[R] sequencial frequency table
Hi.
I have the data frame xyz below and I´d like to perform a sequencial
frequency table using some unique function instead of making 3 different
one-by-one table (table x, table y and table z). But I´can´t figure out
the correct way.
x - c(2,3,2,4)
y - c(3,1,1,1)
z - c(4,2,1,4)
xyz - as.data.frame(cbind(x,y,z))
freq - function(x){
table(x)
}
freq(xyz)
Thank you,
Mauricio
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] filling the area
Please, how to fill the area under the curve? x - c(1:10) y - c(rnorm(10)) plot(x,y) lines(x,y) Thanks, Mauricio Cardeal __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] filling the area
Ok. I´ve tried before and all I got was a polygon indeed with the extremes points connected. Please where is the error ? polygon(x,y,col=gray, border = red) Benilton Carvalho escreveu: take a look at: ?polygon b On Jan 25, 2007, at 8:18 AM, Mauricio Cardeal wrote: Please, how to fill the area under the curve? x - c(1:10) y - c(rnorm(10)) plot(x,y) lines(x,y) Thanks, Mauricio Cardeal __ NOD32 1.1752 (20060912) Information __ This message was checked by NOD32 antivirus system. http://www.nod32.com __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] filling the area
Thank you all. One more question about the syntax below: min(y) twice, is it? polygon(c(min(x), x, max(x)), c(min(y), y, min(y)), col = blue) polygon( c(min(x), x, max(x)), c( min(y), y, min(y)), density=100 ) Best whises, Mauricio Marc Schwartz escreveu: On Thu, 2007-01-25 at 10:18 -0300, Mauricio Cardeal wrote: Please, how to fill the area under the curve? x - c(1:10) y - c(rnorm(10)) plot(x,y) lines(x,y) Thanks, Mauricio Cardeal See ?polygon x - 1:10 y - rnorm(10) plot(x,y, type = o) polygon(c(min(x), x, max(x)), c(min(y), y, min(y)), col = blue) HTH, Marc Schwartz __ NOD32 1.1752 (20060912) Information __ This message was checked by NOD32 antivirus system. http://www.nod32.com __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] clear screen
Hello ! Please, how can I clear the RConsole screen ? Is there any clear command ? Thanks, Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] multiple lines and plot
Ok. I´ve already tried ?lines. An example: x - c(1,2,3,4,5,6) y - c(3,5,2,4,1,4) z - c(2,3,4,3,2,1) plot(x,y) lines(x,y) lines(x,z) Here is the point: how to show the points under the second line (x,z) ? Thanks Mauricio David Barron escreveu: ?lines On 20/09/06, Mauricio Cardeal [EMAIL PROTECTED] wrote: Hi. Please, how can I put together 2 or more lines at the same scatterplot ? Example: measures of protein intake (quantitative) of 4 children over 30 days, by day. How to plot all children at same graphic: Protein X Time ? Is there any command like overlay ? Thank you, Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] multiple lines and plot
Hi. Please, how can I put together 2 or more lines at the same scatterplot ? Example: measures of protein intake (quantitative) of 4 children over 30 days, by day. How to plot all children at same graphic: Protein X Time ? Is there any command like overlay ? Thank you, Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] missing value
Hi all # I have this data set and how can I assign NA´s in just one command ? And why the summary(dat) function preserves the value 9 as real. ? x - c(1,2,3,9,4) y - c(3,6,9,2,3) z - c(9,9,2,2,8) w - c(6,5,3,0,9) dat - cbind(x,y,z,w) summary(dat) x[x==9] - NA y[y==9] - NA z[z==9] - NA w[w==9] - NA summary(dat) summary(x) summary(y) summary(z) summary(w) Thank you all, Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] the first and last case
Hi all Sometime ago I asked for a solution about how to aggregate data and the help was wonderful. Now, I´d like to know how to extract for each individual case below the first and the last observation to obtain this: ind y 18 19 27 2 11 39 3 10 4 8 4 5 # Below the example: ind - c(1,1,1,2,2,3,3,3,4,4,4,4) y - c(8,10,9,7,11,9,9,10,8,7,6,5) dat - as.data.frame(cbind(ind,y)) dat attach(dat) mean.ind - aggregate(dat$y, by=list(dat$ind), mean) mean.ind Thanks Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] new object
Hi ! Please, how can I extract n.event and n.risk as a new object from example below ? Thanks in advance. Mauricio require(survival) fit - survfit(Surv(time, status) ~ x, data=aml) summary(fit) Call: survfit(formula = Surv(time, status) ~ x, data = aml) x=Maintained time n.risk n.event survival std.err lower 95% CI upper 95% CI 9 11 10.909 0.0867 0.75411.000 13 10 10.818 0.1163 0.61921.000 18 8 10.716 0.1397 0.48841.000 23 7 10.614 0.1526 0.37690.999 31 5 10.491 0.1642 0.25490.946 34 4 10.368 0.1627 0.15490.875 48 2 10.184 0.1535 0.03590.944 x=Nonmaintained time n.risk n.event survival std.err lower 95% CI upper 95% CI 5 12 2 0.8333 0.1076 0.64701.000 8 10 2 0.6667 0.1361 0.44680.995 12 8 1 0.5833 0.1423 0.36160.941 23 6 1 0.4861 0.1481 0.26750.883 27 5 1 0.3889 0.1470 0.18540.816 30 4 1 0.2917 0.1387 0.11480.741 33 3 1 0.1944 0.1219 0.05690.664 43 2 1 0.0972 0.0919 0.01530.620 45 1 1 0. NA NA NA [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] help
Please, is there any R-list about survival package ? Thanks Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] mca id numbers
Is it possible to make disappear the id numbers from scatter.dudi (mc analysis) ? a - as.factor(c(1, 2, 3, 2, 1)) b - as.factor(c(3, 2, 3, 1, 1)) x - as.factor(c(1, 2, 2, 1, 3)) y - as.factor(c(2, 2, 3, 1, 1)) dat - data.frame(a=a, b=b,x=x,y=y) summary(dat) dat require(ade4) dat.acm - dudi.acm(dat, scann = FALSE, nf = 2) scatter.dudi(dat.acm) Thank you very much ! Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] factors and mca
Hi ! Wonder if I have this code below: a - c(1, 2, 3, 2, 1) b - c(3, 2, 3, 1, 1) d -as.factor(a) e -as.factor(b) table(d,e) is.factor(a) is.factor(b) is.factor(d) is.factor(e) de - factor(c(d,e)) is.factor(de) require(MASS) mca(de) I'd like to perform a correspondence analysis, but I can't understand why the message error after mca. Aren't those (d and e) factors as is.factors shows ? Erro em mca(de) : all variables must be factors I'm running R 2.3.0 under windows XP Thank you ! Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] sample matrix
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] sample matrix as a new object
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] correct rate
Hi everone ! I know its not a epidemiologic or statistic list, but since I´m using R to solve related problems ... here it goes: This is a code to solve the rate problem, but the real question is: what´s the correct way to calculate the period rate (3 years period put together) The third option is quite different (middle period). Any suggestions ? Thanks Mauricio, Brazil # Example from Field epidemiology basics computer lab 1 # annual period rates (1989, 1990, 1991) years - 1989:1991 deaths - c(125, 130, 131) pop - c(361975, 361401, 366613) # rates and rates per 10.000 per year rates - deaths/pop ratesf - round(rates*1,digits=2) rates ratesf # to calculate the period rate we have 3 possibilities: # 1) sum of deaths by sum of populations: rates89_91_1 - sum(deaths)/sum(pop) rates89_91f_1 - round(rates89_91_1*1,digits=2) rates89_91_1 rates89_91f_1 # 2) mean rates: rates89_91_2 - (rates[1]+rates[2]+rates[3])/3 rates89_91f_2 - round(rates89_91_2*1,digits=2) rates89_91_2 rates89_91f_2 # 3) sum of deahts by middle population (1990): rates89_91_3 - (deaths[1]+deaths[2]+deaths[3])/pop[2] rates89_91f_3 - round(rates89_91_3*1,digits=2) rates89_91_3 rates89_91f_3 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] npmc package
Hi Does anyone know where is the package: npmc (Nonparametric Multiple Comparisons). I found the reference on R Site Search, but not the package itself on CRAN as suggested. Thanks Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] npmc package
So, is there another package to substitute those functions described on ORPHANED npmc package ? Regards, Mauricio Brazil Uwe Ligges escreveu: Carlos Mauricio Cardeal Mendes wrote: Hi Does anyone know where is the package: npmc (Nonparametric Multiple Comparisons). I found the reference on R Site Search, but not the package itself on CRAN as suggested. The packages is ORPHANED and removed from the CRAN main repository. You can get older versions from the archives, though: your-CRAN-mirror/src/contrib/Archive/N/npmc_1.0-1.tar.gz Uwe Ligges Thanks Mauricio __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] if() command
Ok Petr, I run your suggestion and I got this message:
age-sample(seq(10,50,10), 20, replace=T)
if (age =10) {group - 1} else if (age 10 age = 20) {group -
2} else {group - 3}
Warning message:
the condition has length 1 and only the first element will be used in:
if (age = 10) {
What does it means ?
And when I look to the database I have no new classification !
Could you help please ?
Mauricio
Petr Pikal escreveu:
Hallo
On 13 Sep 2005 at 10:29, Carlos Maurício Cardeal Mende wrote:
Hi everyone !
Could you please help me with this problem ?
I´ve trying to write a code that assign to a variable the content from
another, but all I´ve got is a message error. For example:
if (age =10) {group == 1}
else if (age 10 age = 20) {group == 2}
else {group == 3}
if you put your statement on one line it works (at least it does not
give you syntax error) but the result is hardly what you really expect
age-sample(seq(10,50,10), 20, replace=T)
if (age =10) {group - 1} else if (age 10 age = 20) {group - 2}
else {group - 3}
if (age =10) {group == 1} else if (age 10 age = 20) {group == 2}
else {group == 3}
Maybe you want something like
group-as.numeric(cut(age,c(0,10,20,100)))
but it is only guess
HTH
Petr
Syntax error
Or
if (age =10) {group == 1}
else (age 10 age = 20) {group == 2}
else {group == 3}
Syntax error
I know that is possible to find the solution by ifelse command or even
recode command, but I´d like to use this way, because I can add
another variable as a new condition and I believe to expand the
possibilites.
Thanks,
Mauricio
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
Petr Pikal
[EMAIL PROTECTED]
No virus found in this incoming message.
Checked by AVG Anti-Virus.
Version: 7.0.344 / Virus Database: 267.10.21/96 - Release Date: 10/9/2005
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] if() command
Hello reid ! About your third explanation, could you please write the
complete code including that option: a loop ?
Forgiveme, I'm trying to learn R and my mind is full of other
statistical program syntax. And I'd like very very much to improve my
knowledge using R and maybe contribute to someone, someday, somehow.
Thanks, again
Mauricio
Huntsinger, Reid escreveu:
First, == is logical comparison, so if you want to create a variable based
on both age and group you can do that. However, it looks like you want
to define the variable group, so you want to use - or = for that.
Second, if you're typing this at a command prompt, you need to make sure you
tell R you're not finished when it looks like you could be. There are
several ways to do this. One is to put everything inside braces; another is
to deliberately leave lines incomplete, like
if (age = 10) {
group - 1
} else {
if (age = 20) {
group - 2
} else group - 3
}
Third, this will work for a vector of length 1. If you want to take a vector
age and produce a corresponding vector group, you'll need to put this in
a loop, or use lapply, or some iteration.
Fourth, you can also write the above as
group - if (age = 10) 1 else if (age = 20) 2 else 3
that is, if() returns a value you can assign.
Finally, besides ifelse you can use cut for this particular task.
Reid Huntsinger
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Carlos Maurício
Cardeal Mendes
Sent: Tuesday, September 13, 2005 9:29 AM
To: r-help@stat.math.ethz.ch
Subject: [R] if() command
Hi everyone !
Could you please help me with this problem ?
I´ve trying to write a code that assign to a variable the content from
another, but all I´ve got is a message error. For example:
if (age =10) {group == 1}
else if (age 10 age = 20) {group == 2}
else {group == 3}
Syntax error
Or
if (age =10) {group == 1}
else (age 10 age = 20) {group == 2}
else {group == 3}
Syntax error
I know that is possible to find the solution by ifelse command or even
recode command, but I´d like to use this way, because I can add another
variable as a new condition and I believe to expand the possibilites.
Thanks,
Mauricio
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
--
Notice: This e-mail message, together with any attachments...{{dropped}}
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Proportions again
Hello. I asked before and it was great, cause as a beginner I learned a lot. But, if I have this in R (1 and 2 are codes for sex): sex-c(1,2,2,1,1,2,2,2) sex [1] 1 2 2 1 1 2 2 2 I´d like to obtain the proportion according to sex.So I type: prop.table(sex) [1] 0.07692308 0.15384615 0.15384615 0.07692308 0.07692308 0.15384615 0.15384615 [8] 0.15384615 The result is OK, but I expected to see a simple frequency table or something like that: 1 0.375 2 0.625 1.0 How can I get this ? Thank you very much [[alternative HTML version deleted]] __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] proportions
Hi all: Please be patient with my silly question: How can I get proportions if I have a contingency table ? I tried the table command, but I almost sure I made my usual mistakes. Thaks Mauricio __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
