Re: [R] Simulating distribution of max of two die

2011-08-31 Thread Greg Snow
For this example you can work out every possibility, you can use this in place 
(or in addition to) the simulations.  Here is a quick example with a couple 
other ways to look at what is happening:

all.rolls - expand.grid(1:6,1:6)
max.roll - apply(all.rolls, 1, max)
round(prop.table(table(max.roll)),3)

library(MASS)
fractions( prop.table(table(max.roll)))

print( paste(table(max.roll),'/36',sep=''), quote=FALSE )

library(TeachingDemos)
plot.dice( expand.grid(1:6,1:6), layout=c(6,6) )



-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
 project.org] On Behalf Of Jaap van Wyk
 Sent: Monday, August 29, 2011 9:57 PM
 To: r-help@r-project.org
 Subject: [R] Simulating distribution of max of two die
 
 Hallo
 
 I am teaching a very elementary intro course about R, and want to show
 the students how to find the distribution of the maximum of rolling
 two balanced die. Is there perhaps a more elegant way to do this,
 other than the way I am using below? (I would like to show them two
 ways - the one shown here, and perhaps and improved/elegant approach
 (showing off the beauty of R.
 My code is as follows:
 
 R n - 2
 R d1 - sample(1:6, n, replace=TRUE)
 R d2 - sample(1:6, n, replace=TRUE)
 R d - apply(matrix(c(d1,d2), nrow=n, byrow=TRUE), 1, max)
 R round(table(d)/n, 3)
 d
  1 2 3 4 5 6
 0.030 0.084 0.137 0.195 0.246 0.308
 
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Re: [R] Simulating distribution of max of two die

2011-08-30 Thread S Ellison
 

 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of Jaap van Wyk
 Sent: 30 August 2011 04:57
 To: r-help@r-project.org
 Subject: [R] Simulating distribution of max of two die

  how to find the distribution of the 
 maximum of rolling two balanced die. Is there perhaps a more 
 elegant way to do this, other than the way I am using below? 

#Perhaps
dice - matrix(sample(1:6, 4,replace=T), ncol=2)
dice.max - apply(dice, 1, max)
barplot(table(dice.max)) 

#and just for interest
mids-barplot(table(dice.max)/length(dice.max)) #gives proportions
all.pairs - expand.grid(1:6, 1:6)
dice.max.exact - apply(all.pairs, 1, max)

points(mids, table(dice.max.exact)/36, pch=_, cex=2, col=2)


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[R] Simulating distribution of max of two die

2011-08-29 Thread Jaap van Wyk

Hallo

I am teaching a very elementary intro course about R, and want to show  
the students how to find the distribution of the maximum of rolling  
two balanced die. Is there perhaps a more elegant way to do this,  
other than the way I am using below? (I would like to show them two  
ways - the one shown here, and perhaps and improved/elegant approach  
(showing off the beauty of R.

My code is as follows:

R n - 2
R d1 - sample(1:6, n, replace=TRUE)
R d2 - sample(1:6, n, replace=TRUE)
R d - apply(matrix(c(d1,d2), nrow=n, byrow=TRUE), 1, max)
R round(table(d)/n, 3)
d
1 2 3 4 5 6
0.030 0.084 0.137 0.195 0.246 0.308

__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Simulating distribution of max of two die

2011-08-29 Thread Jeff Newmiller
Why not

d - ifelse( d1  d2, d1, d2 )

or

d - pmax( d1, d2 )

?

Apply operations may seem beautiful, but I think the speed and simplicity of 
vectorized operations are truly beautiful.
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
--- 
Sent from my phone. Please excuse my brevity.

Jaap van Wyk j.van...@ru.ac.za wrote:

Hallo

I am teaching a very elementary intro course about R, and want to show 
the students how to find the distribution of the maximum of rolling 
two balanced die. Is there perhaps a more elegant way to do this, 
other than the way I am using below? (I would like to show them two 
ways - the one shown here, and perhaps and improved/elegant approach 
(showing off the beauty of R.
My code is as follows:

R n - 2
R d1 - sample(1:6, n, replace=TRUE)
R d2 - sample(1:6, n, replace=TRUE)
R d - apply(matrix(c(d1,d2), nrow=n, byrow=TRUE), 1, max)
R round(table(d)/n, 3)
d
1 2 3 4 5 6
0.030 0.084 0.137 0.195 0.246 0.308

_

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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.