[R] cumsum function with data frame
Dear list, I have a problem with the cumsum function. I have a data frame like the following one variableYear value EC01 2005 5 EC01 2006 10 AAO12005 2 AAO1 2006 4 what I would like to obtain is variableYear value cumsum EC01 2005 5 5 EC01 2006 10 15 AAO12005 22 AAO1 2006 46 if I use the by function or the aggregate function the result is a list or something else, what I want is a data frame as I showed above... anyone knows how to get it??? THANKS A LOT [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] cumsum function with data frame
See ?split and ?unsplit.
Data - read.table(textConnection(variableYear value
EC01 2005 5
EC01 2006 10
AAO12005 2
AAO1 2006 4),header=T)
Datalist -split(Data,Data$variable)
resultlist - lapply(Datalist,function(x){
x$cumul - cumsum(x$value)
return(x)
})
result - unsplit(resultlist,Data$variable)
result
variable Year value cumul
1 EC01 2005 5 5
2 EC01 20061015
3 AAO1 2005 2 2
4 AAO1 2006 4 6
On a side note: I've used this construction now for a number of problems.
Some could be better solved using more specific functions (e.g. ave() for
adding a column with means for example). I'm not sure however this is the
most optimal approach to applying a function to subsets of a dataframe and
adding the result of that function as an extra variable. Anybody care to
elaborate on how the R masters had it in mind?
Cheers
Joris
On Thu, Jun 3, 2010 at 5:58 PM, n.via...@libero.it n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I have a data frame like the following one
variableYear value
EC01 2005 5
EC01 2006 10
AAO12005 2
AAO1 2006 4
what I would like to obtain is
variableYear value cumsum
EC01 2005 5 5
EC01 2006 10 15
AAO12005 22
AAO1 2006 46
if I use the by function or the aggregate function the result is a list or
something else, what I want is a data frame as I showed above...
anyone knows how to get it???
THANKS A LOT
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Joris Meys
Statistical Consultant
Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control
Coupure Links 653
B-9000 Gent
tel : +32 9 264 59 87
joris.m...@ugent.be
---
Disclaimer : http://helpdesk.ugent.be/e-maildisclaimer.php
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] cumsum function with data frame
You can also use ddply from the plyr package:
library(plyr)
Data - read.table(textConnection(variable Year value
EC01 2005 5
EC01 2006 10
AAO1 2005 2
AAO1 2006 4),header=T)
Data
ddply(Data,.(variable),summarise,Year=Year,value=value,CUMSUM=cumsum(value))
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish Wildlife Service
California, USA
- Original Message
From: Joris Meys jorism...@gmail.com
To: n.via...@libero.it n.via...@libero.it
Cc: r-help@r-project.org
Sent: Thu, June 3, 2010 9:26:17 AM
Subject: Re: [R] cumsum function with data frame
See ?split and ?unsplit.
Data -
read.table(textConnection(variable Year
value
EC01 2005
5
EC01 2006
10
AAO1
2005 2
AAO1
2006 4),header=T)
Datalist
-split(Data,Data$variable)
resultlist -
lapply(Datalist,function(x){
x$cumul -
cumsum(x$value)
return(x)
})
result -
unsplit(resultlist,Data$variable)
result
variable Year value
cumul
1 EC01 2005 5 5
2
EC01 2006 10 15
3 AAO1
2005 2 2
4 AAO1 2006
4 6
On a side note: I've used this construction now for a
number of problems.
Some could be better solved using more specific functions
(e.g. ave() for
adding a column with means for example). I'm not sure however
this is the
most optimal approach to applying a function to subsets of a
dataframe and
adding the result of that function as an extra variable.
Anybody care to
elaborate on how the R masters had it in
mind?
Cheers
Joris
On Thu, Jun 3, 2010 at 5:58 PM, ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I have a
data frame like the following one
variable
Year value
EC01
2005 5
EC01
2006 10
AAO1 2005
2
AAO1 2006
4
what I would like to obtain is
variable Year value
cumsum
EC01
2005 5
5
EC01
2006 10
15
AAO1
2005 2
2
AAO1
2006 4
6
if I use the by function or the aggregate
function the result is a list or
something else, what I want is a data
frame as I showed above...
anyone knows how to get it???
THANKS
A LOT
[[alternative HTML version deleted]]
__
ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
posting guide
http://www.R-project.org/posting-guide.html
and
provide commented, minimal, self-contained, reproducible
code.
--
Joris Meys
Statistical
Consultant
Ghent University
Faculty of Bioscience
Engineering
Department of Applied mathematics, biometrics and process
control
Coupure Links 653
B-9000 Gent
tel : +32 9 264 59
87
href=mailto:joris.m...@ugent.be;joris.m...@ugent.be
---
Disclaimer
: http://helpdesk.ugent.be/e-maildisclaimer.php
[[alternative HTML version
deleted]]
__
ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org mailing list
href=https://stat.ethz.ch/mailman/listinfo/r-help; target=_blank
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
guide http://www.R-project.org/posting-guide.html
and provide commented,
minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] cumsum function with data frame
Better yet, is shorter using tranform instead of summarise:
Data - read.table(textConnection(variable Year value
EC01 2005 5
EC01 2006 10
AAO1 2005 2
AAO1 2006 4),header=T)
ddply(Data,.(variable),transform,CUMSUM=cumsum(value))
- Original Message
From: Felipe Carrillo mazatlanmex...@yahoo.com
To: Joris Meys jorism...@gmail.com; n.via...@libero.it
n.via...@libero.it
Cc: r-help@r-project.org
Sent: Thu, June 3, 2010 11:28:58 AM
Subject: Re: [R] cumsum function with data frame
You can also use ddply from the plyr package:
library(plyr)
Data -
read.table(textConnection(variable Year value
EC01
2005 5
EC01 2006 10
AAO1 2005
2
AAO1 2006
4),header=T)
Data
ddply(Data,.(variable),summarise,Year=Year,value=value,CUMSUM=cumsum(value))
Felipe
D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US
Fish Wildlife Service
California, USA
- Original
Message
From: Joris Meys ymailto=mailto:jorism...@gmail.com;
href=mailto:jorism...@gmail.com;jorism...@gmail.com
To: ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
Cc: ymailto=mailto:r-help@r-project.org;
href=mailto:r-help@r-project.org;r-help@r-project.org
Sent: Thu,
June 3, 2010 9:26:17 AM
Subject: Re: [R] cumsum function with data
frame
See ?split and ?unsplit.
Data -
read.table(textConnection(variable Year
value
EC01
2005
5
EC01 2006
10
AAO1
2005 2
AAO1
2006
4),header=T)
Datalist
-split(Data,Data$variable)
resultlist -
lapply(Datalist,function(x){
x$cumul -
cumsum(x$value)
return(x)
})
result -
unsplit(resultlist,Data$variable)
result
variable Year value
cumul
1 EC01 2005 5 5
2
EC01 2006 10
15
3 AAO1
2005 2 2
4 AAO1 2006
4
6
On a side note: I've used this construction now for a
number
of problems.
Some could be better solved using more specific functions
(e.g. ave() for
adding a column with means for example). I'm not
sure however
this is the
most optimal approach to applying a
function to subsets of a
dataframe and
adding the result of that
function as an extra variable.
Anybody care to
elaborate on how the
R masters had it in
mind?
Cheers
Joris
On Thu, Jun 3,
2010 at 5:58 PM, ymailto=mailto:
href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I
have a
data frame like the following one
variable
Year value
EC01
2005
5
EC01
2006 10
AAO1 2005
2
AAO1
2006
4
what I would like to obtain is
variable Year value
cumsum
EC01
2005 5
5
EC01
2006 10
15
AAO1
2005 2
2
AAO1
2006 4
6
if I use the by function or the aggregate
function the result is a list or
something else, what I want is
a data
frame as I showed above...
anyone knows how to get
it???
THANKS
A
LOT
[[alternative HTML version deleted]]
__
ymailto=mailto: ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org
href=mailto: href=mailto:R-help@r-project.org;R-help@r-project.org
ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org mailing list
target=_blank https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
do read the
posting guide
http://www.R-project.org/posting-guide.html
and
provide
commented, minimal, self-contained, reproducible
code.
--
Joris Meys
Statistical
Consultant
Ghent University
Faculty of Bioscience
Engineering
Department of Applied mathematics, biometrics and process
control
Coupure Links 653
B-9000 Gent
tel : +32 9 264
59
87
href=mailto: href=mailto:joris.m...@ugent.be;joris.m...@ugent.be
ymailto=mailto:joris.m...@ugent.be;
href=mailto:joris.m...@ugent.be;joris.m...@ugent.be
---
Disclaimer
: http://helpdesk.ugent.be/e-maildisclaimer.php
Re: [R] cumsum function with data frame
Or better yet, you can use transform only (in base):
transform(Data, CUMSUM = cumsum(value))
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:30 PM, Felipe Carrillo wrote:
Better yet, is shorter using tranform instead of summarise:
Data - read.table(textConnection(variableYear value
EC0120055
EC01200610
AAO12005 2
AAO1 2006 4),header=T)
ddply(Data,.(variable),transform,CUMSUM=cumsum(value))
- Original Message
From: Felipe Carrillo mazatlanmex...@yahoo.com
To: Joris Meys jorism...@gmail.com; n.via...@libero.it
n.via...@libero.it
Cc: r-help@r-project.org
Sent: Thu, June 3, 2010 11:28:58 AM
Subject: Re: [R] cumsum function with data frame
You can also use ddply from the plyr package:
library(plyr)
Data -
read.table(textConnection(variableYear value
EC01
20055
EC01200610
AAO12005
2
AAO1 2006
4),header=T)
Data
ddply(Data,.(variable),summarise,Year=Year,value=value,CUMSUM=cumsum(value))
Felipe
D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US
Fish Wildlife Service
California, USA
- Original
Message
From: Joris Meys ymailto=mailto:jorism...@gmail.com;
href=mailto:jorism...@gmail.com;jorism...@gmail.com
To: ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it ymailto=mailto:
n.via...@libero.it
href=mailto:n.via...@libero.it;n.via...@libero.it
Cc: ymailto=mailto:r-help@r-project.org;
href=mailto:r-help@r-project.org;r-help@r-project.org
Sent: Thu,
June 3, 2010 9:26:17 AM
Subject: Re: [R] cumsum function with data
frame
See ?split and ?unsplit.
Data -
read.table(textConnection(variableYear
value
EC01
2005
5
EC012006
10
AAO1
2005 2
AAO1
2006
4),header=T)
Datalist
-split(Data,Data$variable)
resultlist -
lapply(Datalist,function(x){
x$cumul -
cumsum(x$value)
return(x)
})
result -
unsplit(resultlist,Data$variable)
result
variable Year value
cumul
1EC01 200555
2
EC01 200610
15
3AAO1
200522
4AAO1 2006
4
6
On a side note: I've used this construction now for a
number
of problems.
Some could be better solved using more specific functions
(e.g. ave() for
adding a column with means for example). I'm not
sure however
this is the
most optimal approach to applying a
function to subsets of a
dataframe and
adding the result of that
function as an extra variable.
Anybody care to
elaborate on how the
R masters had it in
mind?
Cheers
Joris
On Thu, Jun 3,
2010 at 5:58 PM, ymailto=mailto: href=mailto:n.via...@libero.it;
n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I
have a
data frame like the following one
variable
Year value
EC01
2005
5
EC01
200610
AAO12005
2
AAO1
2006
4
what I would like to obtain is
variableYear value
cumsum
EC01
20055
5
EC01
200610
15
AAO1
2005 2
2
AAO1
2006 4
6
if I use the by function or the aggregate
function the result is a list or
something else, what I want is
a data
frame as I showed above...
anyone knows how to get
it???
THANKS
A
LOT
[[alternative HTML version deleted]]
__
ymailto=mailto: ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org
href=mailto: href=mailto:R-help@r-project.org;R-help@r-project.org
ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org mailing list
target=_blank https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
do read the
posting guide
http://www.R-project.org/posting-guide.html
and
provide
commented, minimal, self-contained, reproducible
code.
--
Joris Meys
Statistical
Consultant
Ghent University
Faculty of Bioscience
Engineering
Department of Applied mathematics, biometrics and process
control
Coupure Links 653
B-9000 Gent
tel : +32 9 264
59
87
href=mailto: href=mailto:joris.m...@ugent.be;joris.m...@ugent.be
ymailto=mailto:joris.m...@ugent.be;
href=mailto:joris.m...@ugent.be;joris.m...@ugent.be
Re: [R] cumsum function with data frame
But then you don't apply cumsum within each factor level. Hence the ddply.
Cheers
Joris
On Thu, Jun 3, 2010 at 9:35 PM, Jorge Ivan Velez
jorgeivanve...@gmail.com wrote:
Or better yet, you can use transform only (in base):
transform(Data, CUMSUM = cumsum(value))
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:30 PM, Felipe Carrillo wrote:
Better yet, is shorter using tranform instead of summarise:
Data - read.table(textConnection(variable Year value
EC01 2005 5
EC01 2006 10
AAO1 2005 2
AAO1 2006 4),header=T)
ddply(Data,.(variable),transform,CUMSUM=cumsum(value))
- Original Message
From: Felipe Carrillo mazatlanmex...@yahoo.com
To: Joris Meys jorism...@gmail.com; n.via...@libero.it
n.via...@libero.it
Cc: r-help@r-project.org
Sent: Thu, June 3, 2010 11:28:58 AM
Subject: Re: [R] cumsum function with data frame
You can also use ddply from the plyr package:
library(plyr)
Data -
read.table(textConnection(variable Year value
EC01
2005 5
EC01 2006 10
AAO1 2005
2
AAO1 2006
4),header=T)
Data
ddply(Data,.(variable),summarise,Year=Year,value=value,CUMSUM=cumsum(value))
Felipe
D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US
Fish Wildlife Service
California, USA
- Original
Message
From: Joris Meys ymailto=mailto:jorism...@gmail.com;
href=mailto:jorism...@gmail.com;jorism...@gmail.com
To: ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
Cc: ymailto=mailto:r-help@r-project.org;
href=mailto:r-help@r-project.org;r-help@r-project.org
Sent: Thu,
June 3, 2010 9:26:17 AM
Subject: Re: [R] cumsum function with data
frame
See ?split and ?unsplit.
Data -
read.table(textConnection(variable Year
value
EC01
2005
5
EC01 2006
10
AAO1
2005 2
AAO1
2006
4),header=T)
Datalist
-split(Data,Data$variable)
resultlist -
lapply(Datalist,function(x){
x$cumul -
cumsum(x$value)
return(x)
})
result -
unsplit(resultlist,Data$variable)
result
variable Year value
cumul
1 EC01 2005 5 5
2
EC01 2006 10
15
3 AAO1
2005 2 2
4 AAO1 2006
4
6
On a side note: I've used this construction now for a
number
of problems.
Some could be better solved using more specific functions
(e.g. ave() for
adding a column with means for example). I'm not
sure however
this is the
most optimal approach to applying a
function to subsets of a
dataframe and
adding the result of that
function as an extra variable.
Anybody care to
elaborate on how the
R masters had it in
mind?
Cheers
Joris
On Thu, Jun 3,
2010 at 5:58 PM, ymailto=mailto:
href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I
have a
data frame like the following one
variable
Year value
EC01
2005
5
EC01
2006 10
AAO1 2005
2
AAO1
2006
4
what I would like to obtain is
variable Year value
cumsum
EC01
2005 5
5
EC01
2006 10
15
AAO1
2005 2
2
AAO1
2006 4
6
if I use the by function or the aggregate
function the result is a list or
something else, what I want is
a data
frame as I showed above...
anyone knows how to get
it???
THANKS
A
LOT
[[alternative HTML version deleted]]
__
ymailto=mailto: ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org
href=mailto:
href=mailto:R-help@r-project.org;R-help@r-project.org
ymailto=mailto:R-help@r-project.org;
href=mailto:R-help@r-project.org;R-help@r-project.org mailing list
target=_blank https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
do read the
posting guide
http://www.R-project.org/posting-guide.html
and
provide
commented, minimal, self-contained, reproducible
code.
--
Joris Meys
Statistical
Consultant
Ghent University
Faculty of Bioscience
Engineering
Department of Applied mathematics, biometrics and process
control
Coupure Links 653
B-9000 Gent
tel : +32 9 264
59
87
href
Re: [R] cumsum function with data frame
Thanks Joris, you are absolutely right. Apologies to all for that.
May be this time I can get it right :-)
transform(Data, CUMSUM = do.call(c, with(Data, tapply(value, rev(variable),
cumsum
Regards,
Jorge
On Thu, Jun 3, 2010 at 8:04 PM, Joris Meys wrote:
But then you don't apply cumsum within each factor level. Hence the ddply.
Cheers
Joris
On Thu, Jun 3, 2010 at 9:35 PM, Jorge Ivan Velez
wrote:
Or better yet, you can use transform only (in base):
transform(Data, CUMSUM = cumsum(value))
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:30 PM, Felipe Carrillo wrote:
Better yet, is shorter using tranform instead of summarise:
Data - read.table(textConnection(variableYear value
EC0120055
EC01200610
AAO12005 2
AAO1 2006 4),header=T)
ddply(Data,.(variable),transform,CUMSUM=cumsum(value))
- Original Message
From: Felipe Carrillo mazatlanmex...@yahoo.com
To: Joris Meys jorism...@gmail.com; n.via...@libero.it
n.via...@libero.it
Cc: r-help@r-project.org
Sent: Thu, June 3, 2010 11:28:58 AM
Subject: Re: [R] cumsum function with data frame
You can also use ddply from the plyr package:
library(plyr)
Data -
read.table(textConnection(variableYear value
EC01
20055
EC01200610
AAO12005
2
AAO1 2006
4),header=T)
Data
ddply(Data,.(variable),summarise,Year=Year,value=value,CUMSUM=cumsum(value))
Felipe
D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US
Fish Wildlife Service
California, USA
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From: Joris Meys ymailto=mailto:jorism...@gmail.com;
href=mailto:jorism...@gmail.com;jorism...@gmail.com
To: ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
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Cc: ymailto=mailto:r-help@r-project.org;
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Sent: Thu,
June 3, 2010 9:26:17 AM
Subject: Re: [R] cumsum function with data
frame
See ?split and ?unsplit.
Data -
read.table(textConnection(variableYear
value
EC01
2005
5
EC012006
10
AAO1
2005 2
AAO1
2006
4),header=T)
Datalist
-split(Data,Data$variable)
resultlist -
lapply(Datalist,function(x){
x$cumul -
cumsum(x$value)
return(x)
})
result -
unsplit(resultlist,Data$variable)
result
variable Year value
cumul
1EC01 200555
2
EC01 200610
15
3AAO1
200522
4AAO1 2006
4
6
On a side note: I've used this construction now for a
number
of problems.
Some could be better solved using more specific functions
(e.g. ave() for
adding a column with means for example). I'm not
sure however
this is the
most optimal approach to applying a
function to subsets of a
dataframe and
adding the result of that
function as an extra variable.
Anybody care to
elaborate on how the
R masters had it in
mind?
Cheers
Joris
On Thu, Jun 3,
2010 at 5:58 PM, ymailto=mailto:
href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
href=mailto: href=mailto:n.via...@libero.it;n.via...@libero.it
ymailto=mailto:n.via...@libero.it;
href=mailto:n.via...@libero.it;n.via...@libero.itwrote:
Dear list,
I have a problem with the cumsum function.
I
have a
data frame like the following one
variable
Year value
EC01
2005
5
EC01
200610
AAO12005
2
AAO1
2006
4
what I would like to obtain is
variableYear value
cumsum
EC01
20055
5
EC01
200610
15
AAO1
2005 2
2
AAO1
2006 4
6
if I use the by function or the aggregate
function the result is a list or
something else, what I want is
a data
frame as I showed above...
anyone knows how to get
it???
THANKS
A
LOT
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