining element of each row with be filled with NA, i.e I want : rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) Is there any better way on how I can do that more directly? Thanks and regards, [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
