[R] hist function to give each cell equal area
Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
RE: [R] hist function to give each cell equal area
how about: x - rnorm(400) nbin-7 hist(x,breaks=quantile(x,prob=seq(0,1,length=nbin+1))) Bendix Carstensen -- Bendix Carstensen Senior Statistician Steno Diabetes Center Niels Steensens Vej 2 DK-2820 Gentofte Denmark tel: +45 44 43 87 38 mob: +45 30 75 87 38 fax: +45 44 43 07 06 [EMAIL PROTECTED] www.biostat.ku.dk/~bxc -- -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Dan Bolser Sent: Friday, January 07, 2005 11:21 AM To: R mailing list Subject: [R] hist function to give each cell equal area Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] hist function to give each cell equal area
On Fri, 7 Jan 2005, Dan Bolser wrote: Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) It's not that magic, but such points are usually called quantiles in statistics... For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) quantile(x, 0:3/3, type = 1) hth, Z Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] hist function to give each cell equal area
Dan Bolser [EMAIL PROTECTED] writes: Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) Is there such a function? Probably not giving pretty numbers, but quantile() gets you most of the way quantile(x,seq(0,1,1/3)) hist(x,breaks=quantile(x,seq(0,1,1/3))) table(cut(x,breaks=quantile(x,seq(0,1,1/3 obviously, with that distribution you have to be a little careful: hist(x,breaks=quantile(x)) does look somewhat different... -- O__ Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] hist function to give each cell equal area
On Fri, 7 Jan 2005, Dan Bolser wrote: Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. ?quantile Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) hist(x, quantile(x, seq(0,1,1/3))) isn't the same, but your breaks are arbitrary and based on knowing where the gaps are. Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html -- Roger Bivand Economic Geography Section, Department of Economics, Norwegian School of Economics and Business Administration, Breiviksveien 40, N-5045 Bergen, Norway. voice: +47 55 95 93 55; fax +47 55 95 93 93 e-mail: [EMAIL PROTECTED] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
RE: [R] hist function to give each cell equal area
On Fri, 7 Jan 2005, BXC (Bendix Carstensen) wrote: how about: x - rnorm(400) nbin-7 hist(x,breaks=quantile(x,prob=seq(0,1,length=nbin+1))) Thanks for the replies! Quantiles are my new friend. Its true the example I gave was a bit tricky, I just wanted to get the idea over. One thing that is slightly confusing (probably a slight syntax thing), combining the above with the reply from Peter Dalgaard... nbin-10 x - rnorm(400) hist(x,breaks=quantile(x,prob=seq(0,1,length=nbin+1))) y - table(cut(x,breaks=quantile(x,seq(0,1,length=nbin+1 y [1] 399 I only get 399 counts out, and I put 400 counts in? Cheers, Dan. Bendix Carstensen -- Bendix Carstensen Senior Statistician Steno Diabetes Center Niels Steensens Vej 2 DK-2820 Gentofte Denmark tel: +45 44 43 87 38 mob: +45 30 75 87 38 fax: +45 44 43 07 06 [EMAIL PROTECTED] www.biostat.ku.dk/~bxc -- -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Dan Bolser Sent: Friday, January 07, 2005 11:21 AM To: R mailing list Subject: [R] hist function to give each cell equal area Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
RE: [R] hist function to give each cell equal area
On Fri, 7 Jan 2005, Dan Bolser wrote: On Fri, 7 Jan 2005, BXC (Bendix Carstensen) wrote: how about: x - rnorm(400) nbin-7 hist(x,breaks=quantile(x,prob=seq(0,1,length=nbin+1))) Thanks for the replies! Quantiles are my new friend. Its true the example I gave was a bit tricky, I just wanted to get the idea over. One thing that is slightly confusing (probably a slight syntax thing), combining the above with the reply from Peter Dalgaard... nbin-10 x - rnorm(400) hist(x,breaks=quantile(x,prob=seq(0,1,length=nbin+1))) y - table(cut(x,breaks=quantile(x,seq(0,1,length=nbin+1 y [1] 399 I only get 399 counts out, and I put 400 counts in? y - table(cut(x,breaks=quantile(x,seq(0,1,length=nbin+1)), +include.lowest = TRUE)) It's the include.lowest= argument to cut() Cheers, Dan. Bendix Carstensen -- Bendix Carstensen Senior Statistician Steno Diabetes Center Niels Steensens Vej 2 DK-2820 Gentofte Denmark tel: +45 44 43 87 38 mob: +45 30 75 87 38 fax: +45 44 43 07 06 [EMAIL PROTECTED] www.biostat.ku.dk/~bxc -- -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Dan Bolser Sent: Friday, January 07, 2005 11:21 AM To: R mailing list Subject: [R] hist function to give each cell equal area Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like this... x - c( 1:5, 10+1:5, 100+1:5 ) the breaks would define cells like this hist(x,breaks=c(0,5,15,105)) Is there such a function? __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html -- Roger Bivand Economic Geography Section, Department of Economics, Norwegian School of Economics and Business Administration, Breiviksveien 40, N-5045 Bergen, Norway. voice: +47 55 95 93 55; fax +47 55 95 93 93 e-mail: [EMAIL PROTECTED] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] hist function to give each cell equal area
Dan Bolser [EMAIL PROTECTED] writes: y - table(cut(x,breaks=quantile(x,seq(0,1,length=nbin+1 y [1] 399 I only get 399 counts out, and I put 400 counts in? Look at the include.lowest argument. For some reason this is TRUE in hist() but FALSE in cut(). -- O__ Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
