The apply function is passing each row of you matrix as a single vector into
paste. If paste receives a single vector and collapse is NULL, it will
simply coerce the vector into a character vector.
However, when you collapse instead of sep
test - matrix( as.character(1:4), 2)
apply(test, 1, paste, sep=+)
[,1] [,2]
[1,] 1 2
[2,] 3 4
apply(test, 1, paste, collapse=+)
[1] 1+3 2+4
Which may be closer to what you were expecting, but I'm just guessing.
--Matt
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Kjetil
Brinchmann
halvorsen
Sent: Sunday, November 06, 2005 5:34 AM
To: r-help@stat.math.ethz.ch
Subject: [R] Use of paste with apply()
I was surprised by:
test - matrix( as.character(1:4), 2)
test
[,1] [,2]
[1,] 1 3
[2,] 2 4
apply(test, 1, paste, sep=+)
[,1] [,2]
[1,] 1 2
[2,] 3 4
apply(test, 1, paste, sep=*)
[,1] [,2]
[1,] 1 2
[2,] 3 4
te - matrix(1:4, 2)
te
[,1] [,2]
[1,]13
[2,]24
apply(te, 1, sum)
[1] 4 6
Why doesn't paste behave in apply as sum?
Kjetil
--
Checked by AVG Free Edition.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
