Hi,
I guess you meant this:
dat2- read.table(text=
patient_id t scores
1 0 1.6
1 1 2.6
1 2 2.2
1 3 1.8
2 0 2.3
2 2 2.5
2 4 2.6
2 5 1.5
3 0 1.2
4 0 1.3
4 1 1.8
,sep=,header=TRUE)
library(plyr)
dat2New-ddply(dat2,.(patient_id),summarize,t=seq(min(t),max(t)))
res-join(dat2New,dat2,type=full)
lst1-lapply(split(res,res$patient_id),function(x)
{x1-x[x$t!=0,];do.call(rbind,lapply(split(x1,((x1$t-1)%/%3)+1),function(y)
{y1-if(any(y$t==1)) rbind(x[x$t==0,],y) else y;
data.frame(patient_id=unique(y1$patient_id),t=head(y1$t,1),scores=mean(y1$scores,na.rm=TRUE))})
) })
lst1[lapply(lst1,length)==0]-lapply(lst1[lapply(lst1,length)==0],function(x)
x- dat2[unlist(with(dat2,tapply(t,patient_id,FUN=function(x) x==0
length(x)==1)),use.names=FALSE),])
res1-do.call(rbind,lst1)
row.names(res1)- 1:nrow(res1)
res2- res1[,-2]
res2$period-with(res2,ave(patient_id,patient_id,FUN=seq_along))
res2
# patient_id scores period
#1 1 2.05 1
#2 2 2.40 1
#3 2 2.05 2
#4 3 1.20 1
#5 4 1.55 1
A.K.
From: GUANGUAN LUO guanguan...@gmail.com
To: arun smartpink...@yahoo.com
Sent: Wednesday, May 22, 2013 5:42 AM
Subject: calcul of the mean in a period of time
Hello, AK, This is the code zhich you have written.
dat2- read.table(text=
patient_id t scores
1 0 1.6
1 1 2.6
1 2 2.2
1 3 1.8
2 0 2.3
2 2 2.5
2 4 2.6
2 5 1.5
,sep=,header=TRUE)
library(plyr)
dat2New-ddply(dat2,.(
patient_id),summarize,t=seq(min(t),max(t)))
res-join(dat2New,dat2,type=full)
res1-do.call(rbind,lapply(split(res,res$patient_id),function(x)
{x1-x[x$t!=0,];do.call(rbind,lapply(split(x1,((x1$t-1)%/%3)+1),function(y)
{y1-if(any(y$t==1)) rbind(x[x$t==0,],y) else y;
data.frame(patient_id=unique(y1$patient_id),scores=mean(y1$scores,na.rm=TRUE))})
) }))
row.names(res1)-1:nrow(res1)
res1$period-with(res1,ave(patient_id,patient_id,FUN=seq))
res1
# patient_id scores period
#1 1 2.05 1
#2 2 2.40 1
#3 2 2.05 2
for the same problem, in the case that you have done, you have select the data
x[t!=0], if there are some patients who have only one data when t=0, can i
change a little the code so that i can retain the informations when t=0?
That means when the patients have only one score, so i regarde the score of t=0
as the average of period 1 for these patients.
Thank you so much for your help. I have never worked on programming before, so
i really don't understand much for it.
You are really helpful. Thank you so much.
GG
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