Marc,
Thank you for your help. I had tried assign, but I did not enclose the
table name in quotes in my function call. I needed to see what someone else
had written before I ever would have noticed it!
On Fri, Feb 12, 2010 at 10:00 AM, Marc Schwartz marc_schwa...@me.comwrote:
On Feb 12, 2010, at 8:19 AM, mah wrote:
Hello R Experts,
How can I assign the name of a data frame with the argument of a
function? Specifically I am using RODBC to build local dataframes
from SAS datasets on a
remote server. I would like the local dataframe have the same name as
the source SAS dataset, and the function below is what I am
developing. However, the substitute(table) on the left side of the
assignment
generates the error Error in substitute(table) - sqlQuery(sears,
sql.stmt) :
could not find function substitute-.
Thanks in advance
MakeDF - function(table)
#
# Function makes dataframe from UNIX SAS datasets
#
{
st.time - Sys.time()
print(substitute(table))
sql.stmt - paste(select * from swprod., substitute(table),
sep=)
print(sql.stmt)
substitute(table) - sqlQuery(sears, sql.stmt)
# deparse(substitute(table)) - sqlQuery(sears, sql.stmt)
end.time
print(end.time - st.time)
}
MakeDF(sku_series)
My recommendation would be something like this:
MakeDF - function(table)
{
DF - sqlQuery(channel, paste(select * from swprod., table, sep = ))
assign(table, DF, envir = parent.frame())
}
Then use would be:
MakeDF(sku_series)
The result would be a data frame called 'sku_series' in the calling
environment. You could substitute globalenv() for parent.frame() if you
wanted to create the data frame in the global environment.
See ?assign
HTH,
Marc Schwartz
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