Re: [R] OT - use of R

2007-08-14 Thread Chung-hong Chan
A quick search of google scholar found 2556 cites to the classic paper
by Ihaka et al.

http://scholar.google.com/scholar?hl=enlr=cites=15992947024900415641



On 8/15/07, Andy Bunn [EMAIL PROTECTED] wrote:
 Hello, is there an up-to-date reference for how many people use R? I'm
 giving an R demo and want to cite wonderful R usage stats. How many
 people use it (or download it)? How often is R used in peer-reviewed
 pubs, etc. Is there any whiz-bang citation that says something like R
 is great and developed by the best minds in statistical computing. Any
 thoughts?

 -Andy

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-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

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Re: [R] Meta-Analysis of proportions

2007-06-28 Thread Chung-hong Chan
OpenBUGS should be something related to Bayesian statistics.

You may refer to Chapter 12 of Handbook
http://cran.r-project.org/doc/vignettes/HSAUR/Ch_meta_analysis.pdf
It talks about meta-regression.



On 6/28/07, Monica Malta [EMAIL PROTECTED] wrote:
 Dear colleagues,

 I'm conducting a meta-analysis of studies evaluating adherence of 
 HIV-positive drug users into AIDS treatment, therefore I'm looking for some 
 advice and syntax suggestion for running the meta-regression using 
 proportions, not the usual OR/RR frequently used on RCT studies.

 Have already searched already several handbooks, R-manuals, mailing lists, 
 professors, but... not clue at all...

 Does anyone have already tried this? A colleague of mine recently published a 
 similar study on JAMA, but he used OpenBUGS - a software I'm not familiar 
 with...

 If there is any tip/suggestion for a possible syntax, could someone send me? 
 I need to finish this paper before my PhD qualify, but I'm completely stuck...

 So, any tip will be more than welcome...I will really appreciate it!!!

 Thanks in advance and congrats on the amazing mailing-list.



 Bests from Rio de Janeiro, Brazil.

 Monica





 Monica Malta
 Researcher
 Oswaldo Cruz Foundation - FIOCRUZ
 Social Science Department - DCS/ENSP
 Rua Leopoldo Bulhoes, 1480 - room 905
 Manguinhos
 Rio de Janeiro - RJ 21041-210
 Brazil
 phone +55.21.2598-2715
 fax +55.21.2598-2779
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-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
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[R] Date and selection

2007-06-19 Thread Chung-hong Chan
Dear R experts,

Suppose I have a data.frame recording the date and test results of
some subjects like this:

Name Date results
John 01/01/1991 2
John 02/01/1991 3
John 09/0101991 4
Micheal 02/01/1991 4
Micheal 04/01/1991 5


How to select the earliest (or latest) test result from all subjects?

Thank you.

Regards,

CH



-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] How to load a big txt file

2007-06-06 Thread Chung-hong Chan
Easy solution will be split your big txt files by text editor.

e.g. 5000 rows each.

and then combine the dataframes together into one.



On 6/7/07, ssls sddd [EMAIL PROTECTED] wrote:
 Dear list,

 I need to read a big txt file (around 130Mb; 23800 rows and 49 columns)
 for downstream clustering analysis.

 I first used Tumor - read.table(Tumor.txt,header = TRUE,sep = \t)
 but it took a long time and failed. However, it had no problem if I just put
 data of 3 columns.

 Is there any way which can load this big file?

 Thanks for any suggestions!

 Sincerely,
  Alex

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-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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[R] Proxy Under Mac OS X

2007-05-31 Thread Chung-hong Chan
Dear R programmers,

I can only config. proxy under Mac OS X terminal and launch R under Terminal by

Terminal:

export http_proxy=http://un:[EMAIL PROTECTED]:port

Under R:

chooseCRANmirror(graphics=FALSE)
update.packages()

I don't know how to config this in R for Mac OS X Aqua GUI.
I checked the relevant document but no specific steps for Mac OS X.

Regards,
Ch Chan



-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] R's Spearman

2007-05-28 Thread Chung-hong Chan
Hi,

You can try with
cor.test(rank(y[1]),rank(y[2]))


On 5/29/07, Raymond Wan [EMAIL PROTECTED] wrote:

 Hi all,

 I am trying to figure out the formula used by R's Spearman rho (using
 cor(method=spearman)) because I can't seem to get the same value as by
 calculating by hand.  Perhaps I'm using cor wrong, but I don't know
 where.  Basically, I am running these commands:

   y=read.table(file=tmp,header=TRUE,sep=\t)
   y
IQ Hours
 1 106 7
 2  86 0
 3  9720
 4 11312
 5 12012
 6 11017
   cor(y[1],y[2],method=spearman)
Hours
 IQ 0.2319084

 [it's an abbreviated example of one I took from Wikipedia].  I
 calculated by hand (apologies if the table looks strange when pasted
 into e-mail):

   IQHoursrank(IQ)  rank(hours)diffdiff^2
 110673 2 11
 2 8601 1 00
 3 9720   2 6-416
 411312   5 3.5 1.52.25
 512012   6 3.5 2.56.25
 611017   4 5-11
   26.5

   rho=0.242857

 where rho = (1 - ((6 * 26.5) / 6 * (6^2 - 1))).  I kept modifying the
 table and realized that the difference in result comes from ties.  i.e.,
 if I remove the tie in rows 4 and 5, I get the same result from both cor
 and calculating by hand.  Perhaps I'm handling ties wrong...does anyone
 know how R does it or perhaps I need to change how I'm using it?

 Thank you!

 Ray

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-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
R-help@stat.math.ethz.ch mailing list
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Re: [R] Simple question about function with glm

2007-05-07 Thread Chung-hong Chan
Thank you akk.

I know it is not statistically sounded to check the distribution of
response before glm.
I will check the distribution of xmodel$residuals later on.

About the program problem.
It can print summary(xmodel) but not confint(xmodel) by amending my
code as suggested by Bill Venables.

Regards,
CH


On 5/7/07, Ben Bolker [EMAIL PROTECTED] wrote:
  Bill.Venables at csiro.au writes:

 
  Finally, I'm a bit puzzled why you use glm() when the simpler lm() would
  have done the job.  You are fitting a linear model and do not need the
  extra paraphernaila that generalized linear models require.
 
  Bill Venables.
 

   Perhaps the original poster is confused about the difference
 between general (a la PROC GLM) and generalized (glm) linear
 models?

   The code is also a little puzzling because the same tests
 seem to be run whether p0.05 or not.  Perhaps the code
 will eventually be written to log-transform the data
 if it fails the normality test?

  [ hint: ?boxcox in the MASS package might be a better way
 to go ]

   Ben Bolker

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-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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[R] Simple question about function with glm

2007-05-06 Thread Chung-hong Chan
Dear all,

I coded a function called u.glm

u.glm - function (x,ahi,age,bmiz,gender)
{
library(nortest)
lil.rslt - lillie.test(x)
if (lil.rslt$p.value 0.05)
{
cat(Logtrans=0, lillie=,lil.rslt$p.value,\n)
xmodel-glm(x~ahi+age+bmiz+as.factor(gender))
summary(xmodel)
confint(xmodel)

}
else
{
cat(Logtrans=1, lillie=,lil.rslt$p.value,\n)
xmodel-glm(x~ahi+age+bmiz+as.factor(gender))
summary(xmodel)
confint(xmodel)
}

}

Basically I just want to test the response variable for normality
before modeling.
When I try to use this function, it can do the lillie's test but
failed to do the glm.
What's wrong with my code?

Regards,
CH


-- 
The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can think deeply and be quite insane.
Nikola Tesla
http://www.macgrass.com

__
R-help@stat.math.ethz.ch mailing list
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