Re: [R] lattice question: removing strips
Dear Martin,
Would
-
library(latticeExtra)
useOuterStrips(p)
-
be useful for you?
Gerrit.
--
Message: 1
Date: Mon, 10 Feb 2014 14:12:45 +0200 (EET)
From: Martin Ivanov
To: Pascal Oettli
Cc: r-help@r-project.org
Subject: Re: [R] lattice question: removing strips
Message-ID:
<999135689.229399.1392034366300.javamail.apa...@mail21.abv.bg>
Content-Type: text/plain; charset="UTF-8"
Dear Pascal,
Thank You very much for Your reply. Here is a minimal working example:
library(lattice);
# this is with both strips plotted:
data <- data.frame(x=1:5, y=6:10, f1=c("a1", "a1", "a1", "a2", "a3"), f2=c("b1", "b2", "b2",
"b1", "b2"));
p <- xyplot(y ~ x | f1 + f2, data=data)
print(p);
# and this is my attempt to only plot the strips for the second conditioning
variable, i.e. for f2:
my.strip <- function(which.given, strip.levels, ...) {
if(which.given == 1) {
return(FALSE);
}
else {
strip.default(which.given=which.given, strip.levels=c(TRUE, FALSE), ...);
}
}
p1 <- xyplot(y ~ x | f1 + f2, data=data, strip=my.strip)
print(p1);
#As You can see, here I do not get the strips for f1 potted, but there is an
empty space below
the strips for f1, which I cannot get rid of. I only want to show the strips
for f2. Directly
below them I want to see the panels themselves, instead of an empty space for
the missing f1 strips.
Any suggestions?
Best regards,
Martin
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] lattice question: removing strips
Hi Martin
If you only had 1 strip then strip = FALSE would suffice.
With 2 I think you are getting into the realm of strip.default because of the
first 2 arguments
strip.default(which.given, which.panel, )
and having to modify it
An easy solution is
library(latticeExtra)
useOuterStrips(strip = FALSE,
xyplot(y ~ x | f1 + f2, data=data, strip = FALSE)
)
and to change the strip background to blank or whatever colour
useOuterStrips(strip = FALSE,
xyplot(y ~ x | f1 + f2, data=data, strip = FALSE,
par.settings = list(strip.background = list(col = "transparent"))
)
)
you can format strip.left in the useOuterStrips function. See
?latticeExtra::useOuterStrips
for details
And now to bed
Regards
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@northnet.com.au
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Martin Ivanov
Sent: Monday, 10 February 2014 22:13
To: Pascal Oettli
Cc: r-help@r-project.org
Subject: Re: [R] lattice question: removing strips
Dear Pascal,
Thank You very much for Your reply. Here is a minimal working example:
library(lattice);
# this is with both strips plotted:
data <- data.frame(x=1:5, y=6:10, f1=c("a1", "a1", "a1", "a2", "a3"),
f2=c("b1", "b2", "b2", "b1", "b2"));
p <- xyplot(y ~ x | f1 + f2, data=data)
print(p);
# and this is my attempt to only plot the strips for the second conditioning
variable, i.e. for f2:
my.strip <- function(which.given, strip.levels, ...) {
if(which.given == 1) {
return(FALSE);
}
else {
strip.default(which.given=which.given, strip.levels=c(TRUE, FALSE), ...);
}
}
p1 <- xyplot(y ~ x | f1 + f2, data=data, strip=my.strip)
print(p1);
#As You can see, here I do not get the strips for f1 potted, but there is an
empty space below
the strips for f1, which I cannot get rid of. I only want to show the strips
for f2. Directly
below them I want to see the panels themselves, instead of an empty space for
the missing f1 strips.
Any suggestions?
Best regards,
Martin
> Оригинално писмо
>От: Pascal Oettli
>Относно: Re: [R] lattice question: removing strips
>До: Martin Ivanov
>Изпратено на: Понеделник, 2014, Февруари 10 12:56:21 EET
>
>
>Hello,
>
>Please provide a "commented, minimal, self-contained, reproducible
>code", as requested.
>
>Regards,
>Pascal
>
>On 10 February 2014 19:48, Martin Ivanov wrote:
>> Dear lattice users,
>>
>> I am trying to produce a lattice graph with two conditioning variables.
>> My problem is that I only want to show the strips for the levels of the
>> second conditioning variable.
>> I want to remove the strips for the levels of the first conditioning
>> variable.
>> I tried with the strip function, but if I tell it to return FALSE or NULL
>> whenever which.given == 1, I just get empty space below the strips for the
>> second conditioning variable. And I want to remove that space altogether.
>> Is it somehow achievable in lattice?
>>
>> I also tried setting layout.heights$strip to 0 when which.given == 1,
>> but it seems to only work globally, so either
>> the strips for both conditioning variables vanish, or both are present.
>>
>> Any suggestions will be appreciated.
>>
>>
>> Best regards,
>>
>> __
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
>
>
>--
>Pascal Oettli
>Project Scientist
>JAMSTEC
>Yokohama, Japan
>
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] lattice question: removing strips
Dear Pascal,
Thank You very much for Your reply. Here is a minimal working example:
library(lattice);
# this is with both strips plotted:
data <- data.frame(x=1:5, y=6:10, f1=c("a1", "a1", "a1", "a2", "a3"),
f2=c("b1", "b2", "b2", "b1", "b2"));
p <- xyplot(y ~ x | f1 + f2, data=data)
print(p);
# and this is my attempt to only plot the strips for the second conditioning
variable, i.e. for f2:
my.strip <- function(which.given, strip.levels, ...) {
if(which.given == 1) {
return(FALSE);
}
else {
strip.default(which.given=which.given, strip.levels=c(TRUE, FALSE), ...);
}
}
p1 <- xyplot(y ~ x | f1 + f2, data=data, strip=my.strip)
print(p1);
#As You can see, here I do not get the strips for f1 potted, but there is an
empty space below
the strips for f1, which I cannot get rid of. I only want to show the strips
for f2. Directly
below them I want to see the panels themselves, instead of an empty space for
the missing f1 strips.
Any suggestions?
Best regards,
Martin
> Оригинално писмо
>От: Pascal Oettli
>Относно: Re: [R] lattice question: removing strips
>До: Martin Ivanov
>Изпратено на: Понеделник, 2014, Февруари 10 12:56:21 EET
>
>
>Hello,
>
>Please provide a "commented, minimal, self-contained, reproducible
>code", as requested.
>
>Regards,
>Pascal
>
>On 10 February 2014 19:48, Martin Ivanov wrote:
>> Dear lattice users,
>>
>> I am trying to produce a lattice graph with two conditioning variables.
>> My problem is that I only want to show the strips for the levels of the
>> second conditioning variable.
>> I want to remove the strips for the levels of the first conditioning
>> variable.
>> I tried with the strip function, but if I tell it to return FALSE or NULL
>> whenever which.given == 1, I just get empty space below the strips for the
>> second conditioning variable. And I want to remove that space altogether.
>> Is it somehow achievable in lattice?
>>
>> I also tried setting layout.heights$strip to 0 when which.given == 1,
>> but it seems to only work globally, so either
>> the strips for both conditioning variables vanish, or both are present.
>>
>> Any suggestions will be appreciated.
>>
>>
>> Best regards,
>>
>> __
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
>
>
>--
>Pascal Oettli
>Project Scientist
>JAMSTEC
>Yokohama, Japan
>
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] lattice question: removing strips
Hello, Please provide a "commented, minimal, self-contained, reproducible code", as requested. Regards, Pascal On 10 February 2014 19:48, Martin Ivanov wrote: > Dear lattice users, > > I am trying to produce a lattice graph with two conditioning variables. > My problem is that I only want to show the strips for the levels of the > second conditioning variable. > I want to remove the strips for the levels of the first conditioning variable. > I tried with the strip function, but if I tell it to return FALSE or NULL > whenever which.given == 1, I just get empty space below the strips for the > second conditioning variable. And I want to remove that space altogether. Is > it somehow achievable in lattice? > > I also tried setting layout.heights$strip to 0 when which.given == 1, but it > seems to only work globally, so either > the strips for both conditioning variables vanish, or both are present. > > Any suggestions will be appreciated. > > > Best regards, > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Pascal Oettli Project Scientist JAMSTEC Yokohama, Japan __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] lattice question: removing strips
Dear lattice users, I am trying to produce a lattice graph with two conditioning variables. My problem is that I only want to show the strips for the levels of the second conditioning variable. I want to remove the strips for the levels of the first conditioning variable. I tried with the strip function, but if I tell it to return FALSE or NULL whenever which.given == 1, I just get empty space below the strips for the second conditioning variable. And I want to remove that space altogether. Is it somehow achievable in lattice? I also tried setting layout.heights$strip to 0 when which.given == 1, but it seems to only work globally, so either the strips for both conditioning variables vanish, or both are present. Any suggestions will be appreciated. Best regards, __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
