Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Vito Muggeo (UniPa)
Sent: Monday, October 25, 2010 9:16 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] building lme call via call()
dear all,
I would like to get the lme call without fitting the relevant model.
library(nlme)
data(Orthodont)
fm1 - lme(distance ~ age, random=list(Subject=~age),data = Orthodont)
To get fm1$call without fitting the model I use call():
my.cc-call(lme.formula, fixed= distance ~ age, random =
list(Subject
= ~age))
However the two calls are not the same (apart from the data
argument I
am not interested in), as call() *does* evaluate the arguments:
my.cc$random
$Subject
~age
You can use quote() to avoid the evaluations. E.g.,
better.cc - call(lme.formula,
+ fixed=quote(distance~age),
+ data=quote(Orthodont),
+ random=quote(list(Subject=~age)))
identical(better.cc, fm1$call)
[1] TRUE
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
fm1$call$random
list(Subject = ~age)
How is it possible to get the right call (similar to the one from
fm1$call) by means of call()?
thanks,
vito
--
Vito M.R. Muggeo
Dip.to Sc Statist e Matem `Vianelli'
Università di Palermo
viale delle Scienze, edificio 13
90128 Palermo - ITALY
tel: 091 23895240
fax: 091 485726/485612
http://dssm.unipa.it/vmuggeo
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
