It's because those are character strings and they are sorted lexically
(i.e., alphabetically). I think you probably can get what you prefer
by using the mixedsort/mixedorder functions of the gtools package.
Take a look at this
x - paste0(data,1:100, .fit)
order(x)
sort(x)
library(gtools)
mixedorder(x)
mixedsort(x)
Best,
Michael
On Mon, May 28, 2012 at 10:06 AM, sam84 samiye...@yahoo.co.uk wrote:
The code given below worked well. However, the problem is that when I typed
dir1 to see the results I found that R order the files as:
[1] data1.flt data10.flt data100.flt data101.flt
[5] data102.flt data103.flt data104.flt data105.flt
[9] data106.flt data107.flt data108.flt data109.flt
[13] data11.flt data110.flt data111.flt data112.flt
[17] data113.flt data114.flt data115.flt data116.flt
.
.
to
.
.
[357] data91.flt data92.flt data93.flt data94.flt
[361] data95.flt data96.flt data97.flt data98.flt
[365] data99.flt
which will lead to wrong results.
How to tell R to start reading from 1 to 365 in order.
something like :
[1] data1.flt data2.flt data3.flt data4.flt
not like:
[1] data1.flt data10.flt data100.flt data101.flt
Here is the code:
dir1- list.files(C:\\Users\\Amin\\Desktop\\2001, *.flt, full.names =
TRUE)
results- list()
for (.files in seq_along(dir1)){
file2 - readBin(dir2[.files], double(), size = 4, n = w * 67420,
signed = TRUE)
results[[length(results) + 1L]]- file1[file1 != -]*10}
for (i in seq_along(results)){
fileName - sprintf(C:\\Users\\aalyaari\\Desktop\\New folder
(2)\\NewFile%03d.bin, i)
writeBin(as.integer(results[[i]]), fileName, size = 2)}
--
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and provide commented, minimal, self-contained, reproducible code.
