Re: [R] Replace NA's with value in the next row
On 11/14/2013 04:02 PM, dila radi wrote: Hi all, I have a data set which treat missing value as NA and now I need to replace all these NA's by using number in the same row but different column. Here is the part of my data: V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145 I want to replace (V6, 6) with (V7, 6). I have about 1000 NA's in V6 which I want to replace with the same row in V7. The other values in V6, I want to keep remain the same. How to achieve this? Assuming my data is called Targetstation, I have tried this: Targetstation- within(Targetstation, v6- replace(v6, is.na(v6), v7[is.na (v6)])) But R gives me this: Warning messages: 1: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' 2: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' Hi Dila, You could do this like this: V6NA-is.na(Targetstation$V6) Targetstation$V6[V6NA]-Targetstation$V7[V6NA] but if you want to use the above, I think you will have to replace the is.na(V6) with is.na(Targetstation$V6) or use the method above. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Replace NA's with value in the next row
R purists forbid the use of the for loop, but I am afraid this is the most simple solution: for (i in 1:(length(V6)-1)) if(is.na(V6[i])) V6[i]-V6[i+1] 2013/11/14 Jim Lemon j...@bitwrit.com.au On 11/14/2013 04:02 PM, dila radi wrote: Hi all, I have a data set which treat missing value as NA and now I need to replace all these NA's by using number in the same row but different column. Here is the part of my data: V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145 I want to replace (V6, 6) with (V7, 6). I have about 1000 NA's in V6 which I want to replace with the same row in V7. The other values in V6, I want to keep remain the same. How to achieve this? Assuming my data is called Targetstation, I have tried this: Targetstation- within(Targetstation, v6- replace(v6, is.na(v6), v7[ is.na (v6)])) But R gives me this: Warning messages: 1: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' 2: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' Hi Dila, You could do this like this: V6NA-is.na(Targetstation$V6) Targetstation$V6[V6NA]-Targetstation$V7[V6NA] but if you want to use the above, I think you will have to replace the is.na(V6) with is.na(Targetstation$V6) or use the method above. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/ posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- --- dr F.H.G. (Frans) Marcelissen DigiPsy (www.DigiPsy.nl http://www.digipsy.nl/) Pomperschans 26 5595 AV Leende tel: 040 2065030/06 2325 06 53 skype adres: frans.marcelissen email: frans.marcelis...@digipsy.nl [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Replace NA's with value in the next row
On Thu, Nov 14, 2013 at 1:13 AM, Frans Marcelissen frans.marcelis...@digipsy.nl wrote: R purists forbid the use of the for loop, That is utter nonsense. Please do not make such statements when you have no idea what you're talking about. It just promulgates confusion. -- Bert simple solution: for (i in 1:(length(V6)-1)) if(is.na(V6[i])) V6[i]-V6[i+1] 2013/11/14 Jim Lemon j...@bitwrit.com.au On 11/14/2013 04:02 PM, dila radi wrote: Hi all, I have a data set which treat missing value as NA and now I need to replace all these NA's by using number in the same row but different column. Here is the part of my data: V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145 I want to replace (V6, 6) with (V7, 6). I have about 1000 NA's in V6 which I want to replace with the same row in V7. The other values in V6, I want to keep remain the same. How to achieve this? Assuming my data is called Targetstation, I have tried this: Targetstation- within(Targetstation, v6- replace(v6, is.na(v6), v7[ is.na (v6)])) But R gives me this: Warning messages: 1: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' 2: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' Hi Dila, You could do this like this: V6NA-is.na(Targetstation$V6) Targetstation$V6[V6NA]-Targetstation$V7[V6NA] but if you want to use the above, I think you will have to replace the is.na(V6) with is.na(Targetstation$V6) or use the method above. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/ posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- --- dr F.H.G. (Frans) Marcelissen DigiPsy (www.DigiPsy.nl http://www.digipsy.nl/) Pomperschans 26 5595 AV Leende tel: 040 2065030/06 2325 06 53 skype adres: frans.marcelissen email: frans.marcelis...@digipsy.nl [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Replace NA's with value in the next row
Hi, I think you used a column that doesn't exist in the dataset. Targetstation - read.table(text=V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145,sep=,header=TRUE) within(Targetstation, V6 - replace(V6,is.na(V6),V7[is.na(V6)])) V1 V2 V3 V4 V5 V6 V7 1 0 0.0 0.0 1.2 0.0 0.000 0.259 2 0 0.0 12.8 0.0 23.7 0.000 8.495 3 6 0.0 81.7 0.2 0.0 20.000 19.937 4 0 1.5 60.9 0.0 0.0 15.500 13.900 5 1 13.0 56.8 17.5 32.8 6.400 27.654 6 4 3.0 66.4 2.0 0.3 17.145 17.145 #if you use: !is.na(Targetstation$v6) #'v6' and 'V6' are different logical(0) Warning message: In is.na(Targetstation$v6) : is.na() applied to non-(list or vector) of type 'NULL' A.K. On Thursday, November 14, 2013 2:26 AM, dila radi dilarad...@gmail.com wrote: Hi all, I have a data set which treat missing value as NA and now I need to replace all these NA's by using number in the same row but different column. Here is the part of my data: V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145 I want to replace (V6, 6) with (V7, 6). I have about 1000 NA's in V6 which I want to replace with the same row in V7. The other values in V6, I want to keep remain the same. How to achieve this? Assuming my data is called Targetstation, I have tried this: Targetstation - within(Targetstation, v6 - replace(v6, is.na(v6), v7[is.na (v6)])) But R gives me this: Warning messages: 1: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' 2: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' How to solve this? Thank you in advance. Regards, Dila. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Replace NA's with value in the next row
Hi all, I have a data set which treat missing value as NA and now I need to replace all these NA's by using number in the same row but different column. Here is the part of my data: V1 V2 V3 V4 V5 V6 V7 0 0 0 1.2 0 0 0.259 0 0 12.8 0 23.7 0 8.495 6 0 81.7 0.2 0 20 19.937 0 1.5 60.9 0 0 15.5 13.900 1 13 56.8 17.5 32.8 6.4 27.654 4 3 66.4 2 0.3 NA 17.145 I want to replace (V6, 6) with (V7, 6). I have about 1000 NA's in V6 which I want to replace with the same row in V7. The other values in V6, I want to keep remain the same. How to achieve this? Assuming my data is called Targetstation, I have tried this: Targetstation - within(Targetstation, v6 - replace(v6, is.na(v6), v7[is.na (v6)])) But R gives me this: Warning messages: 1: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' 2: In is.na(v6) : is.na() applied to non-(list or vector) of type 'NULL' How to solve this? Thank you in advance. Regards, Dila. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
