[R] cancor

2005-05-27 Thread zjao yana
Hello,
I'm a beginner to use R. 
When use cancor to analysis two data set X,Y, for
example:
 can-cancor(X, Y)
 then 5 components are returned, that is cor, xcoef,
ycoef, xcentre, ycentre; 

The explained variance can be calculated by X %*%
can$xcoef or Y %*% can$ycoef, but how to alculate the
canonical maps of field X and Y? 
Thanks!

yana

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[R] Cancor

2004-09-15 Thread Irena Komprej
Dear Gabor,
thank you for your answer related to the normalization of cancor
coefficients. If you want to interpret the coefficients in terms of
variables' contributions to canonical variables, loadings, redundancy
measure, etc. ,  you have to normalize the results so that the canonical
variables have identity variance matrix. Multiplying cancor coefficients
xcoef and ycoef by as.numeric(sqrt(nrow(x)-1)) does the job.
(I sometimes miss such information in the R help.)
Best regards,
Irena Komprej

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Re: [R] Cancor

2004-09-15 Thread Prof Brian Ripley
On (she claimed) Thu, 1 Jan 1998, Irena Komprej wrote:

 Dear Gabor,

This is R-help, not `Gabor', although you keep sending mail addressed to
`Gabor' to this list.

 thank you for your answer related to the normalization of cancor
 coefficients. If you want to interpret the coefficients in terms of
 variables' contributions to canonical variables, loadings, redundancy
 measure, etc. ,  you have to normalize the results so that the canonical
 variables have identity variance matrix. Multiplying cancor coefficients
 xcoef and ycoef by as.numeric(sqrt(nrow(x)-1)) does the job.
 (I sometimes miss such information in the R help.)

I think you miss it in the references given on the R help pages.  Please
do read them.  (Any good book will tell you that the scaling of canonical 
variates is arbitrary.)

Please also ask your local IT advisors to set your computer to a 
sensible time: the world is 6.7 years ahead of you.

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] Cancor

2004-09-12 Thread Gabor Grothendieck
Irena Komprej irena.komprej at telemach.net writes:

 
 I am strugling with cancor procedure in R. I cannot figure out the
 meaning of xcoef and of yxcoef.
 Are these:
 1. standardized coefficients
 2. structural coefficients
 3. something else?
 


Look at the examples at the bottom of ?cancor from which its evident
xcoef is such that x %*% cxy$xcoef are the canonical variables.  (More
at the end of this post.)


 I have tried to simulate canonical correlation analysis by checking the
 eigenstructure of the expression:
 
 Sigma_xx %*% Sigma_xy %*% Sigma_yy %*% t(Sigma_xy).
 
 The resulting eigenvalues were the same as the squared values of
 cancor$cor. I have normalized the resulting eigenvectors, the a's with
 
 sqrt(a'%*%Sigma_xx%*%t(a)), and similarly the b's with
 sqrt(b'%*%Sigma_yy%*%t(b)).
 
 The results differed considerably from xcoef and ycoef of the cancor.

Run the example in the help page to get some data and some
output:

   set.seed(1)
   example(cancor)

# Also, define isqrt as the inverse square root of a postive def matrix

   isqrt - function(x) {
  e - eigen(x)
  stopifnot( all(e$values  0) )
  e$vectors %*% diag(1/sqrt(e$values)) %*% solve(e$vectors)
}

# we can reconstruct the canonical correlations and xcoef 
# in the way you presumably intended like this:

   z - svd(cov(x,y) %*% solve(var(y), cov(y,x)) %*% solve(var(x)))
   sqrt(z$d)  # canonical correlations
   isqrt((nrow(x)-1)*var(x)) %*% z$u# xcoef 

Another thing you can do is to type

   cancor

at the R prompt to view its source and see how it works using
the QR decomposition.

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[R] Cancor

2004-09-11 Thread Irena Komprej
Dear R's!
I am strugling with cancor procedure in R. I cannot figure out the
meaning of xcoef and of yxcoef.
Are these:
1. standardized coefficients
2. structural coefficients
3. something else?

I have tried to simulate canonical correlation analysis by checking the
eigenstructure of the expression:

Sigma_xx %*% Sigma_xy %*% Sigma_yy %*% t(Sigma_xy).

The resulting eigenvalues were the same as the squared values of
cancor$cor. I have normalized the resulting eigenvectors, the a's with

sqrt(a'%*%Sigma_xx%*%t(a)), and similarly the b's with
sqrt(b'%*%Sigma_yy%*%t(b)).

The results differed considerably from xcoef and ycoef of the cancor.

I thought then, maybe these coefficients are structural coefficients and
therefore I multiplied them, the a's with
a%*%Sigma_xx, and the b's with
b%*%Sigma_yy,

but the results are nevertheless far from those of the cancor. Now, I
really don't know any more, how to interpret the xcoef and ycoef.
I am thanking you in advance.

Irena Komprej
(an R enthusiast as of last year)

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[R] Cancor

2004-09-11 Thread Irena Komprej
Dear R's!
I am strugling with cancor procedure in R. I cannot figure out the
meaning of xcoef and of yxcoef.
Are these:
1. standardized coefficients
2. structural coefficients
3. something else?

I have tried to simulate canonical correlation analysis by checking the
eigenstructure of the expression:

Sigma_xx %*% Sigma_xy %*% Sigma_yy %*% t(Sigma_xy).

The resulting eigenvalues were the same as the squared values of
cancor$cor. I have normalized the resulting eigenvectors, the a's with

sqrt(a'%*%Sigma_xx%*%t(a)), and similarly the b's with
sqrt(b'%*%Sigma_yy%*%t(b)).

The results differed considerably from xcoef and ycoef of the cancor.

I thought then, maybe these coefficients are structural coefficients and
therefore I multiplied them, the a's with
a%*%Sigma_xx, and the b's with
b%*%Sigma_yy,

but the results are nevertheless far from those of the cancor. Now, I
really don't know any more, how to interpret the xcoef and ycoef.
I am thanking you in advance.

Irena Komprej
(an R enthusiast as of last year)

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