[R] Ranking and selection statistical procedure

2006-08-31 Thread Prasanna BALAPRAKASH 
Dear R helpers

I would like to know if the Ranking and Selection statistical
procedure has been implemented in R. I made a quick search in the R
packages list but I could not find it.

Thanks in advance
Prasanna

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[R] Scaling in plot function

2006-03-11 Thread Prasanna BALAPRAKASH 
Dear R helpers,

I have a vector of 500 numbers and I need to plot them in such a way  
that the first 250 values should occupy 80% of the plot and the  
remaining ones should take 20%. More precisely, x axis ranges form  
1:500 and the idea is to give the snapshot of the first 250 values. I  
tried  axis() and log=x, but I am not getting the required output.


Thanks
Prasanna

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[R] chi-Squared distribution

2005-01-21 Thread Prasanna Balaprakash 
Dear Rs:


outer(1:3, 1:3, function(df1, df2) qf(0.95, df1, df2))  

I compare this F distribution results with the table, the answers were perfect. 
But I need to see for chi-sqaured distribution. When I employed the similar 
formula

outer(1:3, 1:3, function(df1, df2) qchisq(0.95, df1, df2)) , I am getting 
unexpected results. I need to see the following values:

 p=0.750  .
1 1.323

2 2.773   

3 4.108   


Thanking you
Prasanna






Prasanna Balaprakash,
Université Libre de Bruxelles, 
50, Av. F. Roosevelt, CP 194/6, 
B-1050 Brussels, 
Belgium.

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[R] chi-Squared distribution in Friedman test

2005-01-21 Thread Prasanna Balaprakash 
Dear R helpers:


Thanks for the previous reply. I am using Friedman racing test. According the 
the book Pratical Nonprametric Statistic by WJ Conover, after computing the 
statistics, he suggested to use chi-squared or F distribution to accept or 
reject null hypothesis. After looking into the source code, I found that R uses 
chi-sqaured distribution as below:

PVAL - pchisq(STATISTIC, PARAMETER, lower = FALSE)

but still I cant figure out why they are using this pschisq insted of dchisq. 
Sorry I am wrong!!


Thanking you
truly
Prasanna










- Original Message - 
From: Dimitris Rizopoulos [EMAIL PROTECTED]
To: Prasanna Balaprakash [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Friday, January 21, 2005 1:05 PM
Subject: Re: [R] chi-Squared distribution


 if you check ?qchisq, you'll see that the second

My mistake, the third argument

 argument of the function denotes the non-centrality parameter! Try

 qchisq(0.75, 1:3)

 to get your answer.

 Best,
 Dimitris

 
 Dimitris Rizopoulos
 Ph.D. Student
 Biostatistical Centre
 School of Public Health
 Catholic University of Leuven

 Address: Kapucijnenvoer 35, Leuven, Belgium
 Tel: +32/16/336899
 Fax: +32/16/337015
 Web: http://www.med.kuleuven.ac.be/biostat
 http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm


 - Original Message - 
 From: Prasanna Balaprakash [EMAIL PROTECTED]
 To: r-help@stat.math.ethz.ch
 Sent: Friday, January 21, 2005 12:27 PM
 Subject: [R] chi-Squared distribution


 Dear Rs:


 outer(1:3, 1:3, function(df1, df2) qf(0.95, df1, df2))

 I compare this F distribution results with the table, the answers 
 were perfect. But I need to see for chi-sqaured distribution. When 
 I employed the similar formula

 outer(1:3, 1:3, function(df1, df2) qchisq(0.95, df1, df2)) , I am 
 getting unexpected results. I need to see the following values:

 p=0.750  .
 1 1.323

 2 2.773

 3 4.108


 Thanking you
 Prasanna






 Prasanna Balaprakash,
 Université Libre de Bruxelles,
 50, Av. F. Roosevelt, CP 194/6,
 B-1050 Brussels,
 Belgium.

 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide! 
 http://www.R-project.org/posting-guide.html

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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html