Re: [R] How can I test temporal autocorrelation of binary data?

2005-11-01 Thread Pfaff, Bernhard Dr.

Depending on what you are really want to infer from the autocorrelations,
you want to consider the runs-test, too.

HTH,
Bernhard



If you mean you want to test that there is no autocorrelation,
then there is some information on using the Ljung-Box test on
such data in the working paper 'Robustness of the Ljung-Box
test and its rank equivalent' on the Burns Statistics website.

The executive summary is that the test seems to do okay as
long as one of the values is not too dominant.  What 'dominant'
means depends on the length of the series.

If some one has a better answer, I'm keen to hear it.


Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)

[EMAIL PROTECTED] wrote:

Hi,

I have a binary (o/1 - coded) data set and want to test it's
autocorrelation
structure. Is that function implemented in R?
Can I use the ACF - funtion with binary data?

Thanks for your help,
Daniel

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Re: [R] Help with try or tryCatch

2005-11-01 Thread David Scott
On Mon, 31 Oct 2005, McGehee, Robert wrote:

 It sounds like you want `try` with the argument `silent = TRUE`. This
 will allow you to keep running your program without errors. If you want
 to check if the line had an error, you can error control by seeing if
 the class of the resulting object is try-error. For example, let's say
 I wanted to make an error-proof `plus` function, such that trying a +
 2 would result in NA instead of an error.

 newPlus - function(x, y) {
   answer - try(x + y, silent = TRUE)
   if (class(answer) == try-error) return(NA) else return(answer)
 }


This approach worked. I had to define a test function of this sort outside 
of the loops and then call it within the loops with appropriate parameter 
values. Thanks for the assistance.

David Scott


---
David Scott Department of Statistics, Tamaki Campus
The University of Auckland, PB 92019
AucklandNEW ZEALAND
Phone: +64 9 373 7599 ext 86830 Fax: +64 9 373 7000
Email:  [EMAIL PROTECTED]


Graduate Officer, Department of Statistics

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[R] R2WinBUGS: Comparison to WinBUGS

2005-11-01 Thread Hadassa Brunschwig
Hi R-Users!

I know I posted the question before (see archives) but I have not been able to
find the mistake. Again using R2WinBUGS and WinBUGS does not yield the same
result (although to my opinion the commands are the same). The variance of the
parameters is much bigger and the parameter estimates are a bit different, too.
If anybody has the time and interest to get the files and data and see if he/she
has the same problems, I would be happy to provide these (and to discuss it
further). It seems though that it must be my mistake SOMEWHERE because nobody
else reported any problems yet... 

Thanks.

Hadassa
-- 

Hadassa Brunschwig
Birmannsgasse 10A
CH-4055 Basel
Switzerland
Phone: +41 78 797 6065
Email: [EMAIL PROTECTED]

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Re: [R] line vector plots

2005-11-01 Thread Jim Lemon
Eduardo Klein wrote:

  Hi Jim,
 
  Thanks for the tip, but I really need the same polar chart but over a 
line no in a circle. I didn't find it on the plotrix package.
 
Hmmm, are you looking for something like this?

feather.plot-function(x,y,xpos,yref=0,use.arrows=FALSE,...) {
  if(missing(xpos)) xpos-1:length(x)
  xlim-range(x+xpos)
  ylim-range(y)
  plot(0,xlim=xlim,ylim=ylim,type=n)
  abline(h=yref)
  if(use.arrows) arrows(xpos,yref,xpos+x,y,length=0.1,...)
  else segments(xpos,yref,xpos+x,y,...)
}

where x and y are the components of the vectors and xpos is the 
positions on the time line? If so, I'll add that to plotrix - looks useful.

Jim

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[R] standard errors in summary.lm

2005-11-01 Thread Christoph Scherber
Dear R users,

If I have an aov object, how are the standard errors of the estimates in 
summary.lm calculated?

Using treatment contrasts, I would like to use the estimated differences 
in mean values (intercepts) to calculate the mean values per factor 
level, and for these mean values I´f like to use the model output to 
calculate the standard errors.

Many thanks for your help!
Regards,
Christoph.

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[R] How to change label size in a plot

2005-11-01 Thread Fiona Mc Cahey
Dear all,

I have created a plot like this:

matrix-read.table(G:\\my documents\\names.txt,header=T)
hc-hclust(dist(matrix)^2,cen)
memb-cutree(hc,k=10)
plot(hc,col=black)

This prints out a dendrogram with labels, but the text of the labels is
large, so they overlap and are unreadable. How can I decrease the size of
the lable text on a dendrogram so that it does not overlap and is therefore
readable?

I know the question is similar to that posted by Michael Schmitt on 19 March
2005, but as far as I can see, the question was not answered.

Many Thanks,

Fiona

Fíona Mc Cahey

Department of Chemistry
University of Cambridge
Lensfield Road
Cambridge, CB2 1EW

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[R] Doubly Non-Central F-Distribution

2005-11-01 Thread Viechtbauer Wolfgang (STAT)
Hello All,

Has anyone written a function for the distribution function of a
*doubly* non-central F-distribution? I looked through the archives, but
didn't find anything. Thanks!

Wolfgang

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Re: [R] R Graphs in Powerpoint

2005-11-01 Thread Randall C Johnson {Contr.]
Have you tried using Keynote? It is a part of iWork and handles pdf files
properly (you can resize as many times as you want without loosing image
quality). It also will convert to and from Power Point. I would highly
recommend it to anyone using OS X.

Randy


On 10/31/05 6:14 PM, Jarrett Byrnes [EMAIL PROTECTED] wrote:

 Hey, all.  Quick question.  I'm attempting to use some of the great
 graphs generated in R for an upcoming talk that I'm writing in
 Powerpoint.  Copying and pasting (I'm using OSX) yields graphs that
 look great in Powerpoint - until I resize them.  Then fonts, points,
 and lines all become quite pixelated and blurry.  Even if I size the
 window properly first, and then copy and paste in the graph, when I
 then view the slideshow, the graphs come out pixelated and blurry.
 
 Is there any good solution to this, or is this some fundamental
 incompatibility that I can't get around?
 
 -Jarrett
 
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~~
Randall C Johnson
Bioinformatics Analyst
SAIC-Frederick, Inc (Contractor)
Laboratory of Genomic Diversity
NCI-Frederick
P.O. Box B
1050 Boyles Street
Bldg 560, Rm 11-85
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Phone: (301) 846-1304
Fax: (301) 846-1686
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Re: [R] Help with try or tryCatch

2005-11-01 Thread Liaw, Andy
Just a bit of nitpicking:  I believe the preferred way is to see if the
result of try() _inherits_ the try-error class.  This applies to all S3
classes.  I.e., the relevant line should be something like:

if (inherits(answer, try-error)) ...

Andy

 From: David Scott
 
 On Mon, 31 Oct 2005, McGehee, Robert wrote:
 
  It sounds like you want `try` with the argument `silent = 
 TRUE`. This
  will allow you to keep running your program without errors. 
 If you want
  to check if the line had an error, you can error control by 
 seeing if
  the class of the resulting object is try-error. For 
 example, let's say
  I wanted to make an error-proof `plus` function, such that 
 trying a +
  2 would result in NA instead of an error.
 
  newPlus - function(x, y) {
  answer - try(x + y, silent = TRUE)
  if (class(answer) == try-error) return(NA) else return(answer)
  }
 
 
 This approach worked. I had to define a test function of this 
 sort outside 
 of the loops and then call it within the loops with 
 appropriate parameter 
 values. Thanks for the assistance.
 
 David Scott
 
 
 ---
 David Scott   Department of Statistics, Tamaki Campus
   The University of Auckland, PB 92019
   AucklandNEW ZEALAND
 Phone: +64 9 373 7599 ext 86830   Fax: +64 9 373 7000
 Email:[EMAIL PROTECTED]
 
 
 Graduate Officer, Department of Statistics
 
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Re: [R] write.table call

2005-11-01 Thread Liaw, Andy
RTFM, in particular the CSV Files section of ?write.table.

BTW, R itself does not write xls files.

Andy

 From: Li,Qinghong,ST.LOUIS,Molecular Biology
 
 Hi,
 
 I use write.table() to write a file to an external xls file. 
 the column names left-shift one position in output file. I 
 check with col.names() row.names(), the file is fine. How to 
 prevent the shifting? 
 
 I71   I111I304I307I305I306I114I72 
 AFFX-BioB-5_at6.66435 6.7878075.335962
 5.250163  6.47423 5.8821045.9651096.591687195 
 AFFX-BioB-M_at6.1632275.965427
 4.665569  2.7435316.0972445.77137 
 5.113683  6.314003982 
 
 Thanks,
 Johnny
 
   [[alternative HTML version deleted]]
 
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Re: [R] Greek letters in plots

2005-11-01 Thread Barry Rowlingson
Johanna Hardin wrote:

 
 *  paste(rho=, cor2[i])

 will produce a label of rho=0.74, or whatever.  But if I use
 'substitute' or 'evaluate' commands in order to get a real Greek letter,
 I lose the ability to paste it with a data value.

  Use parse() to turn that text into an expression. And use '==':

   rho=0.78
   plot(1:10,main=parse(text=paste(rho == ,rho)))

Not sure where your label is going, but the same thing should work for 
axes and text labels.

Baz

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Re: [R] Greek letters in plots

2005-11-01 Thread Marc Schwartz
On Tue, 2005-11-01 at 05:20 -0800, Johanna Hardin wrote:
 Hi, all.  I know that this is probably something that others have asked,
 but I can't find a reference in either the FAQ or the help pages.
 
 I'm trying to find a way to put Greek letters as a label of the plot
 *with* a value from the data.  Previously I've used pasted and the word
 rho.

 *  paste(rho=, cor2[i])
 
 will produce a label of rho=0.74, or whatever.  But if I use
 'substitute' or 'evaluate' commands in order to get a real Greek letter,
 I lose the ability to paste it with a data value.

 Any ideas?

 Thanks, Jo

Try this:

  cor2 - 0.74
  plot(1:5)
  title(bquote(rho == .(cor2)))

See ?plotmath and ?bquote for more information, noting the use of
the .(Variable) syntax for variable substitution.

HTH,

Marc Schwartz

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Re: [R] R2WinBUGS: Comparison to WinBUGS

2005-11-01 Thread Uwe Ligges
Hadassa Brunschwig wrote:
 Hi R-Users!
 
 I know I posted the question before (see archives) but I have not been able to
 find the mistake. Again using R2WinBUGS and WinBUGS does not yield the same
 result (although to my opinion the commands are the same). The variance of the
 parameters is much bigger and the parameter estimates are a bit different, 
 too.
 If anybody has the time and interest to get the files and data and see if 
 he/she
 has the same problems, I would be happy to provide these (and to discuss it
 further). It seems though that it must be my mistake SOMEWHERE because nobody
 else reported any problems yet... 
 
 Thanks.
 
 Hadassa

Please send me your data in a private message. Perhaps we (let me 
include Sibylle Sturtz here, since she certainly knows better) find some 
time during the next week to look into it.

Uwe Ligges

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Re: [R] Greek letters in plots

2005-11-01 Thread Thomas Lumley
On Tue, 1 Nov 2005, Marc Schwartz wrote:

 On Tue, 2005-11-01 at 05:20 -0800, Johanna Hardin wrote:
 Hi, all.  I know that this is probably something that others have asked,
 but I can't find a reference in either the FAQ or the help pages.

FAQ 7.13

and the example in ?plotmath that starts
  ## How to combine math and numeric variables :


-thomas

Thomas Lumley   Assoc. Professor, Biostatistics
[EMAIL PROTECTED]   University of Washington, Seattle

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Re: [R] Greek letters in plots

2005-11-01 Thread Peter Dalgaard
Marc Schwartz [EMAIL PROTECTED] writes:

 Try this:
 
   cor2 - 0.74
   plot(1:5)
   title(bquote(rho == .(cor2)))
 
 See ?plotmath and ?bquote for more information, noting the use of
 the .(Variable) syntax for variable substitution.

Yep, bquote() is nice. Other solutions include

  substitute(rho == . , list( . = cor2))

which I suppose is pretty much what bquote does internally
-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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[R] Unexpected result from binary greater than operator

2005-11-01 Thread chris . bodily
Hi All,

I recently encountered results that I did not expect, exhibited by the
following code snippet:

test - function() {
minX - 4.2
min0 - 4.1
sigmaG - 0.1
Diff - minX-min0
print(c(Diff=Diff,sigmaG=sigmaG))
cat(is Diff  sigmaG?:, Diff  sigmaG,\n)
cat(is (4.2 - 4.1)  0.1?:,(4.2 - 4.1)  0.1,\n)
cat(is 0.1  0.1?:, 0.10.1,\n)
}

When I execute the above function I get the following:
 test()
  Diff sigmaG
   0.10.1
is Diff  sigmaG?: TRUE
is (4.2 - 4.1)  0.1?: TRUE
is 0.1  0.1?: FALSE

Can someone please help me understand why R returns TRUE for (4.2 - 4.1) 
0.1 ?

Thanks so much,
Chris


I'm running the precompiled R-2.2.0 binary for Windows on WinXP Pro SP1.

Sys.getlocale()
LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
States.1252;LC_MONETARY=English_United
States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252

version
 _
platform i386-pc-mingw32
arch i386
os   mingw32
system   i386, mingw32
status
major2
minor2.0
year 2005
month10
day  06
svn rev  35749
language R

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Re: [R] Unexpected result from binary greater than operator

2005-11-01 Thread Duncan Murdoch
On 11/1/2005 11:15 AM, [EMAIL PROTECTED] wrote:

 Can someone please help me understand why R returns TRUE for (4.2 - 4.1) 
 0.1 ?

Rounding error.  See the FAQ item

7.31 Why doesn't R think these numbers are equal?

The only numbers that can be represented exactly in R's numeric type are 
integers and fractions whose denominator is a power of 2. Other numbers 
have to be rounded to (typically) 53 binary digits accuracy. As a 
result, two floating point numbers will not reliably be equal unless 
they have been computed by the same algorithm, and not always even then. 
For example

  R a - sqrt(2)
  R a * a == 2
  [1] FALSE
  R a * a - 2
  [1] 4.440892e-16

The function all.equal() compares two objects using a numeric tolerance 
of .Machine$double.eps ^ 0.5. If you want much greater accuracy than 
this you will need to consider error propagation carefully.

For more information, see e.g. David Goldberg (1991), “What Every 
Computer Scientist Should Know About Floating-Point Arithmetic”, ACM 
Computing Surveys, 23/1, 5–48, also available via 
http://docs.sun.com/source/806-3568/ncg_goldberg.html

Duncan Murdoch

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Re: [R] Unexpected result from binary greater than operator

2005-11-01 Thread Sundar Dorai-Raj


[EMAIL PROTECTED] wrote:
 Hi All,
 
 I recently encountered results that I did not expect, exhibited by the
 following code snippet:
 
 test - function() {
 minX - 4.2
 min0 - 4.1
 sigmaG - 0.1
 Diff - minX-min0
 print(c(Diff=Diff,sigmaG=sigmaG))
 cat(is Diff  sigmaG?:, Diff  sigmaG,\n)
 cat(is (4.2 - 4.1)  0.1?:,(4.2 - 4.1)  0.1,\n)
 cat(is 0.1  0.1?:, 0.10.1,\n)
 }
 
 When I execute the above function I get the following:
 
test()
 
   Diff sigmaG
0.10.1
 is Diff  sigmaG?: TRUE
 is (4.2 - 4.1)  0.1?: TRUE
 is 0.1  0.1?: FALSE
 
 Can someone please help me understand why R returns TRUE for (4.2 - 4.1) 
 0.1 ?
 
 Thanks so much,
 Chris
 
 
 I'm running the precompiled R-2.2.0 binary for Windows on WinXP Pro SP1.
 
 
Sys.getlocale()
 
 LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
 States.1252;LC_MONETARY=English_United
 States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252
 
 
version
 
  _
 platform i386-pc-mingw32
 arch i386
 os   mingw32
 system   i386, mingw32
 status
 major2
 minor2.0
 year 2005
 month10
 day  06
 svn rev  35749
 language R
 

Seems like this is coming up about once a week. See FAQ 7.31.

http://cran.r-project.org/doc/FAQ/R-FAQ.html

Hint:

print(4.2 - 4.1, digits = 16)

--sundar

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Re: [R] Unexpected result from binary greater than operator

2005-11-01 Thread Peter Dalgaard
[EMAIL PROTECTED] writes:

 Hi All,
 
 I recently encountered results that I did not expect, exhibited by the
 following code snippet:
 
 test - function() {
 minX - 4.2
 min0 - 4.1
 sigmaG - 0.1
 Diff - minX-min0
 print(c(Diff=Diff,sigmaG=sigmaG))
 cat(is Diff  sigmaG?:, Diff  sigmaG,\n)
 cat(is (4.2 - 4.1)  0.1?:,(4.2 - 4.1)  0.1,\n)
 cat(is 0.1  0.1?:, 0.10.1,\n)
 }
 
 When I execute the above function I get the following:
  test()
   Diff sigmaG
0.10.1
 is Diff  sigmaG?: TRUE
 is (4.2 - 4.1)  0.1?: TRUE
 is 0.1  0.1?: FALSE
 
 Can someone please help me understand why R returns TRUE for (4.2 - 4.1) 
 0.1 ?

Section 7.31 in the FAQ should help:

http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
 


-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] Unexpected result from binary greater than operator

2005-11-01 Thread Petr Pikal
Hi.
Easy. Regardless of OS and R version answer is

binary representation of fractions.

(4.2-4.1).1
[1] TRUE

but

(4.3-4.2).1
[1] FALSE

 print(4.3-4.2, digits=20)
[1] 0.099645

You can not expect precise results using not precise computers.

Use e.g. round

round(4.3-4.2).1
[1] FALSE

HTH
Petr


On 1 Nov 2005 at 9:15, [EMAIL PROTECTED] wrote:

To: r-help@stat.math.ethz.ch
From:   [EMAIL PROTECTED]
Date sent:  Tue, 1 Nov 2005 09:15:50 -0700
Subject:[R] Unexpected result from binary greater than operator

 Hi All,
 
 I recently encountered results that I did not expect, exhibited by the
 following code snippet:
 
 test - function() {
 minX - 4.2
 min0 - 4.1
 sigmaG - 0.1
 Diff - minX-min0
 print(c(Diff=Diff,sigmaG=sigmaG))
 cat(is Diff  sigmaG?:, Diff  sigmaG,\n)
 cat(is (4.2 - 4.1)  0.1?:,(4.2 - 4.1)  0.1,\n)
 cat(is 0.1  0.1?:, 0.10.1,\n)
 }
 
 When I execute the above function I get the following:
  test()
   Diff sigmaG
0.10.1
 is Diff  sigmaG?: TRUE
 is (4.2 - 4.1)  0.1?: TRUE
 is 0.1  0.1?: FALSE
 
 Can someone please help me understand why R returns TRUE for (4.2 -
 4.1)  0.1 ?
 
 Thanks so much,
 Chris
 
 
 I'm running the precompiled R-2.2.0 binary for Windows on WinXP Pro
 SP1.
 
 Sys.getlocale()
 LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
 States.1252;LC_MONETARY=English_United
 States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252
 
 version
  _
 platform i386-pc-mingw32
 arch i386
 os   mingw32
 system   i386, mingw32
 status
 major2
 minor2.0
 year 2005
 month10
 day  06
 svn rev  35749
 language R
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide!
 http://www.R-project.org/posting-guide.html

Petr Pikal
[EMAIL PROTECTED]

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Re: [R] Unexpected result from binary greater than operator

2005-11-01 Thread Andy Bunn
Look at ?all.equal and ?identical as well as searching the archives for
those terms. You'll find many an illuminating thread on precision, floating
point arithmetic and other wonders.

minX - 4.2
min0 - 4.1
sigmaG - 0.1
Diff - minX-min0
all.equal(Diff, sigmaG)
identical(Diff, sigmaG)

HTH, Andy

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[R] dataframe conversion

2005-11-01 Thread Pieter Provoost
The data structures in R are still very puzzling to me. Can anyone tell 
me how I can easily convert these two dataframes to one single dataframe 
with two columns (mean and sd) with 7 rows?

  meanprofile
   V1   V2   V3   V4   V5   V6   V7
2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
  sdprofile
   V1   V2   V3   V4   V5   V6   V7
310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017

Thanks!
Pieter

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Re: [R] dataframe conversion

2005-11-01 Thread Andy Bunn
 The data structures in R are still very puzzling to me. Can anyone tell 
 me how I can easily convert these two dataframes to one single dataframe 
 with two columns (mean and sd) with 7 rows?
 
   meanprofile
V1   V2   V3   V4   V5   V6   V7
 2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
   sdprofile
V1   V2   V3   V4   V5   V6   V7
 310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017

There are several ways to go about this. Here's one:
t(rbind(meanprofile, sdprofile))

?rbind and ?t
HTH, Andy

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Re: [R] dataframe conversion

2005-11-01 Thread Uwe Ligges
Pieter Provoost wrote:
 The data structures in R are still very puzzling to me. Can anyone tell 
 me how I can easily convert these two dataframes to one single dataframe 
 with two columns (mean and sd) with 7 rows?
 
   meanprofile
V1   V2   V3   V4   V5   V6   V7
 2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
   sdprofile
V1   V2   V3   V4   V5   V6   V7
 310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017


This is quite an unusual task, because you won't have data structure in 
a data.frame most of the times. In particular, you cannot make a row 
from a data.frame to a column generally.

In this case, we just convert the data.frame to matrix. I think most 
easily you can write:

   dat - t(rbind(meanprofile, sdprofile))
   colnames(dat) - c(meanprofile, sdprofile)

Uwe Ligges



 Thanks!
 Pieter
 
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Re: [R] How to change label size in a plot

2005-11-01 Thread Uwe Ligges
Fiona Mc Cahey wrote:

 Dear all,
 
 I have created a plot like this:
 
 matrix-read.table(G:\\my documents\\names.txt,header=T)
 hc-hclust(dist(matrix)^2,cen)
 memb-cutree(hc,k=10)
 plot(hc,col=black)

What about specifying argument cex?

Uwe Ligges


 This prints out a dendrogram with labels, but the text of the labels is
 large, so they overlap and are unreadable. How can I decrease the size of
 the lable text on a dendrogram so that it does not overlap and is therefore
 readable?
 
 I know the question is similar to that posted by Michael Schmitt on 19 March
 2005, but as far as I can see, the question was not answered.
 
 Many Thanks,
 
 Fiona
 
 Fíona Mc Cahey
 
 Department of Chemistry
 University of Cambridge
 Lensfield Road
 Cambridge, CB2 1EW
 
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Re: [R] Build R package with shared library

2005-11-01 Thread Uwe Ligges
Marcelo Damasceno wrote:

 Hello to all,
 
 I am try to build a package, I do the follow commands: R CMD check pack,
 R CMD pack build and run OK, no errors. I put my shared library in package
 subdirectory R, src, but it is not put a shared library .so in directory
 /usr/lib/R/library/pack/lib. Below is my code :


Hmmm. You have to INSTALL a package. Shared libraries will be build on 
the fly while installing. Hence I think you have not read the mnauals 
carefully enough.

You can put C and Fortran files in ./src, the shared library will be 
installed during
   R CMD INSTALL pack
into the ./lib directory.


 dyn.load(pack.so,PACKAGE=pack)
 argc-2
 argv-c(./test,file1)
 .C(main,as.integer(argc),as.vector(argv),PACKAGE=pack)

You really want to pass a directory and a filename to your shared 
library? So, why are you using R in between?

Uwe Ligges



 What am I doing wrong?
 
 --
 Marcelo Damasceno de Melo
 Graduando em Ciência da Computação
 Departamento de Tecnologia da Informação - TCI
 Universidade Federal de Alagoas - UFAL
 Maceió - Alagoas - Brasil
 Projeto CoCADa - Construção do Conhecimento por Agrupamento de dados
 +55 82 8801-2119
 
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[R] kernel smoothing

2005-11-01 Thread Zhu, Chao \(UMC-Student\)
Dear all,
 
I want to use kernel estimator to smooth some step funtions such as the 
empirical distribution and hazard function in survival analysis. Is there a 
function or package to deal with it in R? 
How do I use it?
 
Thanks for your help.
 
Jimmy

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[R] glmmpql and lmer keep failing

2005-11-01 Thread Roel de Jong
Hello,

I'm running a simulation study of a multilevel model with binary 
response using the binomial probit link. It is a random intercept and 
random slope model.  GLMMPQL and lmer fail to converge on a 
*significant* portion of the *generated* datasets, while MlWin gives 
reasonable estimates on those datasets. This is unacceptable. Does 
anyone has similar experiences?

Regards,
Roel de Jong

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Re: [R] dataframe conversion

2005-11-01 Thread Gabor Grothendieck
On 11/1/05, Uwe Ligges [EMAIL PROTECTED] wrote:
 Pieter Provoost wrote:
  The data structures in R are still very puzzling to me. Can anyone tell
  me how I can easily convert these two dataframes to one single dataframe
  with two columns (mean and sd) with 7 rows?
 
meanprofile
 V1   V2   V3   V4   V5   V6   V7
  2292.001 2178.620 1654.310 1784.004 1160.052 1142.061 1046.675
sdprofile
 V1   V2   V3   V4   V5   V6   V7
  310.6714 347.2072 197.2464 532.3916 161.2955 227.3634 108.5017


 This is quite an unusual task, because you won't have data structure in
 a data.frame most of the times. In particular, you cannot make a row
 from a data.frame to a column generally.

 In this case, we just convert the data.frame to matrix. I think most
 easily you can write:

   dat - t(rbind(meanprofile, sdprofile))
   colnames(dat) - c(meanprofile, sdprofile)


Or perhaps:

data.frame(meanprofile = unlist(meanprofile), sdprofile = unlist(sdprofile))

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[R] percent rank by an index key?

2005-11-01 Thread t c

What is the easiest way to calculate a percent rank “by” an index key?

 

Foe example, I have a dataset with 3 fields:

 

Year,State,   Income ,

 

I wish to calculate the rank, by year, by state.

I also wish to calculate the “percent rank”, where I define percent rank as 
rank/n.

 

(n is the number of numeric data points within each date-state grouping.)

 

 

This is what I am currently doing:

 

1.  I create a “group by” field by using the paste function to combine date and 
state into a field called date_state.   I then use the rank function to 
calculate the rank by date, by state. 

 

2. I then add a field called “one” that I set to 1 if the value in income is 
numeric and to 0 if it is not.

 

3. I then take an aggregate sum of “one”.  This gives me a count (n) for each 
date-state grouping.

 

 

4. I next use merge to add this count to the table.

 

5. Finally, I calculate the percent rank.

 

Pr-rank/n

 

The merge takes quite a bit of time to process. 

 

Is there an easier/more efficient way to calculate the percent rank?

 

 



-

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Re: [R] kernel smoothing

2005-11-01 Thread Berton Gunter
Please, please read the docs! That's what they're for.

RsiteSearch(smoothing)
help.search(smoothing)

-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
 
The business of the statistician is to catalyze the scientific learning
process.  - George E. P. Box
 
 

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED] On Behalf Of Zhu, 
 Chao (UMC-Student)
 Sent: Tuesday, November 01, 2005 8:57 AM
 To: r-help@stat.math.ethz.ch
 Subject: [R] kernel smoothing
 
 Dear all,
  
 I want to use kernel estimator to smooth some step funtions 
 such as the empirical distribution and hazard function in 
 survival analysis. Is there a function or package to deal 
 with it in R? 
 How do I use it?
  
 Thanks for your help.
  
 Jimmy
 


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Re: [R] percent rank by an index key?

2005-11-01 Thread Sundar Dorai-Raj


t c wrote:
 What is the easiest way to calculate a percent rank “by” an index key?
 
  
 
 Foe example, I have a dataset with 3 fields:
 
  
 
 Year,State,   Income ,
 
  
 
 I wish to calculate the rank, by year, by state.
 
 I also wish to calculate the “percent rank”, where I define percent rank as 
 rank/n.
 
  
 
 (n is the number of numeric data points within each date-state grouping.)
 
  
 
  
 
 This is what I am currently doing:
 
  
 
 1.  I create a “group by” field by using the paste function to combine date 
 and state into a field called date_state.   I then use the rank function to 
 calculate the rank by date, by state. 
 
  
 
 2. I then add a field called “one” that I set to 1 if the value in income is 
 numeric and to 0 if it is not.
 
  
 
 3. I then take an aggregate sum of “one”.  This gives me a count (n) for each 
 date-state grouping.
 
  
 
  
 
 4. I next use merge to add this count to the table.
 
  
 
 5. Finally, I calculate the percent rank.
 
  
 
 Pr-rank/n
 
  
 
 The merge takes quite a bit of time to process. 
 
  
 
 Is there an easier/more efficient way to calculate the percent rank?
 

How about using ?by:

set.seed(100)
# fake data set, replace with your own
# Subject is just a dummy to produce replicates
x - expand.grid(Year = 2000:2005,
  State = c(TX, AL),
  Subject = 1:10)
x$Income - floor(runif(NROW(x)) * 10)

r - by(x$Income, x[c(Year, State)],
 function(x) {
   r - rank(x)
   n - length(x)
   cbind(Rank = r, PRank = r/n)
 })
x - cbind(x, do.call(rbind, r))

HTH,

--sundar

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Re: [R] kernel smoothing

2005-11-01 Thread Liaw, Andy
Smoothing CDF or survival functions are not quite the same as usual
scatterplot smoothing, at least because of the monotonicity contraint.  I
don't know of kernel methods for smoothing such functions, but I believe
people have used splines.  I'm no expert though.  It's best for you to
consult an expert or search the literature.

Andy

 From: Zhu, Chao (UMC-Student)
 
 Dear all,
  
 I want to use kernel estimator to smooth some step funtions 
 such as the empirical distribution and hazard function in 
 survival analysis. Is there a function or package to deal 
 with it in R? 
 How do I use it?
  
 Thanks for your help.
  
 Jimmy
 


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[R] function effect and standard error

2005-11-01 Thread Emilie Berthiaume
Hi list!

I did the following regression:
reg1 -  glm(alti~sp + ovent + vivent + nuage, family=gaussian, data=meteo1)

I was interested in knowing the effect of the species (sp) in reg1 and so I 
used the function «effect»:

effect.sp - effect (sp, reg1, se=TRUE)

with this output:
sp
  AK   BW   NH   OS   RT   SS 
2.730101 2.885363 2.753774 2.750311 3.084606 2.834390 

If I enter the following command:
effect.sp$se
I get this output:
1253   3100488514   6100 
0.07924610 0.06713200 0.11493178 0.13106639 0.05252749 0.04208334 

My question is:  Do the numbers on the second line of this output represent the 
standard error?  What do the numbers on the top line represent?

Thank you,

Emilie Berthiaume
graduate student
Biology Departement
Université de Sherbrooke
2500 boul. de l'Université
Sherbrooke, Québec
J1K 2R1 CANADA

Tél: 1-819-821-8000 poste 2059
Fax: 1-819-821-8049
[EMAIL PROTECTED]
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Re: [R] Doubly Non-Central F-Distribution

2005-11-01 Thread Ken Kelley
Hi Wolfgang.

I would be surprised if a doubly noncentral F-distribution function is 
available (and encourage you to check its accuracy if it is). Although R 
allows pf() to have a noncentral value specified, the results are not 
always accurate. I posted about this about a week ago (10/24/05) and 
didn't hear anything back regarding the accuracy issue. The bug I 
reported is here (# 8251): 
http://viggo.kubism.ku.dk/cgi-bin/R/Accuracy?id=8251;user=guest

I am very interested in (singularly) noncentral F-distribution 
functions, so I too would like to learn of a doubly noncentral 
F-distribution function (since the singularly noncentral F is a special 
case of the doubly noncentral F; or learn of an alternative or fix to 
pf() as it now stands).

Have a good day,
Ken

Viechtbauer Wolfgang (STAT) wrote:
 Hello All,
 
 Has anyone written a function for the distribution function of a
 *doubly* non-central F-distribution? I looked through the archives, but
 didn't find anything. Thanks!
 
 Wolfgang
 
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-- 
Ken Kelley, Ph.D.
Inquiry Methodology Program
Indiana University
201 North Rose Avenue, Room 4004
Bloomington, Indiana 47405
http://www.indiana.edu/~kenkel

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[R] Error on read.table

2005-11-01 Thread Lars G. Johnsen

Hello

When trying to read a table from excel, the generated error message is not  
documented in the R data import document:

 v2 - read.table(v2-101-405-excel.txt, header=T,row.names=0)
Error in read.table(v2-101-405-excel.txt, header = T, row.names = 0) :
attempt to select less than one element

How do I proceed to resolve this problem?

thanks
Lars

Here are the first three out of around 500 rows in the file (missing data  
in Target.RESP col is marked as NA):

Subject Sex Age Gruppe  TypeTarget.CRESPTarget.RESP 
Target.RT   Prime.OnsetTime Target.OnsetTimeOrdning Ident
101 female  22  7   t   0   0   1520155074  158497  
101 145
101 female  22  9   o   0   1   3020161678  166005  
102 160

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Re: [R] function effect and standard error

2005-11-01 Thread John Fox
Dear Emilie,

This is, I think, the effect() function in the effects() package.

By the way, the model that you've fit with glm() is just a linear
model, and could also have been fit with lm().

For a model with this simple structure, effect() computes the adjusted
means for the factor sp, holding other predictors to their average
values. These effects are just fitted values under the model, and the
standard errors reported are for the fitted values.

For details, see the paper at
http://www.jstatsoft.org/counter.php?id=75url=v08/i15/effect-displays-revised.pdf.

I hope this helps.

John

On Tue, 1 Nov 2005 12:55:17 -0500
 Emilie Berthiaume [EMAIL PROTECTED] wrote:
 Hi list!
 
 I did the following regression:
 reg1 -  glm(alti~sp + ovent + vivent + nuage, family=gaussian,
 data=meteo1)
 
 I was interested in knowing the effect of the species (sp) in reg1
 and so I used the function «effect»:
 
 effect.sp - effect (sp, reg1, se=TRUE)
 
 with this output:
 sp
   AK   BW   NH   OS   RT   SS 
 2.730101 2.885363 2.753774 2.750311 3.084606 2.834390 
 
 If I enter the following command:
 effect.sp$se
 I get this output:
 1253   3100488514   6100 
 0.07924610 0.06713200 0.11493178 0.13106639 0.05252749 0.04208334
 
 
 My question is:  Do the numbers on the second line of this output
 represent the standard error?  What do the numbers on the top line
 represent?
 
 Thank you,
 
 Emilie Berthiaume
 graduate student
 Biology Departement
 Université de Sherbrooke
 2500 boul. de l'Université
 Sherbrooke, Québec
 J1K 2R1 CANADA
 
 Tél: 1-819-821-8000 poste 2059
 Fax: 1-819-821-8049
 [EMAIL PROTECTED]
   [[alternative HTML version deleted]]
 


John Fox
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox/

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Re: [R] Error on read.table

2005-11-01 Thread Marc Kirchner
Hello Lars,

from the read.table documentation:

row.names: a vector of row names.  This can be a vector giving the
  actual row names, or a single number giving the column of the
  table which contains the row names, or character string
  giving the name of the table column containing the row names.

Column numbering in R starts at 1 but you tell read.table to use the 0th column
- this is consitent with your error message.

The folowing works for me:

 x - read.table(bla, header=T)
 x
  SubjectSex Age Gruppe Type Target.CRESP Target.RESP Target.RT
1 101 female  22  7t0   0  1520
2 101 female  22  9o0   1  3020
  Prime.OnsetTime Target.OnsetTime Ordning Ident
1  155074   158497 101   145
2  161678   166005 102   160

-Marc

-- 

Dipl. Inform. Med. Marc Kirchner
Interdisciplinary Centre for Scientific Computing (IWR)
Multidimensional Image Processing
INF 368
University of Heidelberg
D-69120 Heidelberg
Tel: ++49-6221-54 87 97
Fax: ++49-6221-54 88 50
[EMAIL PROTECTED]



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[R] Problems with dyn.load()

2005-11-01 Thread Marcelo Damasceno
 I have a question, Is there some function that returns the directory where
the libraries of the instaled package are?
Because in Mandrake, R installs in /usr/lib/R/library/pack/libs, and in
Debian it installs in /usr/local/lib/R/library/pack /libs.
Thanks.


--
Marcelo Damasceno de Melo
Graduando em Ciência da Computação
Departamento de Tecnologia da Informação - TCI
Universidade Federal de Alagoas - UFAL
Maceió - Alagoas - Brasil
Projeto CoCADa - Construção do Conhecimento por Agrupamento de dados
+55 82 8801-2119

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[R] index question

2005-11-01 Thread Jeffrey Stratford
Thanks for those on the list that answered my previous question.  I'm
just about where I need to be (looking at output).  

In the hier.part documentation there is a line env - urbanwq[,2:8].  

This means use rows 2 through 8 in the data frame urbanwq, right? 
What does the comma represent?  If one wasn't using column headers would
this be necessary?

Thanks,

Jeff




Jeffrey A. Stratford, Ph.D.
Postdoctoral Associate
331 Funchess Hall
Department of Biological Sciences
Auburn University
Auburn, AL 36849
334-329-9198
FAX 334-844-9234
http://www.auburn.edu/~stratja

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Re: [R] Problems with dyn.load()

2005-11-01 Thread Paul Roebuck
On Tue, 1 Nov 2005, Marcelo Damasceno wrote:

 Is there some function that returns the directory where
 the libraries of the instaled package are? Because in
 Mandrake, R installs in /usr/lib/R/library/pack/libs, and in
 Debian it installs in /usr/local/lib/R/library/pack/libs.

?system.file

--
SIGSIG -- signature too long (core dumped)

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Re: [R] index question

2005-11-01 Thread Sundar Dorai-Raj


Jeffrey Stratford wrote:
 Thanks for those on the list that answered my previous question.  I'm
 just about where I need to be (looking at output).  
 
 In the hier.part documentation there is a line env - urbanwq[,2:8].  
 
 This means use rows 2 through 8 in the data frame urbanwq, right? 
 What does the comma represent?  If one wasn't using column headers would
 this be necessary?
 
 Thanks,
 
 Jeff
 
 

Hi, Jeff,

Actually it means *columns* 2:8. See the documentation and examples in 
help([).

--sundar

/war eagle

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Re: [R] R Graphs in Powerpoint

2005-11-01 Thread Smith, Daniel \(DHS-DEODC-EHIB\)
I've tried several methods in OS X, and here's what works best for me.  Save 
the R graphic as a PDF file.  Open it with Apple's Preview application, and 
save it as a PNG file.  The resulting .png file can be inserted into MS Word or 
PowerPoint, can be resized, and looks good on either OS X or Windows.  There 
are other programs available for translating the pdf file to png (like the 
shareware application Graphic Converter), but I've found that Preview produces 
the best results.

Daniel Smith
Environmental Health Investigations Branch
California Dept of Health Services


-Original Message-
Date: Mon, 31 Oct 2005 15:14:06 -0800
From: Jarrett Byrnes [EMAIL PROTECTED]
Subject: [R] R Graphs in Powerpoint
To: r-help@stat.math.ethz.ch
Message-ID: [EMAIL PROTECTED]
Content-Type: text/plain; charset=US-ASCII; format=flowed

Hey, all.  Quick question.  I'm attempting to use some of the great 
graphs generated in R for an upcoming talk that I'm writing in 
Powerpoint.  Copying and pasting (I'm using OSX) yields graphs that 
look great in Powerpoint - until I resize them.  Then fonts, points, 
and lines all become quite pixelated and blurry.  Even if I size the 
window properly first, and then copy and paste in the graph, when I 
then view the slideshow, the graphs come out pixelated and blurry.

Is there any good solution to this, or is this some fundamental 
incompatibility that I can't get around?

-Jarrett

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[R] RODBC error

2005-11-01 Thread Evan Sergeant
Hi,

I hope that someone can help me with the following problem with RODBC 
connection to a MySQL database

I am running R version 2.2.0 on windows XP, and have the MySQL database 
registered in Windows ODBC.

I have set up a web interface on my personal ISS web server using PhP 
to accept input values and then call Rterm with an R script to access 
the database and return a summary of the analysed data.

This works perfectly if I run it from Rgui, or if I run Rterm from the 
dos prompt using the same command line arguments, but returns an RODBC 
error (below) when calling Rterm from the web interface

1: [RODBC] ERROR: state IM002, code 0, message [Microsoft][ODBC Driver 
Manager] Data source name not found and no default driver specified 

There appears to be some problem with recognising the database when 
called from the web page, even though it is not a problem at any other 
times.

Does anyone have any suggestions as to what I can do to overcome this 
error

Thanks for your help

cheers

Evan Sergeant

AusVet Animal Health Services
69 Turner Cr, 
Orange NSW 2800 
Australia

Phone +61 2 6362 1598
Fax  +61 2 6369 1473
Email:  [EMAIL PROTECTED]
Web site: http://www.ausvet.com.au
MLA's Q Fever Register: www.qfever.org

This transmission is for the intended addressee only and is 
confidential 
information. If you have received this transmission in error, please 
delete 
it and notify the sender. The contents of this email are the opinion of 
the 
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[R] coding nesting in data for nlme example of Wafer data set.

2005-11-01 Thread Bill Shipley
I am trying to understand the proper way to encode the nesting structure
for data in the context of nlme, in the specific case of individuals
nested within species for which each individual is unique.  I have
searched through Pinheiro  Bates and also past postings, but without
success.

 

Take the Wafer data set which has 2 levels: Wafer (8 values) and Site
nested within Wafer (10 values for each value of Wafer)  (Pinheiro 
Bates book).  The data set has Sites coded as values from 1 to 8 for
Wafer 1, values 1 to 8 for Wafer 2 etc.  Does this mean that the SAME
sites are used for each Wafer (i.e. site 1 of water 1 is the same as
site 1 of wafer 2)?  If different sites were chosen for each of the
wafers would one have to code the sites = 1 to 8 for Wafer 1, sites = 9
to 16 for Wafer 2, and so on?

In the case of individuals nested within species, each individual is
unique - analogous to different sites being chosen for each wafter.  

 

Thanks.

 

Bill Shipley

 


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[R] Area under standard normal density

2005-11-01 Thread YOST Andrew
What is the correct syntax for finding the area under the standard
normal density for a particular value of z?
 
Thanks

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[R] help with hier.part

2005-11-01 Thread Jeffrey Stratford
R-users,

Attached is the file  (SR_use2.txt) I'd like to include and includes
column headers.  nat_est is the response variable and is the number of
species at a particular point.  The other variables are the explanatory
vars (vark, var2, var1, UK, U2, U1, GK, G2, G1, PK, P2, P1).  

Here is Walsh's sample code for hier.part:

data(urbanwq)
env - urbanwq[,2,8]
hier.part(urbanwq$lec, env, fam=gaussian, gof=Rssqu)

The code I wrote is 

library(hier.part)
SRUSE- read.table(F:\\GEORGIA\\species_richness\\SR_use2.txt, sep=
, header = TRUE, row.names = 1)
TEMP- SRUSE[2:13]
hier.part(SRUSE$nat_est,TEMP, family=NegBin, gof=logLik, barplot=
TRUE)

So far this doesn't work and I'd really appreciate some help.

While I have your ears, what books would one make for the clueless?  

Many thanks,

Jeff

PS. nat_est is the estimated number of species (species richness). 
Around each of the sampling points I calculated the % of different types
of cover (pine, hardwoods, number of different covers) in three scales
around the sampling points (1000, 200, and 100 m).  What I'm hoping to
do with the analysis is to find the best scales and parameters that best
predicts species richness. 
.  


Jeffrey A. Stratford, Ph.D.
Postdoctoral Associate
331 Funchess Hall
Department of Biological Sciences
Auburn University
Auburn, AL 36849
334-329-9198
FAX 334-844-9234
http://www.auburn.edu/~stratja

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Re: [R] Area under standard normal density

2005-11-01 Thread Sundar Dorai-Raj


YOST Andrew wrote:
 What is the correct syntax for finding the area under the standard
 normal density for a particular value of z?
  
 Thanks
 

?qnorm

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Re: [R] Area under standard normal density

2005-11-01 Thread Sundar Dorai-Raj
Sorry, ?pnorm.

--sundar

P.S. Thanks to the anonymous correction.

Sundar Dorai-Raj wrote:
 
 YOST Andrew wrote:
 
What is the correct syntax for finding the area under the standard
normal density for a particular value of z?
 
Thanks

 
 
 ?qnorm
 
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[R] multidimensional integration not over a multidimensional rectangle

2005-11-01 Thread Lynette Sun
Hi,

anyone knows about any functions in R can get multidimensional integration 
not over a multidimensional rectangle (not adapt).

For example, I tried the following function f(x,n)=x^n/n!

phi.fun-function(x,n)
{ if (n==1) {
x
}else{
integrate(phi.fun, lower=0, upper=x, n=n-1)$value
}
}

I could get f(4,2)=4^2/2!=8, but failed in f(4,3)=4^3/3! Thanks

Best,
Lynette

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Re: [R] glmmpql and lmer keep failing

2005-11-01 Thread Roel de Jong
Formulated more directly, are there plans for the implementation of the 
crude but more robust Marginal Quasi Likelihood estimation in for 
example LME?

Regards,
Roel de Jong

Roel de Jong wrote:
 Hello,
 
 I'm running a simulation study of a multilevel model with binary 
 response using the binomial probit link. It is a random intercept and 
 random slope model.  GLMMPQL and lmer fail to converge on a 
 *significant* portion of the *generated* datasets, while MlWin gives 
 reasonable estimates on those datasets. This is unacceptable. Does 
 anyone has similar experiences?
 
 Regards,
 Roel de Jong


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[R] two sample Cramer-von Mises test

2005-11-01 Thread Weijie Cai

Hello list,

Is there any function in some package can calculate two sample Cramer-von 
Mises test statistic? I searched around and only find one sample version 
cvm.test() in nortest package.


thanks,
WC

_
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Re: [R] glmmpql and lmer keep failing

2005-11-01 Thread Doran, Harold
Sorry to be blunt, but to make the statement that it is unacceptable without 
providing any reason why the model may fail to converge seems a little 
presumptious. Your statement really bothers me, especially knowing how hard the 
developer works on keeping this function at a premier level. Ask anyone working 
with mixed models and they will all agree that Doug Bates and this function are 
shining stars in the world of computational statistics. 

R is open source, and therefore you are certainly welcome and encouraged to add 
to its functionality if you wish. Basically, one may argue that you are in a 
put up, or shut up position. Feel free to write a nice piece of code based on 
MQL that we can use (and critique).

But even more importantly, in order to provide any help to you at all, you 
should provide sample data and examples of your code. We may find that the 
problem is the user and not the function. 

I generally disagree with rudeness on this list, and agree that my tone is not 
very agreeable, but please read the posting guide and follow basic protocol by 
describing your problem, create sample data, illustrate your code, and then ask 
for help.

Harold
 


-Original Message-
From:   [EMAIL PROTECTED] on behalf of Roel de Jong
Sent:   Tue 11/1/2005 6:05 PM
To: r-help
Cc: 
Subject:Re: [R] glmmpql and lmer keep failing

Formulated more directly, are there plans for the implementation of the 
crude but more robust Marginal Quasi Likelihood estimation in for 
example LME?

Regards,
Roel de Jong

Roel de Jong wrote:
 Hello,
 
 I'm running a simulation study of a multilevel model with binary 
 response using the binomial probit link. It is a random intercept and 
 random slope model.  GLMMPQL and lmer fail to converge on a 
 *significant* portion of the *generated* datasets, while MlWin gives 
 reasonable estimates on those datasets. This is unacceptable. Does 
 anyone has similar experiences?
 
 Regards,
 Roel de Jong


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[R] glmmpql and lmer keep failing

2005-11-01 Thread dave fournier
Hi,

I believe we could extend our upcoming release of our
freely available AD Model Builder negative binomial mixed model

   http://otter-rsch.com/admbre/admbre.html

packaqge for R to include your model.  Writing the model is
simple, it is the interface with R that is a bit more difficult.
If you contact me privately I will take a look at it.

   Cheers,

   Dave

-- 
David A. Fournier
P.O. Box 2040,
Sidney, B.C. V8l 3s3
Canada
http://otter-rsch.com


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Re: [R] glmmpql and lmer keep failing

2005-11-01 Thread Roel de Jong
The word unacceptable was maybe poorly chosen, but I meant it was 
unacceptable for my purposes that a lot of samples needed to be 
discarded. Further, I don't need to give code, data, or other reasons 
why the model may fail because it is well known that PQL can suffer from 
convergence problems, and this issue is already well documented in the R 
help list and articles I skimmed through before posting.  So all I 
wanted to know if how someone else with similar experiences tackled this 
problem, and if there are plans for the implementation of MQL in lme or 
another package.

As of my own contribution, I will soon release a Gibbs sampler for 
multilevel models under the binomial probit link that also can handle 
random slopes.

But I'm sorry I bothered you, guardian of the shining multilevel star.

Roel.





Doran, Harold wrote:
 Sorry to be blunt, but to make the statement that it is unacceptable 
 without providing any reason why the model may fail to converge seems a 
 little presumptious. Your statement really bothers me, especially 
 knowing how hard the developer works on keeping this function at a 
 premier level. Ask anyone working with mixed models and they will all 
 agree that Doug Bates and this function are shining stars in the world 
 of computational statistics.
 
 R is open source, and therefore you are certainly welcome and encouraged 
 to add to its functionality if you wish. Basically, one may argue that 
 you are in a put up, or shut up position. Feel free to write a nice 
 piece of code based on MQL that we can use (and critique).
 
 But even more importantly, in order to provide any help to you at all, 
 you should provide sample data and examples of your code. We may find 
 that the problem is the user and not the function.
 
 I generally disagree with rudeness on this list, and agree that my tone 
 is not very agreeable, but please read the posting guide and follow 
 basic protocol by describing your problem, create sample data, 
 illustrate your code, and then ask for help.
 
 Harold
 
 
 
 -Original Message-
 From:   [EMAIL PROTECTED] on behalf of Roel de Jong
 Sent:   Tue 11/1/2005 6:05 PM
 To: r-help
 Cc:
 Subject:Re: [R] glmmpql and lmer keep failing
 
 Formulated more directly, are there plans for the implementation of the
 crude but more robust Marginal Quasi Likelihood estimation in for
 example LME?
 
 Regards,
 Roel de Jong
 
 Roel de Jong wrote:
   Hello,
  
   I'm running a simulation study of a multilevel model with binary
   response using the binomial probit link. It is a random intercept and
   random slope model.  GLMMPQL and lmer fail to converge on a
   *significant* portion of the *generated* datasets, while MlWin gives
   reasonable estimates on those datasets. This is unacceptable. Does
   anyone has similar experiences?
  
   Regards,
   Roel de Jong
  
 
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[R] help with the coordinates of the ECDF object

2005-11-01 Thread klebyn


Hi all R users


I would like to know how acess the coordinates
of the ECDF object.

I look for the example,
in this part:
##
 print(ls.Fn12 - ls(env= environment(Fn12)))
##

but I do not know to extract
the Y coordinate and put it in other variable.

My objective is to make a plot
and identify the points with labels.


# Example by  ?ecdf

 y - round(rnorm(12),1); y[3] - y[1]
 Fn12 - ecdf(y)
 Fn12
 print(knots(Fn12), dig=2)
 12*Fn12(knots(Fn12)) ## ~= 1:12  if there were no ties

 summary(Fn12)
 summary.stepfun(Fn12)

 print(ls.Fn12 - ls(env= environment(Fn12)))
 ##[1] f  method  n  x  y  yleft  yright

# Example by  ?ecdf


My objetive seems to this:

plot(Fn12)
identify( x = knots(Fn12),  y = ??, labels=my string set)

or text...


thanks in advanced

klebyn

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Re: [R] help with the coordinates of the ECDF object

2005-11-01 Thread Nolwenn LeMeur
Hi,

try environment(Fn12)$y
environment(Fn12)$x

Nolwenn

**
Nolwenn Le Meur, PhD
Fred Hutchinson Cancer Research Center
Computational Biology
1100 Fairview Ave. N., M2-B876
P.O. Box 19024
Seattle, WA 98109-1024

On Tue, 1 Nov 2005, klebyn wrote:

 
 
 Hi all R users
 
 
 I would like to know how acess the coordinates
 of the ECDF object.
 
 I look for the example,
 in this part:
 ##
  print(ls.Fn12 - ls(env= environment(Fn12)))
 ##
 
 but I do not know to extract
 the Y coordinate and put it in other variable.
 
 My objective is to make a plot
 and identify the points with labels.
 
 
 # Example by  ?ecdf
 
  y - round(rnorm(12),1); y[3] - y[1]
  Fn12 - ecdf(y)
  Fn12
  print(knots(Fn12), dig=2)
  12*Fn12(knots(Fn12)) ## ~= 1:12  if there were no ties
 
  summary(Fn12)
  summary.stepfun(Fn12)
 
  print(ls.Fn12 - ls(env= environment(Fn12)))
  ##[1] f  method  n  x  y  yleft  yright
 
 # Example by  ?ecdf
 
 
 My objetive seems to this:
 
 plot(Fn12)
 identify( x = knots(Fn12),  y = ??, labels=my string set)
 
 or text...
 
 
 thanks in advanced
 
 klebyn
 
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Re: [R] help with the coordinates of the ECDF object

2005-11-01 Thread Murray Pung
If you wish to apply labels to identified points: I am sure there is a better 
way, but what I have done is use

locator(n)  #n is how many points you wish to identify. Then click on the 
points. The coordinates of each point are returned.

Then I use

identify(x, y, labels = My Label)

...for each point identified. It would be great if you could click on the 
points and have them identified  labelled, but I'm not sure how to do it.

-Original Message-
From: klebyn [mailto:[EMAIL PROTECTED]
Sent: Wednesday, 2 November 2005 12:25 PM
To: r-help@stat.math.ethz.ch
Subject: [R] help with the coordinates of the ECDF object




Hi all R users


I would like to know how acess the coordinates
of the ECDF object.

I look for the example,
in this part:
##
 print(ls.Fn12 - ls(env= environment(Fn12)))
##

but I do not know to extract
the Y coordinate and put it in other variable.

My objective is to make a plot
and identify the points with labels.


# Example by  ?ecdf

 y - round(rnorm(12),1); y[3] - y[1]
 Fn12 - ecdf(y)
 Fn12
 print(knots(Fn12), dig=2)
 12*Fn12(knots(Fn12)) ## ~= 1:12  if there were no ties

 summary(Fn12)
 summary.stepfun(Fn12)

 print(ls.Fn12 - ls(env= environment(Fn12)))
 ##[1] f  method  n  x  y  yleft  yright

# Example by  ?ecdf


My objetive seems to this:

plot(Fn12)
identify( x = knots(Fn12),  y = ??, labels=my string set)

or text...


thanks in advanced

klebyn

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Re: [R] index question

2005-11-01 Thread ronggui


=== 2005-11-02 05:13:45 您在来信中写道:===

Thanks for those on the list that answered my previous question.  I'm
just about where I need to be (looking at output).  

In the hier.part documentation there is a line env - urbanwq[,2:8].  

This means use rows 2 through 8 in the data frame urbanwq, right? 
his means use columns 2 through 8 in the data frame urbanwq

What does the comma represent? 
It means the first argument to function [ is left blank,so makes R knows 2:8 
is the second argument to [.

 If one wasn't using column headers would
this be necessary?
It still is necessary.


Thanks,

Jeff




Jeffrey A. Stratford, Ph.D.
Postdoctoral Associate
331 Funchess Hall
Department of Biological Sciences
Auburn University
Auburn, AL 36849
334-329-9198
FAX 334-844-9234
http://www.auburn.edu/~stratja

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= = = = = = = = = = = = = = = = = = = =



 

2005-11-02

--
Deparment of Sociology
Fudan University

My new mail addres is [EMAIL PROTECTED]
Blog:http://sociology.yculblog.com

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[R] Tcl/tk

2005-11-01 Thread Sokol Haxhinasto
Hello,
I recently installed the R (the most recent) and Bioconductor on my
computer. 
I installed the packages in affy, the affyGui and the limmaGui on my
computer and they all appear in the Load Package window.
After trying to load the affyGui or the limmaGui packages I receive the
following message entitled: Tcl/Tk Extension(s) Not Found-

limmaGUI requires the Tcl/Tk extensions, BWidget and Tktable.
You must have Tcl/Tk installed on your computer, not just the minimal
Tcl/Tk installation which comes with R (for Windows).  If you do have
Tcl/Tk installed, including the extensions (e.g. using the ActiveTcl
distribution in Windows), make sure that R can find the path to the Tcl
library, e.g. C:\Tcl\lib (on Windows) or /usr/lib (on Linux/Unix) or
/sw/lib on Mac OSX.

Any suggestions.
Also I am trying to get the R.app installed and run on my mac, and am not
successful.
Thanks for your help
Sokol 

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[R] NLME

2005-11-01 Thread Guy Forrester
Dear All,
 
Using:-
R : Copyright 2005, The R Foundation for Statistical Computing
Version 2.1.1  (2005-06-20), ISBN 3-900051-07-0
 and 
 
 Jose Pinheiro, Douglas Bates, Saikat DebRoy and Deepayan Sarkar (2005). nlme: 
Linear and
 nonlinear mixed effects models. R package version 3.1-65.

on a WINDOWS 2000 machine
 
I am trying to run the scripts from the Mixed Models book and am running into 
some difficulty - could any one tell me why this doesn't work (from pages 369 - 
370) 
 
 
CO2  #FINE
plot(CO2,outer= ~Treatment*Type,layout=c(4,1)) #FINE
 
fm1CO2.lis - nlsList( SSasympOff, CO2 ) #FINE
fm1CO2.lis #FINE
 

fm1CO2.nlme - nlme( fm1CO2.lis ) #COPIED DIRECTLY FROM BOOK!!??
 
Gives the error message:-
 
Error in nlme.formula(model = uptake ~ SSasympOff(conc, Asym, lrc, c0),  : 
Maximum number of iterations reached without convergence

 
Any assistance would be greatly appreciated
 
Guy Forrester
 
 
 
 
 

Guy J Forrester
Biometrician
Manaaki Whenua - Landcare Research
PO Box 69, Lincoln, New Zealand.
Tel. +64 3 325 6701 x3738
Fax +64 3 325 2418
E-mail [EMAIL PROTECTED] 
www.LandcareResearch.co.nz 




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