Re: [R] Creating zoo object on monthly time series
On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck [EMAIL PROTECTED] wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal [EMAIL PROTECTED] wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) NANANANANANA 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal [EMAIL PROTECTED] wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y However I got following : head(ss) NANANANANANA 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.451187.001398.771883.231431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck [EMAIL PROTECTED] wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
You need to unambiguously specify what your data looks like. Please provide the dput output as previously requested. Also what version of zoo are you using? packageDescription(zoo)$Version On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal [EMAIL PROTECTED] wrote: I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.451187.001398.771883.231431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck [EMAIL PROTECTED] wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
Also here is an example showing it works with the assumed format and zoo version: data1 - structure(list(V1 = structure(c(6L, 2L, 4L, 3L, 5L, 1L), .Label = c(Apr-81, + Dec-80, Feb-81, Jan-81, Mar-81, Nov-80), class = factor), + V2 = c(NA, NA, NA, NA, NA, NA), V3 = c(1007.44, 982.05, 994.25, + 996.31, 939.91, 923.32)), .Names = c(V1, V2, V3), class = data.frame, row.names = c(1, + 2, 3, 4, 5, 6)) data1 V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) Nov 1980 Dec 1980 Jan 1981 Feb 1981 Mar 1981 Apr 1981 1007.44 982.05 994.25 996.31 939.91 923.32 zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) 1980-11-01 1980-12-01 1981-01-01 1981-02-01 1981-03-01 1981-04-01 1007.44 982.05 994.25 996.31 939.91 923.32 packageDescription(zoo)$Version [1] 1.5-3 On Sun, Jun 1, 2008 at 9:44 AM, Gabor Grothendieck [EMAIL PROTECTED] wrote: You need to unambiguously specify what your data looks like. Please provide the dput output as previously requested. Also what version of zoo are you using? packageDescription(zoo)$Version On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal [EMAIL PROTECTED] wrote: I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.451187.001398.771883.231431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck [EMAIL PROTECTED] wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
packageDescription(zoo)$Version [1] 1.1-1 Gabor Grothendieck [EMAIL PROTECTED] wrote: You need to unambiguously specify what your data looks like. Please provide the dput output as previously requested. Also what version of zoo are you using? packageDescription(zoo)$Version On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal wrote: I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.451187.001398.771883.231431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
Please upgrade to the latest version of zoo. as.yearmon.factor was only added to zoo in recent versions and its likely your date column is a factor. If that is not the problem then please provide the dput output as requested. On Sun, Jun 1, 2008 at 9:59 AM, Megh Dal [EMAIL PROTECTED] wrote: packageDescription(zoo)$Version [1] 1.1-1 Gabor Grothendieck [EMAIL PROTECTED] wrote: You need to unambiguously specify what your data looks like. Please provide the dput output as previously requested. Also what version of zoo are you using? packageDescription(zoo)$Version On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal wrote: I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Creating zoo object on monthly time series
Thanks Gabor, I have updated that and it is now working fine Gabor Grothendieck [EMAIL PROTECTED] wrote: Please upgrade to the latest version of zoo. as.yearmon.factor was only added to zoo in recent versions and its likely your date column is a factor. If that is not the problem then please provide the dput output as requested. On Sun, Jun 1, 2008 at 9:59 AM, Megh Dal wrote: packageDescription(zoo)$Version [1] 1.1-1 Gabor Grothendieck wrote: You need to unambiguously specify what your data looks like. Please provide the dput output as previously requested. Also what version of zoo are you using? packageDescription(zoo)$Version On Sun, Jun 1, 2008 at 9:37 AM, Megh Dal wrote: I got following: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) head(z) Jan 0001 Jan 0002 Jan 0003 Jan 0004 Jan 0005 Jan 0006 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) head(z) 0001-01-01 0002-01-01 0003-01-01 0004-01-01 0005-01-01 0006-01-01 1206.68 782.45 1187.00 1398.77 1883.23 1431.80 Nowhere 1980 is coming. Any better suggestion? Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:47 AM, Gabor Grothendieck wrote: On Sun, Jun 1, 2008 at 8:35 AM, Megh Dal wrote: Hi all, I have following monthly time series : head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 If the suggestion below does not work then try dput(head(data1)) to display it in an unambiguous form that is readily re-input into R. Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format=%m/%y)) See ?strptime and try %b-%y That should be: z - zoo(data1[,3], as.yearmon(data1[,1], %b-%y)) or, if you want it as Date instead of yearmon: z - zoo(data1[,3], as.Date(as.yearmon(data1[,1], %b-%y))) However I got following : head(ss) 1007.44 982.05 994.25 996.31 939.91 923.32 Can anyone please tell me what will be the correct syntax? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
