Re: [R] curvedarrow (some graphics problem)

2009-06-25 Thread casperyc

Hi there,

This is now the code

%
library(grid)

vp -  viewport(
x = unit(0, npc),
y = unit(0, npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))

vp2 -  viewport( # probably not needed but I had trouble placing the xaxis
x = unit(0,npc),
y = unit(0.5,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))


pushViewport(vp)
grid.xaxis(at=seq(-1, 1, by=0.2), label=FALSE,  vp=vp2)
grid.points(x=0.3, y=0.5, gp=gpar(col=NA), default.units = npc,   
name=h1, vp=vp)
grid.points(x=0.7, y=0.5, gp=gpar(col=NA), default.units = npc,   
name=h2, vp=vp)
grid.text(s, x=0.3, y=unit(-1, lines), vp=vp2)
grid.text(t, 0.7, unit(-1, lines), gp=gpar(col=red), vp=vp2)
grid.text(mu(s,t), 0.5, unit(5, lines), vp=vp2)

grid.curve(grobX(h2, 180),
grobY(h2, 180),
grobX(h1, 180),
grobY(h1, 180),
shape=1, ncp=10,
square=FALSE,
curvature=.4,
arrow=arrow(angle=20,ends=first) )

upViewport()



%

for this line:
grid.text(mu(s,t), 0.5, unit(5, lines), vp=vp2)

how do I change mu(s,t) to the expression mu?
I have tried 
grid.text(expression=mu(s,t), 0.5, unit(5, lines), vp=vp2)
grid.text(expression(mu(s,t)), 0.5, unit(5, lines), vp=vp2)

both didnt work

AND

when I tried to save the output as PDF file

it returns:

Error in function (name)  : Grob 'h2' not found

I have no idea what to do?


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Re: [R] curvedarrow (some graphics problem)

2009-06-25 Thread baptiste auguie


This will give you a greek character, see ?plotmath

grid.text(expression(mu*(s,t)), 0.5, unit(5, lines), vp=vp2)

The following works for me, it may be that you're using an outdated 
version of R,



vp -  viewport(
x = unit(0, npc),
y = unit(0, npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))

vp2 -  viewport( # probably not needed but I had trouble placing the xaxis
x = unit(0,npc),
y = unit(0.5,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))


pdf() # open the pdf device

pushViewport(vp)
grid.xaxis(at=seq(-1, 1, by=0.2), label=FALSE,  vp=vp2)
grid.points(x=0.3, y=0.5, gp=gpar(col=NA), default.units = npc,  
name=h1, vp=vp)
grid.points(x=0.7, y=0.5, gp=gpar(col=NA), default.units = npc,  
name=h2, vp=vp)

grid.text(s, x=0.3, y=unit(-1, lines), vp=vp2)
grid.text(t, 0.7, unit(-1, lines), gp=gpar(col=red), vp=vp2)
grid.text(expression(mu*(s,t)), 0.5, unit(5, lines), vp=vp2)

grid.curve(grobX(h2, 180),
grobY(h2, 180),
grobX(h1, 180),
grobY(h1, 180),
shape=1, ncp=10,
square=FALSE,
curvature=.4,
arrow=arrow(angle=20,ends=first) )

upViewport()

dev.off() # close the device


casperyc wrote:

Hi there,

This is now the code

%
library(grid)

vp -  viewport(
x = unit(0, npc),
y = unit(0, npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))

vp2 -  viewport( # probably not needed but I had trouble placing the xaxis
x = unit(0,npc),
y = unit(0.5,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))


pushViewport(vp)
grid.xaxis(at=seq(-1, 1, by=0.2), label=FALSE,  vp=vp2)
grid.points(x=0.3, y=0.5, gp=gpar(col=NA), default.units = npc,   
name=h1, vp=vp)
grid.points(x=0.7, y=0.5, gp=gpar(col=NA), default.units = npc,   
name=h2, vp=vp)

grid.text(s, x=0.3, y=unit(-1, lines), vp=vp2)
grid.text(t, 0.7, unit(-1, lines), gp=gpar(col=red), vp=vp2)
grid.text(mu(s,t), 0.5, unit(5, lines), vp=vp2)

grid.curve(grobX(h2, 180),
grobY(h2, 180),
grobX(h1, 180),
grobY(h1, 180),
shape=1, ncp=10,
square=FALSE,
curvature=.4,
arrow=arrow(angle=20,ends=first) )

upViewport()



%

for this line:
grid.text(mu(s,t), 0.5, unit(5, lines), vp=vp2)

how do I change mu(s,t) to the expression mu?
I have tried 
grid.text(expression=mu(s,t), 0.5, unit(5, lines), vp=vp2)

grid.text(expression(mu(s,t)), 0.5, unit(5, lines), vp=vp2)

both didnt work

AND

when I tried to save the output as PDF file

it returns:

Error in function (name)  : Grob 'h2' not found

I have no idea what to do?





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Re: [R] curvedarrow (some graphics problem)

2009-06-24 Thread casperyc



baptiste auguie-4 wrote:
 
 Hi,
 
 Grid offers several functions to help drawing such graphs,
 
 see Paul Murrell's Can R Draw Graphs?  (useR! 2006)
 
 I came up with this, as a quick example,
 
 vp -  viewport(
 x = unit(0, npc),
 y = unit(0,  npc),
 just = c(left, bottom),
 xscale = c(-1, 1) ,
 yscale = c(-1, 1))
 
 
 
 


Hi,

I tried to do the first part. However, it returned with no such function
'viewport'  error.

Do I have to load some package first?

And this is a lot 'more' code than I expected since I am very new to R.
It amazes me that R can be so POWERFUL!

I will try make your code work and have a look at the page you pointed out.

Thank you for you help.

Chen

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Re: [R] curvedarrow (some graphics problem)

2009-06-24 Thread casperyc

[quote]  grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
Error in valid.units(units) : Invalid unit
  grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2) 
Error in valid.units(units) : Invalid unit[/quote]

Hi,

I have loaded the [grid] package. It seems that I have to load another
package?

Thanks
-- 
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[[alternative HTML version deleted]]

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Re: [R] curvedarrow (some graphics problem)

2009-06-24 Thread David Winsemius


On Jun 24, 2009, at 1:21 AM, casperyc wrote:



[quote]  grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
Error in valid.units(units) : Invalid unit

grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2)

Error in valid.units(units) : Invalid unit[/quote]

Hi,

I have loaded the [grid] package. It seems that I have to load another
package?

No. Such a need might have been suggested by a function not found  
error. In this case the details are in the help page for the unit  
function in grid. The unit parameter was mis-specified.


?unit

Try:

 grid.text(t, x=0.3, y=unit(-1, lines), vp=vp2)
--
 grid.text(s, 0.8, unit(-1, lines), gp=gpar(col=red), vp=vp2)


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
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Re: [R] curvedarrow (some graphics problem)

2009-06-24 Thread baptiste auguie


You're right, I meant to write linesnot line. The strange thing is, 
although line isn't listed in ?unit, it doesn't return an error on my 
machine,


 unit(-1, line)
[1] -1line
 unit(-1, lines)
[1] -1lines

Reading from 
http://svn.r-project.org/R/trunk/src/library/grid/src/unit.c line is 
listed as a pseudonym, so I guess it is a valid unit after all.


sessionInfo()
R version 2.9.0 (2009-04-17)
i386-apple-darwin8.11.1

locale:
en_GB.UTF-8/en_GB.UTF-8/C/C/en_GB.UTF-8/en_GB.UTF-8

attached base packages:
[1] datasets  stats grid ( 2.9.0 ) graphics  grDevices utils 
methods   base




Best,

baptiste





David Winsemius wrote:


On Jun 24, 2009, at 1:21 AM, casperyc wrote:



[quote]  grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
Error in valid.units(units) : Invalid unit

grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2)

Error in valid.units(units) : Invalid unit[/quote]

Hi,

I have loaded the [grid] package. It seems that I have to load another
package?

No. Such a need might have been suggested by a function not found 
error. In this case the details are in the help page for the unit 
function in grid. The unit parameter was mis-specified.


?unit

Try:

 grid.text(t, x=0.3, y=unit(-1, lines), vp=vp2)
--
 grid.text(s, 0.8, unit(-1, lines), gp=gpar(col=red), vp=vp2)


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html

and provide commented, minimal, self-contained, reproducible code.




--
_

Baptiste AuguiƩ

School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK

Phone: +44 1392 264187

http://newton.ex.ac.uk/research/emag

__
R-help@r-project.org mailing list
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Re: [R] curvedarrow (some graphics problem)

2009-06-24 Thread David Winsemius

I get:
 unit(-1, line)
Error in valid.units(units) : Invalid unit
 unit(-1, lines)
[1] -1lines

I have an older version of R (2.8.1) and of grid (2.8.1). The source  
for grid 2.8.1 does not have pseudonyms.


http://svn.r-project.org/R/branches/R-2-8-branch/src/library/grid/src/unit.c
--
David

On Jun 24, 2009, at 9:48 AM, baptiste auguie wrote:



You're right, I meant to write linesnot line. The strange thing  
is, although line isn't listed in ?unit, it doesn't return an  
error on my machine,


 unit(-1, line)
[1] -1line
 unit(-1, lines)
[1] -1lines

Reading fromhttp://svn.r-project.org/R/trunk/src/library/grid/src/unit.c 
 line is listed as a pseudonym, so I guess it is a valid unit  
after all.


sessionInfo()
R version 2.9.0 (2009-04-17)
i386-apple-darwin8.11.1

locale:
en_GB.UTF-8/en_GB.UTF-8/C/C/en_GB.UTF-8/en_GB.UTF-8

attached base packages:
[1] datasets  stats grid ( 2.9.0 ) graphics  grDevices  
utils methods   base



Best,

baptiste





David Winsemius wrote:


On Jun 24, 2009, at 1:21 AM, casperyc wrote:



[quote]  grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
Error in valid.units(units) : Invalid unit

grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2)

Error in valid.units(units) : Invalid unit[/quote]

Hi,

I have loaded the [grid] package. It seems that I have to load  
another

package?

No. Such a need might have been suggested by a function not found  
error. In this case the details are in the help page for the unit  
function in grid. The unit parameter was mis-specified.


?unit

Try:

grid.text(t, x=0.3, y=unit(-1, lines), vp=vp2)
--
grid.text(s, 0.8, unit(-1, lines), gp=gpar(col=red), vp=vp2)


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.




--
_

Baptiste AuguiƩ

School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK

Phone: +44 1392 264187

http://newton.ex.ac.uk/research/emag

__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
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Re: [R] curvedarrow (some graphics problem)

2009-06-23 Thread baptiste auguie

Hi,

Grid offers several functions to help drawing such graphs,

see Paul Murrell's Can R Draw Graphs?  (useR! 2006)

I came up with this, as a quick example,

vp -  viewport(
x = unit(0, npc),
y = unit(0,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))

vp2 -  viewport( # probably not needed but I had trouble placing the xaxis
x = unit(0, npc),
y = unit(0.5,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))


pushViewport(vp)
grid.xaxis(at=seq(-1, 1, by=0.2), label=FALSE,  vp=vp2)
grid.points(x=0.3, y=0.5, gp=gpar(col=NA), default.units = npc,
name=h1, vp=vp)
grid.points(x=0.8, y=0.5, gp=gpar(col=NA), default.units = npc,
name=h2, vp=vp)

grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2)

grid.curve(grobX(h2, 180),
grobY(h2, 180),
grobX(h1, 180),
grobY(h1, 180),
shape=1, ncp=10,
square=FALSE,
curvature=1,
arrow=arrow())

upViewport()


HTH,

baptiste


casperyc wrote:

Hi there,

I just wonder how to draw this kind of picture...

http://www.nabble.com/file/p24158796/b.jpg 
http://www.nabble.com/file/p24158796/a.jpg 


and this is what i have done

%
library(shape)
library(diagram)
curve(sin(x),bty=n,-8,8,yaxt=n,ylab=,xaxt=n,type=n,xlab=)
axis(1,labels=F,at=seq(-8,8,1))
curvedarrow(from=c(-4,-1), to=c(4,-1),curve=-0.035,arr.pos=1,lwd=1)
text(0,-0.62,substitute(mu(s,t)))
axis(1,labels=s,at=-4)
axis(1,labels=t,at=4)
%

is there any easier way
or
the most proper  way to draw these to graphs?

Thanks in advance!

Chen



__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] curvedarrow (some graphics problem)

2009-06-23 Thread Paul Murrell

Hi


baptiste auguie wrote:

Hi,

Grid offers several functions to help drawing such graphs,

see Paul Murrell's Can R Draw Graphs?  (useR! 2006)



The recent article in The R Journal 
http://journal.r-project.org/2009-1/RJournal_2009-1_Murrell.pdf

might also be useful.

Paul



I came up with this, as a quick example,

vp -  viewport(
x = unit(0, npc),
y = unit(0,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))

vp2 -  viewport( # probably not needed but I had trouble placing the xaxis
x = unit(0, npc),
y = unit(0.5,  npc),
just = c(left, bottom),
xscale = c(-1, 1) ,
yscale = c(-1, 1))


pushViewport(vp)
grid.xaxis(at=seq(-1, 1, by=0.2), label=FALSE,  vp=vp2)
grid.points(x=0.3, y=0.5, gp=gpar(col=NA), default.units = npc,
name=h1, vp=vp)
grid.points(x=0.8, y=0.5, gp=gpar(col=NA), default.units = npc,
name=h2, vp=vp)

grid.text(t, x=0.3, y=unit(-1, line), vp=vp2)
grid.text(s, 0.8, unit(-1, line), gp=gpar(col=red), vp=vp2)

grid.curve(grobX(h2, 180),
grobY(h2, 180),
grobX(h1, 180),
grobY(h1, 180),
shape=1, ncp=10,
square=FALSE,
curvature=1,
arrow=arrow())

upViewport()


HTH,

baptiste


casperyc wrote:

Hi there,

I just wonder how to draw this kind of picture...

http://www.nabble.com/file/p24158796/b.jpg 
http://www.nabble.com/file/p24158796/a.jpg

and this is what i have done

%
library(shape)
library(diagram)
curve(sin(x),bty=n,-8,8,yaxt=n,ylab=,xaxt=n,type=n,xlab=)
axis(1,labels=F,at=seq(-8,8,1))
curvedarrow(from=c(-4,-1), to=c(4,-1),curve=-0.035,arr.pos=1,lwd=1)
text(0,-0.62,substitute(mu(s,t)))
axis(1,labels=s,at=-4)
axis(1,labels=t,at=4)
%

is there any easier way
or
the most proper  way to draw these to graphs?

Thanks in advance!

Chen



__
R-help@r-project.org mailing list
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PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html

and provide commented, minimal, self-contained, reproducible code.


--
Dr Paul Murrell
Department of Statistics
The University of Auckland
Private Bag 92019
Auckland
New Zealand
64 9 3737599 x85392
p...@stat.auckland.ac.nz
http://www.stat.auckland.ac.nz/~paul/

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[R] curvedarrow (some graphics problem)

2009-06-22 Thread casperyc

Hi there,

I just wonder how to draw this kind of picture...

http://www.nabble.com/file/p24158796/b.jpg 
http://www.nabble.com/file/p24158796/a.jpg 

and this is what i have done

%
library(shape)
library(diagram)
curve(sin(x),bty=n,-8,8,yaxt=n,ylab=,xaxt=n,type=n,xlab=)
axis(1,labels=F,at=seq(-8,8,1))
curvedarrow(from=c(-4,-1), to=c(4,-1),curve=-0.035,arr.pos=1,lwd=1)
text(0,-0.62,substitute(mu(s,t)))
axis(1,labels=s,at=-4)
axis(1,labels=t,at=4)
%

is there any easier way
or
the most proper  way to draw these to graphs?

Thanks in advance!

Chen
-- 
View this message in context: 
http://www.nabble.com/curvedarrow-%28some-graphics-problem%29-tp24158796p24158796.html
Sent from the R help mailing list archive at Nabble.com.

__
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