I don't know if you have factors in your data frame, but in any case,
you can try the following approach:
mydata - data.frame(id = 1:10, x = rnorm(10, 80),
z = rnorm(10, 80), w = gl(2, 5))
mydata
f - function (x) {
if (is.numeric(x))
x[x 80] - NA
x
}
mydata[-1] - lapply(mydata[-1], f)
mydata
I hope it helps.
Best,
Dimitris
On 6/20/2011 10:40 AM, Chris Beeley wrote:
I am using the following command to replace all the missing values and
assorted typos in a dataframe with NA:
mydata[mydata80]=NA
The problem is that the first column contains values which should be
more than 80, so really I want to do it just for
mydata[,2:length(mydata)]
I can't seem to re-write the code to fit:
mydata[,2:length(mydata)80]=NA # no error message, but doesn't work-
doesn't do anything, it would seem
I realise I can just keep the first column somewhere safe and copy it
back again when I'm done, but I wondered if there was a more elegant
solution, which would be much more important, if say I just wanted to
replace the odd columns, or something like that.
I found this code on the internet too:
idx- which(foo80, arr.ind=TRUE)
foo[idx[1], idx[2]]- NA
But I can't seem to rewrite that either, for the same reason
Many thanks!
Chris Beeley
Institute of Mental Health
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--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
Web: http://www.erasmusmc.nl/biostatistiek/
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and provide commented, minimal, self-contained, reproducible code.
