[R] R: mean from list
great!! thanks very much, mean(unlist(lapply(listdata, function(z) z$c))) works well. and what about getting the average table $a (displaying the average elements across all 1000 matrix)? could you please help me? I am struggling with this... thanks in advance Roberto mean(unlist(lapply(x, function(z) z$d))) should do the trick On Sun, 12 Feb 2006 20:06:12 +, [EMAIL PROTECTED] wrote: hi all, I have a simple problem that i am not able to solve. I've a list called datalist with the following structure: [...] [[10]] [[10]]$a -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$b -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$c [1] 0.855 [[10]]$d [1] 0.855 [...] with [[1]] ... [[100]]. How can i get the mean value of datalist[[x]]$d, where x represents all elements from 1 to 1000 ? thanks in advance Roberto Furlan University of Turin La mia Cartella di Posta in Arrivo è protetta da SPAMfighter 205 messaggi contenenti spam sono stati bloccati con successo. Scarica gratuitamente SPAMfighter! __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Rajarshi Guha [EMAIL PROTECTED] http://jijo.cjb.net La mia Cartella di Posta in Arrivo è protetta da SPAMfighter 205 messaggi contenenti spam sono stati bloccati con successo. Scarica gratuitamente SPAMfighter! __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R: mean from list
[EMAIL PROTECTED] wrote: great!! thanks very much, mean(unlist(lapply(listdata, function(z) z$c))) WHY unlist(lapply(... when sapply(... is simpler? Kjetil works well. and what about getting the average table $a (displaying the average elements across all 1000 matrix)? could you please help me? I am struggling with this... thanks in advance Roberto mean(unlist(lapply(x, function(z) z$d))) should do the trick On Sun, 12 Feb 2006 20:06:12 +, [EMAIL PROTECTED] wrote: hi all, I have a simple problem that i am not able to solve. I've a list called datalist with the following structure: [...] [[10]] [[10]]$a -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$b -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$c [1] 0.855 [[10]]$d [1] 0.855 [...] with [[1]] ... [[100]]. How can i get the mean value of datalist[[x]]$d, where x represents all elements from 1 to 1000 ? thanks in advance Roberto Furlan University of Turin La mia Cartella di Posta in Arrivo è protetta da SPAMfighter 205 messaggi contenenti spam sono stati bloccati con successo. Scarica gratuitamente SPAMfighter! __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Rajarshi Guha [EMAIL PROTECTED] http://jijo.cjb.net La mia Cartella di Posta in Arrivo è protetta da SPAMfighter 205 messaggi contenenti spam sono stati bloccati con successo. Scarica gratuitamente SPAMfighter! __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R: mean from list
On Sun, 2006-02-12 at 19:21 -0400, Kjetil Brinchmann Halvorsen wrote: [EMAIL PROTECTED] wrote: great!! thanks very much, mean(unlist(lapply(listdata, function(z) z$c))) WHY unlist(lapply(... when sapply(... is simpler? Aah! Immediately after sending it I realized the simpler form :-/ --- Rajarshi Guha [EMAIL PROTECTED] http://jijo.cjb.net GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE --- Finally I am becoming stupider no more - Paul Erdos' epitaph __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
