try the following:
arrivals - matrix(sample(1:24, 100, TRUE), 10, 10)
apply(arrivals, 2, function(x) table(factor(x, levels = 1:24)))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
- Original Message -
From: Spencer Jones [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Wednesday, August 16, 2006 5:22 PM
Subject: [R] list to balanced array
I am working with a large data set of arrivals, for each day I have
aggregated the arrivals into hrs (1-24) via: apply(x,2,table). On
some days
there are zero arrivals during some hours of the day, this leaves me
with
(I believe) a list of vectors of differnt lengths (see below).
[[4]]
1 2 3 5 6 8 9 10 11 13 14 15 16 17 18 19 20 21 22 23 24
1 3 2 3 1 1 2 3 4 4 4 3 2 6 2 5 1 2 2 2
1
[[5]]
2 5 6 8 9 10 11 12 13 14 15 16 17 18 19 20 22 23 24
2 1 1 2 1 5 3 6 6 3 2 2 1 4 3 3 4 2 1
I would like to be able to create an array with equal numbers of
rows (24)
for each column, i.e., fill in the gaps with Zeros.
[[5]]
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
23 24
0 2 0 0 1 1 0 2 1 5 3 6 6 3 2 2 1 4 3 0
3
4 2 1
Any suggestions?
thanks,
Spencer
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
