Re: [R] delete selecting rows and columns
A one-dimensional delete might be faster: n - 4000 m - 0.01 matr - matrix(1:(n^2), n, n) excl_r - sample(n, m*n) incl_r - setdiff(1:n, excl_r) excl_c - sample(n, m*n) incl_c - setdiff(1:n, excl_c) system.time(matr[-excl_r, -excl_c]) system.time( { m4 - matr[outer(incl_r, incl_c, function(i, j) i + n*(j - 1)) ] dim(m4) - c(length(incl_r), length(incl_c)) } ) Heikki Kaskelma jastar wrote: Hi, I'm working with a big square matrix (15k x 15k) and I have some trouble. I want to delete selecting rows and columns. I'm using something like this: sel_r=c(15,34,384,985,4302,6213) sel_c=c(3,151,324,3384,7985,14302) matrix=matrix[-sel_r,-sel_c] but it works very slow. Does anybody know how to make it in faster way? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Conditional Sum
Yes, consider: df=data.frame(Clinic=rep(c(A, B, C), 2), Rep=c(1, 1, 1, 2, 2, 2), colM1=c(1, 0, 0, 1, -1, 1), ColM2=c(0, -1, -1, 1, 0, 0), ColM3=c(0, 0, 1, -1, 0, 1), ColM40=c(1, 0, -1, 0, 1, -1) ) Clinic=1; Rep=2 ff=function(x, v) sum(x == v) Dataframe1=aggregate(df[, -c(Clinic, Rep)], df[Clinic], ff, 1) names(Dataframe1)[1]=Clinic Dataframe2=aggregate(df[, -c(Clinic, Rep)], df[Clinic], ff, -1) names(Dataframe2)[1]=Clinic Dataframe1 Dataframe2 Heikki Kaskelma -- Bert Jacobs kirjoitti jokin aikaa sitten: I would like to make a conditional sum for certain columns in a dataframe. This is how my dataframe looks like: Clinic Rep ColM1 ColM2 ColM3 ... ColM40 A 1 10 01 B 1 0-1 00 C 1 0-1 1-1 A 2 11 -1 0 B 2 -1 0 01 C 2 10 1 -1 I would like to have two new dataframes so that Dataframe1: with the count of all 1 Clinic ColM1 ColM2 ColM3 .. ColM40 A2 10 1 B0 00 1 C1 02 0 Dataframe2: with the count of all -1 Clinic ColM1 ColM2 ColM3 .. ColM40 A0 01 0 B1 10 0 C0 10 2 Is there an easy way to achieve this. Thx, Bert __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Can this loop be delooped?
Consider na=43; nb=5; x=1:na ns=rep(na %/% nb, nb) + (1:nb = na %% nb) split(x, rep(1:nb, ns)) Heikki Kaskelma On Fri, 2 Feb 2007, jim holtman [EMAIL PROTECTED] wrote: This might do what you want: # test data x - 1:43 nb - 5 # number of subsets # create vector of lengths of subsets ns - rep(length(x) %/% nb, nb) # see if we have to adjust counts of initial subsets if ((.offset - length(x) %% nb) != 0) ns[1:.offset] = ns[1:.offset] + 1 # create the subsets split(x, rep(1:nb,ns)) __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to optimize this loop ?
Given a series of observations, I want to know how many consecutive past observations are below the last one. prune=function(m) { mr=rev(m) ms=cumsum(mr mr[1]) sum(seq_along(ms) - ms == 1) - 1 } prune(c(3, 4, 10, 14, 8, 3, 4, 8, 9)) # 4 prune(c(3, 4, 10, 14, 8, 3, 4, 11, 9)) # 0 Heikki Kaskelma __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] indexing question
idx = c(31, 36, 41, 61, 66, 71, 91, 96, 101, 121, 126, 131) temp = 1:150 res = temp[idx] dim(res) = c(3, length(res) %/% 3) res = t(rbind(res, res[2, ] - res[1, ], res[3, ] - res[2, ])) res Heikki Kaskelma -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Leeds, Mark (IED) Sent: Monday, November 13, 2006 10:06 PM To: r-help@stat.math.ethz.ch Subject: [R] indexing question I have the following set of indices, call it idx, that correspond to the indices of a vector say temp. [1] 31 36 41 61 66 71 91 96 101 121 126 131 151 156 161 181 186 191 211 216 221 241 246 251 271 276 281 301 306 311 331 336 341 361 366 [36] 371 391 396 401 421 426 431 451 456 461 481 486 491 511 516 521 541 546 551 571 576 581 601 606 611 631 636 641 661 666 671 691 696 701 721 [71] 726 731 751 756 761 781 786 791 811 816 821 841 846 851 871 876 881 901 906 911 931 936 941 961 966 971 991 996 1001 1021 1026 1031 1051 1056 1061 [106] 1081 1086 1091 1116 1121 1141 1146 1151 1171 1176 1181 1201 1206 1211 1231 1236 1241 1261 1266 1271 1291 1296 1301 1321 1326 1331 1351 1356 1361 1381 1386 1391 1411 1416 [141] 1421 I want to calculate temp[36] - temp[31] and temp[41] - temp[36] Similarly, temp[66] - temp[61] and temp[71] - temp[66] . . . . Similarly temp[1416]-temp[1411] temp[1421] - temp[1416] I'm doing this because the above subractions represent pairs of returns and the correlations between them wil be calculated eventually. In other words, eventually I will have X_36_31 ( i.e : temp[36] - temp[31] ) X_66-61 X_96-91 . . . . . . . X_1411-1416 as one vector and Y_41-36 Y_71-66 Y_101-96 . . . . . Y_1416_1421 as another vector. and will calculate the correlation between the two vectors in order to get one number. The point is I am really only using the indices 31, 61, 91 etc as anchor's so a regular diff(temp[idx]) won't work because it will diff all the elements that are next to each other ? This is a weird problem. I'm still thinking about it. I'm hoping to figure it out before someone sends me something but I won't mind so much if I get an external solution first. I have no pride. This is not an offer (or solicitation of an offer) to buy/se...{{dropped}} __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.