No, the "cut" command won't understand that "z" is an R connection and
not a file in the current working directory: there is no overlap
between the R object name space and the Windows object name space.
Unfortunately, you may be forced to unzip to a temporary file, and
then read from that.
One thing that you might want to try, if you're using cygwin, is to
create a named pipe, and use "shell()" with wait=FALSE to unzip and
pipe into "cut" and then output to the named pipe. Open an R
connection for reading from the named pipe. This leaves open the
question of how to deal with failures, and whether you can invoke a
command pipeline from R under Windows...
I haven't tried this, so if you manage to make it work, it may be
something that's of interest to the list in general.
Regards,
Mike
On 9/25/06, Anupam Tyagi <[EMAIL PROTECTED]> wrote:
> Hello, is there a way to pass a connection to a file in a zipped archive as
> argument (instead of a file name of unzipped file) to shell command "cut". In
> general, is it possible to pipe output of a R function to a shell command?
> How?
>
> I want to do something like:
>
> z = unz("zipArchive.zip", "fileASCII.ASC")
> # open connection
> open(z)
> # cut lines of the ASCII file in zipped archive at specific postions and send
> results to another file.
> shell("cut -c2-3,5-8 z > test2.dat")
>
> Anupam.
>
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Regards,
Mike Nielsen
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