Re: [R] convert decimals to fractions - sorted
Ah I see, I did not read your story well enough. You want to sort after applying table() Well, the idea I suggested was to keep the real numbers in, because the fractions are sorted as characters strings (alphabetically), which is not what you want. So, now I suggest the following: # First apply table() tmp1 - as.data.frame(table(df)) # Note that table() turned your numeric data into factors, # this might not be a handy approach, anyways, it is possible I guess. # You have to convert back using as.numeric(as.character(tmp1$V2)) # or, more efficiently, as.numeric(levels(tmp1$V2))[tmp1$V2] # Add the column with the fractions tmp2 - cbind(tmp1, fracs=as.character(as.fractions(as.numeric(as.character(tmp1$V2) # Finally hide that sort colum if you want ( tmp2[-2] ) # Everybody happy? JeeBee __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] convert decimals to fractions - sorted
Dear JeeBee and all, It is nice. Thanks you very much. I must learn much more about ?as.fractions, ?as.numeric, ?as.character and ?table functions. Best wishes, Muhammad Subianto On 7/28/06, JeeBee [EMAIL PROTECTED] wrote: Ah I see, I did not read your story well enough. You want to sort after applying table() Well, the idea I suggested was to keep the real numbers in, because the fractions are sorted as characters strings (alphabetically), which is not what you want. So, now I suggest the following: # First apply table() tmp1 - as.data.frame(table(df)) # Note that table() turned your numeric data into factors, # this might not be a handy approach, anyways, it is possible I guess. # You have to convert back using as.numeric(as.character(tmp1$V2)) # or, more efficiently, as.numeric(levels(tmp1$V2))[tmp1$V2] # Add the column with the fractions tmp2 - cbind(tmp1, fracs=as.character(as.fractions(as.numeric(as.character(tmp1$V2) # Finally hide that sort colum if you want ( tmp2[-2] ) # Everybody happy? JeeBee __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] convert decimals to fractions - sorted
Hi Muhammad, How about this? at - read.table(textConnection(a)) at2 - cbind(at, jeebee=as.character(as.fractions(as.numeric(at[,2] sort.order - order(at2$V2) at2[sort.order,] at2[sort.order,c(1,3)] JeeBee. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] convert decimals to fractions - sorted
Dear all, Thanks for your help. I played with you suggest and still didn't sort (summary) which I need. t(table(at2[sort.order,c(1,3)])) V1 jeebee -1 1 0 0 4 11/21 0 1 1/21 0 1/21 1 1 13/42 1 1 17/42 0 2 2/21 0 3 3/14 1 2 5/42 0 1 8/21 0 1 I need the result summary (order) like, -1 1 0/42 0 4 2/42 1 1 4/42 0 3 5/42 0 1 9/42 1 2 13/42 1 1 16/42 0 1 17/42 0 2 21/42 1 0 22/42 0 1 Thanks very much for any suggestions. Groeten Regards, Muhammad Subianto On 7/26/06, JeeBee [EMAIL PROTECTED] wrote: Hi Muhammad, How about this? at - read.table(textConnection(a)) at2 - cbind(at, jeebee=as.character(as.fractions(as.numeric(at[,2] sort.order - order(at2$V2) at2[sort.order,] at2[sort.order,c(1,3)] JeeBee. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. On 7/25/06, Muhammad Subianto [EMAIL PROTECTED] wrote: Dear all, Based on my question a few months ago https://stat.ethz.ch/pipermail/r-help/2006-January/086952.html and solved with https://stat.ethz.ch/pipermail/r-help/2006-January/086955.html https://stat.ethz.ch/pipermail/r-help/2006-January/086956.html and from https://stat.ethz.ch/pipermail/r-help/2006-January/086958.html frac.fun - function(x, den){ dec - seq(0, den) / den nams - paste(seq(0, den), den, sep = /) sapply(x, function(y) nams[which.min(abs(y - dec))]) } ### frac.fun(c(0, 1, 0.827, .06, 0.266), 75) Now, I have a dataset something like this: a -1 0 1 0.095238095238095 1 0.214285714285714 -1 0.5 1 0.309523809523810 -1 0.0476190476190476 1 0.404761904761905 1 0.119047619047619 -1 0.214285714285714 -1 0.309523809523810 1 0 1 0 1 0.404761904761905 1 0.095238095238095 1 0.047619047619047 1 0.380952380952381 1 0.214285714285714 1 0.523809523809524 1 0 1 0.095238095238095 First, I make it as fractions and then sorted. I have played around to make it sort, but it didn't succes. df - read.table(textConnection(a)) library(MASS) as.fractions(as.numeric(df[,2])) cbind(table(df[,2], df[,1]), summary(as.factor(df[,2]))) table(frac.fun(as.numeric(df[,2]),42), df[,1]) table(frac.fun(as.numeric(df[,2]),42), df[,1]) -1 1 0/42 0 4 13/42 1 1 16/42 0 1 17/42 0 2 21/42 1 0 22/42 0 1 2/42 1 1 4/42 0 3 5/42 0 1 9/42 1 2 How to make the result as sort (to increase) like this, -1 1 0/42 0 4 2/42 1 1 4/42 0 3 5/42 0 1 9/42 1 2 13/42 1 1 16/42 0 1 17/42 0 2 21/42 1 0 22/42 0 1 Thank's for any help. Best, Muhammad Subianto __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] convert decimals to fractions - sorted
Dear all, Based on my question a few months ago https://stat.ethz.ch/pipermail/r-help/2006-January/086952.html and solved with https://stat.ethz.ch/pipermail/r-help/2006-January/086955.html https://stat.ethz.ch/pipermail/r-help/2006-January/086956.html and from https://stat.ethz.ch/pipermail/r-help/2006-January/086958.html frac.fun - function(x, den){ dec - seq(0, den) / den nams - paste(seq(0, den), den, sep = /) sapply(x, function(y) nams[which.min(abs(y - dec))]) } ### frac.fun(c(0, 1, 0.827, .06, 0.266), 75) Now, I have a dataset something like this: a -1 0 1 0.095238095238095 1 0.214285714285714 -1 0.5 1 0.309523809523810 -1 0.0476190476190476 1 0.404761904761905 1 0.119047619047619 -1 0.214285714285714 -1 0.309523809523810 1 0 1 0 1 0.404761904761905 1 0.095238095238095 1 0.047619047619047 1 0.380952380952381 1 0.214285714285714 1 0.523809523809524 1 0 1 0.095238095238095 First, I make it as fractions and then sorted. I have played around to make it sort, but it didn't succes. df - read.table(textConnection(a)) library(MASS) as.fractions(as.numeric(df[,2])) cbind(table(df[,2], df[,1]), summary(as.factor(df[,2]))) table(frac.fun(as.numeric(df[,2]),42), df[,1]) table(frac.fun(as.numeric(df[,2]),42), df[,1]) -1 1 0/42 0 4 13/42 1 1 16/42 0 1 17/42 0 2 21/42 1 0 22/42 0 1 2/42 1 1 4/42 0 3 5/42 0 1 9/42 1 2 How to make the result as sort (to increase) like this, -1 1 0/42 0 4 2/42 1 1 4/42 0 3 5/42 0 1 9/42 1 2 13/42 1 1 16/42 0 1 17/42 0 2 21/42 1 0 22/42 0 1 Thank's for any help. Best, Muhammad Subianto __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.