Re: [R] How create columns for squared values from previous columns?

[Mike C]

Ah, that works! Thank you!


From: PIKAL Petr <petr.pi...@precheza.cz>
Sent: Tuesday, May 2, 2017 7:56:33 AM
To: C W; r-help
Subject: RE: [R] How create columns for squared values from previous columns?

Hi

you can use data.frame
data.frame(dat, dat[,1:3]^2)

and you can set names afterwards by names function.

Cheers
Petr


> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of C W
> Sent: Saturday, April 29, 2017 3:22 AM
> To: r-help <r-help@r-project.org>
> Subject: Re: [R] How create columns for squared values from previous
> columns?
>
> I came up with this solution,
>
> > cbind(dat, dat[, 1:3]^2)
>X1 X2 X3 X4  X5  X1
> X2X3
> 1  0.72776481 -1.1332612 -1.9857503 0.46189400 -0.09016379 0.529641625
> 1.28428102 3.9432044
> 2  0.05126592  0.2858707  0.9075806 1.27582713 -0.49438507 0.002628194
> 0.08172203 0.8237026
> 3 -0.40430146  0.5457195 -1.1924042 0.15025594  1.99710475 0.163459669
> 0.29780978 1.4218277
> 4  1.40746971 -1.2279416  0.3296075 0.84411774 -0.52371619 1.980970990
> 1.50784058 0.1086411
> 5 -0.53841150  0.4750082 -0.4705148 0.05591914 -0.31503500 0.289886944
> 0.22563275 0.2213842
> 6  0.90691210  0.7247171  0.8244184 0.73328097 -1.05284737 0.822489552
> 0.52521494 0.6796657
>
> But, you would NOT ONLY get undesired variable names, BUT ALSO
> duplicated names. I suppose I can use paste() to solve that?
>
> Any better ideas?
>
>
> On Fri, Apr 28, 2017 at 8:57 PM, C W <tmrs...@gmail.com> wrote:
>
> > Dear R list,
> >
> > I am am a little unsure what is the best way to approach this. I
> > suppose I have
> >
> > > dat <- matrix(rnorm(30), ncol = 5)
> > > dat <- data.frame(dat)
> > > dat
> >X1  X2  X3 X4  X5
> > 1 -1.1317 -0.87868106 -0.33000492  1.5241765 -0.92483388
> > 2 -0.56168006 -0.08837883  1.96237792 -0.5335615  0.02880586
> > 3  0.82800071 -1.89965562 -0.05438815 -0.9162857 -0.57470053
> > 4 -0.03218412 -0.23119263 -1.10671765 -0.2885518 -0.30953951
> > 5  1.70525779 -0.93854817 -1.05932636 -0.2983139 -0.21980145
> > 6  1.19047531  0.38301678 -0.20830015 -0.6668266  0.82578534
> >
> > Suppose I want to add columns X6, X7, X8, where
> > X6 = X1^2
> > X7 = X2^2
> > X8 = X3^2
> >
> > I am thinking of using apply(), but df asks for column names, what's a
> > quick way to generate names on the fly?
> >
> > Thank you very much!
> >
> >
>
>   [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.


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The sender of th

Re: [R] How create columns for squared values from previous columns?

[PIKAL Petr]

Hi

you can use data.frame
data.frame(dat, dat[,1:3]^2)

and you can set names afterwards by names function.

Cheers
Petr


> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of C W
> Sent: Saturday, April 29, 2017 3:22 AM
> To: r-help <r-help@r-project.org>
> Subject: Re: [R] How create columns for squared values from previous
> columns?
>
> I came up with this solution,
>
> > cbind(dat, dat[, 1:3]^2)
>X1 X2 X3 X4  X5  X1
> X2X3
> 1  0.72776481 -1.1332612 -1.9857503 0.46189400 -0.09016379 0.529641625
> 1.28428102 3.9432044
> 2  0.05126592  0.2858707  0.9075806 1.27582713 -0.49438507 0.002628194
> 0.08172203 0.8237026
> 3 -0.40430146  0.5457195 -1.1924042 0.15025594  1.99710475 0.163459669
> 0.29780978 1.4218277
> 4  1.40746971 -1.2279416  0.3296075 0.84411774 -0.52371619 1.980970990
> 1.50784058 0.1086411
> 5 -0.53841150  0.4750082 -0.4705148 0.05591914 -0.31503500 0.289886944
> 0.22563275 0.2213842
> 6  0.90691210  0.7247171  0.8244184 0.73328097 -1.05284737 0.822489552
> 0.52521494 0.6796657
>
> But, you would NOT ONLY get undesired variable names, BUT ALSO
> duplicated names. I suppose I can use paste() to solve that?
>
> Any better ideas?
>
>
> On Fri, Apr 28, 2017 at 8:57 PM, C W <tmrs...@gmail.com> wrote:
>
> > Dear R list,
> >
> > I am am a little unsure what is the best way to approach this. I
> > suppose I have
> >
> > > dat <- matrix(rnorm(30), ncol = 5)
> > > dat <- data.frame(dat)
> > > dat
> >X1  X2  X3 X4  X5
> > 1 -1.1317 -0.87868106 -0.33000492  1.5241765 -0.92483388
> > 2 -0.56168006 -0.08837883  1.96237792 -0.5335615  0.02880586
> > 3  0.82800071 -1.89965562 -0.05438815 -0.9162857 -0.57470053
> > 4 -0.03218412 -0.23119263 -1.10671765 -0.2885518 -0.30953951
> > 5  1.70525779 -0.93854817 -1.05932636 -0.2983139 -0.21980145
> > 6  1.19047531  0.38301678 -0.20830015 -0.6668266  0.82578534
> >
> > Suppose I want to add columns X6, X7, X8, where
> > X6 = X1^2
> > X7 = X2^2
> > X8 = X3^2
> >
> > I am thinking of using apply(), but df asks for column names, what's a
> > quick way to generate names on the fly?
> >
> > Thank you very much!
> >
> >
>
>   [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.


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Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně 
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zpožděním přenosu e-mailu.

V případě, že je tento e-mail součástí obchodního jednání:
- vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a 
to z jakéhokoliv důvodu i bez uvedení důvodu.
- a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; 
Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce 
s dodatkem či odchylkou.
- trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným 
dosažením shody na všech jejích náležitostech.
- odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost 
žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně 
pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně 
osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi 
či osobě jím zastoupené známá.

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intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender. 
Delete the contents of this e-mail with all attachments and its copies from 
your system.
If you are not the intended recipient of this e-mail, you are not authorized to 
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by 
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Re: [R] How create columns for squared values from previous columns?

[C W]

I came up with this solution,

> cbind(dat, dat[, 1:3]^2)
   X1 X2 X3 X4  X5  X1
X2X3
1  0.72776481 -1.1332612 -1.9857503 0.46189400 -0.09016379 0.529641625
1.28428102 3.9432044
2  0.05126592  0.2858707  0.9075806 1.27582713 -0.49438507 0.002628194
0.08172203 0.8237026
3 -0.40430146  0.5457195 -1.1924042 0.15025594  1.99710475 0.163459669
0.29780978 1.4218277
4  1.40746971 -1.2279416  0.3296075 0.84411774 -0.52371619 1.980970990
1.50784058 0.1086411
5 -0.53841150  0.4750082 -0.4705148 0.05591914 -0.31503500 0.289886944
0.22563275 0.2213842
6  0.90691210  0.7247171  0.8244184 0.73328097 -1.05284737 0.822489552
0.52521494 0.6796657

But, you would NOT ONLY get undesired variable names, BUT ALSO duplicated
names. I suppose I can use paste() to solve that?

Any better ideas?


On Fri, Apr 28, 2017 at 8:57 PM, C W  wrote:

> Dear R list,
>
> I am am a little unsure what is the best way to approach this. I suppose I
> have
>
> > dat <- matrix(rnorm(30), ncol = 5)
> > dat <- data.frame(dat)
> > dat
>X1  X2  X3 X4  X5
> 1 -1.1317 -0.87868106 -0.33000492  1.5241765 -0.92483388
> 2 -0.56168006 -0.08837883  1.96237792 -0.5335615  0.02880586
> 3  0.82800071 -1.89965562 -0.05438815 -0.9162857 -0.57470053
> 4 -0.03218412 -0.23119263 -1.10671765 -0.2885518 -0.30953951
> 5  1.70525779 -0.93854817 -1.05932636 -0.2983139 -0.21980145
> 6  1.19047531  0.38301678 -0.20830015 -0.6668266  0.82578534
>
> Suppose I want to add columns X6, X7, X8, where
> X6 = X1^2
> X7 = X2^2
> X8 = X3^2
>
> I am thinking of using apply(), but df asks for column names, what's a
> quick way to generate names on the fly?
>
> Thank you very much!
>
>

[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.