Re: [R] replacing zeros with above/below numbers ?
HI, May be this helps: a1 <-a indx <- which(c(0,diff(a!=0)) <0) indx1 <- which(c(0,diff(a!=0)) >0) a[a==0] <- rep( rowMeans(cbind(a[indx-1],a[indx1])),indx1-indx) a # [1] 0.97210 0.97220 0.97300 0.97230 0.97145 0.97145 0.97145 0.97060 0.96980 #[10] 0.97040 0.97100 0.96990 #Another option is na.approx() from library(zoo) a1[a1==0] <- NA na.approx(a1) ##there is difference in the result though (depends on what you want) [1] 0.972100 0.972200 0.973000 0.972300 0.971875 0.971450 0.971025 0.970600 [9] 0.969800 0.970400 0.971000 0.969900 A.K. Dear all, My data is : a <- c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) I want to replace zeros with average of before and after values of them. But sometimes there is one zero sometimes more than one. What is the most elegant way to do this ? Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] replacing zeros with above/below numbers ?
Yes , indeed this is what I am looking for : a[ a == 0.0 ] = NA na.approx(a,na.rm="FALSE") Thanks a lot. -Original Message- From: "Jeff Newmiller" [jdnew...@dcn.davis.ca.us] Date: 02/05/2014 10:35 PM To: "ce" , "" Subject: Re: [R] replacing zeros with above/below numbers ? You seem to be treating zeroes as unknown values. Perhaps you should consider setting them to NA and using the na.approx function from the zoo package. --- Jeff NewmillerThe . . Go Live... DCN:Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On February 5, 2014 7:05:46 PM PST, ce wrote: > >Dear all, > > My data is : > >a <- >c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) > >I want to replace zeros with average of before and after values of >them. But sometimes there is one zero sometimes more than one. What is >the most elegant way to do this ? >Thanks a lot > >__ >R-help@r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] replacing zeros with above/below numbers ?
In fact I don't want to replace with average of whole series, just before and
after values something like this :
for (i in seq(from=2,to=nrow(a)-1,by=1))
{
if ( a[i] == 0 ) a[i] = ( a[i+1] + a[i-1] ) / 2
}
but I can't handle gracefully repeated zeros or first and last values.
Jeff proposed na.approx function , I didn't know it, looks promising , I will
look into it .
ce
-Original Message-
From: "Pascal Oettli" [kri...@ymail.com]
Date: 02/05/2014 10:20 PM
To: "ce"
CC: "r-help"
Subject: Re: [R] replacing zeros with above/below numbers ?
Hello,
If you mean replacing 0 by the average of non-zero values, I guess one way is:
> a[a==0] <- mean(a[a!=0])
Maybe some senior user might correct it.
Regards,
Pascal
On 6 February 2014 12:05, ce wrote:
>
> Dear all,
>
> My data is :
>
> a <-
> c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699)
>
> I want to replace zeros with average of before and after values of them.
> But sometimes there is one zero sometimes more than one. What is the most
> elegant way to do this ?
> Thanks a lot
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Pascal Oettli
Project Scientist
JAMSTEC
Yokohama, Japan
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] replacing zeros with above/below numbers ?
You seem to be treating zeroes as unknown values. Perhaps you should consider setting them to NA and using the na.approx function from the zoo package. --- Jeff NewmillerThe . . Go Live... DCN:Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On February 5, 2014 7:05:46 PM PST, ce wrote: > >Dear all, > > My data is : > >a <- >c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) > >I want to replace zeros with average of before and after values of >them. But sometimes there is one zero sometimes more than one. What is >the most elegant way to do this ? >Thanks a lot > >__ >R-help@r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] replacing zeros with above/below numbers ?
Hello, If you mean replacing 0 by the average of non-zero values, I guess one way is: > a[a==0] <- mean(a[a!=0]) Maybe some senior user might correct it. Regards, Pascal On 6 February 2014 12:05, ce wrote: > > Dear all, > > My data is : > > a <- > c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) > > I want to replace zeros with average of before and after values of them. > But sometimes there is one zero sometimes more than one. What is the most > elegant way to do this ? > Thanks a lot > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Pascal Oettli Project Scientist JAMSTEC Yokohama, Japan __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] replacing zeros with above/below numbers ?
Dear all, My data is : a <- c(0.9721,0.9722,0.9730,0.9723,0.0,0.0,0.0,0.9706,0.9698,0.0,0.9710,0.9699) I want to replace zeros with average of before and after values of them. But sometimes there is one zero sometimes more than one. What is the most elegant way to do this ? Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
