[R] Expression for pedices
I know that this maybe a trivial question. I am not able to plot pedices in graph axes. Instead I am able to plot different math symbols : XLABEL - expression(paste(cmH,lim(f(x), x %-% 0),O PEEP)) works well XLABEL - expression(paste(cmH,[2],O PEEP)) is considered a wrong expression. Thanks __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Expression for pedices
On 4/15/2007 2:05 PM, Cressoni, Massimo (NIH/NHLBI) [F] wrote: I know that this maybe a trivial question. I am not able to plot pedices in graph axes. Instead I am able to plot different math symbols : I think you mean subscripts. XLABEL - expression(paste(cmH,lim(f(x), x %-% 0),O PEEP)) works well XLABEL - expression(paste(cmH,[2],O PEEP)) is considered a wrong expression. Yes, you don't want the comma before the bracket: XLABEL - expression(paste(cmH[2],O PEEP)) Duncan Murdoch __ [EMAIL PROTECTED] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression()
Thanks you,
this works right.
I just would like to note one thing:
although I've found italic() in the help for plotmath and I can see that
the italic function:
mtext(expression(italic(beta)[max]),side=1,line=2)
does not work on the greek beta character.
Though not strictly necessary, this would be perfect for my plots, as I
use them for papers to be published.
Wishes,
Javier
--
Benilton Carvalho wrote:
mtext(expression(beta[max]), side=1, line=2)
is it what you want?
b
On Dec 12, 2006, at 10:59 AM, javier garcia-pintado wrote:
Hi,
I'm trying to use expression() to write a text to a graphic in the
margin.
Using:
mtext(expression(beta),side=1,line=2)
writes a perfect beta greek character, but I need to add a subindex
max, and I'm trying:
mtext(paste(expression(beta),max),side=1,line=2)
simply writes beta max in the plot.
Please, Could you tell me what I'm doing wrong?
By the way, is there a way to add Latex expressions to graphics? Then I
could use the Latex expression: $\beta_{\mathrm{max}}$. This also would
be very useful for me for more complex expressions in plots.
Best regards,
Javier
--
Javier García-Pintado
Institute of Earth Sciences Jaume Almera (CSIC)
Lluis Sole Sabaris s/n, 08028 Barcelona
Phone: +34 934095410
Fax: +34 934110012
e-mail:[EMAIL PROTECTED]
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--
Javier García-Pintado
Institute of Earth Sciences Jaume Almera (CSIC)
Lluis Sole Sabaris s/n, 08028 Barcelona
Phone: +34 934095410
Fax: +34 934110012
e-mail:[EMAIL PROTECTED]
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Re: [R] expression()
On Wed, 13 Dec 2006, javier garcia-pintado wrote: Thanks you, this works right. I just would like to note one thing: although I've found italic() in the help for plotmath and I can see that the italic function: mtext(expression(italic(beta)[max]),side=1,line=2) does not work on the greek beta character. No, and there is no italic symbol font in the R graphics model so no means of plotting such a symbol. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression()
Hi
javier garcia-pintado wrote:
Thanks you,
this works right.
I just would like to note one thing:
although I've found italic() in the help for plotmath and I can see that
the italic function:
mtext(expression(italic(beta)[max]),side=1,line=2)
does not work on the greek beta character.
Though not strictly necessary, this would be perfect for my plots, as I
use them for papers to be published.
Take a look at
http://www.stat.auckland.ac.nz/~paul/Talks/fonts.pdf
(and maybe http://www.stat.auckland.ac.nz/~paul/Talks/fonts.tar.gz)
especially the latter half on mathematical formulas in plots, which
shows an example of using TeX fonts in R plots.
It includes links to further materials and explanations.
Paul
Wishes,
Javier
--
Benilton Carvalho wrote:
mtext(expression(beta[max]), side=1, line=2)
is it what you want?
b
On Dec 12, 2006, at 10:59 AM, javier garcia-pintado wrote:
Hi,
I'm trying to use expression() to write a text to a graphic in the
margin.
Using:
mtext(expression(beta),side=1,line=2)
writes a perfect beta greek character, but I need to add a subindex
max, and I'm trying:
mtext(paste(expression(beta),max),side=1,line=2)
simply writes beta max in the plot.
Please, Could you tell me what I'm doing wrong?
By the way, is there a way to add Latex expressions to graphics? Then I
could use the Latex expression: $\beta_{\mathrm{max}}$. This also would
be very useful for me for more complex expressions in plots.
Best regards,
Javier
--
Javier García-Pintado
Institute of Earth Sciences Jaume Almera (CSIC)
Lluis Sole Sabaris s/n, 08028 Barcelona
Phone: +34 934095410
Fax: +34 934110012
e-mail:[EMAIL PROTECTED]
__
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--
Dr Paul Murrell
Department of Statistics
The University of Auckland
Private Bag 92019
Auckland
New Zealand
64 9 3737599 x85392
[EMAIL PROTECTED]
http://www.stat.auckland.ac.nz/~paul/
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[R] expression()
Hi,
I'm trying to use expression() to write a text to a graphic in the margin.
Using:
mtext(expression(beta),side=1,line=2)
writes a perfect beta greek character, but I need to add a subindex
max, and I'm trying:
mtext(paste(expression(beta),max),side=1,line=2)
simply writes beta max in the plot.
Please, Could you tell me what I'm doing wrong?
By the way, is there a way to add Latex expressions to graphics? Then I
could use the Latex expression: $\beta_{\mathrm{max}}$. This also would
be very useful for me for more complex expressions in plots.
Best regards,
Javier
--
Javier García-Pintado
Institute of Earth Sciences Jaume Almera (CSIC)
Lluis Sole Sabaris s/n, 08028 Barcelona
Phone: +34 934095410
Fax: +34 934110012
e-mail:[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression()
mtext(expression(beta[max]), side=1, line=2)
is it what you want?
b
On Dec 12, 2006, at 10:59 AM, javier garcia-pintado wrote:
Hi,
I'm trying to use expression() to write a text to a graphic in the
margin.
Using:
mtext(expression(beta),side=1,line=2)
writes a perfect beta greek character, but I need to add a subindex
max, and I'm trying:
mtext(paste(expression(beta),max),side=1,line=2)
simply writes beta max in the plot.
Please, Could you tell me what I'm doing wrong?
By the way, is there a way to add Latex expressions to graphics?
Then I
could use the Latex expression: $\beta_{\mathrm{max}}$. This also
would
be very useful for me for more complex expressions in plots.
Best regards,
Javier
--
Javier García-Pintado
Institute of Earth Sciences Jaume Almera (CSIC)
Lluis Sole Sabaris s/n, 08028 Barcelona
Phone: +34 934095410
Fax: +34 934110012
e-mail:[EMAIL PROTECTED]
__
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and provide commented, minimal, self-contained, reproducible code.
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Re: [R] expression()
Hallo, for the first question: mtext(expression(beta[max]),side=1,line=2) and: ?plotmath demo(plotmath) for the second. Hope it helped, Scionforbai __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Expression
Hi all,
I have a question about expression.
In a figure I want to include the term D*obs with the star as as
superscript and obs as subscript. I have even just tried to get the
star to be superscript.
The code I tried was
text(Dstar+7,120,expression(paste({}D,^*))), but that doesn't work and I
get a syntax error.
I can't seem to find anything in the help files that explains it.
Thanks in advance.
Cameron Guenther, Ph.D.
100 8th Ave. SE
St. Petersburg, Fl 33701
727-896-8626 ext. 4305
[EMAIL PROTECTED]
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Re: [R] Expression
Try:
plot(1, main = ~ D[obs]^*)
On 11/30/06, Guenther, Cameron [EMAIL PROTECTED] wrote:
Hi all,
I have a question about expression.
In a figure I want to include the term D*obs with the star as as
superscript and obs as subscript. I have even just tried to get the
star to be superscript.
The code I tried was
text(Dstar+7,120,expression(paste({}D,^*))), but that doesn't work and I
get a syntax error.
I can't seem to find anything in the help files that explains it.
Thanks in advance.
Cameron Guenther, Ph.D.
100 8th Ave. SE
St. Petersburg, Fl 33701
727-896-8626 ext. 4305
[EMAIL PROTECTED]
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Re: [R] Expression
Guenther, Cameron wrote:
The code I tried was
text(Dstar+7,120,expression(paste({}D,^*))), but that doesn't work and I
get a syntax error.
I can't seem to find anything in the help files that explains it.
plot(1:10)
text(8,5,expression(D[obs]^*))
works for me...
Barry
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Re: [R] Expression
Guenther, Cameron wrote:
Hi all,
I have a question about expression.
In a figure I want to include the term D*obs with the star as as
superscript and obs as subscript. I have even just tried to get the
star to be superscript.
The code I tried was
text(Dstar+7,120,expression(paste({}D,^*))), but that doesn't work and I
get a syntax error.
I can't seem to find anything in the help files that explains it.
Well, ?plotmath does say
A mathematical expression must obey the normal rules of syntax for
any R expression, but it is interpreted according to very
different rules than for normal R expressions.
which should at least explain why you get a syntax error from the above
code. Beyond that, you do need to understand how R's syntax rules work,
including at least a feel for how expressions are represented
internally, and how that influences the plotting of expressions.
The easiest solution is probably expression(D^*)
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[R] expression() - Superscript in y-axis, keeping line break in string
I've tried several different ways to accomplish this, but as yet to no avail. My y-axis for a plot has a rather long label, and thus I have been using /n to break it into two lines. However, to make it technically correct for publication, I also need to use superscript in the label. For example: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=14C-glyphosate line1\n line2) will provide the text in two lines as I would like it. However, I am trying to keep those same line breaks when using expression() to get my superscript number. This will not work, as it aligns the 14C section with the bottom line of the expression making little sense to the reader. par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=expression( ^14*C*-glyphosate line1\n line2)) Is there a way to align the 14C portion of the expression with the top line of the string rather than the bottom line? Any suggestions are greatly appreciated. Andrew -- Andrew Kniss Assistant Research Scientist University of Wyoming Department of Plant Sciences [EMAIL PROTECTED] Office: (307) 766-3949 Fax:(307) 766-5549 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression() - Superscript in y-axis, keeping line break in string
On Fri, 2006-08-04 at 09:47 -0600, Andrew Kniss wrote: I've tried several different ways to accomplish this, but as yet to no avail. My y-axis for a plot has a rather long label, and thus I have been using /n to break it into two lines. However, to make it technically correct for publication, I also need to use superscript in the label. For example: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=14C-glyphosate line1\n line2) will provide the text in two lines as I would like it. However, I am trying to keep those same line breaks when using expression() to get my superscript number. This will not work, as it aligns the 14C section with the bottom line of the expression making little sense to the reader. par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=expression( ^14*C*-glyphosate line1\n line2)) Is there a way to align the 14C portion of the expression with the top line of the string rather than the bottom line? Any suggestions are greatly appreciated. Andrew plotmath, as has been covered many times previously, does not support multi-line expressions. A note should probably be added to ?plotmath on this. Thus, you need to create each line in the label separately: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab = ) # Now use mtext() to place each line of the y axis label mtext(2, text = expression( ^14*C*-glyphosate line1), line = 3) mtext(2, text = line2, line = 2) See ?mtext for more information. HTH, Marc Schwartz __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression() - Superscript in y-axis, keeping line break in string
Use atop: plot(1, main = expression(atop( ^14*C*-glyphosate line, line2))) On 8/4/06, Andrew Kniss [EMAIL PROTECTED] wrote: I've tried several different ways to accomplish this, but as yet to no avail. My y-axis for a plot has a rather long label, and thus I have been using /n to break it into two lines. However, to make it technically correct for publication, I also need to use superscript in the label. For example: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=14C-glyphosate line1\n line2) will provide the text in two lines as I would like it. However, I am trying to keep those same line breaks when using expression() to get my superscript number. This will not work, as it aligns the 14C section with the bottom line of the expression making little sense to the reader. par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=expression( ^14*C*-glyphosate line1\n line2)) Is there a way to align the 14C portion of the expression with the top line of the string rather than the bottom line? Any suggestions are greatly appreciated. Andrew -- Andrew Kniss Assistant Research Scientist University of Wyoming Department of Plant Sciences [EMAIL PROTECTED] Office: (307) 766-3949 Fax:(307) 766-5549 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression() - Superscript in y-axis, keeping line break in string
Sorry, you wanted a ylab=, not a main=. Try using xyplot in lattice: library(lattice) xyplot(1~1, ylab = expression(atop(phantom(0)^14*C*-glyphosate line, line2))) On 8/4/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Use atop: plot(1, main = expression(atop( ^14*C*-glyphosate line, line2))) On 8/4/06, Andrew Kniss [EMAIL PROTECTED] wrote: I've tried several different ways to accomplish this, but as yet to no avail. My y-axis for a plot has a rather long label, and thus I have been using /n to break it into two lines. However, to make it technically correct for publication, I also need to use superscript in the label. For example: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=14C-glyphosate line1\n line2) will provide the text in two lines as I would like it. However, I am trying to keep those same line breaks when using expression() to get my superscript number. This will not work, as it aligns the 14C section with the bottom line of the expression making little sense to the reader. par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=expression( ^14*C*-glyphosate line1\n line2)) Is there a way to align the 14C portion of the expression with the top line of the string rather than the bottom line? Any suggestions are greatly appreciated. Andrew -- Andrew Kniss Assistant Research Scientist University of Wyoming Department of Plant Sciences [EMAIL PROTECTED] Office: (307) 766-3949 Fax:(307) 766-5549 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression() - Superscript in y-axis, keeping line break in string
Actually Gabor, using your solution with 'atop', which I had not considered, it will work with base graphics: par(oma = c(0, 0, 2, 0), mar = c(5, 6, 0.25, 2), lheight = 1) plot(1:10, ylab = expression(atop( ^14*C*-glyphosate line1, line2))) HTH, Marc On Fri, 2006-08-04 at 12:09 -0400, Gabor Grothendieck wrote: Sorry, you wanted a ylab=, not a main=. Try using xyplot in lattice: library(lattice) xyplot(1~1, ylab = expression(atop(phantom(0)^14*C*-glyphosate line, line2))) On 8/4/06, Gabor Grothendieck [EMAIL PROTECTED] wrote: Use atop: plot(1, main = expression(atop( ^14*C*-glyphosate line, line2))) On 8/4/06, Andrew Kniss [EMAIL PROTECTED] wrote: I've tried several different ways to accomplish this, but as yet to no avail. My y-axis for a plot has a rather long label, and thus I have been using /n to break it into two lines. However, to make it technically correct for publication, I also need to use superscript in the label. For example: par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=14C-glyphosate line1\n line2) will provide the text in two lines as I would like it. However, I am trying to keep those same line breaks when using expression() to get my superscript number. This will not work, as it aligns the 14C section with the bottom line of the expression making little sense to the reader. par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1) plot(1:10, ylab=expression( ^14*C*-glyphosate line1\n line2)) Is there a way to align the 14C portion of the expression with the top line of the string rather than the bottom line? Any suggestions are greatly appreciated. Andrew __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression() - Superscript in y-axis, keeping line break in string
On Fri, 4 Aug 2006, Marc Schwartz (via MN) wrote:
On Fri, 2006-08-04 at 09:47 -0600, Andrew Kniss wrote:
I've tried several different ways to accomplish this, but as yet to no
avail. My y-axis for a plot has a rather long label, and thus I have
been using /n to break it into two lines. However, to make it
technically correct for publication, I also need to use superscript in
the label. For example:
par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1)
plot(1:10,
ylab=14C-glyphosate line1\n line2)
will provide the text in two lines as I would like it. However, I am
trying to keep those same line breaks when using expression() to get my
superscript number. This will not work, as it aligns the 14C section
with the bottom line of the expression making little sense to the
reader.
par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1)
plot(1:10,
ylab=expression( ^14*C*-glyphosate line1\n line2))
Is there a way to align the 14C portion of the expression with the top
line of the string rather than the bottom line? Any suggestions are
greatly appreciated.
Andrew
plotmath, as has been covered many times previously, does not support
multi-line expressions. A note should probably be added to ?plotmath on
this.
I've added a note. I think what is exact is that control chars are not
interpreted ('expresssion' is an overloaded work in this context).
Thanks for the nudge (and please do continue to make such remarks).
Brian
Thus, you need to create each line in the label separately:
par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1)
plot(1:10, ylab = )
# Now use mtext() to place each line of the y axis label
mtext(2, text = expression( ^14*C*-glyphosate line1), line = 3)
mtext(2, text = line2, line = 2)
See ?mtext for more information.
HTH,
Marc Schwartz
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--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax: +44 1865 272595
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Re: [R] expression() - Superscript in y-axis, keeping line break in string
On Fri, 2006-08-04 at 19:44 +0100, Prof Brian Ripley wrote:
On Fri, 4 Aug 2006, Marc Schwartz (via MN) wrote:
On Fri, 2006-08-04 at 09:47 -0600, Andrew Kniss wrote:
I've tried several different ways to accomplish this, but as yet to no
avail. My y-axis for a plot has a rather long label, and thus I have
been using /n to break it into two lines. However, to make it
technically correct for publication, I also need to use superscript in
the label. For example:
par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1)
plot(1:10,
ylab=14C-glyphosate line1\n line2)
will provide the text in two lines as I would like it. However, I am
trying to keep those same line breaks when using expression() to get my
superscript number. This will not work, as it aligns the 14C section
with the bottom line of the expression making little sense to the
reader.
par(oma=c(0,0,2,0),mar=c(5,6,0.25,2),lheight=1)
plot(1:10,
ylab=expression( ^14*C*-glyphosate line1\n line2))
Is there a way to align the 14C portion of the expression with the top
line of the string rather than the bottom line? Any suggestions are
greatly appreciated.
Andrew
plotmath, as has been covered many times previously, does not support
multi-line expressions. A note should probably be added to ?plotmath on
this.
I've added a note. I think what is exact is that control chars are not
interpreted ('expresssion' is an overloaded work in this context).
Thanks for the nudge (and please do continue to make such remarks).
Brian
snip
Happy to help and thanks for both noticing and taking the time to
incorporate the update.
Best regards,
Marc
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[R] execute R expression from command line
Can I execute an R expression from the command line without having it
in an infile, something like perl's -e flag. So it would look like:
R {Rexpression;} outfile
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Re: [R] execute R expression from command line
On 8 Sep 2005, [EMAIL PROTECTED] wrote:
Can I execute an R expression from the command line without having
it in an infile, something like perl's -e flag. So it would look
like:
R {Rexpression;} outfile
With a bash-like shell, you can do:
echo library(foo); somefunc(5) | R --slave
HTH,
+ seth
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[R] R: expression
hi all i am having a problem with the expression/paste command say we estimate a variable, named PHI it contains the value of say 2 and we want to display this value as hat(phi) = PHI onto a graphic i.e. hat(phi)=2 how does one do this? i've tried the following: 1. legend(-5,.3,expression(hat(phi)*=*PHI)) 2. legend(-5,.3,paste(expression(phi),=,PHI)) but they do not work. any help? / allan__ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R: expression
Clark Allan wrote: hi all i am having a problem with the expression/paste command say we estimate a variable, named PHI it contains the value of say 2 and we want to display this value as hat(phi) = PHI onto a graphic i.e.hat(phi)=2 how does one do this? i've tried the following: 1.legend(-5,.3,expression(hat(phi)*=*PHI)) 2.legend(-5,.3,paste(expression(phi),=,PHI)) See ?plotmath or the Help Desk Article Automation of Mathematical Annotation in Plots in R News 2 (3), 32-34. legend(-5, .3, substitute(hat(phi) == PHI, list(PHI = PHI))) Uwe Ligges but they do not work. any help? / allan __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R: expression
Something like this : x - 0.5 plot( 1:10, main=substitute( hat(Phi) ~ = ~ x, list(x=x) ) ) Also see http://tolstoy.newcastle.edu.au/R/help/04/09/3371.html Regards, Adai On Tue, 2005-07-19 at 13:35 +0200, Clark Allan wrote: hi all i am having a problem with the expression/paste command say we estimate a variable, named PHI it contains the value of say 2 and we want to display this value as hat(phi) = PHI onto a graphic i.e.hat(phi)=2 how does one do this? i've tried the following: 1.legend(-5,.3,expression(hat(phi)*=*PHI)) 2.legend(-5,.3,paste(expression(phi),=,PHI)) but they do not work. any help? / allan __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] R: expression
On Tue, 19 Jul 2005, Uwe Ligges wrote: Clark Allan wrote: hi all i am having a problem with the expression/paste command say we estimate a variable, named PHI it contains the value of say 2 and we want to display this value as hat(phi) = PHI onto a graphic i.e. hat(phi)=2 how does one do this? legend(-5, .3, substitute(hat(phi) == PHI, list(PHI = PHI))) or legend(-5, .3, bquote(hat(phi) == .(PHI))) -thomas Thomas Lumley Assoc. Professor, Biostatistics [EMAIL PROTECTED] University of Washington, Seattle __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Expression in panel.text
Hi,
I've got a lattice xyplot and I want to superimpose correlation
coefficients and p values on each panel. I've been trying to get this
to work using something of the form:
x - rnorm(400)
y - rnorm(400)
a - gl(4, 100)
xyplot(y~x | a,
panel=function(x,y, ...){
panel.xyplot(x,y, ...)
curr.cor - cor.test(x,y)
crho - round(curr.cor$estimate,2)
cpv - format.pval(curr.cor$p.value, eps = 0.01, digits=2)
exprrho - substitute(rho == crho, list(crho=crho))
exprpv - substitute(italic(p) == cpv, list(cpv=cpv))
panel.text(-2, 2, label=exprrho)
panel.text(2, 2, label=exprpv)
})
The two expressions (expprho and exprpv) plot as expected on a normal
text() call but in the panels, all that appears at the coordinates is
==. This is the first element in exprrho; other than that, I can't
figure out what is going wrong.
Any suggestions?
Thanks in advance.
David
version
_
platform powerpc-apple-darwin6.8
arch powerpc
os darwin6.8
system powerpc, darwin6.8
status
major2
minor0.0
year 2004
month10
day 04
language R
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Re: [R] Expression in panel.text
On Friday 22 April 2005 10:12, David Orme wrote:
Hi,
I've got a lattice xyplot and I want to superimpose correlation
coefficients and p values on each panel. I've been trying to get this
to work using something of the form:
x - rnorm(400)
y - rnorm(400)
a - gl(4, 100)
xyplot(y~x | a,
panel=function(x,y, ...){
panel.xyplot(x,y, ...)
curr.cor - cor.test(x,y)
crho - round(curr.cor$estimate,2)
cpv - format.pval(curr.cor$p.value, eps = 0.01, digits=2)
exprrho - substitute(rho == crho, list(crho=crho))
exprpv - substitute(italic(p) == cpv, list(cpv=cpv))
panel.text(-2, 2, label=exprrho)
panel.text(2, 2, label=exprpv)
})
The two expressions (expprho and exprpv) plot as expected on a normal
text() call but in the panels, all that appears at the coordinates is
==. This is the first element in exprrho; other than that, I can't
figure out what is going wrong.
Any suggestions?
I believe this came up a few days back.
exprrho - substitute(rho == crho, list(crho=.12))
is.expression(exprrho)
[1] FALSE
i.e., the label you are using is not an expression. The 'panel.text' you have
didn't take this possibility into account (unlike 'text').
The good news is that this has been fixed in R 2.1.0.
Deepayan
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Re: [R] expression + paste + arguments + ...
[EMAIL PROTECTED] wrote:
dear R wizards: I would like to write a function that roughly places
the equivalent of the following latex text into the current plot:
\newcommand{ \placesigma }[4]{ \put(\#1,\#2){ \sigma_{A , #3} = #4 }
???
You are just defining a new LaTeX command ... nothing will be printed
in LaTeX.
Instead of using \put, you can specify coordinates as usual in R using
text(), title() or mtext().
Instead of \sigma_{A , #3} = #4, you can use
substitute(sigma[v3] == v4, list(v3 = paste(A,,v3), v4 = v4))
which leads to, e.g.
plot(1:10)
v3 - 99
v4 - 55
text(4, 1, label = substitute(sigma[v3] == v4,
list(v3 = paste(A,,v3), v4 = v4)))
See also ?plotmath and the R Help Desk Column in R News 2 (3).
Uwe Ligges
I cannot figure out how to do this. I know I have to use a function
that uses expressions in a text() invoke. But passing arguments and
nesting strings and expressions has so far not worked for me. I hope
this is an obvious question---if not, please just tell me and I can give
up. help appreciated.
sincerely,
/iaw
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[R] expression + paste + arguments + ...
dear R wizards: I would like to write a function that roughly places
the equivalent of the following latex text into the current plot:
\newcommand{ \placesigma }[4]{ \put(\#1,\#2){ \sigma_{A , #3} = #4 }
I cannot figure out how to do this. I know I have to use a function
that uses expressions in a text() invoke. But passing arguments and
nesting strings and expressions has so far not worked for me. I hope
this is an obvious question---if not, please just tell me and I can
give up. help appreciated.
sincerely,
/iaw
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Re: [R] expression + paste + arguments + ...
I don't know latex, but have you looked at ?plotmath, including
'demo(plotmath)', the examples in the documentation, and an R site
search suggested in the posting guide
(http://www.R-project.org/posting-guide.html)? What you want is
probably fairly easy, once you parse the plotmath documentation. hope
this helps. spencer graves
[EMAIL PROTECTED] wrote:
dear R wizards: I would like to write a function that roughly places
the equivalent of the following latex text into the current plot:
\newcommand{ \placesigma }[4]{ \put(\#1,\#2){ \sigma_{A , #3} = #4 }
I cannot figure out how to do this. I know I have to use a function
that uses expressions in a text() invoke. But passing arguments and
nesting strings and expressions has so far not worked for me. I hope
this is an obvious question---if not, please just tell me and I can
give up. help appreciated.
sincerely,
/iaw
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[R] expression with running index
Hi, I need a list of expression of the form expression(b[i]), where i is a running index. So for example, if i - -1:2, I would like to have a list equivalent to list(expression(b[-1]), expression(b[0]), expression(b[1]), expression(b[2])) i might be a character vector (like c(f, g, h)) Could somebody help me out by writing a function that produces the list above for a given string in place of b and a vector of subscripts? Sorry if this has been discussed before, I tried searching the archives but expression as a keyword gives too many results on different subjects. Thanks, Tamas -- Tamás K. Papp E-mail: [EMAIL PROTECTED] Please try to send only (latin-2) plain text, not HTML or other garbage. __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] expression with running index
Tamas Papp wrote: Hi, I need a list of expression of the form expression(b[i]), where i is a running index. So for example, if i - -1:2, I would like to have a list equivalent to list(expression(b[-1]), expression(b[0]), expression(b[1]), expression(b[2])) i might be a character vector (like c(f, g, h)) Could somebody help me out by writing a function that produces the list above for a given string in place of b and a vector of subscripts? Sorry if this has been discussed before, I tried searching the archives but expression as a keyword gives too many results on different subjects. Thanks, Tamas For example: lapply(as.double(-1:2), function(x) substitute(b[i], i = list(i=x))) Uwe Ligges __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] expression with running index
lapply(-1:2, function(i) substitute(expression(b[i]), list(i=i))) would be a good start. (Note that what it gives is [[1]] expression(b[as.integer(-1)]) which is not what you asked for but is what I think you intended. Then we can elaborate this to f - function(ind, vec) lapply(ind, function(i, vec) substitute(expression(vec[i]), list(i=i, vec=vec)), vec=as.name(vec)) f(-1:2, b) and f(c(f, g, h), b) both work Also, I am not sure you need the expression() in there, as without it you have a language call which will almost certainly do. On Sun, 25 Apr 2004, Tamas Papp wrote: Hi, I need a list of expression of the form expression(b[i]), where i is a running index. So for example, if i - -1:2, I would like to have a list equivalent to list(expression(b[-1]), expression(b[0]), expression(b[1]), expression(b[2])) i might be a character vector (like c(f, g, h)) Could somebody help me out by writing a function that produces the list above for a given string in place of b and a vector of subscripts? Sorry if this has been discussed before, I tried searching the archives but expression as a keyword gives too many results on different subjects. -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ [EMAIL PROTECTED] mailing list https://www.stat.math.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] expression for simple EM
Dear R users, I know this is the wrong forum for such a question but I need help. I would like to write down the likelihood expression for a simple EM problem. I have one categorical covariate with 5 levels and a missing count which can fall in any of the categories. I know the solution to the problem but can't seem to get the likelihood expression correct (if it is possible). Thanks. Vumani Dlamini, Student Faculty of Health Sciences University of Natal __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
