Re: [R] [R-SIG-Finance] Method dispatch in functions?

2007-06-30 Thread Carlos J. Gil Bellosta
Look at the UseMethod function. The help for the print method, a
heavily overloaded function, can also help.

Regards,

Carlos J. Gil Bellosta
http://www.datanalytics.com

On Thu, 2007-06-28 at 09:05 -0700, John McHenry wrote:
 Hi,
 
 Could someone point me in the right direction for documentation on the 
 following question? 
 
 Let's say I have two objects a and b of classes A and B, respectively.
 Now let's say I write a function foo that does something similar to 
 objects of type A and B. Basically I want to overload the function
 in C++ talk, so if I give foo and object of type A something (and this
 is my question) dispatches the call to, say, foo.A, and if I give foo
 and object of type B something dispatches the call to, say, foo.B.
 
 I want to write foo.A and foo.B. How to I perform the method 
 dispatch? From what I understand there are two ways in R:
 S3 and S4. What is the simple S3 way?
 
 Thanks!
 
 Jack.
 

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Re: [R] sobre tutorial

2007-05-15 Thread Carlos J. Gil Bellosta
Hello,

There are a number of resources (in Spanish) at the bottom of the page

http://es.wikipedia.org/wiki/Lenguaje_de_programación_R

Regards,

Carlos J. Gil Bellosta
http://www.datanalytics.com


On Tue, 2007-05-15 at 18:49 +0200, Danilo Ceschin wrote:
 Estimado, te agradeceria me envies el tutorial en espaniol para R. Estoy
 dando mis primeros pasos con esta aplicacion.
 Desde ya muchas gracias
 
 
 Danilo Ceschin Ph.D
 IGBMC
 1 rue Laurent Fries
 67404 ILLKIRCH CEDEX - FRANCE
 tel 33 3 88 65 3457
 email [EMAIL PROTECTED]
 
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Re: [R] R and SAS proc format

2007-03-07 Thread Carlos J. Gil Bellosta
On 3/7/07, Peter Dalgaard [EMAIL PROTECTED] wrote:
 Jason Barnhart wrote:
  - Original Message -
  From: John Kane [EMAIL PROTECTED]
  To: lamack lamack [EMAIL PROTECTED]; R-help@stat.math.ethz.ch
  Sent: Tuesday, March 06, 2007 2:13 PM
  Subject: Re: [R] R and SAS proc format
 
 
 
  --- lamack lamack [EMAIL PROTECTED] wrote:
 
 
  Dear all, Is there an R equivalent to SAS's proc
  format?
 
  What does the SAS PROC FORMAT do?
 
 
  It formats or reformats data in the SAS system.
 

 Slightly more precisely: It creates user-defined formats, which are
 subsequently associated with variables and used for reading, printing,
 tabulating, and analyzing data. It is akin to R's factor()
 constructions, but not quite. For one thing, SAS's formats are separate
 entities - same format can be used for many variables, whereas R's
 factors have the formatting coded as a part of the object. For related
 reasons, a variable in SAS can have more distinct values than there are
 value labesl for, etc.
  It looks this:
 
  proc format; value kanefmt 1='A' 2='B' 3='C' 4='X' 5='Throw me
  out';
  data temp; do i=1 to 10; kanevar=put(i,kanefmt.); output; end;
  proc print; run;
 
  And produces this:
 
  Obs i  kanevar
1 1A
2 2B
3 3C
4 4X
5 5Throw me out
6 6   6
7 7   7
8 8   8
9 9   9
   1010  10
 
 
  But it is more robust than what is shown here.
 
 
 
 
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 --
O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
   c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
  (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
 ~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Also, SAS formats are used as a (somewhat cumbersome) replacement for
dictionary data structures. Starting from SAS 9.1 (I believe), hash
tables can be used within data steps for the same purpose (albeit
still cumbersome).

In this regard, not only formats but also lists could be a replacement
for them. They can be used as a way to get key-value mappings.

These key-value mappings (I mean, these kind of data structures) are
very handy tools. I have used both factors and lists for some kind of
ad hoc replacement for these data structures. Hasn't anybody
considered the posibility of having these data structures implemented
in R in a much python-like or java-like touch and feel?

Regards,

Carlos J. Gil Bellosta
http://www.datanalytics.com

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[R] Error loading a dependency in a package: missing namespace?

2007-03-05 Thread Carlos J. Gil Bellosta
Dear r-helpers,

I am building a package that depends on some others. I recently added
a new dependency: package outliers. But does not work any more.

Let me show some information below:

[EMAIL PROTECTED]:pcrAnalysis$ cat DESCRIPTION
Package: pcrAnalysis
Type: Package
Title: pcrAnalysis
Version: 0.7.2
Date: 2007-02-27
Depends: Biobase, methods, outliers
Author: Carlos J. Gil Bellosta [EMAIL PROTECTED]
Maintainer: Carlos J. Gil Bellosta [EMAIL PROTECTED]
Description: Package for the analysis of Taqman experiments
License: TBA

[EMAIL PROTECTED]:pcrAnalysis$ cat NAMESPACE
import(methods, Biobase, outliers)
exportPattern(^tqmn)
exportClasses(pcrExprSet)
exportMethods(task, task-, phenoData.sort)

But now, the load of the packages fails. If I try to run

[EMAIL PROTECTED]:tmp$ R CMD check pcrAnalysis

I get the following log:

* checking for working latex ... OK
* using log directory '/tmp/pcrAnalysis.Rcheck'
* using R version 2.4.1 (2006-12-18)
* checking for file 'pcrAnalysis/DESCRIPTION' ... OK
* checking extension type ... Package
* this is package 'pcrAnalysis' version '0.7.2'
* checking package dependencies ... OK
* checking if this is a source package ... OK
* checking whether package 'pcrAnalysis' can be installed ... OK
* checking package directory ... OK
* checking for portable file names ... OK
* checking for sufficient/correct file permissions ... OK
* checking DESCRIPTION meta-information ... OK
* checking top-level files ... OK
* checking index information ... OK
* checking package subdirectories ... OK
* checking whether the package can be loaded ... ERROR
Loading required package: Biobase
Loading required package: tools

Welcome to Bioconductor

   Vignettes contain introductory material. To view, type
   'openVignette()' or start with 'help(Biobase)'. For details
   on reading vignettes, see the openVignette help page.

Loading required package: outliers
Error in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source
= keep.source) :
   in 'pcrAnalysis' classes for export not defined: pcrExprSet
In addition: Warning message:
package 'pcrAnalysis' contains no R code in: loadNamespace(package,
c(which.lib.loc, lib.loc), keep.source = keep.source)
Error: package/namespace load failed for 'pcrAnalysis'
Execution halted

It seems that the error is related to something having to do with
namespaces. The thing is that package outliers does not have a
NAMESPACE file. Could this be an issue?

I have contacted the author of the package and he sais that outliers
has been used in another package, quantchem (also in CRAN). However,
quantchem does not have a NAMESPACE file either.

I have been looking for information on how the loadNamespace function
works and even looking at its code.

But can anybody give me a clue? Would the outliers package require a
NAMESPACE file?

By the way, I have contacted the author of the package and he has been
quite helpful, but he says he feels that that (lack of this file) may
not be causing the problem. And I am using R version 2.4.1
(2006-12-18) on an Ubuntu Edgy (6.10) box.

Regards,

Carlos J. Gil Bellosta
http://www.datanalytics.com

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Re: [R] read.csv issue

2006-08-16 Thread Carlos J. Gil Bellosta
Dear Harold,

One thing you can do is to read the file plainly, even if the \ is
lost and then, inside R, change the string value with gsub.

Sincerely,

Carlos J. Gil Bellosta

http://www.datanalytics.com
http://www.data-mining-blog.com


El mié, 16-08-2006 a las 14:43 -0400, Doran, Harold escribió:
 I'm trying to read in some data from a .csv format and have come across
 the following issue. Here is a simple example for replication
 
 # A sample .csv format
 schid,sch_name
 331-802-7081,School One
 464-551-7357,School Two
 388-517-7627,School Three \ Four
 388-517-4394,School Five
 
 Note the third line includes the \ character. However, when I read the
 data in I get
 
  read.csv(file.choose())
  schid  sch_name
 1 331-802-7081School One
 2 464-551-7357School Two
 3 388-517-7627 School Three  Four
 4 388-517-4394   School Five
 
 It turns out to be very important to read in this character as I have a
 program that loops through a data set and Sweave's about 30,000 files.
 The variable sch_name gets dropped into the tex file using
 \Sexpr{tmp$sch_name}. However, if there is an , the latex file won't
 compile properly. So, what I need is for the data to be read in as
 
  schid  sch_name
 1 331-802-7081School One
 2 464-551-7357School Two
 3 388-517-7627 School Three \ Four
 4 388-517-4394   School Five
 
 I am obligated by a client to include the  in the school name, so
 eliminating that isn't an option. I thought maybe comment.char or quote
 would be what I needed, but they didn't resolve the issue. I'm certain
 I'm missing something simple, I just can't see it.
 
 Any thoughts?
 
 Harold
 
 
 
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Re: [R] the first and last case

2006-07-26 Thread Carlos J. Gil Bellosta
Dear Jacques,

I believe you need dat ordered by ind and y before you apply your solution,
right?

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com

Quoting Jacques VESLOT [EMAIL PROTECTED]:

 do.call(rbind,lapply(split(dat, dat$ind), function(x) x[c(1,nrow(x)),]))
 ---
 Jacques VESLOT

 CNRS UMR 8090
 I.B.L (2ème étage)
 1 rue du Professeur Calmette
 B.P. 245
 59019 Lille Cedex

 Tel : 33 (0)3.20.87.10.44
 Fax : 33 (0)3.20.87.10.31

 http://www-good.ibl.fr
 ---


 Mauricio Cardeal a écrit :
 Hi all

 Sometime ago I asked for a solution about how to aggregate data and the
 help was wonderful. Now, I´d like to know how to extract for each
 individual case below the first and the last observation to obtain this:

 ind  y
 18
 19
 27
 2   11
 39
 3   10
 4   8
 4   5

 # Below the example:

 ind - c(1,1,1,2,2,3,3,3,4,4,4,4)
 y - c(8,10,9,7,11,9,9,10,8,7,6,5)
 dat - as.data.frame(cbind(ind,y))
 dat
 attach(dat)
 mean.ind - aggregate(dat$y, by=list(dat$ind), mean)
 mean.ind

 Thanks
 Mauricio

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Re: [R] random section of samples based on group membership

2006-07-24 Thread Carlos J. Gil Bellosta
Dear Wade,

Say that your groups are

groups - sort(sample(1:10, 100, replace = TRUE))

Create a dummy

rows - 1:length(groups)

Then

tapply( rows, groups, function(x) sample(x, 1))

does the trick to select the row numbers you need for your sampling.

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com


Quoting Wade Wall [EMAIL PROTECTED]:

 Hi all,

 I have a matrix of 474 rows (samples) with 565 columns (variables).
 each of the 474 samples belong to one of 120 groups, with the
 groupings as a column in the above matrix. For example, the group
 column would be:

 1
 1
 1
 2
 2
 2
 .
 .
 .
 120
 120

 I  want to randomly select one from each group.  Not all the groups
 have the same number of samples, some have 4, some 3 etc.  Is there a
 function to do this, or would I need to write a looping statement to
 look at each successive group?

 I basically want to combine the randomly selected samples from the 120
 groups into a new matrix in order to perform a cluster analysis.

 Thanks,
 Wade

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Re: [R] grouping by consecutive integers

2006-07-24 Thread Carlos J. Gil Bellosta
Dear Kevin,

Try something like

groups - cut( tmp, c(-Inf, which(diff(tmp)  1 ) + 0.5, Inf) )

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com

Quoting Kevin J Emerson [EMAIL PROTECTED]:

 Hello R-helpers!

 I have a question concerning extracting sequence information from a
 vector.  I have a vector (representing the bins of a time series where
 the frequency of occurrences is greater than some threshold) where I
 would like to extract the min, median and max of each group of
 consecutive numbers.

 For Example:

 tmp - c(24,25,29,35,36,37,38,39,40,41,42,43,44,45,46,47,68,69,70,71)

 I would like to have the max,min,median of the following groups:

 24,25
 29
 35,36,37,38,39,40,41,42,43,44,45,46,47,
 68,69,70,71

 I would like to be able to perform this for many time series so an
 automated process would be nice.  I am hoping to use this as a peak
 detection protocol.

 Any advice would be greatly appreciated,
 Kevin

 -
 -
 Kevin J Emerson
 Center for Ecology and Evolutionary Biology
 1210 University of Oregon
 Eugene, OR 97403
 USA
 [EMAIL PROTECTED]

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Re: [R] ifelse command

2006-07-22 Thread Carlos J. Gil Bellosta
Dear Xin,

Although I have no idea what your function does, I believe it would be
formally correct in the following way:

foo - function (parameters,y,x1,x2)
{
p -parameters[1]
alpha1-parameters[2]
beta1-parameters[3]
delta1-parameters[4]
alpha2-parameters[5]

mu-alpha1*((x1)^beta1)*exp(-delta1*(x1^alpha2))

if(y0  x10  x2==1) return( lgamma(y+p)+p*(log(p)-log(mu
+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p) )
if(y0  x10  x2==2) return( lgamma(y+p)+p*(log(p)-log(mu
+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p) )
if(y0  x10  x2==3) return( lgamma(y+p)+p*(log(p)-log(mu
+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p) )

return( what then? )
}

Please, compare your code to mine. You will discover more than one error
in your code. See also where the if() parenthesis closes. I do not
believe your else's are necessary within a function. See also that the
code after your ifs is always the same.

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com


El sáb, 22-07-2006 a las 13:25 +0100, Xin escribió:
 Dear:
 
I try to revise the maximum likelihood function below using something 
 constrains. But it seems something wrong with it.  Becasue R would not allow 
 me to edit the function like this. It is very appreciate if you can help.
   
 function (parameters,y,x1,x2)
 
 {
 
 p-parameters[1]
 
 alpha1-parameters[2]
 
 beta1-parameters[3)]
 
 delta1-parameters[4]
 
 alpha2-parameters[5]
 
 mu-alpha1*((x1)^beta1)*exp(-delta1*(x1^alpha2))
 
 if(y0  x10  x2==1,
 
 L-lgamma(y+p)+p*(log(p)-log(mu+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p)
 
 )
 
 else
 
 if(y0  x10  x2==2,
 
 L-lgamma(y+p)+p*(log(p)-log(mu+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p)
 
 )
 
 else
 
 if(y0  x10  x2==3,
 
 L-lgamma(y+p)+p*(log(p)-log(mu+p))+y*(log(mu)-log(mu+p))-lfactorial(y)-lgamma(p)
 
 )
 
 else
 
 L
 
 }
 
 Thanks a lot!
 
 Xin Shi
 
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Re: [R] Automating package building packages and repository uploading

2006-07-20 Thread Carlos J. Gil Bellosta
Dear Rusers,

Well, then it seems that the problem is that I am building linux binary
packages. Since I do not have any compiled code within --just R code--, their
contents should --and, in fact, are-- directly installable on Windows 
platforms
(which is what I intend to do).

If I understand things right, I could just rebundle the packages using zip
instead of tar | gzip and getting rid of the arch string in the file name.
They they would work on Windows. And they actually do when I do this by hand.

But, is there a less involved way to generate these binary Windows 
packages with
proper file names and compression method directly from my linux box?

Thank you very much,

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com

Quoting Prof Brian Ripley [EMAIL PROTECTED]:

 On Thu, 20 Jul 2006, Carlos J. Gil Bellosta wrote:

 Dear Rusers,

 I have developed two packages for a client of mine. After new features
 are added or bugs corrected, I upload them to my own web repository. I
 create both source and binary versions.

 binary Linux packages, it seems.  The latter are .tar.gz with the arch as
 part of the name.

 .zip is used for Windows packages only.

 update.packages for Linux is designed to look for source packages only:
 see the 'type' argument.  You can use the distro's packaging facilities
 for binary packages, and Dirk does for the Debian R distribution.

 I think those misconceptions explain your confusion.


 In fact, I made an script that checks, builds, and uploads them via ftp.
 However, I am facing two nuisances that do make it difficult to
 automate:

 1) Even if I build the binary version with the command

 R CMD build --use-zip --binary $package

 within my script, the output package still gets tarballed and gzipped
 instead than simply zipped. I come around this automatically extracting
 and compressing back the files but, am I missing something some other
 option that would make all this simpler?

 2) I expect my packages to be named something like
 mypackage_1.3.12.tar.gz or mypackage_1.3.12.zip. However, sometimes
 --I haven't looked at the code that decides the name to give to the
 packages, so it looks quite random to me-- they get renamed into
 something like mypackage_1.3.12_R_i486-pc-linux-gnu.tar.gz or
 mypackage_1.3.12_R_i486-pc-linux-gnu.zip. The problem is that, then, the
 update.packages() function cannot find them. Is there a way to prevent
 this trailing string from appearing in the file name? Or else, is there
 a way to have update.packages() find the package regardless of it?

 I am running

 platform   i486-pc-linux-gnu
 arch   i486
 os linux-gnu
 system i486, linux-gnu
 status
 major  2
 minor  3.1
 year   2006
 month  06
 day01
 svn rev38247
 language   R
 version.string Version 2.3.1 (2006-06-01)

 on Debian Etch with kernel 2.6.15-1-k7.

 Thank you very much.

 Carlos J. Gil Bellosta
 http://www.datanalytics.com
 http://www.data-mining-blog.com


 --
 Brian D. Ripley,  [EMAIL PROTECTED]
 Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
 University of Oxford, Tel:  +44 1865 272861 (self)
 1 South Parks Road, +44 1865 272866 (PA)
 Oxford OX1 3TG, UKFax:  +44 1865 272595


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[R] Automating package building packages and repository uploading

2006-07-19 Thread Carlos J. Gil Bellosta
Dear Rusers,

I have developed two packages for a client of mine. After new features
are added or bugs corrected, I upload them to my own web repository. I
create both source and binary versions.

In fact, I made an script that checks, builds, and uploads them via ftp.
However, I am facing two nuisances that do make it difficult to
automate:

1) Even if I build the binary version with the command

R CMD build --use-zip --binary $package

within my script, the output package still gets tarballed and gzipped
instead than simply zipped. I come around this automatically extracting
and compressing back the files but, am I missing something some other
option that would make all this simpler?

2) I expect my packages to be named something like
mypackage_1.3.12.tar.gz or mypackage_1.3.12.zip. However, sometimes
--I haven't looked at the code that decides the name to give to the
packages, so it looks quite random to me-- they get renamed into
something like mypackage_1.3.12_R_i486-pc-linux-gnu.tar.gz or
mypackage_1.3.12_R_i486-pc-linux-gnu.zip. The problem is that, then, the
update.packages() function cannot find them. Is there a way to prevent
this trailing string from appearing in the file name? Or else, is there
a way to have update.packages() find the package regardless of it?

I am running

platform   i486-pc-linux-gnu
arch   i486
os linux-gnu
system i486, linux-gnu
status
major  2
minor  3.1
year   2006
month  06
day01
svn rev38247
language   R
version.string Version 2.3.1 (2006-06-01)

on Debian Etch with kernel 2.6.15-1-k7.

Thank you very much.

Carlos J. Gil Bellosta
http://www.datanalytics.com
http://www.data-mining-blog.com

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and provide commented, minimal, self-contained, reproducible code.


[R] Distributing packages online

2006-05-05 Thread Carlos J. Gil Bellosta
Dear R users,

A customer of mine has asked me to develop a R-package. The sitiuation
is as follows:

1) Being a special purpose package, it does not merit to be uploaded to
any CRAN server. 
2) It is subject to many changes, bug fixes, and the like.
3) It has then to be distributed to a relatively large and sparse base
of users. 

I thought that it would be convenient to have it distributed in the
following way:

1) I upload new versions to a server.
2) I provide a function that points to that server and installs it.

Therefore, users need only invoke this function in order to access the
last package version.

Suppose I upload the package to

http://www.myserver.com/packages/mypackage_X.Y.Z.tar.gz

Typically, several versions would be stored there.

The uploading function should be invoked simply. For instance,

 update.mypackage()

Can anybody give me a hint as to which would be key command in this
function how could the uploading function be defined so that the latest
version would be updated or installed?

Thank you very much for your help.

Carlos J. Gil Bellosta
http://www.datanalytics.com

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Re: [R] trace of matrix product

2006-04-05 Thread Carlos J. Gil Bellosta
Try

sum( rowSums( A * t(B)) )

Then you do not make any calculation you do not really need.

Carlos J. Gil Bellosta
http://www.datanalytics.com

Quoting Robin Hankin [EMAIL PROTECTED]:

 Hi

 what is the best way to calculate the trace of a product
 of two matrices?

 If

 A - matrix(rnorm(48),nrow=6)
 B - matrix(rnorm(48),nrow=8)


 Is there a better (faster, more elegant) way to compute the trace of
 A%*%B  than


 sum(diag(A %*% B))?


 I would call the above solution inelegant because all
 the elements of A %*% B are calculated, when one
 really only needs the elements on the diagonal.
 It  also uses %*% instead of crossprod() or trcrossprod()







 --
 Robin Hankin
 Uncertainty Analyst
 National Oceanography Centre, Southampton
 European Way, Southampton SO14 3ZH, UK
  tel  023-8059-7743

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Re: [R] trace of matrix product

2006-04-05 Thread Carlos J. Gil Bellosta
It is still better to do

sum( A * t(B) )

Sorry!!

Carlos J. Gil Bellosta
http://www.datanalytics.com

Quoting Robin Hankin [EMAIL PROTECTED]:

 Hi

 what is the best way to calculate the trace of a product
 of two matrices?

 If

 A - matrix(rnorm(48),nrow=6)
 B - matrix(rnorm(48),nrow=8)


 Is there a better (faster, more elegant) way to compute the trace of
 A%*%B  than


 sum(diag(A %*% B))?


 I would call the above solution inelegant because all
 the elements of A %*% B are calculated, when one
 really only needs the elements on the diagonal.
 It  also uses %*% instead of crossprod() or trcrossprod()







 --
 Robin Hankin
 Uncertainty Analyst
 National Oceanography Centre, Southampton
 European Way, Southampton SO14 3ZH, UK
  tel  023-8059-7743

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[R] Patient Rule Induction Method implemented in R?

2006-02-25 Thread Carlos J. Gil Bellosta
Dear R users,

I have not been able to find any implementation of Friedman's Patient
Rule Induction Method, PRIM, available on R. Is there any?

In any case, is there any reasonable alternative? So far, I have been
using trees and just keeping the extreme leaves. But a project of mine
requires a method that would just hunt the bumps in a high dimensional
data set and that would produce a relatively understandable/graphical
set of rules.

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com

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[R] Are minbucket and minsplit rpart options working as expected?

2005-12-07 Thread Carlos J. Gil Bellosta
Dear r-list:

I am using rpart to build a tree on a dataset. First I obtain a perhaps too
large tree:

 arbol.bsvg.02 - rpart(formula, data = bsvg, subset=grp.entr,
control=rpart.control(cp=0.001))
 arbol.bsvg.02
n= 10

node), split, n, loss, yval, (yprob)
  * denotes terminal node

  1) root 10 6657 0 (0.93343000 0.06657000)
2) meses_antiguedad_svg=10.5 73899 3658 0 (0.95050001 0.0494)
  4) eor_n1_gns 1.5 63968 2807 0 (0.95611868 0.04388132)
8) tarifa_gas=31,32,33,34 63842 2771 0 (0.95659597 0.04340403) *
9) tarifa_gas=NO 126   36 0 (0.71428571 0.28571429)
 18) tipo_mercado=ESP,N/A 90   10 0 (0.8889 0.) *
 19) tipo_mercado=NE ,SAH,SAV 36   10 1 (0.2778 0.7222) *
  5) eor_n1_gns=1.5 9931  851 0 (0.91430873 0.08569127)
   10) sn_calef=0.5 8390  546 0 (0.93492253 0.06507747) *
   11) sn_calef 0.5 1541  305 0 (0.80207657 0.19792343)
 22) tarifa_gas=31,NO 1134  141 0 (0.87566138 0.12433862) *
 23) tarifa_gas=32 407  164 0 (0.59705160 0.40294840)
   46) cons_gas_delta_1 6997 196   51 0 (0.73979592 0.26020408) *
   47) cons_gas_delta_1=6997 211   98 1 (0.46445498 0.53554502)
 94) meses_antiguedad_svg=23.5 134   54 0 (0.59701493 0.40298507)
  188) altitud 312 61   16 0 (0.73770492 0.26229508) *
  189) altitud=312 73   35 1 (0.47945205 0.52054795)
378) back_office=1.5 39   12 0 (0.69230769 0.30769231) *
379) back_office 1.5 348 1 (0.23529412 0.76470588) *
 95) meses_antiguedad_svg 23.5 77   18 1 (0.23376623 0.76623377) *
3) meses_antiguedad_svg 10.5 26101 2999 0 (0.88510019 0.11489981)
  6) sn_calef=0.5 20129 1853 0 (0.90794376 0.09205624) *
  7) sn_calef 0.5 5972 1146 0 (0.80810449 0.19189551)
   14) tarifa_gas=31 4406  664 0 (0.84929641 0.15070359) *
   15) tarifa_gas=32,NO 1566  482 0 (0.69220945 0.30779055)
 30) eor_n1_gns 0.5 1168  306 0 (0.73801370 0.26198630) *
 31) eor_n1_gns=0.5 398  176 0 (0.55778894 0.44221106)
   62) back_office=0.5 148   35 0 (0.76351351 0.23648649) *
   63) back_office 0.5 250  109 1 (0.4360 0.5640) *

So I decide not to consider branches with less than 1000 observations, a 1% of
the original number of observations. Therefore, according to the rpart.control
help pages, I set minbucket=1000. However,

 arbol.bsvg.02
n= 10

node), split, n, loss, yval, (yprob)
  * denotes terminal node

1) root 10 6657 0 (0.9334300 0.0665700) *

And I get an empty tree. But there were branches in the original tree with
more than 1000 observations. Something similar happens if I set minsplit (or
both minbucket and minsplit) to a similar value: I end up with the same root,
branch-less tree.

Am I misreading something? Can anybody cast a light on the correct usage of the
minbucket (and/or minsplit) for me?

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com

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Re: [R] hamming distance

2005-11-24 Thread Carlos J. Gil Bellosta
True, but if

 x - c(1, 0, 0)
 y - c(1, 0, 1),

then you can just define

hamming.distance - function(x,y){
  sum(x != y)
}

The problem is just a bit harder when x and y are, for instance, strings.

Carlos J. Gil Bellosta
http://www.datanalytics.com

Quoting JeeBee [EMAIL PROTECTED]:

 You could install.packages(e1071)
 and see help(hamming.distance)

 JeeBee.


 hamming.distancepackage:e1071R Documentation
 Hamming Distances of Vectors
 Description:
 If both 'x' and 'y' are vectors, 'hamming.distance' returns the
 Hamming distance (number of different bytes) between this two
 vectors. If 'x' is a matrix, the Hamming distances between the
 rows of 'x' are computed and 'y' is ignored.
 Usage:
  hamming.distance(x, y)
 Arguments:
   x: a vector or matrix.
   y: an optional vector.
 Examples:
 x - c(1, 0, 0)
 y - c(1, 0, 1)
 hamming.distance(x, y)
 z - rbind(x,y)
 rownames(z) - c(Fred, Tom)
 hamming.distance(z)


 On Thu, 24 Nov 2005 11:33:45 +0100, Ana Conesa wrote:


Hi,
Does anyone know an R function to impute hamming distance?
Thanks
Ana

   O@  nb @@@O@@O@   Centro de Genómica
  @OO@   Instituto Valenciano de Investigaciones Agrarias (IVIA)
  @@@O   Carretera Moncada - Naquera, Km. 4,5
   O@46113 Moncada (Valencia) SPAIN
 ||  ||  
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Re: [R] Applying a function to a vector

2005-10-31 Thread Carlos J. Gil Bellosta
You should then try apply. See ?apply.

For instance:


a - matrix(c(1:10), 5, 2)
apply(a, 1, function(x) x[1] + 100 * x[2])

This way you can disaggregate the components of your input (that is not a
singleton) and use them inside your function separately.

Carlos J. Gil Bellosta
http://www.datanalytics.com

Quoting Florent Bresson [EMAIL PROTECTED]:

 I just have a try with sapply. The problem is that my
 function pbeta2 has two parameters z and p (wich is a
 vector of two parameters). If I use sapply , R returns
 a message incicating that parameter p is missing. It
 is a problem since both z and p are varying along my
 data.frame.

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Re: [R] Problem with RCMD build ...

2005-08-23 Thread Carlos J. Gil Bellosta
Dear Justin,

I also had similar problems recently...  In fact, I have just created a 
package using package.skeleton and if I try to build it without 
editing the DESCRIPTION file (you did not mention you did, right?) R 
complains. In fact, it appears to be malformed (I am running version 
2.1.0 of R on a Debian (testing) Linux box); it is [sic]:

Package: fooType: Package
Title: What the package does (short line)
Version: 1.0
Date: 2005-08-23
Author: Who wrote it
Maintainer: Who to complain to [EMAIL PROTECTED]
Description: More about what it does (maybe more than one line)
License: What license is it under?

As you can see, the two first lines are pasted together. Can this 
perhaps be the problem?

Sincerely,

Carlos J. Gil Bellosta
http://www.datanalytics.com

justin bem wrote:

Hi 
I have write A function to draw pyramid of age. I have two function
draw.pyramide(h,f,l) , pyramide(h,f,l) and a data frame with data.
 
I first use package.skeleton(pyra)
I got the package structure
Then in my shell I use 
 
  

RCMD build pyra


I get this :
check for description ... OK

removing junk files 
but
cannot open pyra/description
and Install failed.
 
I use windows XP, with and intel PIV with 2.66GHZ and 512MO of memory.
 
Can you help me ?
 
 
 


Justin BEM
Elève Ingénieur Statisticien Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
   
-


   [[alternative HTML version deleted]]

  



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[R] write.table() performance.

2004-07-01 Thread Carlos J. Gil Bellosta
Dear r-helpers,
I know that there has already been enough questions on IO performance 
these last days, but I came accross the following situation today. I was 
comparing the performance of R with that of SAS's Risk Dimensions at 
generating random scenarios. My dataset --all numeric entries-- would 
nicely fit into RAM and R would outperform SAS until... I wanted to 
export the results to a .csv file using the write.table() function. For 
reference, this output file was of about 30MB.  Moreover, the memory 
needed by R would increase sharply during the writing process.

I had a look at the code for the write.table() function and I found out 
that, basically, what it does is to create a very long text string from 
the data using paste() and then to print it using writeLines(). Rprof() 
showed that writeLines() would only use a mere 3% of the computing time, 
the rest being taken almost entirely by paste().

There are two directions in which performance could potentially be improved:
1.- Writing speed.
2.- Memory usage.
Regarding memory usage, I thought that perhaps a little rewriting of the 
write.table() function could be considered: instead of writing in RAM a 
single long text string, with a little overhead, the data frame to be 
printed could be splitted into shorter, recyclable, chunks, then 
paste()-ing them into shorter buffer strings and print them 
sequentially into the the output file. (Note: I am a complete ignorant 
on R's memory recycling rules and this could perhaps not work as 
intended because of them).

Regarding speed considerations, I see little hope as long as the paste() 
function is implicitly called by write.table(). Most likely, its 
execution time scales linearly with the number of lines in the data 
frame, so splitting it would render no benefits. Are there any hints on 
how could a performance improvement (other than linking external, ad hoc 
C code) be achieved? Do we really need to go through parse()? Would it 
perhaps be beneficial to include in R some specialized functions that 
achieved high output performance for writing out, say, only numeric 
values (this happens to be the case for me most of the time)?

Sorry for the long posting.
Carlos J. Gil Bellosta
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[R] BoxPlots, 1 Way ANOVA and Non-Statisticians.

2004-03-30 Thread Carlos J. Gil Bellosta
Dear R-Helpers,

I am working in a project and I have a number of observations belonging 
to several classes. Using a 1 Way ANOVA, I have rejected the equality of 
means hypothesis with a very small p-value. However, the people I have 
to present my results to are not statisticians and they are not very 
likely to be much impressed by a 1.32434e-12 like number/thing.

Therefore I have decided to make to boxplots, one for the actual data 
and the second one for simulated data where the equality of the means 
holds so that the difference in the distributions can be visually 
appreciated.

The problem is that, for the simulated values, being more regular, the 
range of variation is smaller and, therefore, the heigth of the window 
where their boxplot is drawn is also smaller. As a result, the scales of 
the two boxplots are not the same and part of the appeal of the visual 
approach is lost in the way.

My question is, is there a way to make two different boxplots within a 
common window? (Or rather, a common size window or, more concretely, 
so that it spans over the same range on the vertical axis).

Sincerely,

Carlos J. Gil Bellosta
Sigma Consultores Estadi'sticos
http://www.consultoresestadisticos.com
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[R] Partial least squares.

2003-10-31 Thread Carlos J. Gil Bellosta
Dear R-helpers,

I am looking, quite unsuccesfully, for a number of functions/packages.

Firstly, I am interested in a package for partial least squares. I have 
found that there seemed to exist a package called pls, but which seems 
not to run any more with modern versions of R. I have not been able to 
find certain chemometrics package I found some people discussing about 
in this list some time ago and that, it seems, included these kind of 
functions.

Secondly, I have not been able to find a function equivalent to the 
SAS procedure STEPDISC which performs a step process (only available for 
lm and glm on R) on linear discriminant analysis (lda on R).

Does anybody know of a top-the-shelf answer to these questions?

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
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[R] R icon for RedHat 9.

2003-09-30 Thread Carlos J. Gil Bellosta
Dear R-helpers,

I just installed R on a RedHat 9 machine and when I was trying add a 
launcher on the panel to it, I could not find any R icon in png format. 
Is there any available? Do I have it and I could not find it in my file 
hierarchy?

Thank you for your help.

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
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[R] R-icon for RH Linux 9.

2003-09-30 Thread Carlos J. Gil Bellosta
Dear R helpers,

It is the first time I have to install R under Linux (Red Hat 9) and as 
I was setting up the panels, I could not find any png icon to launch the 
program. Does it exist and I have overlooked it? Can I get it somewhere?

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
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Re: [R] test for equal distributions with small numbes of observations

2003-08-19 Thread Carlos J. Gil Bellosta
Probably, to check homogenity you only need to consider a vector of 
dimension 8 consisting in the number of times you get any of the 
configurations (0,7), (1,6), (2,5),...(7,0). This is most likely a 
sufficient statistics. Under homogeneity, it should be distributed 
according to a multinomial random variable with probability vector equal 
to the density of a binomial variable of unknown parameter p.

Then you can use standard tests to see if the MVE fits or if it does not 
fit the data.

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
Christoph Lehmann wrote:

Dear R-pros

I have a problem, for which usually I would apply a chisq.test or a
fisher.test:


40 objects, each given either a 0 or 1, regarding if this object
later on will be remembered by a subject or not.
7 subjects investigated

means: we have a 2x40 matrix, each cell the number of subjects for who
the object i has been given either 0 or 1 e.g.
objects:
1   1   3   39  40
--
0   1   2   2   ..  7   7
1   4   4   5   ..  0   0
over all 40 objects, we have 67% of 1 and 33% of 0

I want to know, if for the 40 objects, the ratio of 0/1 differs or
not, i.e. if they have the same distribution.
I cannot use a chisq.test since the expected frequencies are  5 for the
0 cells.
Fisher.test seems to run for  12h on a PIV 1.8GHz...

what do you recommend me to do?

Many thanks

Christoph
--
 

recognition
   

[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14]
[1,]122223333 3 3 3 4 4
[2,]445443444 4 3 4 3 3
[,15] [,16] [,17] [,18] [,19] [,20] [,21] [,22] [,23] [,24] [,25] [,26]
[1,] 4 4 4 4 4 4 5 5 5 5 5 5
[2,] 3 2 3 3 2 3 2 2 2 2 2 2
[,27] [,28] [,29] [,30] [,31] [,32] [,33] [,34] [,35] [,36] [,37] [,38]
[1,] 5 5 5 5 5 6 6 6 6 6 6 6
[2,] 2 2 2 2 2 1 1 1 1 1 1 1
[,39] [,40]
[1,] 7 7
[2,] 0 0
 

fisher.test(recognition)
   



 

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[R] Statistical analysis of huge datasets.

2003-08-07 Thread Carlos J. Gil Bellosta
Dear R-users,

I am faced with the problem of analyzing a huge dataset (+ 2 million 
records, +150 variables) which does not fit into memory. I would like to 
know if there are pre-packaged tools (in the spirit of Insigthful 
I-Miner, for instance) aimed at subsampling or splitting the dataset 
into data-frameable subdatasets, applying functions record-wise, etc.

Thank you very much for your help.

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
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Re: [R] C compiler to R

2003-07-17 Thread Carlos J. Gil Bellosta
gcc (I just need to write that; I tried Borland's and I only got trouble).

Sincerely,

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
Cezar Augusto de Freitas Anselmo wrote:

Hi, all.
I'd like know which is the more appropriate C compiler to use with R
programs.
Thanks,
C.

Cezar Freitas (ICQ 109128967)
IMECC - UNICAMP
Campinas, SP - Brasil
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Re: [R] univariate normal mixtures

2003-07-17 Thread Carlos J. Gil Bellosta
Well,

If k is known, you can use maximun likelihood to fit the weights, means, 
and sd's. The EM algorithm can be of help to solve the optimization 
problem. You would have to implement it yourself for your particular 
case, but I do not think it is big trouble.

Then you could estimate k using Bayesian formalism: from a reasonable a 
priory distribution on k=1, 2,... compute the posterior distributions 
using the densities obtained above, etc.

Carlos J. Gil Bellosta
Sigma Consultores Estadísticos
http://www.consultoresestadisticos.com
Joke Allemeersch wrote:

Hello,

I have a concrete statistical question:
I have a sample of an univariate mixture of an unknown number (k) of 
normal distributions, each time with an unknown mean `m_i' and a 
standard deviation `k * m_i', where k is known factor constant for all 
the normal distributions. (The `i' is a subscript.)
Is there a function in R that can estimate the number of normal 
distributions k and the means `m_i' for the different normal 
distributions from a sample?  Or evt. a function that can estimate the 
`m_i', when the number of distributions `k' is known?
So far I only found a package, called `normix'.  But at first sight it 
only provides methods to sample from such distributions and to 
estimate the densities; but not to fit such a distribution.
Can someone indicate where I can find an elegant solution?

Thank you in advance

Joke Allemeersch

Katholieke universiteit Leuven.
Belgium.
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