[R] basic question
Dear R users, Up to now, I only used precompiled packages. As I am working on vegetation ecology, I would be interested in using a package not stored by CRAN called labdsv_0.9-1.tar.gz and developped by Dave Roberts at the National Center for Ecological Analysis and Synthesis (unfortunately I did not find any corresponding .zip file). Although I tried to follow the proposed guidelines to install such a file in R, I did not succeed. I installed the library tools, the Perl and the MinGW softwares, but I feel all this stuff is useless in my case (my knowledge in informatic in so poor that I am reduced to intuitions!) I know this is probably one of the most FAQ, but I did not find the answer to my problem on the R-CRAN web site. Thank you in advance! Have a good day. Frédéric Archaux (PhD, Engineer) Biodiversity and Forest Management Team CEMAGREF Domaine des Barres F-45290 Nogent-sur-Vernisson FRANCE [[alternate HTML version deleted]] __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] basic question
Hi, From your description I am guessing you're using Windows. What you may need is to compile this package from source. It is explained in one of the R manuals (I can't remember which one though). You can also look at my R Guide for Windows Users at http://www.stat.auckland.ac.nz/~kwan022/rinfo.php (Section 5). I'm not sure the exact contents in the labdsv_0.9-1.tar.gz , but in general you can first unpack it with, e.g.: tar zxvf labdsv_0.9-1.tar.gz then you may need: Rcmd labdsv_0.9-1 Hope this helps, Kevin Ko-Kang Kevin Wang Master of Science (MSc) Student Department of Statistics University of Auckland New Zealand www.stat.auckland.ac.nz/~kwan022 - Original Message - From: Archaux Frederic [EMAIL PROTECTED] To: '[EMAIL PROTECTED]' [EMAIL PROTECTED] Sent: Tuesday, February 04, 2003 9:46 PM Subject: [R] basic question Dear R users, Up to now, I only used precompiled packages. As I am working on vegetation ecology, I would be interested in using a package not stored by CRAN called labdsv_0.9-1.tar.gz and developped by Dave Roberts at the National Center for Ecological Analysis and Synthesis (unfortunately I did not find any corresponding .zip file). Although I tried to follow the proposed guidelines to install such a file in R, I did not succeed. I installed the library tools, the Perl and the MinGW softwares, but I feel all this stuff is useless in my case (my knowledge in informatic in so poor that I am reduced to intuitions!) I know this is probably one of the most FAQ, but I did not find the answer to my problem on the R-CRAN web site. Thank you in advance! Have a good day. Frédéric Archaux (PhD, Engineer) Biodiversity and Forest Management Team CEMAGREF Domaine des Barres F-45290 Nogent-sur-Vernisson FRANCE [[alternate HTML version deleted]] __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] basic question
On Tue, 2003-02-04 at 10:46, Archaux Frederic wrote: Up to now, I only used precompiled packages. As I am working on vegetation ecology, I would be interested in using a package not stored by CRAN called labdsv_0.9-1.tar.gz and developped by Dave Roberts at the National Center for Ecological Analysis and Synthesis (unfortunately I did not find any corresponding .zip file). Although I tried to follow the proposed guidelines to install such a file in R, I did not succeed. I installed the library tools, the Perl and the MinGW softwares, but I feel all this stuff is useless in my case (my knowledge in informatic in so poor that I am reduced to intuitions!) I know this is probably one of the most FAQ, but I did not find the answer to my problem on the R-CRAN web site. Thank you in advance! Frédéric, Dave Roberts is not yet quite finished up with his package -- it is labelled as a zero version for a reason. He wrote to me that it won't compile in Windows yet, for an unknown reason. He said that he got to edit the FORTRAN files to compile them in Windows (they work in Linux). However, he had still some other problems and so you got to dyn.load the resulting dll into R, which, but in Dave's words That concept is completely foreign to windows people of course, so it's pretty much useless. It may be that you have to wait until Dave Roberts lectures on these methods again, since then he may have to finish up the package. cheers, jari oksanen -- Jari Oksanen -- Dept Biology, Univ Oulu, 90014 Oulu, Finland Ph. +358 8 5531526, cell +358 40 5136529, fax +358 8 5531061 email [EMAIL PROTECTED], homepage http://cc.oulu.fi/~jarioksa/ __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] basic question
On Tue, 4 Feb 2003, Ko-Kang Kevin Wang wrote: From your description I am guessing you're using Windows. What you may need is to compile this package from source. It is explained in one of the R manuals (I can't remember which one though). The file README.packages in the Windows distribution, if on Windows. You can also look at my R Guide for Windows Users at http://www.stat.auckland.ac.nz/~kwan022/rinfo.php (Section 5). I'm not sure the exact contents in the labdsv_0.9-1.tar.gz , but in general you can first unpack it with, e.g.: tar zxvf labdsv_0.9-1.tar.gz then you may need: Rcmd labdsv_0.9-1 Rcmd INSTALL labdsv_0.9-1.tar.gz is all that is needed. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] [Out off-topic] SJava under Windows
Philippe, I didn't use JDK 1.4 (and R1.6.2) yet, but may be I can help you anyway: - Did you add the directory that holds the jvm.dll to your PATH? - If you take a look to the source of .JavaInit() ($R_HOME/ library/SJava/R/SJava), there is a line: pathSeparator - ifelse(version$os == Win32, ;, :) this should be: pathSeparator - ifelse(version$os == mingw32, ;, :) All versions of R that I know of, return mingw32 for version$os. Best regards, Heinz Grimm begin:vcard n:Grimm;Heinz tel;fax:+41 61 9715 072 tel;work:+41 61 9751 109 x-mozilla-html:FALSE url:www.rcc.ch org:RCC Ltd.;IT version:2.1 email;internet:[EMAIL PROTECTED] title:Dipl.Ing.(FH) adr;quoted-printable:;;Zelgliweg 1=0D=0A;Itingen;BL;CH-4452;Switzerland fn:Heinz Grimm end:vcard This e-mail transmission contains confidential or legally privileged information that is intended for the addressee(s) only. You are hereby notified that any disclosure, copying, distribution or use of the contents of this e-mail is strictly prohibited if you are not the intended recipient. Please inform the sender and delete the message from your system if you have received this e-mail transmission in error. Thank you.
[R] test for two samples
Hi R-users, My question is more methodological one, rather than technical. I have to samples representing residuals based on two measurements techniques (resid1,resid2; n=69). I need to compare two samples, to reject one technique (the worse one), and to keep the one which gave lower residuals (better one). What to look for? What should I analyse? Means, variance, std. deviations? Based on preliminary EDA: mean_resid1 mean_resid2 #I would reject resid2 technique stdev_resid1 stdev_resid2 #I would reject resid1 technique var_resid1 var_resid2 #I would reject resid1 technique Based on means I would reject resid2 technique, but based on analyses of stdev. and variance I would reject resid1 technique. How to deal with that problem? What is proper statist. atrribute to look for? Should I use t.test()? Best regards, Rado Bonk -- Radoslav Bonk M.S. Dept. of Physical Geography and Geoecology Faculty of Sciences, Comenius University Mlynska Dolina 842 15, Bratislava, SLOVAKIA tel: +421 905 968 127 e-mail: [EMAIL PROTECTED] __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] downloaf.file
Dear List-members, to download a file from the net, the function download.file(..) does the job. However, before embarking on the download, I would like to find out how large the file is. Is there a way to know it? Most easily, this question has been asked before, but I am new to the list. Regards, with thanks in advance, Adelchi Azzalini Adelchi Azzalini [EMAIL PROTECTED] Dipart.Scienze Statistiche, Università di Padova, Italia http://azzalini.stat.unipd.it/ __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] downloaf.file
Essentially no. Most servers will give you the length if you start the download, and then R prints it out, but it may be unknown. As in update.packages() trying URL `http://cran.r-project.org/src/contrib/PACKAGES' Content type `text/plain; charset=iso-8859-1' length 95407 bytes opened URL .. .. .. .. .. .. .. .. .. ... downloaded 93Kb and you can (probably) interrupt during those dots. On Tue, 4 Feb 2003, Adelchi Azzalini wrote: to download a file from the net, the function download.file(..) does the job. However, before embarking on the download, I would like to find out how large the file is. Is there a way to know it? Most easily, this question has been asked before, but I am new to the list. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
RE: [R] [Out off-topic] SJava under Windows
For those who are interested, I posted a Windows compiled version of SJava
0.64 that works with R 1.6.2 and JDK 1.4 on ftp.sciviews.org, under
/Download/Rwindows/.
Thanks Simon, Heinz and Brian for helping me getting this running version.
When compiling SJava 0.64 under Windows (R 1.6.2, JDK 1.4.0-02, Win XP),
line 286 of $R_HOME/library/SJava/R/SJava has to be changed from:
pathSeparator - ifelse(version$os == Win32, ;, :)
to
pathSeparator - ifelse(.Platform$OS.type == windows, ;, :)
in order to work in R 1.6.2. Of course, the path to jvm.dll must also be
added to the path environment variable. With my installation, it is:
c:\progra~1\Java\j2re1.4.0_02\bin\Client
Best regards,
Philippe Grosjean
...](({?...?}))...
) ) ) ) )
( ( ( ( ( Dr. Philippe Grosjean
) ) ) ) )
( ( ( ( ( LOV, UMR 7093
) ) ) ) ) Station Zoologique
( ( ( ( ( Observatoire Oceanologique
) ) ) ) ) BP 28
( ( ( ( ( 06234 Villefranche sur mer cedex
) ) ) ) ) France
( ( ( ( (
) ) ) ) ) tel: +33.4.93.76.38.16, fax: +33.4.93.76.38.34
( ( ( ( (
) ) ) ) ) e-mail: [EMAIL PROTECTED]
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[R] Background color of plot
I'm using the parameters mfrow and mfg to display some graphics(plots)
at the same time. Although, because of the parameter mfg, the parameter
bg don´t change the background color.
What can I do to solve this?
Here is the code I'm using...
...
i - 1
for(j in 1:4){
for(k in 1:2){
limiares - tabLimiar(arrayMetricas[,i])
op - par(mfrow=c(4,2),pty=s)
par(mfg=c(j,k))
plot(limiares,main=a[i],ylab=frequencia,xlab=limiares,bg=white,col=green,col.main=seagreen,type=b)
box(which=figure,lty=solid,col=white)
par(op)
i - i+1
if(i == ncol(arrayMetricas))
break
}
}
...
Patricia.
--
Patrícia Maforte dos Santos
Centro de Informatica
Universidade Federal de Pernambuco
Recife/PE - Brasil
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Re: [R] downloaf.file
to download a file from the net, the function download.file(..)
does the job. However, before embarking on the download, I would
like to find out how large the file is. Is there a way to know it?
You can send web servers a 'HEAD' request, which can give you some
basic information about the download. I cant see a way to get this from
the current R functions, so here's a little routine to leverage the
'lynx' web browser:
head.download -
function (url)
{
if (system(lynx -help /dev/null) == 0) {
method - lynx
}
else {
stop(No lynx found)
}
if (method == lynx) {
heads - system(paste(lynx -head -dump ', url,', sep =
),intern=T)
}
# turn name: value lines into named list. prob vectorisable
ret - list(status=heads[1])
for(l in 2:length(heads)){
col - regexpr(:,heads[l])
if(col-1){
name - substr(heads[l],1,(col-1))
value - substr(heads[l],(col+1),nchar(heads[l]))
ret[[name]] - value
}else{
ret - c(ret,heads[l])
}
}
ret
}
this borrows bits from download.file(), but it does depend on you
having lynx installed. The return value is a list with names
corresponding to the header titles and values being the values. It looks
for a : as the title: value separator, and anything that doesnt have a :
is just added verbatim unnamed.
For example, how big is the R logo on the home page?
head.download(http://www.r-project.org/Rlogo.jpg;)$Content-Length
[1] 8793
That's bytes. Yes I know its character! I dont think web servers are
under any obligation to provide accurate Content-length values. Many
dynamic web servers have pages that change length every time. This will
also not for for ftp:// URLs or local file:// URLs (or gopher:// URLs?).
Perhaps HEAD-getting functionality can be put in the next release of
R? It would probably have a better name: value - named list routine
than the one I just hacked up in two minutes above. Oops. Shame.
Baz
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Re: [R] downloaf.file
On Tue, 4 Feb 2003, Barry Rowlingson wrote: That's bytes. Yes I know its character! I dont think web servers are under any obligation to provide accurate Content-length values. Many dynamic web servers have pages that change length every time. This will also not for for ftp:// URLs or local file:// URLs (or gopher:// URLs?). The HTTP protocol says that a content length SHOULD be provided and MUST be accurate if it is provided. -thomas __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] SORTING Arrays by index value
Hello, I'm somewhat new to R. I've searched the archive for the last year and tried to consult the manual pages for the following problem, but did not find an answer. I want to sort an array by the index values. Here is the array acc.gp.bl.wtmn Gp17 Gp4 1 0.5703125 0.6406250 10 0.7812500 0.7109375 11 0.8046875 0.7343750 12 0.8359375 0.7890625 13 0.8515625 0.7109375 14 0.8281250 0.7343750 15 0.8671875 0.7812500 16 0.8125000 0.7578125 17 0.7734375 0.750 18 0.800 0.780 19 0.870 0.730 2 0.8046875 0.7265625 20 0.830 0.740 21 0.750 0.800 22 0.770 0.760 23 0.820 0.780 24 0.760 0.740 25 0.810 0.800 3 0.7578125 0.7812500 4 0.8203125 0.7890625 5 0.7890625 0.7421875 6 0.7265625 0.7812500 7 0.8125000 0.7421875 8 0.8515625 0.7265625 9 0.8203125 0.6953125 My question is: How do I sort by the first index (the values are 1:25) without losing the associated values per index value for the two columns(Gp17 and Gp4). I want ascending order (1:25) of the index values. Thank you in advance. -Mark Orr Postdoctoral Fellow Psychology Dept. Carnegie Mellon Univ. Pittsburgh, PA 15213 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] downloaf.file
On Tue, 4 Feb 2003, Thomas Lumley wrote: On Tue, 4 Feb 2003, Barry Rowlingson wrote: That's bytes. Yes I know its character! I dont think web servers are under any obligation to provide accurate Content-length values. Many dynamic web servers have pages that change length every time. This will also not for for ftp:// URLs or local file:// URLs (or gopher:// URLs?). The HTTP protocol says that a content length SHOULD be provided and MUST be accurate if it is provided. Most proxies of my acquaintance will report unknown unless they are asked to actually get the file or have it already cached. Further, the IE internals used under Windows with --internet2 usually seems to get the wrong length (far too short) when talking to a proxy. Why is this of interest: there are lots of internet download tools available apart from R? -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] SORTING Arrays by index value
acc.gp.bl.wtmn[sort.list(row.names(acc.gp.bl.wtmn)), ] I am not clear how you missed order/sort.list, which have examples like this. It's referenced off ?sort. Indeed, sort() can be used too. On Tue, 4 Feb 2003, Mark G Orr wrote: Hello, I'm somewhat new to R. I've searched the archive for the last year and tried to consult the manual pages for the following problem, but did not find an answer. I want to sort an array by the index values. Here is the array acc.gp.bl.wtmn Gp17 Gp4 1 0.5703125 0.6406250 10 0.7812500 0.7109375 11 0.8046875 0.7343750 12 0.8359375 0.7890625 13 0.8515625 0.7109375 14 0.8281250 0.7343750 15 0.8671875 0.7812500 16 0.8125000 0.7578125 17 0.7734375 0.750 18 0.800 0.780 19 0.870 0.730 2 0.8046875 0.7265625 20 0.830 0.740 21 0.750 0.800 22 0.770 0.760 23 0.820 0.780 24 0.760 0.740 25 0.810 0.800 3 0.7578125 0.7812500 4 0.8203125 0.7890625 5 0.7890625 0.7421875 6 0.7265625 0.7812500 7 0.8125000 0.7421875 8 0.8515625 0.7265625 9 0.8203125 0.6953125 My question is: How do I sort by the first index (the values are 1:25) without losing the associated values per index value for the two columns(Gp17 and Gp4). I want ascending order (1:25) of the index values. I think the `first column' is the row names. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] test for two samples
On 4 Feb 2003 at 15:27, Rado Bonk wrote: You should really give more details, i.e. which model did you fit? If it is a linear model with intercept, the residuals theoretically have sum zero, and for a non-linear model the sum should be close to zero. Comparing means of residuals doesn't seem to make much sense. Kjetil Halvorsen Hi R-users, My question is more methodological one, rather than technical. I have to samples representing residuals based on two measurements techniques (resid1,resid2; n=69). I need to compare two samples, to reject one technique (the worse one), and to keep the one which gave lower residuals (better one). What to look for? What should I analyse? Means, variance, std. deviations? Based on preliminary EDA: mean_resid1 mean_resid2 #I would reject resid2 technique stdev_resid1 stdev_resid2 #I would reject resid1 technique var_resid1 var_resid2 #I would reject resid1 technique Based on means I would reject resid2 technique, but based on analyses of stdev. and variance I would reject resid1 technique. How to deal with that problem? What is proper statist. atrribute to look for? Should I use t.test()? Best regards, Rado Bonk -- Radoslav Bonk M.S. Dept. of Physical Geography and Geoecology Faculty of Sciences, Comenius University Mlynska Dolina 842 15, Bratislava, SLOVAKIA tel: +421 905 968 127 e-mail: [EMAIL PROTECTED] __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] SORTING Arrays by index value
On Tue, 4 Feb 2003, Mark G Orr wrote: My question is: How do I sort by the first index (the values are 1:25) without losing the associated values per index value for the two columns(Gp17 and Gp4). I want ascending order (1:25) of the index values. order() -thomas __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] SORTING Arrays by index value
On 02/04/03 11:46, Mark G Orr wrote: Hello, I'm somewhat new to R. I've searched the archive for the last year and tried to consult the manual pages for the following problem, but did not find an answer. I want to sort an array by the index values. Here is the array Looks like a matrix (which is, I guess, a type of array). To sort by the first column, try acc.gp.bl.wtmn[order(acc.gp.bl.wtmn[,1],] acc.gp.bl.wtmn Gp17 Gp4 1 0.5703125 0.6406250 10 0.7812500 0.7109375 11 0.8046875 0.7343750 12 0.8359375 0.7890625 13 0.8515625 0.7109375 14 0.8281250 0.7343750 15 0.8671875 0.7812500 16 0.8125000 0.7578125 17 0.7734375 0.750 18 0.800 0.780 19 0.870 0.730 2 0.8046875 0.7265625 20 0.830 0.740 21 0.750 0.800 22 0.770 0.760 23 0.820 0.780 24 0.760 0.740 25 0.810 0.800 3 0.7578125 0.7812500 4 0.8203125 0.7890625 5 0.7890625 0.7421875 6 0.7265625 0.7812500 7 0.8125000 0.7421875 8 0.8515625 0.7265625 9 0.8203125 0.6953125 My question is: How do I sort by the first index (the values are 1:25) without losing the associated values per index value for the two columns(Gp17 and Gp4). I want ascending order (1:25) of the index values. Thank you in advance. -Mark Orr Postdoctoral Fellow Psychology Dept. Carnegie Mellon Univ. Pittsburgh, PA 15213 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help -- Jonathan Baron, Professor of Psychology, University of Pennsylvania R page: http://finzi.psych.upenn.edu/ __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] SORTING Arrays by index value
This should do it: acc.gp.bl.wtmn[order(as.numeric(row.names(acc.gp.bl.wtmn))),] (This is not completely straightforward because in a dataframe, row names are almost always stored as character vectors, which means that you need to convert the row names to numeric values before calling order()) -- Tony Plate At Tuesday 11:46 AM 2/4/2003 -0500, Mark G Orr wrote: Hello, I'm somewhat new to R. I've searched the archive for the last year and tried to consult the manual pages for the following problem, but did not find an answer. I want to sort an array by the index values. Here is the array acc.gp.bl.wtmn Gp17 Gp4 1 0.5703125 0.6406250 10 0.7812500 0.7109375 11 0.8046875 0.7343750 12 0.8359375 0.7890625 13 0.8515625 0.7109375 14 0.8281250 0.7343750 15 0.8671875 0.7812500 16 0.8125000 0.7578125 17 0.7734375 0.750 18 0.800 0.780 19 0.870 0.730 2 0.8046875 0.7265625 20 0.830 0.740 21 0.750 0.800 22 0.770 0.760 23 0.820 0.780 24 0.760 0.740 25 0.810 0.800 3 0.7578125 0.7812500 4 0.8203125 0.7890625 5 0.7890625 0.7421875 6 0.7265625 0.7812500 7 0.8125000 0.7421875 8 0.8515625 0.7265625 9 0.8203125 0.6953125 My question is: How do I sort by the first index (the values are 1:25) without losing the associated values per index value for the two columns(Gp17 and Gp4). I want ascending order (1:25) of the index values. Thank you in advance. -Mark Orr Postdoctoral Fellow Psychology Dept. Carnegie Mellon Univ. Pittsburgh, PA 15213 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] forecast
Dear helpers I have a 55 observations of a time series that I want to make predictions 17 steps ahead. I read that it is possible to use neural networks to do that. How can I do that with R? Luis -- Kit SAPO.ADSL.PT Apenas 50 . Adira já em http://www.sapo.pt/kitadsl __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] UltraEdit syntax highlighting
Hello everyone... I was curious if anyone had an UltraEdit (syntax highlighting) wordfile for R. The UltraEdit webpage previously made available an R wordfile on their webpage, however, it is no longer posted. Thanks in advance... Jason *** Jason C. Fisher UCLA Graduate Student Civil Environmental Engineering Dept. 5731 Boelter Hall Box 951593 Los Angeles, CA 90095-1593 Phone Number: (310) 825-2292 Email: [EMAIL PROTECTED] *** __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] testing slope
Hi all, I try to test a linear slope using offset. I have: m2 - glm(Y~X*V) summary(m2) Call: glm(formula = Y ~ X * V) Deviance Residuals: Min1QMedian3Q Max -2.01688 -0.56028 0.05224 0.53213 3.60216 Coefficients: Estimate Std. Error t value Pr(|t|) (Intercept) 1.3673 0.8476 1.613 0.119788 X 4.0235 0.1366 29.453 2e-16 *** Vn2 0.9683 1.1987 0.808 0.427131 Vn3 4.6043 1.1987 3.841 0.000787 *** X:Vn2 4.1108 0.1932 21.279 2e-16 *** X:Vn3-4.0069 0.1932 -20.740 2e-16 *** --- Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1 (Dispersion parameter for gaussian family taken to be 1.53955) Null deviance: 15303.977 on 29 degrees of freedom Residual deviance:36.949 on 24 degrees of freedom AIC: 105.39 Number of Fisher Scoring iterations: 2 It is clear that X slope is diferent of Zero. X 4.0235 0.1366 29.453 2e-16 *** It is too clear that X:Vn2's slope is diferent of X's slope and diferent of Zero, because is greater than X'slope. X:Vn2 4.1108 0.1932 21.279 2e-16 *** But, the X:Vn3' slope is different of X'slope, but not necessarily different of Zero. How I make to introduce this parameter in a new model for test? An offset only with Vn3 slope??? I try: m2 - glm(Y~V*offset(0*X)) m2 - glm(Y~X*V+V*offset(0*X)) m2 - glm(Y~V:X+V*offset(0*X)) but neither work :(( Thanks for all. Ronaldo -- If you live in a country run by committee, be on the committee. -- Graham Summer -- | //|\\ [*][***] || ( õ õ ) [Ronaldo Reis Júnior ][PentiumIII-600 ] | V [ESALQ/USP-Entomologia, CP-09 ][HD: 30 + 10 Gb ] || / l \ [13418-900 Piracicaba - SP][RAM: 128 Mb] | /(lin)\ [Fone: 19-429-4199 r.229 ][Video: SiS620-8Mb ] ||/(linux)\ [[EMAIL PROTECTED] ][Modem: Pctel-onboar] |/ (linux) \[ICQ#: 5692561][Kernel: 2.4.18 ] || ( x ) [*][***] ||| _/ \_Powered by Gnu/Debian Woody D+:) | Lxuser#: 205366 __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] rearranging rows
Dear all, I am working with a matrix structured as follows Factor 1Factor2 ... Country 1 Country 1 Country 2 Country 2 ... Country N Country N and I need to rearrange it according to the following scheme Factor 1Factor2 ... Country 2 Country 2 Country N Country N ... Country 1 Country 1 where countries are ordered accordingly to the average value of factor 1 correspondent to each country. What is the easy way of doing it? Many thanks in advance, Luca __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Re: [R] rearranging rows
On 5 Feb 2003 at 1:22, Luca De Benedictis wrote:
Well, you want to rearrange according to the mean of factor 1.
Factors are catecorical variables, and doesn't have means, so
I assume you really want to say a numerical variable.
Assuming your data is in a data frame with Country 1 etc levels of
a factor Country :
attach(your.data.frame)
Something like
means - tapply(Factor1, Country, mean)
s - sort(means)
na - names(s)
ns - vector(length=length(s))
for (i in 1:n) {
ns[i] - sum(Country==na[i])
}
names - rep(na, ns)
your.data.frame - your.data.frame[names,]
This is assuming that the different countries are contiguous
in the data frame, and is not tested. Surely somebody
have a nicer solution.
Kjetil Halvorsen
Dear all,
I am working with a matrix structured as follows
Factor 1Factor2 ...
Country 1
Country 1
Country 2
Country 2
...
Country N
Country N
and I need to rearrange it according to the following scheme
Factor 1Factor2 ...
Country 2
Country 2
Country N
Country N
...
Country 1
Country 1
where countries are ordered accordingly to the average value of factor 1
correspondent to each country.
What is the easy way of doing it?
Many thanks in advance,
Luca
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