Re: [R] lme: reproducing example

2003-12-03 Thread Karl Knoblick
Thanks!
I think the minor differences taking the values with
rnorm result of the homogen distribution without an
effect. But the results of aov and lme should be
similiar for data with effects, too (at least for
simple and balanced designs).

Karl

 --- Pascal A. Niklaus [EMAIL PROTECTED]
schrieb:  Karl Knoblick wrote:
 
 Dear R-community!
 
 I still have the problem reproducing the following
 example using lme.
 
 id-factor(rep(rep(1:5,rep(3,5)),3))
 factA - factor(rep(c(a1,a2,a3),rep(15,3)))
 factB - factor(rep(c(B1,B2,B3),15))
 Y-numeric(length=45)
 Y[ 1: 9]-c(56,52,48,57,54,46,55,51,51)
 Y[10:18]-c(58,51,50,54,53,46,54,50,49)
 Y[19:27]-c(53,49,48,56,48,52,52,52,50)
 Y[28:36]-c(55,51,46,57,49,50,55,51,47)
 Y[37:45]-c(56,48,51,58,50,48,58,46,52)
 df-data.frame(id, factA, factB, Y) 
 df.aov - aov(Y ~ factA*factB + Error(factA:id),
 data=df)
 summary(df.aov)
 
 Is there a way to get the same results with lme as 
 with aov with Error()? HOW???
 
 One idea was the following:

df$factAid=factor(paste(as.character(df$factA),:,as.character(df$id),sep=))
 df.lme -

lme(Y~factA*factB,df,random=~1|factAid,method=REML)
 
 The degrees of freedom look right, but the F values
 don't match aov.
 
 Hope somebody can help! Thanks!!
 
 Karl
   
 
 Hmmm, strange, it works if I use factB:id as plot...
 it also works when 
 I use factA:id as plot and replace your Y's by
 random numbers... is this 
 a problem with convergence?
 
 Pascal
 
 
   df$Y=rnorm(45)
   summary(aov(Y ~ factB*factA +
 Error(id:factA),data=df))
 
 Error: id:factA
   Df  Sum Sq Mean Sq F value Pr(F)
 factA  2  2.9398  1.4699  0.9014 0.4318
 Residuals 12 19.5675  1.6306
 
 Error: Within
 Df  Sum Sq Mean Sq F value   Pr(F)
 factB2  7.1431  3.5716  7.4964 0.002956 **
 factB:factA  4  4.2411  1.0603  2.2254 0.096377 .
 Residuals   24 11.4345  0.4764
 ---
 Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.'
 0.1 ` ' 1
 
   anova(lme(Y ~ factB*factA ,data=df, random = ~ 1
 | plot))
 numDF denDF  F-value p-value
 (Intercept) 124 0.014294  0.9058
 factB   224 7.496097  0.0030
 factA   212 0.901489  0.4318
 factB:factA 424 2.225317  0.0964
 
 Pascal
 
 
   summary(aov(Y ~ factA*factB + Error(factB:id)))
 
 Error: factB:id
   Df Sum Sq Mean Sq F valuePr(F)
 factB  2 370.71  185.36  51.488 1.293e-06 ***
 Residuals 12  43.203.60
 ---
 Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.'
 0.1 ` ' 1
 
 Error: Within
 Df Sum Sq Mean Sq F value  Pr(F)
 factA2  9.911   4.956  1.6248 0.21788
 factA:factB  4 45.556  11.389  3.7341 0.01686 *
 Residuals   24 73.200   3.050
 
   df$plot - factor(paste(df$factB,df$id))
   anova(lme(Y ~ factB*factA , data=df, random = ~1
 | plot))
 numDF denDF  F-value p-value
 (Intercept) 124 33296.02  .0001
 factB   21251.47  .0001
 factA   224 1.63  0.2178
 factB:factA 424 3.73  0.0168
  


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[R] lme: reproducing example

2003-12-02 Thread Karl Knoblick
Dear R-community!

I still have the problem reproducing the following
example using lme.

id-factor(rep(rep(1:5,rep(3,5)),3))
factA - factor(rep(c(a1,a2,a3),rep(15,3)))
factB - factor(rep(c(B1,B2,B3),15))
Y-numeric(length=45)
Y[ 1: 9]-c(56,52,48,57,54,46,55,51,51)
Y[10:18]-c(58,51,50,54,53,46,54,50,49)
Y[19:27]-c(53,49,48,56,48,52,52,52,50)
Y[28:36]-c(55,51,46,57,49,50,55,51,47)
Y[37:45]-c(56,48,51,58,50,48,58,46,52)
df-data.frame(id, factA, factB, Y) 
df.aov - aov(Y ~ factA*factB + Error(factA:id),
data=df)
summary(df.aov)

Is there a way to get the same results with lme as 
with aov with Error()? HOW???

One idea was the following:
df$factAid=factor(paste(as.character(df$factA),:,as.character(df$id),sep=))
df.lme -
lme(Y~factA*factB,df,random=~1|factAid,method=REML) 
The degrees of freedom look right, but the F values
don't match aov.

Hope somebody can help! Thanks!!

Karl

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Re: [R] lme: reproducing example

2003-12-02 Thread Pascal A. Niklaus
Karl Knoblick wrote:

Dear R-community!

I still have the problem reproducing the following
example using lme.
id-factor(rep(rep(1:5,rep(3,5)),3))
factA - factor(rep(c(a1,a2,a3),rep(15,3)))
factB - factor(rep(c(B1,B2,B3),15))
Y-numeric(length=45)
Y[ 1: 9]-c(56,52,48,57,54,46,55,51,51)
Y[10:18]-c(58,51,50,54,53,46,54,50,49)
Y[19:27]-c(53,49,48,56,48,52,52,52,50)
Y[28:36]-c(55,51,46,57,49,50,55,51,47)
Y[37:45]-c(56,48,51,58,50,48,58,46,52)
df-data.frame(id, factA, factB, Y) 
df.aov - aov(Y ~ factA*factB + Error(factA:id),
data=df)
summary(df.aov)

Is there a way to get the same results with lme as 
with aov with Error()? HOW???

One idea was the following:
df$factAid=factor(paste(as.character(df$factA),:,as.character(df$id),sep=))
df.lme -
lme(Y~factA*factB,df,random=~1|factAid,method=REML) 
The degrees of freedom look right, but the F values
don't match aov.

Hope somebody can help! Thanks!!

Karl
 

Hmmm, strange, it works if I use factB:id as plot... it also works when 
I use factA:id as plot and replace your Y's by random numbers... is this 
a problem with convergence?

Pascal

 df$Y=rnorm(45)
 summary(aov(Y ~ factB*factA + Error(id:factA),data=df))
Error: id:factA
 Df  Sum Sq Mean Sq F value Pr(F)
factA  2  2.9398  1.4699  0.9014 0.4318
Residuals 12 19.5675  1.6306
Error: Within
   Df  Sum Sq Mean Sq F value   Pr(F)
factB2  7.1431  3.5716  7.4964 0.002956 **
factB:factA  4  4.2411  1.0603  2.2254 0.096377 .
Residuals   24 11.4345  0.4764
---
Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
 anova(lme(Y ~ factB*factA ,data=df, random = ~ 1 | plot))
   numDF denDF  F-value p-value
(Intercept) 124 0.014294  0.9058
factB   224 7.496097  0.0030
factA   212 0.901489  0.4318
factB:factA 424 2.225317  0.0964
Pascal

 summary(aov(Y ~ factA*factB + Error(factB:id)))

Error: factB:id
 Df Sum Sq Mean Sq F valuePr(F)
factB  2 370.71  185.36  51.488 1.293e-06 ***
Residuals 12  43.203.60
---
Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
Error: Within
   Df Sum Sq Mean Sq F value  Pr(F)
factA2  9.911   4.956  1.6248 0.21788
factA:factB  4 45.556  11.389  3.7341 0.01686 *
Residuals   24 73.200   3.050
 df$plot - factor(paste(df$factB,df$id))
 anova(lme(Y ~ factB*factA , data=df, random = ~1 | plot))
   numDF denDF  F-value p-value
(Intercept) 124 33296.02  .0001
factB   21251.47  .0001
factA   224 1.63  0.2178
factB:factA 424 3.73  0.0168

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