Re: [R] R-help Digest, Vol 35, Issue 7
Uwe Ligges пишет:
Evgeniy Kachalin wrote:
Hello, dear participants!
Could you tip me, is there any simple and nice way to build
scatter-plot for three different types of data (, and o and * - signs,
for example) with legend.
Now i can guess only that way:
plot(x~y,data=subset(mydata,factor1=='1'), pch='.',col='blue')
points(x~y,data=subset(mydata,factor1=='2'), pch='*',col='green')
points( etc
What is the simple and nice way?
Thank you very much for your kindness and help.
Example:
with(iris,
plot(Sepal.Length, Sepal.Width, pch = as.integer(Species)))
with(iris,
legend(7, 4.4, legend = unique(as.character(Species)),
pch = unique(as.integer(Species
Uwe, sorry for my stupid question. You mean that when pch=factor , plot
can recycle the factor and use it for subscripts or marks.
Then pch=as.integer(Species) results in c(1,2,3) for 3 factor levels.
And I need symbols 15,16,17 and colors red, blue, green.
So then I do:
iris$Species-spec.symb
iris$Species-spec.col
levels(spec.symb)-c(15,16,17)
levels(spec.col)-c('red','green','blue')
That's the only way?
More of that!!! 'Plot' does not like factors in 'pch'. So it must be so:
plot(x~y,data, pch=as.integer(as.character(spec.symb))).
That's totally crazy...
--
Evgeniy
__
R-help@stat.math.ethz.ch mailing list
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Re: [R] R-help Digest, Vol 35, Issue 7
Hi!
Just use your factors for indexing c(15,16,17) and
c(red,green,blue). So, with the iris data:
with(iris, plot(Sepal.Length, Sepal.Width,
pch=c(15,16,17)[as.integer(Species)],
col=c(red,green,blue)[as.integer(Species)] ))
Best regards,
Kyosti Kurikka
Evgeniy Kachalin wrote:
Hello, dear participants!
Could you tip me, is there any simple and nice way to build
scatter-plot for three different types of data (, and o and * - signs,
for example) with legend.
Now i can guess only that way:
plot(x~y,data=subset(mydata,factor1=='1'), pch='.',col='blue')
points(x~y,data=subset(mydata,factor1=='2'), pch='*',col='green')
points( etc
What is the simple and nice way?
Thank you very much for your kindness and help.
Example:
with(iris,
plot(Sepal.Length, Sepal.Width, pch = as.integer(Species)))
with(iris,
legend(7, 4.4, legend = unique(as.character(Species)),
pch = unique(as.integer(Species
Uwe, sorry for my stupid question. You mean that when pch=factor , plot
can recycle the factor and use it for subscripts or marks.
Then pch=as.integer(Species) results in c(1,2,3) for 3 factor levels.
And I need symbols 15,16,17 and colors red, blue, green.
So then I do:
iris$Species-spec.symb
iris$Species-spec.col
levels(spec.symb)-c(15,16,17)
levels(spec.col)-c('red','green','blue')
That's the only way?
More of that!!! 'Plot' does not like factors in 'pch'. So it must be so:
plot(x~y,data, pch=as.integer(as.character(spec.symb))).
That's totally crazy...
--
Evgeniy
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R-help Digest, Vol 35, Issue 7
Evgeniy Kachalin wrote:
Uwe Ligges пишет:
Evgeniy Kachalin wrote:
Hello, dear participants!
Could you tip me, is there any simple and nice way to build
scatter-plot for three different types of data (, and o and * -
signs, for example) with legend.
Now i can guess only that way:
plot(x~y,data=subset(mydata,factor1=='1'), pch='.',col='blue')
points(x~y,data=subset(mydata,factor1=='2'), pch='*',col='green')
points( etc
What is the simple and nice way?
Thank you very much for your kindness and help.
Example:
with(iris,
plot(Sepal.Length, Sepal.Width, pch = as.integer(Species)))
with(iris,
legend(7, 4.4, legend = unique(as.character(Species)),
pch = unique(as.integer(Species
Uwe, sorry for my stupid question. You mean that when pch=factor , plot
can recycle the factor and use it for subscripts or marks.
Yes, it can recycle, but in the example above it does not recycle but
takes the whole Species vector.
Then pch=as.integer(Species) results in c(1,2,3) for 3 factor levels.
And I need symbols 15,16,17 and colors red, blue, green.
What about adding 14 as in as.integer(Species)+14, or 1 for the colors,
respectively?
So then I do:
iris$Species-spec.symb
iris$Species-spec.col
levels(spec.symb)-c(15,16,17)
levels(spec.col)-c('red','green','blue')
That's the only way?
This is one qay of many.
More of that!!! 'Plot' does not like factors in 'pch'. So it must be so:
plot(x~y,data, pch=as.integer(as.character(spec.symb))).
That's totally crazy...
You can set up your own pch variable of course, if you don't like it
this fast and easy way.
Uwe Ligges
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R-help Digest, Vol 35, Issue 7
Hello, dear participants! Could you tip me, is there any simple and nice way to build scatter-plot for three different types of data (, and o and * - signs, for example) with legend. Now i can guess only that way: plot(x~y,data=subset(mydata,factor1=='1'), pch='.',col='blue') points(x~y,data=subset(mydata,factor1=='2'), pch='*',col='green') points( etc What is the simple and nice way? Thank you very much for your kindness and help. -- Evgeniy Kachalin __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R-help Digest, Vol 35, Issue 7
Evgeniy Kachalin wrote: Hello, dear participants! Could you tip me, is there any simple and nice way to build scatter-plot for three different types of data (, and o and * - signs, for example) with legend. Now i can guess only that way: plot(x~y,data=subset(mydata,factor1=='1'), pch='.',col='blue') points(x~y,data=subset(mydata,factor1=='2'), pch='*',col='green') points( etc What is the simple and nice way? Thank you very much for your kindness and help. Example: with(iris, plot(Sepal.Length, Sepal.Width, pch = as.integer(Species))) with(iris, legend(7, 4.4, legend = unique(as.character(Species)), pch = unique(as.integer(Species Uwe Ligges __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
